Prasanna

Kerala Plus One Zoology Model Question Paper 2

Time: 1 Hours
Cool off time : 10 Minutes
Maximum : 30 Scores

General Instructions to candidates

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

QUESTIONS

Questions 1-3. Answers all questions. Each question carries 1 score.

Question 1.
Choose the correctly matched pair.

a. Collagen fibres – connective tissue
b. Axon – Walls of blood vessels
c. Squamous epithelium – Neuron

Question 2.
From the following list, pick out the en-zyme, that takes part in carbohydrate digestion.
(Salivary amylase, peptidase, lipase, carboxypeptidase)

Question 3.
Diagram of a joint is given below :

Questions 4-14. Answers any 9 questions. Each question carries 2 score.

Question 4.

Question 5.
Classify the organisms below based on segmentation :
a. Ascaris
b. Taenia
c. Fasciola
d. Wuchereria
e. Neries
f. Pheretima

Question 6.
Observe the figure. No need to redraw the figure.

Label A and B and write the function of A and B.

Question 7.
Complete each of the following sen ten- ces using appropriate words.

a. Ascending limb of Henle’s loop is …. to water whereas the descending limb is …… to water.
b. An excessive loss of fluid from the body stimulates the hypothalamus to release …….. hormone from the ………….

Question 8.
“The functioning of human kidney is e f- feiciency monitored and regulated by hor-monal actions of hypothalamus is pituitary, JGAand to a certain extent by heart.”
a. Do you agree with this statement?
b. Justify your answer with suitable rea- sons.

Question 9.
Answer the following in a few words.
a. Significance of pulmonary circulatior I in man.
b. Function of erythrocytes
c. Pacemaker for a human heart and its significance.
d. Normal blood pressure of human beings and its variation during hypertension.

Question 10.
The output of urine increases in cold days while decreases in hot and sunny days. Can you give a reason for this phenom¬enon as realized from the graph given below?

Question 11.
Your Biology teacher exhibited a labora-tory specimen in the classroom. Based on which features will you distinguish it as a chordate or a nonchordate ?

Question 12.
Give two examples for each of the following :
a. Synovial joints
b. Muscular proteins

Question 13.
Distinguish between cofactor and coenzyme with an example for each.

Question 14.
The male and female cockroaches can be identified by the difference in their mor-phological features.
a. Name this phenomenon.
b. Give one external difference between males and females.

Questions 15 – 18. Answers any3 questions. Each question carries 3 scores.

Question 15.
Observe the graph showing the activity of an enzyme influenced by pH.

a. Name the possible enzyme involved in this reaction. [1/2]
b. Where is its site of action? [1/2]
c. Mention any other factor which affects this enzyme activity that results in a similar pattern of graph.
d. Name another Similar enzyme acting on the same substrate.

Question 16.
Observe the organization chart given be¬low and fill appropriately. No need to redraw the chart.

Question 17.
0bserve the structural representation of the muscle given below.

a. Which among this represents the con-tracted state? [1/2 + 1/2]
b. Name the parts labelled as A, B and C.

Question 18.
Longitudinal section of the human heart showing internal structure is given below. Observe the diagram and answer the following questions. Redraw the diagram and label the parts marked as A, B, C.

ANSWERS

Answer 1.
a

Answer 2.
Salivary amylase

Answer 3.
Hinge joint or synovial joint

Answer 4.
Cold blooded animal – Shark
Living fossil – Limulus
Egg laying mammal – Platypus
Water vascular system – Sea Cucumber

Answer 5.

True Seqmentation	False Seqmentation	No Seqmentation
Neries Pheretime	Taenia	Ascaris Fasciola Wucheraria

Answer 6.
A – Proximal convoluted tubule: Reab-sorb major part of electrolytes, essential nutri¬ents and water.
B – Collecting duct: Reabsorb water and urea. It also secrete H+ and K+ ions.

Answer 7.
a. Impermeable, permeable
b. ADH (Anti Diuretic Hormone), ditaitary

Answer 8.
a. Yes
b. ADH fecilites water reabsorption from tubule, there by preventing diuresis. ADH can also affect the kidney function by its constrictory effect on vessel. This cause an increase in blood pressure.

Renin-Angiotensin Mechanism.

Decreased blood pressure → Kidney Renin → Liver → Anglotensiongen → Angiotensin l

Answer 9.
a. For purification of blood, ie., release of CO₂ and intake of O₂.
b. For the gas transport of O₂ and CO₂.
c. SA node or sinu-auricular node, the area where cardiac impulse starts.
d. 80/120 mmHg is the normal blood pressure 80mmHg is the diastolic pressure. 120 mmHg is the systolic pressure. Above normal BP is called Hypertension.

Answer 10.
When temperature increases ADH level increases ADH hormone increase re-absorption of water form urine as a re¬sult only small quantity of urine is produced.

Answer 11.
Animals with notochord are called chordates and those animals which do not form this structure are called non-chordates, e. g., porifera to echinoderms.

Answer 12.
a. Synovial joint – Hinge joint (knee joint)
b. Muscular protein – Troponin

Answer 13.
Cofacter: Non protein part of enzyme,
eg., Zinc in carboxy peptidase.
Co-enzyme : Organic compound that bound to apoenzyme loosely, eg., NAD.

Answer 14.
a. Sexual dimorphism.
b. In male, short thread like anal styles present. In females, it is absent.

Answer 15.
a. Salivary amylase
b. Buccal cavity
c. Temperature or substrate concentration
d. Pancreatic amylase or intestinal amylase

Answer 16.
a. Axial skeleton – 80
b. Vertebral column – 26
c. Ribs-12 pairs
d. Sternum – 1

Answer 17.
a. II
b. A – Z-line,
B – H-zone,
C- Myosin

Answer 18.
A – Aorta
B – Semilunar valve
C – Left ventricle

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Zoology Model Question Paper 1

Time: 1 Hours
Cool off time : 10 Minutes
Maximum : 30 Scores

General Instructions to candidates

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provied.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

QUESTIONS

Questions 1-3. Answers all questions. Each question carries 1 score.

Question 1.
Rearrange the following flowchart in the correct sequence.

Question 2.
Note the relationship between the first two words and suggest words for the fourth place.
Collection of living plants: Botanical garden. Animals kept in protected environment : ……………..

Question 3.
Pick out the acoelomate organism from the folllowing.

1. Roundworm
2. Hookworm
3. Filarial worm
4. Tapeworm

Questions 4-14. Answers any 9 questions. Each question carries 2 score.

Question 4.
Identify the protein structures, (A) and (B) from the following figure.

Question 5.
Arrange the following words into two groups and give appropriate heading to each group.

Testes, oviduct, cloaca, Bidder’s canal, ova¬ries, urinogenital duct, vasa efferen-tia, cloaca.

Question 6.
You may have an experience of sudden withdrawal of body parts when you come in contact with objects that are extre-mely cold. This response occurs invol- untarily With out conscious efforts
a. Name the process behind this. [1/2]
b. Construct a flowchart showing the path way of impulses during this process.[1/2]

Question 7.
After diagnosing the blood of a foetus, a doctor comments that the foetus has some immunological diseases and it may be due to the malfunctioning of an endocrine gland.
a. Name the gland. [1/2]
b. Which are the hormones produced by this gland?

Question 8.
‘During the advengturous trip a plus one student got a skull and skeletal part of rare animal from the Chinnar forest.
Select the suitable location for keeping it from the list of taxonomic aids given below. (Herbarium, Museum, Zoological park, Botanical garden)

Question 9.
A schematic sketch representing the ali-mentary canal of a cockroach is given be¬low. Fill the boxes with the appropria-te organs from the list. No need to redraw the diagram.

