Practicing with 6th Standard Maths Question Paper with Answers Kerala Syllabus and 6th Standard Maths Annual Exam Model Question Paper will help students prepare effectively for their upcoming exams.
Class 6 Maths Annual Exam Model Question Paper Kerala Syllabus
Time : 2 Hours
Total Score : 60
Activity – I
a) Draw a circle with shaded portion 3/5 parts
Answer:
\(\frac{3}{5}\) part of circle
Angle for division = \(\frac{360}{5}\) = 72°
b) Draw a diagram using the given measures.
Answer:
Activity – II
a) One of the linear pair measures 75°. Give the other angle.
Answer:
Sum of Angles of linear pair makes 180°
One angle = 75°
Other angle = 180° – 75° = 105°
b) From the figure give all other measures.
Answer:
∠POB = 180° – (90° + 15°) = 75°
∠AOQ = 75° (∴ Opposite angle)
∠QOB = 180° – 75°= 105°
or ∠QOB = ∠AOP (∴ Opposite angle)
c) One pair of linear pair and opposite angles.
Answer:
Linear pair ∠POB, ∠BOQ
Opposite angle ∠POB, ∠AOQ
d) Specialities of linear pair & opposite angles.
Answer:
The opposite angles formed by two lines crossing each other are equal.
Sum of angles of linear pair are 180°.
Two angles likes nearby as a part of a line, the sum of the angles on either side is 180° is called linear pair.
Activity – III
Height of 5 students are given 1.45cm, 1.5 cm, 1.46cm, 1.42cm. 1.40cm.
a) What is the average height.
Answer:
Average = \(\frac{\text { Sum of the values }}{\text { No. of values }}\)
= \(\frac{1.45+1.5+1.46+1.42+1.4}{5}\)
= \(\frac{7.23}{5}\) = 1.446 cm
b) Average weight is 36.25kg. What is the total weight.
Answer:
Average body weight = 36.25
No. of students = 5
Total weight = 36.25 × 5
= 181.25 kg
c) Write the height in ascending order
Answer:
1.4, 1.42, 1.45, 1.46, 1.5
Activity – IV
a) 2 × 2 × 3 × 3 is the prime factors of a number. What is the number.
Answer:
2 × 2 × 3 × 3 = 36
∴ number is 36
b) Give any two factor pairs of this number.
Answer:
(2, 18) (4, 9)
c) Without making factor table find out the number of factors and explain the method.
Answer:
\(\frac{2 \times 2 \times 3 \times 3}{P_1} \frac{3 \times 3}{P_2}\)
Number of factors
N = (P1 + 1)(P2 + 1)
[Here P1 and P2 are number of factors of 2 and 3 respectively]
= 3 × 3 = 9 factors
The prime factors are 2 × 2 × 3 × 3
1st group of factors (1, 2, 4) – 3
Now group that of 3 – (1, 3, 9)
Multiplies of 2 × 3, 2 × 9, 4 × 3, 4 × 9, 1 × 1 etc
∴ Number of factor formed = 3 × 3 = 9
Activity – V
Salary is divided as shown in the figure Education -10%, Dress 10%, saving – 20% Entertainment – 5%, Others – 10%. Rest is used for food. Total salary is Rs. 30000/-.
a) How much amount is used for food
Answer:
Total salary = Rs.30000
Amount of Percent for food
=100 – (20 + 10 + 10 + 10 + 5)
= 100 – 55
= 45%
Rupees for food = 45% of 30000
= \(\frac{45}{100}\) × 30000
= 13, 500/-
b) What part is used for education.
Answer:
Education = 10% = \(\frac{10}{100}\)
= \(\frac{1}{10}\) Part of salary
c) What fraction is used for saving.
Answer:
Savings = 20% of 30000
= \(\frac{20}{100}\) × 30000
= Rs. 6000
20% = \(\frac{20}{100}=\frac{2}{10}=\frac{1}{5}\) = part or
\(\frac{6000}{3000}=\frac{6}{30}=\frac{2}{10}=\frac{1}{5}\) part
∴ \(\frac{1}{5}\) fraction is used for savings.
Activity – VI
a) Calculate other angles if ∠APC = ∠BPD.
Answer:
∠BPE = 90°
∠BPF = 90° – 30° = 60°
∠APE = 90°
∠BPF = ∠APC = 60° (∵ opposite angles)
∠APC = ∠BPD =60°
∠CPD =180° – (∠APC + ∠BPD)
= 180° – (60° + 60°)
= 180°- 120°
= 60°
Activity – VII
a) Calculate the perimeter of the given figure.
Answer:
Perimeter = 2 (length + breadth)
= 2 (7 + 3)
= 20 cm
b) If P, l, b are the denomination the relate them with respect of the figure.
Answer:
Perimeter = P, length = 1, breadth = b Relation connecting them – P = 2 (/+b)
c) If ∠P, ∠Q, ∠R, ∠S are the angles formed when two diagonals are cross over connect the relation.
Answer:
∠P + ∠Q + ∠R + ∠S = 360°
∠P = ∠Q, ∠R = ∠S
∠p + ∠R = 180° = ∠Q+ ∠s
Activity – VIII
The cultivation ofRamu’s field is given in bar graph. Analyse and answer the following questions.
Scale limit = 10 kg
1) In which of the months same yield is obtained
Answer:
July, October
2) Heighest harvest is in which month.
Answer:
August
3) Which is the month with least performance.
Answer:
Septmeber
4) What are the things to mind while preparing bar graph.
Answer:
All bars should be of equal size
All of the bars should be equidistant.
Scale that is used should be mentioned on the diagram.