Practicing with 6th Standard Maths Question Paper with Answers Kerala Syllabus and 6th Standard Maths Annual Exam Question Paper 2021-22 will help students prepare effectively for their upcoming exams.
Class 6 Maths Annual Exam Question Paper 2021-22 Kerala Syllabus
Time : 2 Hours
Total Score : 60
Activity – 1
Find the Angles
a) In figure (1), what is the measure of ∠ABD?
Answer:
In the figure
∠ABC =125°
∠DBC = 45°
∠ABD = ?
∠ABD= ∠ABC – ∠DBC
= 125 – 45
= 80°
b) In figure (3), what is the measure of ∠ABD?
Answer:
∠ABD & ∠DBC are linear pair ∠ABD + ∠DBC = 180°
∠ABD + 50 = 180°
∠ABD = 180 – 50 = 130°
c) Using set squares draw figure (2).
Answer:
∠ABD = 135° = 90°+ 45°
Using 90° & 45° set square side we can draw 135°.
Activity -2
Age Calculation
There are 24 students in 6 A. Five of these are of 11 years old 14 students with the age of 12 and then others are of 13y old.
a) How many are of 13 years?
Answer:
Total Number of students = 24
Number of students of 12 years =14
Number of students with 11 years = 5
Number of students with 13 years
= 24 – (14 + 5)
= 24 – 19 = 5
Number of students with 13 years is 5
b) What is the total age of students in the class?
Answer:
Total age of all of the students
= (5 × 11) + (12 × 14) + (5 × 13)
= 55 + 168 + 65
= 288
c) Find the average age of each of 6A students.
Answer:
Average age = \(\frac{\text { Total age }}{\text { No. of students }}\)
= \(\frac{288}{24}\)
= 12 years
Activity – 3
Milk distribution
In Ammu’s home same quantity of milk is supplied 4 everyday, j of the per day milk is need to making tea and the rest is Ammu’s drinking milk.
a) What part of daily milk is consumed by Ammu?
Answer:
Milk for tea = \(\frac{4}{5}\) Part
Milk for Ammu = 1 – \(\frac{4}{5}\)
= \(\frac{5}{5}-\frac{4}{5}\)
= \(\frac{1}{5}\) part
b) If \(\frac{1}{4}\)L is Ammu used to drink. What is the quantity of milk per day they bought?
Answer:
Milk drink by Ammu = \(\frac{1}{4}\)l = 250 ml
\(\frac{1}{5}\) part of milk = 250 ml
Quantity of milk = 250 × 5
= 1250 ml
= 1 litre 250 ml
c) What is the quantity of milk per week in that home?
Answer:
Milk for 1 week = 7 × 1 day’s milk
= 7 × 1250
= 8750 ml
= 8litre 750 ml
= 8.75 litre
Activity – 4
Factor calculation
a) The prime factors of 12 is given below:
12 = 2 × 2 × 3
What is the number of factors of 12?
Answer:
12 = 2 × 2 × 3
P1 = 2, P2 = 1
Number of factors, N = (P1 + 1)(P2 + 1)
= (2 + 1)(1 + 1)
= 3 × 2
= 6
b) Write the factor table of 108.
Answer:
108 = 2 × 2 × 3 × 3 × 3
Activity – 5
Water supply
The inner length 5 m, breadth 4 m and height 3 m of a reservoir.
a) Find out the capacity of reservoir.
Answer:
Inner length of reservoir = 5m
Breadth = 4 m Height = 3 m
Capacity = inner volume = 5 × 4 × 3
= 60 m3
b) After one days supply the reservoir hold 40 m
Answer:
After 1 day distribution
Quantity of water = 40 m3
Height of water level = \(\frac{\text { Volume }}{\text { Length } \times \text { Breadth }}\)
= \(\frac{40}{5 \times 4}\)
= 2m
c) How much water is distributed on that day?
Answer:
Quantity of water distributed on that day = Volume of water before distribution – Volume of water after distribution
= 60 – 40
= 20 m3
Activity – 6
Raju’s garden
Raju has a rectangular shaped garden of length
a) Correct length of the garden into decimal form.
Answer:
Length of Raju’s garden = 2 m 65 cm
= 2\(\frac{65}{100}\) m
= 2.65 m
b) How much is length more than breadth?
Answer:
Length = 2.65 m
Breadth = 1.45 m
Difference = 2.65 – 1.45
= 1.20 m
c) What is the area of Raju’s garden?
Answer:
Area of Raju’s garden = Length × breadth
= 2.65 × 1.45
= 3.8425 m2
Activity – 7
Income and expenditure
The monthly income of Ramu is Rs. 12500.10% is used for son’s education and Rs. 2500 is to repay the loan. \(\frac{1}{5}\) th of the remaining is the saving per month.
a) What is the amount used for son’s education?
Answer:
Ramu’s monthly income = Rs. 12500
% of income spend on education = 10%
Amount spend for education = 10% of 12500
= \(\frac{10}{100}\) × 12500
= Rs. 1250
b) What is the percentage of repayment of loan?
Answer:
Amount spent for repayment = Rs. 2500
% of repayment = \(\frac{1}{2}\) × 100
= 20%
c) How much is used to save per month?
Answer:
Total amount for education and repayment
= 2500 + 1250
= Rs. 3750
Remaining amount = 12500 – 3750
= Rs. 8750
Savings = \(\frac{1}{5}\) of 8750
= \(\frac{1}{2}\) × 8750
= Rs. 1750
Activity – 8
Bar Graph
5th standard have 5 divisions. The number of girls and boys are given in the bar graph. Answer the following questions.
a) In which class the number of boys & girls are equal?
Answer:
5D
b) In 5 A and 5D together what is the total number of boys and that of girls?
Answer:
Number of boys in 5A = 15
Number of boys in 5D= 20
Total number of boys in 5A & 5D
= 15 + 20
= 35
Number of girls in 5 A = 20
No. of girls in 5D = 20
Total number of girls 20 + 20
= 40
c) What is the total number of girls in 5th class?
Answer:
Total girls in 5th standard
= 20 + 10 + 15 + 20 + 30
= 95
Activity – 9
Joining rectangles
1) Complete the table.
Answer:
2) What is the relation between number of rectangles and number of match sticks?
Answer:
Number of match = (3 × Number of rectangles) + 1
3) Give the relation using letters.
Answer:
Let number of rectangles = r
No. of match sticks = m
Relation ⇒ m = 3r + 1