Question 10.
Observe the diagram :

a. Lable the parts A and B [1]
b. Even though concentrated HCl is stored in the stomach, it will not generally damage the stomach wall. Why? [1]

Question 11.
Hormonal abnormality is responsible for certain diseases in main. List of some diseases are given below. Write the hormone related to eash of it.

(a) Diabetes mellitus
(b) Gigantism
(c) Diabetes insipidus
(d) Cretinism

Question 12.
Observe the following representation and fill up the blanks appropriately.

Question 13.
Name the phyla in which the following cells/ structures/organs are present

a. Radula
b. Cnidoblast
c. Pneumatic bone
d. Proboscis gland

Question 14.
Name the distinctive character (responsible for their names) of the following animal groups.

a. Cnidaria
b. Arthropoda
c. Porifera
d. Annelida
e. Chordata
f. Ctenophora

Questions 15 – 18. Answers any3 questions. Each question carries 3 scores.

Question 15.
Fill the table appropriately

Question 16.
Observe the molecule given below and answer the following questions.

a. Identify the molecule.
b. Label 1 and 2.
c. Mention any three structural details of the molecule shown in the diagram.

Question 17.

a. Identify this compound. [1/2]
b. Name the bond produced when another biomolecule of the same category combines with this. [1/2]
c. If a number of such molecules are bonded together, what will be the resultant molecule? [1/2]

Question 18.
During a seashore visit, a student collected two organisms. Observing the mor-phology, it is clear that the organisms are radially symmetrical. One of them shows bioluminescence.
a. To which phylum does this organism belong? [1]
b. Identify the possible phyla to which the other organism can be included. [1]
c. Which distinctive feature of this organism will help you to categorize it into a particular phylum? [1]

ANSWERS

Answer 1.
SA Node →AV Node → Atrial contraction →AV Bundles →Ventricle contraction

Answer 2.
Zoological park

Answer 3.
Tape worm

Answer 4.
A – Protein secondary structure or Helical
B – Protein tertiary structure or 3D

Answer 5.

Answer 6.
a.Reflex action
b. Receptor → Sensory (afferent) neuron → Inter neuron → Motor neuron (efferent) neuron → Effector.

Answer 7.
a. Thymus gland
b. Thymosin

Answer 8.
Herbarium, Museum

Answer 9.
a. Salivary gland
b. Crop
c. Gizzard
d. Hepatic caeca
e. Malpighian tubule
f. Rectum

Answer 10.
a. A-Cardiac stomach,
B – Pyloric stomach
b. Mucus layer in stomach and bicarbonate present in gastric juice protects stomach wall.

Answer 11.
a. Insulin
b. Growth hormone / GH / STH.
c. ADH / Vassopressin
d. Thyroxine / T₄, T₃

Answer 12.
A – secondary metabolites
B – amino acids
C – pigments

Answer 13.
a. Mollusca
b. Cnidaria / Coelenterata
c. Chordata / Aves – Birds
d. Hemichordata

Answer 14.
a. Cnidaria – Presence of Cnidoblast
b. Arthropoda – Joint footed animals
c. Porifera – Body contains pores
d. Annelida – Rings on body
e. Chordata – Notochord bearing animals
f. Ctenofora – Comb plates

Answer 15.
a. Secretion of pancreatic enzyme and bile juice.
b. Juxtaglomerular cells of kidney
c. Atrial natriuretic factor
d. Thyroid gland

Answer 16.
a. Structure of DNA

b. 1. Thymine
2. Hydrogen bond

c. Sugar phosphate back bone is present. Adenine pairs with thymine by 2 hydrogen bond. Guanine pairs with cytosine by 3 hydrogen bond.

Answer 17.
a. Amino acid
b. Peptide bond
c. Protein

Answer 18.
a. Phylum – Ctenophara
b. Phylum – Echinodermata
c. Bioluminescence

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Zoology Previous Year Question Paper 2017

Time : 1 Hours
Cool off time : 10 Minutes
Maximum : 30 Scores

General Instructions to candidates

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further there is ‘5 minutes’ ‘Preparatory Time’ at the end of the Botany Examination and before the commencement of Zoology Examination.
• Your are not allowed to write your answers nor to discuss anything with others during the ‘cool off time’ and ‘Preparatory time’.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read questions carefully before answering.
• All questions are compulsory and only internal choice is allowed.
• When you select a question, all the sub questions must be answered from the same question itself.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

QUESTIONS

Question 1.
Select the correct sequence of taxonomic hierarchy.

a. Kingdom – Phylum – Class – Order – Genus – Family -Species.
b. Kingdom – Phylum – Order – Class – Family- Genus – Species
c. Kingdom – Phylum – Class – Order- Family – Genus – Species
d. Kingdom – Class – Phylum – Family Order- Species – Genus

Question 2.
In cockroach spiracles are present in

a. Alimentary canal
b. Tracheal system
c. Malpighian tubules
d. Reproductive system

Question 3.
Complete the given branching diagram based on connective tissue.

Question 4.
Match the items in columns B and C with A.

Features of different phyla / class are given below. Identify the phylum / class and give examples of each group.

a. Body is covered by scales, heart is three or four chambered. They respire through lungs.
b. They are exclusively marine, commonly called sea walnuts and show biolumi-nescence.
c. Body is divided into proboscis, collar and trunk.They have open circulatory system and presence of proboscis gland.

Question 5.
Among the different phyla of animals ….. have pseudocoelom

Question 6.
Categorize the following animals under ra dial symmetry and bilateral symmetry.

Question 7.
Differentiate the process of inspiration and expiration.

Question 8.
a. Observe the diagram and label A and B.

b. Dental formula of permanent teeth in man is ………….

Question 9.
Identify the given biomolecules

Question 10.
Select the wrongly matched pair from the following :

Question 11.
Complete the following chart showing struc ture of myosin filament and it’s protein based on the hints given in the brackets.(Light meromyosin, Actin, Tropomyosin, Meromy osin).

Question 12.
Answer the following :
a. Cerebral hemispheres of human brain are connected by ………………..

1. Association area
2. Corpus callosum
3. Corpora quadrigemina
4. Pons varoli

b. Observe the diagram and label A, B,CandD.

Question 13.
Complete the table

Question 14.
a. Select the correct statement regard¬ing the ECG of man.

1. P – wave represents auricular re-polarization.
2. P- wave represents ventricular re-polarization.
3. P- wave represents auricular de-polarization.
4. P – wave represents ventricular de-polarization.

b. Observe the diagram and label A, B, C and D

Question 15.
Prepare two matching pairs from the given list of animals and excretory organs.

ANSWERS

Answer 1.
c. Kingdom – Phylum – Class – Order – Family – Genus – Species.

Answer 2.
b. Tracheal system

Answer 3.
A. Specialised connective tissue
B. Adipose tissue
C. Irregular
D. Cartilage

Answer 4.
a – iv – 3
b – iii – 1
c – i – 2
OR
a. Class: Reptilia. Eg., Chelon (Turtle)
b. Phylum : Ctenophora. Eg., Ctenoplana
c. Phylum : Hemichordata. Eg., Balano glossus.

Answer 5.
Phylum : Aschelminthes

Answer 6.
Radial symmetry : Physalia , Adamsia
Bilateral symmetry : Tapeworm,Fasciola

Answer 7.

Inspiration	Expiration
The process of intake of air into the alveoli of lungs. It is an active process	The breathing out of air from the lungs is called expiration.
Inspiration takes place when pressure within the lungs becomes less than the atmospheric pressure, i.e., there is a negative pressure in the lungs with respect to atmospheric pres sure.	It takes place when the intra pulmonary pressure is higher than the atmospheric pressure.
The contraction of intercostal muscle lifts up the ribs and sternum.This causes an increase in the volume of the thoracic chamber.	Relaxation of the diaphragm and the in ter coastal muscles returns the diaphragm and sternum to the normal position.

Answer 8.
a. A – Canine
B. Molars b. ii. 2123/2123

Answer 9.
A – Serine
B – Adenylic acid
C – Cholesterol

Answer 10.
Antibody – Sensory reception

Answer 11.
A – Meromyosin
B – Light meromyosin

Answer 12.
a. Corpus callosum
b. A – Axon B – Synaptic vesicles
C – Synaptic cleft D – Neurotransmitter

Answer 13.
A – ANF
B – Decreases blood glucose level
C – Juxta gomerular cells of kidney
D – Thymosin

Answer 14.
a. P – wave represents auricular depolarization.
b. A – Aorta
B – Venacava
C – Pulmonary vein
D – Chordae tendinae.

Answer 15.
a – ii, b – , c – i

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Zoology Previous Year Question Paper 2018

Time: 1 Hours
Cool off time : 10 Minutes
Maximum : 30 Scores

General Instructions to candidates

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Exami¬nation and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provied.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

QUESTIONS

Answer all questions from question numbers 1 to 3. Each carry one score. (3 × 1 = 3)

Question 1.
Rearrange the following taxonomic categories in the correct sequence.

Question 2.
Note the relationship in the first pair and then complete the second pair

Osteichthyes : Cycloid scales
Chondrichthyes : ……………….

Question 3.
The innermost layer of the eyeball is ……………….

a. Choroid
b. Iris
c. Retina
d. Sclera

Answer any nine from question numbers 4 to 14. Each carries two scores.

Question 4.
The molecular structure of 2 amino acids are given below.
Name them.

Question 5.
Arrange the following terms under two headings based on symmetry.

Question 6.
a. Expand GFR.
b. Even though GFR in a healthy person is 180 litres per day, the amount of urine released per day is only about 1.5 litres. Give a reason.

Question 7.
Select the bones of the leg from the given list of bones.

Question 8.
Name the following :
a. The antibacterial enzyme present in the saliva of man which helps in prevention of infection.
b. The digestive enzyme present in salvia.

Question 9.
Observe the diagram showing the alimen¬tary canal of cockroach. Name the parts labelled A,B,C and D.

Question 10.
Diagrammatic representation of a standard ECG is given below :


a. What does the QRS complex denotes ?
b. Mention the clinical significance of ECG.

Question 11.
Distinguish between the following :

Question 12.
Complete the given flow chart.

Question 13.
Name the hormones whose deficiency is responsible for the following :

a. Dwarfism
b. Diabetes mellitus
c. Cretinism
d. Diuresis

Question 14.
Identify the following tissues :

a. Tissue that stores fat
b. Tissue that connects bones together
c. Tissue that connects bones to muscles
d. Tissue that conducts impulses

Answer any three from question numbers 15 to 18. Each carries three scores.

Question 15.
Match the terms in column A with those in columms B and C

Question 16.
a. Complete the diagrammatic representation showing the nature of enzyme action :

b. List out any two factors affecting enzyme activity.

c. Based on the reaction formulae given below, identify the classes of the enzymes.

Question 17.
Protein digestion by proteolytic enzymes is given below :

a. Name the enzymes marked as A and B.
b. Identify the gland which secrete these enzymes.
c. Write the inactive form of the enzymes A and B.

Question 18.
a. A table showing examples of vertebrates given below. But some of the examples are wrongly given. Identify and rearrange it


b. Which of the above mentioned class is characterized by the presence of pneumatic bones?

ANSWERS

Answer 1.
Kingdom ← Phylum ← Class ← Order ← Family ← Genus ← Species

Answer 2.
Placoid scales

Answer 3.
Retina

Answer 4.
a. Serine
b. Alanine

Answer 5.
Radial symmetry – Ctenophores, Coelen- terates.
Bilateral symmetry – Arthropods, Molluscs

Answer 6.
a. Glomerular Filtration Rate
b. Due to tubular reabsorption. Nearly 99% of the filtrate is reabsorbed by the renal tubules.

Answer 7.
Femur, Tibia, Fibula, Tarsals

Answer 8.
a. Lysozyme
b. Salivary amylase / amylase

Answer 9.
A – Crop
B – Hepatic caecae
C – Malpighian tubules
D – Colon / Hindgut

Answer 10.
a. Depolarisation of the ventricles or ven tricular contraction.
b.Any deviation from the normal shape indicates a possible abnormality or dis-ease, heart disease, defective heart functioning and chance of heart attack.

Answer 11.
a. IRV (Respiratory Reserve Volume) :
Additional volume of air that can be inspired forcibly after a normal inspiration. This averages 2500mL – 3000mL.

ERV (Expiratory Reserve Volume) :
Additional volume of air that can be expired forcibly after a normal expira¬tion. This averages 1100 mL – 1200mL.

b. IC(inspiratory Capacity)
Total volume of air, a person can inspire after a normal expiration/ relevant volume. Which is equal to (TV + IRV).

EC(Expiratory Capacity):
Total volume of air, a person can expire after a normal inspiration / relevant volume. Which is equal to TV + ERV.

Answer 12.

Answer 13.
a. Growth hormone
b. Insulin
c. Thyroxine
d. Vasopressin

Answer 14.
a. Adipose tissue
b. Ligaments
c. Tendon
d. Neural / Nervous tissue

Answer 15.

	A	B	C
(a)	Neutrophils	60-65%	Phagocytic
(b)	Eosinophils	2-3%	Allergic re­action
(c)	Lymphocytes	20-25%	Immune response

Answer 16.
a. (a) EP / Enzyme Product Complex, (b) Product / P
b. i. Temperature
ii. pH

c. i. Oxidoreductases/dehydrogenases.
ii. Lyases

Answer 17.
a. A – Chymotrypsin
B – Carboxy peptidase
b. Pancreas
c. A – Chymotrypsinogen
B – Proarboxypeptidases

Answer 18.
a.

Pisces	Amphi­bia	Reptilia	Aves	Mam­malia
Dog fish	Frog	Alliga­tor	Penguin	Blue Whale
Rohu	Salama­nder	Tortoise	Vulture	Flying fox

b. Class – Aves / Birds

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Botany Model Question Paper 5

Time: 1 Hours
Cool off time : 10 Minutes

General Instructions to candidates :

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time ‘ of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

Qn.No.1 to 3. Answer all questions. Each question carries 1 score. (3×1=3)

Question 1.
Choose the correctly matched pair.
a. Telocentric chromosome
– Middle centromere
b. Metacentric chromosome
-Centromere slightly away from the middle
c. Acrocentric chromosome
-Centromere close to its end

Question 2.
Choose the correct answer.
Law of limiting factors is proposed by
a. Cornelius Van Niel
b. Blackman
c. Joseph Priestley
d. Engelmann

Question 3.
Observe the figure given below and identify the blue green alga.

Qn.No.4 to 11. Answer any 6 questions. Each question carries 2 scores.

Question 4.
Certain compounds formed during Krebs’ cycle are given below. Draw Krebs’cycle using the compounds.

Question 5.
Water from the root hairs move deeper into the root layers by two pathways. Name the two pathways. Which pathway is blocked in the endodermis? Give reason.

Question 6.
Analyse the table and fill in the blanks.

Question 7.
Artificial system and natural system are two systems of classification. Who are the proponents of these classifications.

Question 8.
Names of certain essential elements are given below:

Choose the macro nutrients and write one function of each of them.

Question 9.
Pili and fimbriae are surface structures seen in bacterial cells. Differentiate these structures.

Question 10.
Carbohydrates and fats are respiratory substrates. But their RQ is different. Define RQ. Write the RQ of these substrates.

Question 11.
Certain life cycle patterns of various plant groups are given below:

Choose the life cycle pattern shown by gymnosperms and angiosperms. Write the peculiarities of the identified life cycle pattern.

Qn. No 12 to 17. Answer any 5 questions. Each question carries 3 scores.

Question 12.
Observe the figure given below:

a. Source of which plant hormone is indicated in the figure.
b. Write four roles of the above identified hormone.

Question 13.
Observe the terms given below :
Vexillary, Axile, Marginal, Imbricate, Basal, Valvate.
Identify the three kinds of placentation from the above. Explain them.

Question 14.
Observe the figure.

a. Identify the above stage of mitosis.
b. Name the preceding stage of the above stage. Write its main events.

Question 15.
Observe the flow chart given below :

a. Identify A, B, C, Write the function of B.
b. Differentiate endarch and exarch xylem.

Question 16.
Observe the diagrammatic representation of Hatch and Slack pathway given below.

Identify the cells A and B. Explain the process of formation of C₄ acid specifying the enzyme involved.

Question 17.
Periderm is constituted by three kinds of tissues. Name them. Write one peculiarity of each of them.

Answers

Answer 1.
c. Acrocentric chromosome
-Centromere close to its end

Answer 2.
b. Blackman

Answer 3.
Nostoc

Answer 4.

Answer 5.
Apoplast and Symplast pathways are two pathways.
Apoplast pathway is blocked in the endodermis.
Due to the presence of casparian strips / suberin thickenings.

Answer 6.
a. golgi apparatus
b. basal body of cilia/ flagella/ spindle fibers
c. protein synthesis
d. mitochondria

Answer 7.
Artificial system- Carl Linnaeus
Natural system – George Bentham and Joseph Hooker
Artificial system – based on external characters
Natural system – based on both external and internal characters

Answer 8.
Potassium, Magnesium
Potassium – anoin cation balance/opening and closing of stomata/maintain turgidity of cells.
Magnesium – maintain ribosome structure/ constituent of chlorophyll/activates enzymes of photosynthesis.

Answer 9.
Pilli are elongated tubular structures. Fimbriae are small bristle like structures.

Answer 10.
Ratio of volume of Co₂ evolved to the ratio of oxygen absorbed is RQ.
RQ of carbohydrate is 1
RQ of fats are less than 1

Answer 11.
Diplotonic
Here diploid sporophytic phase is dominant.
In this type lifecycle the diploid sporophyte is the dominant, photosynthetic, independent phase of the plant. The gametophytic phase is represented by the single to fewcelled haploid gametophyte. This kind of lifecycle is termed as diplontic. All seed-bearing plants i.e., gymnosperms and angiosperms, follow this pattern.

Answer 12.
a. Auxin
b. Initiate rooting in stem cuttings
Induce parthenocarpy
Control xylem differenciation
Cause apical dominance

Answer 13.
Axial, Marginal and Basal
Axial : placenta is axial and ovules attached to it.
Marginal : Ovules are at margines of car-pels
Basal : Placenta at base of ovary

Answer 14.
a. Anaphase
b. Preceding stage – Metaphase .
Main events
Chromosomes are highly condensed they are arranged at equatorial plane.

Answer 15.
a. A – Parenchyma
B – Collenchyma
C – Sclerenchyma
Function of B – Give support
b.Endarch – protoxylem pointing towards centre
Exarch – Protoxylem pointing towards periphery

Answer 16.
A-mesophyll
B – Bundle sheath cell
The primary Co₂ acceptor is a 3-carbon molecule phosphoenol pyruvate (PEP) and is present in the mesophyll cells. The enzyme responsible for this fixation is PEP carboxylase or PEPcase. It is important to register that the mesophyll cells lack Ru- BisCO enzyme. The C₄ acid OAA is formed in the mesophyll cells. It then forms other 4-carbon compounds like malic acid or aspartic acid in the mesophyll cells itself, which are transported to the bundle sheath cells. In the bundle sheath cells these C₄ acids are broken down to release Co₂ and a 3-carbon molecule. The 3-carbon molecule is transported back to the mesophyll where it is converted to PEP again, thus, completing the cycle. The Co₂ released in the bundle sheath cells enters the C₃ or the Calvin pathway, a pathway common to all plants. The bundle sheath cells are rich in an enzyme Ribulose bisphosphate carboxylase-oxygenase (RuBisCO), but lack PEPcase. Thus, the basic pathway that results in the formation of the sugars, the Calvin pathway, is common to the C₃ and C₄ plants.

Answer 17.
Phellum, phellogen and phelloderm are the three kinds of tissue.

One type of meristematic tissue called cork cambium or phellogen develops, usually in the cortex region. Phellogen is a couple of layers thick. It is made of narrow, thin-walled and nearly rectangular Cells. Phellogen cuts off cells on both sides. The outer cells differentiate into cork or phellem while the inner cells differentiate into secondary cortex or phelloderm. The cork is impervious to water due to suberin deposition in the cell wall. The cells of secondary cortex are parenchymatous. Phellogen, phellem, and phelloderm are collectively known as periderm.

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Botany Model Question Paper 4

Time: 1 Hours
Cool off time : 10 Minutes

General Instructions to candidates :

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time ‘ of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

Answer all questions from question numbers 1 to 4. Each carry one score.

Question 1.
The class of fungi known as imperfect fungi is ……

Question 2.
Which one of the plant growth regulators induce immediate stomatal closure in leaves.

Question 3.
By observing the relationship of the first pair, fill in the blanks of the second pair
Auxins : Apical dominance
____: Overcome apical dominance

Question 4.
The reaction center of photosystems in green plants during light reaction is ……
a. Xanthophyll
b. Carotenoids
c. Chlorophyll b
d. Chlorophyll a

Answer any seven from question numbers 5 to 13. Each carries two scores.

Question 5.
Match the following:

Question 6.
Complete the diagram by filling the gaps.

Question 7.
Suggest a method for identification of stem and root in plants based on the arrangement of protoxylem.

Question 8.
A cell with a chromosome number 42 undergoes mitosis and another cell with 42 chromosomes undergoes meiosis. Give the chromosome number of daughter cells after mitosis and meiosis. Give reasons for your answer.

Question 9.
Observe the diagrammatic view of a cell and answer the questions.
a. Identify the phase in which DNA synthesis takes place.
b. Mention any one event that takes place in the stages marked as ‘X’ and ‘Y’.

Question 10.
Observe the given diagram. Analyze this diagram and explain the structure of plasma membrane.

Question 11.
Write any two distinguishing features of the algal class Rhodophyceae.

Question 12.
There is a clear division of labour within the chloroplast. Substantiate the given statement with an explanation stating two points.

Question 13.
Botany teacher brought a diseased plant in the classroom. Manoj identified the pathogen as a virus. Can you list any two symptoms of diseases, that helped him to identify the pathogen?

Answer any four from question numbers 14 to 18. Each carries 3 scores.

Question 14.
Three potato pieces of equal weight (2g) were left in three types of solutions (A, B and C) overnight. The weight change of potato pieces are as shown in the figure.

a. Identify the solutions A and C.
b. Discuss the reason for not having any change in the piece put in solution B.

Question 15.
C₄ plants are adapted to overcome a wasteful process found in C₃ plants and hence productivity and yields are better in these plants.
a. Name the wasteful process found in C₃ plants.
b. Identify the cells involved in the C₄ pathway.
c. Write any two differences between C₃ plants and C₄ plants.

Question 16.
Plants that are adapted to dry tropical regions have a special type of Co₂ fixation in addition to the C₃ cycle.
a. Name this pathway.
b. Can you identify any specialty in the leaf anatomy of such plants? If so, what is this anatomy called?
c. Which is the primary Co₂ acceptor in this pathway?
d. Write any one advantage of such plants over C₃ plants.

Question 17.
In most of the plants, roots are meant for absorption and fixation. But there are exceptions to these functions. Justify the statement citing at least three examples.

Question 18.
In a dicotyledonous stem, secondary growth takes place at two regions by the activity of two lateral meristems.
a. Identify the two lateral meristems.
b. List the new tissues formed from each of these meristems.

Answers

Answer 1.
Deuteromycetes

Answer 2.
Abscissic acid

Answer 3.
Cytokinin

Answer 4.
d. Chlorophyll a

Answer 5.
a. Synthesis and storage of energy – Mitochondria.
b. Packaging and delivery of materials – Golgi apparatus.
c. Digestion of intercellular materials – Lysosome.
d. Formation of basal body of cilia and flagella – Centriole.

Answer 6.
4C – Oxyloacetic acid
4C – Malic acid/ fumaric acid
5C – α-Ketoglutaric acid

Answer 7.
In root, the protoxylem are in exarch arrangement, while in stem, endarch.

Answer 8.
After mitosis chromosome doesn’t change. Because its division doesn’t cause any decrease in amount of chromosome. But meosis is known as reduction division. So it bring half of the chromosome number.

Answer 9.
a. DNA division occurs at S-phase.
b. X – Metaphase: During which chromosome align at metaphase plate.
Y – Anaphase: Centromere of the sister chromatids split and chromatids separate. Chromatids move to opposite poles.

Answer 10.
Fluid – mosaic model. According to this model quasi-fluid nature of lipid enables lateral movement of proteins within the overall bilayer. This ability to move within the membrane is measured as its fluidity. This fluid nature of the membrane is also important from the point of view of function like cell growth.

Answer 11.
• The members of Rhodophyceae are known as red algae.
• The food is stored as floridean starch.

Answer 12.
Within the chloroplast there is the membranous system consisting of grana, the stroma lamellae, and the fluid stroma. There is a clear division of labour within the chloroplast. The membrane system is respon¬sible for trapping the light energy and also for the synthesis of ATP and NADPH.

Answer 13.
In this plant, the symptoms are mosaic formation, leaf rolling and curling, yellowing and veinclearing, dwarfing and stunted growth.

Answer 14.
a. A – Hypertonic, C – Hypotonic
b. B – Solution is isotonic. The osmotic pressure of the external solution and cell sap are same. Hence no net flow of water towards inside or outside of potato pieces.

Answer 15.
a. Photo respiration
b. Bundle sheeth cells around the vascu lar bundles.
c. C₃ cycle C₄ cycle
1. Co₂ accepter is Co₂ accepter is PEP RuBp
2. The enzyme – The enzyme involved
RUBISCO – PEP case

Answer 16.
a. C₄ Pathway or Hatch and Slack pathway.
b. Yes. Kranz anatomy.
c. Phosphoenol pyruvate (PEP).
d. In C₄ plants photorespiration is absent so the productivity is high.

Answer 17.
Roots are modified for:
Storage of food: Tap roots of carrot, turnip and adventitious roots of sweet potato, get swollen and store food.
Respiration: Roots modified for physiological function like breathing are called breathing roots or pneumato phores. eg., Mangrove rees.
For mechanical support: Prop roots/ pillar roots of banyan trees are developing from the aerial branches and it grows vertically downwards.

Answer 18.
a. Vascular cambium and cork cambium.
b. From vascular cambium: Secondary xylem, secondary phloem, secondary medullary rays dulps.
From cork cambium: Phellem, phelloderm

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Botany Model Question Paper 3

Time: 1 Hours
Cool off time : 10 Minutes

General Instructions to candidates :

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time ‘ of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

Questions 1-3. Answers all questions. Each question carries 1 score.

Question 1.
Choose the correctly matched pair
a. Golgi apparatus – Synthesis and storage of energy
b. Lysosome – Digestion of intercellular materials
c. Mitochondria – Packaging and delivery of materials

Question 2.
Identify the statement which is applicable to cyanobacteria.
a. Important decomposers
b. Form blooms in polluted water
c. Presence of prominent nucleus
d. Completely lack of a cell wall

Question 3.
The following diagram represents five petals of a flower in a plant belonging to a major family.

Identify the family.

Questions 4 -11. Answers any 6 questions. Each question carries 2 score.

Question 4.
Complete the given table of algal divisions and their main characteristics by filling ‘a’, ‘b’, ‘c’ and ‘d’.

Question 5.
Transpiration has more than one purpose in plants. Write any one purpose of transpiration in plants and list any two factors that affect this process.

Question 6.
Unlike a majority of the pteridophytes, genera like Selaginella and Salvinia show a unique feature in spore formation.
a. What is this feature?
b. Briefly comment on its significance.

Question 7.
Even though more than, sixty elements are found in different plants, all are not essential.
Write any two criteria for the essentially of an element.

Question 8.
C₄ plants have special features. List out any four specialities of C₄ plants compared to C₃ plants.

Question 9.
Glycolysis is a partial oxidation process. Justify.

Question 10.
Light reaction is otherwise called photo-phosphorylation

a. Locate the site of this reaction.
b. Write any two differences between cyclic photo phosphorylation and non-cyclic photo phosphorylation.

Question 11.
Analyse the given statements and correct them with respect to the underlined words.
a. Respiration is an anabolic pathway.
b. The site of perception of light by a plant for a photoperiodic response is a flower.

Questions 12-17. Answers any 5 questions. Each question carries 3 score.

Question 12.
The diagram given below shows parts of a true fruit.

a. Write the technical name of this fruit developed from a monocarpellary superior ovary.
b. Label the parts A and B.
c. Can you distinguish a parthenocarpic fruit from the given fruit.

Question 13.
Given below are the scientific terms related to photosynthesis. Classify them in appropriate manner, in the given table.

Question 14.
Observe the diagram and answer the following.

a. This is a peculiar type of plant cultivation. Name it.
b. Aeration is necessary for the conduct of this type of cultivation. Why?

Question 15.
Given below is the floral diagram of a family you have studied.

a. Identify the family and aestivation of corolla.
b. Describe three other floral characters from the floral diagram using technical terms.

Question 16.
In an anatomy lab, Ramu and Salim were taking transverse sections (T.S) of two specimens, A and B respectively. Their observations are given in the table. Complete the table.

Question 17.
Even though algae are primary producers on aquatic ecosystems, man is benefited by algae in a variety of ways. Write any four points in favour of this statement.

Answers

Answer 1.
b.

Answer 2.
Form blooms in polluted water.

Answer 3.
Fabaceae.

Answer 4.
a – Starch
b – Fucoxanthin
c – Rhodophyceae
d – Floridean starch

Answer 5.
Transpiration is a mechanism for water ex-change.
Transpiration is affected by:
External temperature, humidity, light.
Wind speed
Number and distribution of stomata.
Percentage of open stomata.

Answer 6.
a. Heterosporous.
b. It produces megaspores and micros-pores. Microspore develops into male gametophyte and megaspore develops into female gametophyte. The female gametophyte retained in the parent sporophyte for a short period and it is considered to be the seed habit.

Answer 7.
The mineral should support growth and re-production. The requirement of the element should be specific and not replaceable by another element. The element should directly involved in the metabolism of plant.

Answer 8.

Answer 9.
Glycolysis is a partial oxidation, glucose undergo oxidation to form two molecules of pyruvic acid. And this pyruvic acid undergo many type of reaction according to the organism and form the sub-stance which our body need. Pyruvic acid, in yeast like organism undergo fermentation and form Co₂ and ethanol. In animal cells it form lactic acid. Finally reach in Krebs cycle then undergo electron transport then it form ATP. Such a long cycle is needed to convert glucose to ATP. So we say that glycolysis is a partial oxidation.

Answer 10.
b. Grana.
c. Non-cyclic: When the two photosystems work in a series, first PS II and then the PS I, a process called non- cyclic photo-phosphorylation occurs. The two photo-systems are connected through an electron transport chain, as seen earlier -in the Z scheme. Both ATP and NADPH + H⁺ are synthesised by this kind of electron flow.

Cyclic: When only PS I is functional, the electron is circulated within the photosystem and the phosphorylation occurs due to cyclic flow of electrons. A possible location this could be happening is in the stroma lamellae. The excited electron does not pass on to NADP+ but is cycled back to the PS I complex through the electron transport chain. The cyclic flow hence, results only in the synthesis of ATP.

Answer 11.
a. The term anabolism means building up process. The term catabolism means break down process. Respiration involve the break down of organic molecules like glucose. But Intermediate compounds produced during the break down of glucose is used for synthesis of complex molecules like fats and proteins. Therefore respiratory pathway involve both anabolism and catabolism, hence can be considerate as amphibolic pathway.
b. The site of perception of light by a plant for a photo periodic responds is not a flower but leaves.

Answer 12.
a. Drupe.
b. A – Epicarp, B – Mesocarp
c. Parthenocarpic fruit is the fruit which formed without fertilization of the ovary. But in figure it is true fruit which formed by fertilization of monocarpellary superior ovary.

Answer 13.

Answer 14.
a. Hydroponics.
b. In this system plants are cultivated under greatful nutrient medium. A plant can live only in the presence of O₂. O₂ supply is necessary for the growth of plants/absorption of nutrients.

Answer 15.
a. Fabaceae. The aestivation of corella is vexillary.
b. Infloroscence – Racemose Flower – Bisexual, zygomorphic.
Calyx – Sepals five, gamosepalous.

Answer 16.

Answer 17.
Agar is obtained from gracillaria and geledium used for the preparation of icecream and jellies.
Chorella and spirullina are abundant in protein and used as food supplement by the space travellers.
70 species of marine algae are used as food. Half of the Co₂ fixation on earth is done by algae.

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Botany Model Question Paper 2

Time: 1 Hours
Cool off time : 10 Minutes

General Instructions to candidates :

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time ‘ of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

Answer all questions from question numbers 1 to 4. Each carry one score.

Question 1.
Fill in the blank
Cork cambium is otherwise called …..

Question 2.
Glycolysis is present in all organisms and it is the only process of respiration in anaerobic organisms.
Where does glycolysis occur?

Question 3.
By observing the relationship of the first pair, fill in the blanks of the second pair
F. W. Went : Auxins
E. Kurosawa : …….

Question 4.
Out of the four statements given below related to respiration, the correct statements are:
i. Though respiration has traditionally been considered a catabolic process, it would be better to consider it as an amphibolic pathway.
ii. In muscles when oxygen is inadequate, lactic acid is reduced to pyruvic acid.
iii. When facts are used in respiration, the RQ is greater than one.
iv. In respiration, the energy of oxidation- reduction is utilized for phosphorylation,
a. i) and ii)
b. ii) and iii)
c. iii) and iv)
d. i) and iv)

Answer any seven from question numbers 5 to 13. Each carries two scores.

Question 5.
Match the following columns A,B.

Question 6.
Observe the incomplete schematic representation given below and answer the questions.
Identify this pathway common for both

a. aerobic and anaerobic respiration.
b. Complete the scheme by filling the boxes A, B, C and D.
c. Mention the three major ways in which different cells handle pyruvic acid produced by this pathway.

Question 7.
‘Diatoms, the chief producers in the oceans, are useful to us even after their death.’ Evaluate the statement.

Question 8.
In dicot stem, cambium occurs between xylem and phloem and the vascular bundles are arranged in a broken ring fashion. However, dicot stem grows in diameter in a circular manner. Explain briefly how this could happen.

Question 9.
Identify the cycle and name the scientist who traced the pathway.

Question 10.
Two crucial events of aerobic respiration takes place in two parts of mitochondria. Locate the two parts and mention the two events in one or two sentences each.

Question 11.
Observe the given floral diagram.

a. Identify the family.
b. Write any four floral characters of the identified family.

Question 12.
How can you differentiate active transport from facilitated diffusion?

Question 13.
Fermentation is the incomplete oxidation of pyruvic acid. Find the difference between two types of fermentations in micro-organisms.

Answer any four from question numbers 14 to 18. Each carries 3 scores.

Question 14.
Breakdown of glucose into two molecules of pyruvic acid is called glycolysis. Draw the scheme of glycolysis using the following, starting from glucose ending in pyruvic and 1,3-biphosphoglyceric acid, glyceraldehyde 3 phosphate—> dihydroxy acetone phosphate, fructose, 1, 6- biphosphate, 3-phosphoglycerate, fructose-6-phosphate phosphoenol pyruvate, glucose-6 phosphate, 3 phos-phoglyceric acid.

Question 15.
A diagram prophase I stage of a Meiosis is given below. Draw similar diagrams to il-lustrate the following stages.

Question 16.
Comment on the following statements.
a. Abscisic acid is also known as stress hormone.
b. There are hormones promoting apical dominance and those acting against apical dominance.

Question 17.
An anatomist observed peculiar type of large spherical bundle sheath cells in sugarcane leaf and a physiologist identified the presence of PEP carboxylase in that leaf mesophyll.
a. Name the peculiar leaf anatomy.
b. Explain the physiological advantage of such type of plants.

Question 18.
The use of radioactive C¹⁴ by Melvin Calvin in algal photosynthesis studies led to the discovery of Co₂ fixation in green plants.
a. Identify the first stable product in this Co₂ fixation cycle.
b. Which are the three main stages of this cycle?
c. Name the enzyme which catalyzes the first stage of this cycle.
d. Work out how many ATP and NADPH molecules will be required to make one molecule of glucose?

Answers

Answer 1.
Phellogen

Answer 2.
In cytoplasm.

Answer 3.
Gibberellin/GA

Answer 4.
d – i and iv

Answer 5.

Answer 6.
a. Glycolysis/EM P Pathway
b. A – Glucose 6- phosphate
B – Triose phosphate/glyceraldehyde- 3 phosphate
C – 2 -phosphoglyceric acid
D – 2 -phosphoenolpyruvic acid
c. Lactic acid fermentation in muscle cells. Alcoholic fermentation in Yeast. Aerobic respiration.

Answer 7.
In diatoms the cell wall form 2 thin over laping shells which fit together as in soap box. These walls are embeded with silica. So it is very tough and Indistricta Diatoms deposits their cell wall in their habitat. This accumulation of cell wall over a billion year is known diatomaceous earth used in pol-ishing, filtration of oils and syrups.

Answer 8.
The inter-fascicular cambium joins with in- tra-fascicular cambium and forms ring of cambium.

Answer 9.
Kreb’s cycle. Adolf Hanns Krebs

Answer 10.
For aerobic respiration to take place within the mitochondria, the final product of gly-colysis, pyruvate is transported from the cytoplasm into the mitochondria.
The crucial events in aerobic respiration are:
i. The complete oxidation of pyruvate by the stepwise removal of all the hydrogen atoms, leaving three molecules of C02.
ii. The passing on of the electrons removed as part of the hydrogen atoms to molecular O2 with simultaneous synthesis of ATP.
The first process takes place in the matrix of the mitochondria while the second process is located on the inner membrane of the mitochondria.

Answer 11.
a. Liliaceae / Lily family
b. a. Inflorescence: solitary/cymose; often umbellate clusters
Flower: bisexual; actinomorphic
Perianth tepal six (3+3), often united into tube; valvate aestivation
Androecium: stamen six, 3+3, epitepalous
Gynoecium: tricarpellary.syncarpous, ovary superior, trilocular with many ovules; axile placentation
Fruit : capsule, rarely berry
Seed: endospermous

Answer 12.
Active transport : Transport of substances from low concentration to a higher concentration (uphill transport). It requires ATP to carry substances across the cell mem-brane.
Facilitated diffusion: Transport of substances from higher concentration to lower concentration. Substances move across the cell membrane without the expenditure of energy.

Answer 13.
Alcoholic fermentation :- Pyruvic acid is converted to carbon dioxide and ethanol.
Lactic acid fermentation :- Pyruvic acid is converted to lactic acid.

Answer 14.
Glucose → glucose 6 – phosphate → Fructose 6 phosphate →fructose 1, 6- biphosphate (6c) → Dihydroxy acetone phosphate (3c)
↓
Glyceraldehydel, 3 phosphate (3c)
↓
1, 3 biphospho glyceric acid
↓
3 phospho glyceric acid
↓
2 phosphoglyceric acid
↓
2 phosphoenol pyruvate
↓
Pyruvic acid (3c)

Answer 15.

Answer 16.
a. ABA stimulates closure of stomata/ increases tolerance of plants to various kinds of stress
b. Apical dominance – Auxin/Ethylene. Cytokinin act against apical dominance.

Answer 17.
a. Kranz anatomy
b. 1. High temperature.
2. Photorespiration does not occur.
3. Several layers of bundle sheath cells.
4. Having large number of chloroplast.
5. No intercellular spaces.

Answer 18.
a. 3-Phosphoglyceric acid (3-PGA).
b. Carboxylation, Reduction and Regeneration.
c. RuBP carboxylase – oxygenase (RuBis CO)
d. 18 ATP molecules and 12 NADPH molecules.

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Botany Model Question Paper 1

Time: 1 Hours
Cool off time : 10 Minutes

General Instructions to candidates :

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time ‘ of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

Questions 1-3. Answers all questions. Each question carries 1 score.

Question 1.
Choose the correctly matched pair
a. Banyan tree – Assimillatorry roots
b. Ribizophora – Prop roots
c. Radish – Fusiform root

Question 2.
The name ‘Virus’ that means venom or poisonous fluid was given by …..
a. Pasteur
b. Ivanowsky
c. Beijerinck
d. Stanley

Question 3.
Observe the figure given below and identify the cell organalle.

Questions 4-11. Answers any 6 questions. Each question carries 2 score.

Question 4.
Calvin and his co-workers worked out the whole pathway of Co₂ fixation and showed that the pathway is operated in a cyclic manner.
Draw this cycle using the given terms in the correct order. 3 phosphoglycerate, Regeneration, Carboxylation, Triose phosphate, Reduction, Ribulose, 1,5 biphosphate, Co₂, Sucrose.

Question 5.
Most pteriodophytes are homosporous but there are exceptions.
‘Heterospory is a precursor to seed habit’. Point out any one common character found in heterospory and seed habit.

Question 6.
Analyse the table and fill in the blanks,

Question 7.
Proteins in the membrane are responsible for facilitated diffusion and active transport and hence both show common characteristics. List any two such characteristics.

Question 8.
‘Double fertilization is an event unique to angiosperms’.
a. Mention the two fusions in this event.
b. Name the products obtained as a result of these fusions.

Question 9.
In a plants, deficiency of N₂ is visible inorder parts and that of Ca is visible in younger parts’. Critically evaluate the statement.

Question 10.
Photosynthesis can be considered as the most significant physicochemical process on earth. Evaluate this statement citing any two significances.

Question 11.
A diagrammatic view of a cell cycle is given below.

a. Identify the phase in which
i. DNA synthesis takes place
ii. Chromosomes are arranged at the equator of the spindle,
b. Mention two significant points of mitosis in the life of an organism.

Questions 12 – 17. Answers any 5 questions.Each question carries 3 scores.

Question 12.
a. Identify the cell organelle found both in eukaryotic and prokaryotic cells.
b. Justify its presence in both types of cells.

Question 13.
Observe the given diagram of cell division.
a. Identify the state.

b. Label the parts A and B.
c. Mention any one peculiarity for the pachytene stage of meiosis.

Question 14.
In the anatomy lab, Eugin observed the following features in the T.S of a plant part.
a. adial and polyarch xylem bundles.
b. Parenchymatous (homogenous) cortex
c. Large Path
d. Epidermis with unicellular hairs.
e. Pericycle.
ii. Re-arrange the given regions from the periphery to the center in their correct sequence.
iii. Give an account of casparian strips.

Question 15.
Observe the flow chart given below :

a. Identify A, B, C. Write the function of B
b. Differentiate radial & conjoint arrangements.

Question 16.
Pigments in plants are organized into two photochemical light harvesting com-plexes.
a. Name the reaction center of PS-1 and write its absorption peak.
b. Name the reaction center of PS-II and write its absorption peak.
c. Explain non-cyclic photo phosphorylation giving reasons for the naming of the phenomenon, with the help of a diagram.

Question 17.
Prophase of the first meiotic division is typically longer and complex. It has been further subdivided into five phases. The major events of these substages are given below:
a. Pairing of homologous chromosomes.
b. Terminalization of chiasmata.
c. Occurs crossing over.
d. Chromosomes-are visible under a light microscope.
e. Formation of chiasmata.
i. Identify the stages a,b,c,d and e.
ii. Arrange these stages in correct order of occurrence.

Answers

Answer 1.
c.

Answer 2.
a. Pasteur

Answer 3.
Mitochondria

Answer 4.

Answer 5.
Heterospory means production of two kinds of spores ie, megaspore and microspore. Megaspore germinate and give rise to fe-male gametophyte. Micro- spore germinate and give rise to male gametophyte. So the development of zygote into embryo takes place in the female gametophyte.

Answer 6.
a. Auxin
b. Bolting
c. Overcome apical dominance

Answer 7.
Active transport is carried out by some membrane-protein like facilitated transport. Rate of both of them reach maximum when all membrane proteins are used up. Both are more specific.

Answer 8.
a. Syngamy and triple fusion.
b. By sygamy zygote is formed, by triple fusion primary endosperm nucleus (PEN) is formed.

Answer 9.
The elements that are actively mobilised within the plants and exported to young developing tissue the deficiency symp-toms appears first at the older tissues, i.e., the deficiency of N₂, K⁺ Mg⁺ are visible at the older parts.

The elements that are relatively in mobile and are not transported out the mature organs show deficiency sympto-ms of younger parts, i.e., the deficiency of S, Ca²⁺ are visible at younger parts.

Answer 10.
It is the only natural process by which light energy is converted to chemical energy. It provide food either directly or indirectly. It maintains the equilibrium of oxygen in at-mosphere. It provide vast reserves of en-ergy in the form of petro-lium products like diesel, natural gase etc.

Answer 11.
a. i. Synthesis phase
ii. Metaphase
b. Growth of multicellular organisms is due to mitosis.
Restore the nucleo cytoplasmic ratio.

Answer 12.
a. Ribosome.
b. Ribosome is a site of protein synthesis in both prokaryotes and eukaryotes.

Answer 13.
a. Metaphase.
b. A – Spindle fibers, B – Chromatids.
c. Crossing over occurs between the chromatids of homologous chromosomes. It gives the appearance of recombination nodule.

Answer 14.
i. Monoroot root
ii. Epidermis with unicellular hairs.
Parenchymatous cortex.
Endodermis with casparian strips.
Pericycle.
Radial and polyarch xylem bundles.
Large pith.
iii. The tangential, as well as radial walls of the endodermal cells, have a deposition i of water-impermeable, waxy material suberin in the form of casparian strips.

Answer 15.
a. A- Epidermis, B – Stomata
C – Epidermal appendages
b. Radial: When xylem and phloem within a vascular bundle are arranged in alternate manner on different radii, e.g., roots.
Conjoint : Xylem and phloem are situated at the same radius of vascular bundles. Such vascular bundles are common in stems and leaves. The conjoint vascular bundles usually have the phloem located only on the outer side of xylem.

Answer 16.
a. P₇₀₀ – Peak is 700 nm
b. P₆₈₀ – Peak is 680 nm

The schematic representation showing Z-scheme.

Answer 17.
i. a. Zygotene
b. Diplotene
c. Pachytene
d. Leptotene
e. Pachytene
ii. Leptotene, Zygotene, Pachytene, Diplotene.

Plus One Chemistry Previous Year Question Papers and Answers

Kerala Plus One Botany Previous Year Question Paper 2017

Time: 1 Hours
Cool off time : 10 Minutes

General Instructions to candidates :

• There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time ‘ of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
• Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
• Read the instructions carefully.
• Read questions carefully before you answering.
• Calculations, figures and graphs should be shown in the answer sheet itself.
• Malayalam version of the questions is also provided.
• Give equations wherever necessary.
• Electronic devices except non programmable calculators are not allowed in the Examination Hall.

Question 1.
Who among the following scientists is related with the identification of cytokinins?
a. E. Kurosawa
b. F. Skoog
c. C.Darwin
d. F. W. Went

Question 2.
Read the following statements and select the correct statements from the given choices.
i. Methanogens are present in the guts of ruminant animals
ii. Mycoplasma has distinct cell wall.
iii. Viroids are infectious naked DNA molecule.
iv. Algal component of lichen is phycobiont.
a. ii and iii
b. i and iv
c. i and iii
d. ii and iv.

Question 3.
Algae are useful to man in a variety of ways.
Suggest any four uses of algae.

Question 4.
The root nodules of leguminous plants contain two necessary biochemical compounds for N₂ fixation. Identify these compounds.

Question 5.
An important difference between C₃ and C₄ plants is photorespiration. Explain how photorespiration occurs in C₃ plants.

Question 6.
Write any four agricultural applications of ethylene.

Question 7.
Define Blackman’s law of limiting factors and identify any two important factors which influence the rate of photosynthesis in plants.

Question 8.
The movement of water through the root layers is ultimately symplastic in the endodermis. Give a reason.

Question 9.
a. The arrangement of flowers on the floral axis is called ……
i. Aestivation
ii. Phyllotaxy
iii.Placentation
iv.Inflorescence
b. How can you differentiate an actinomorphic flower from a zygomorphic flower ?

Question 10.
a. The tissues involves in secondary growth of dicot plants are vascular cambium and ….
b. Compare the formation of vascular cambia in dicot stem and dicot root.

Question 11.
a. Identify a cell organelle that contains hydrolytic enzymes.
b. Rough Endoplasmic Reticulum (RER) and Smooth Endoplasmic Reticulum (SER) are morphologically and functionally different. Justify this statement.

Question 12.
Given below is the metaphase of mitosis. Analyze the diagram and draw a sketch of anaphase. Write any two events of anaphase.

Question 13.
Glycolysis is the partial oxidation of glucose to produce two molecules of pyruvic acid.
a. Where does glycolysis occur ?
b. Steps of glycolysis are given below. Fill up the blank boxes.


The complete oxidation of pyruvic acid yields three molecules of C0₂ by a cyclic process in the matrix of mitochondria.
a. Who first develop this cycle ?
b. Draw a diagramatic sketch of the identified cycle.

Answers

Answer 1.
b. F. Skoog

Answer 2.
b. i and iv.

Answer 3.
Helps in Co₂ fixation by photosynthesis, in-crease level of oxygen, primary producers on ocean, used as food.

Answer 4.
Nitrogeneous enzyme / Mo – Fe protein leg hemoglobin

Answer 5.
In C₃ plants O₂ binds to RuBisCO. The RuBP instead of being converted to 2 molecules of PGA, binds with O₂ to form one molecule of phosphoglycerate and phosphogly collate in a pathway called photorespiration. Condition for photorespiration are dual nature of RuBisCO, increases O₂ concentration, moderate temperature etc.

Answer 6.
1. Ethylene breaks seed and bud dormancy, initiates germination in peanut seeds, sproutind of potatao tubers.
2. Ethylene promotes rapid internode/petiole elongation in deep water rice plants, It helps leaves/ upper parts of the shoot to remain above water.
3. Ethylene also promotes root growth and root hair formation.
4. Ethylene is used to initiate flowering and synchronising fruit – set in pineapples.

Answer 7.
The law states that, if a chemical process is affected by more than one factor, then its rate will be determined by the factor which directly affects the process if its quantity is changed.
For example, despite the presence of a green leaf and optimal light and Co₂ conditions, the plant may not photosynthesis, if the temperature is very low. This leaf, if given the optimal temperature will start photosynthesizing.

Answer 8.
Simplistic system is the movement of water occurs from cell to cell through plasmodesmata. Most of the water flow in the roots occur via apoplast since the cortical cells are loosly packed, hence offer no resistance to water movement. The continuation of cell walls breaks in the endodermis of the root due to presence of waxy casperian strips which are impermeable. So the movement of substances in endodermis occurs any simplest.

Answer 9.
a. iv. Inflorescence
b.The flower can be divided into two equal halves along more than one longitudinal plane, i.e., they are radially symmetrical. Such flowers are actinomorphic. Zygomorphic flower cannot be divided into two similar halves in any plane.

Answer 10.
a. Cork cambium
b.

Answer 11.
a. Lysosomes
b. In some ER, spherical granular structures called ribosomes are attracted on the surface. This type of ER is called RER. It occurs in almost all cells which are actively engaged in protein synthesis.
In SER, ribosomes are not attached with ER and the surface is smooth. It is well developed in cells that synthesize steroid hormones.

Answer 12.
Anaphase

Centromeres split and chromatids separate.Chromatids move to opposite poles.
The centromere of each chromosome is towards the pole arms towards the equator.

Answer 13.
a. Cytoplasm (Cytosol)
b. A. Glucose – 6 – phosphate
B. Fructose – 6 – phosphate
C. Fructose – 1, 6 – biphosphate
D. 1, 3 biphosphoglyceric acid / Triose biphosphate
E. 2 – phosphoglycerate / 2 – phosphoglyceric acid
F. Phosphoenol pyruvate / Phospho enolpyruvic acid
OR
a. Hans Kreb
b.

Plus One Chemistry Previous Year Question Papers and Answers