Practicing with Class 8 Maths Question Paper Pdf Kerala Syllabus and Model Question Paper Set 1 will help students prepare effectively for their upcoming exams.
Class 8 Maths Model Question Paper Set 1 Kerala Syllabus
Time : 1½ Hours
Score : 40
(Answer any 4 questions from 1-6. Each question carries 2 scores) (4 × 2 = 8)
Question 1.
Are the triangles ∆ABC and ∆CDE equal? Why?
Answer:
∆ABC, ∆CDE are equal triangle
∆ABC = ∆CDE because
∠B = ∠D
∠A = ∠E
AB = ED
Question 2.
The number of boys and girls in a class are in the ratio 4:3. The total number of students in the class is 56. Find the number of boys and girls.
Answer:
Boys = 56 × \(\frac{4}{7}\) = 32
Girls = 56 × \(\frac{3}{7}\) = 24
Question 3.
In the figure, the length of parallel sides of the trapezium are 6 cm and 4 cm and the distance be-tween parallel sides is 3 cm. Find its area.
Answer:
Area = \(\frac{1}{2}\)h(a + b)
= \(\frac{1}{2}\) × 3(6 + 4)
= 15 cm²
Question 4.
Fill in the blanks:
(a) 4 – 7 = -( -4) = ____
(b) – 5 + 14 = ____ – ____ = 9
Answer:
(a) 4 – 7 = – (7 – 4) = -3
(b) – 5 + 14 = 14 – 5 = 9
Question 5.
Fourteen less than eight times a number is two more than four times the number. What is the number?
Answer:
Number = x
∴ 8x – 14 = 4x + 2
4x = 16
∴ x = \(\frac{16}{4}\)
x = 4
Question 6.
The perimeter of a rhombus is 100 cm. One of the diagonals is 40 cm.
(a) Find one side.
Answer:
One side = \(\frac{100}{4}\) = 25
(b) Find the second diagonal.
Answer:
Second diagonal = 2 × \(\sqrt{25^2-20^2}\)
= 2 × \(\sqrt{225}\)
= 2 × 15
= 30 cm
Length of second diagonal = 30 cm
Answer any 4 questions from 7 to 12. Each question carries 3 scores. (4 × 3 = 12)
Question 7.
Compute the following:
(a) (-3) × (-7)
(b) 2 ÷ (-4)
(c) -3 + 12 =
Answer:
(a) (-3) × (-7) = 21
(b) 2 ÷ (-4) = 2 × \(\frac{-1}{4}=\frac{-2}{4}=\frac{-1}{2}\)
(c) -3 + 12 = 12 – 3 = 9
Question 8.
Draw a rhombus of sides 6 cm and area 18 square centimetres.
Answer:
Question 9.
The sum of angles of a polygon is 6300°. How many sides does it have?
Answer:
Sum of inner angles of a polygon = (n – 2) 180°
∴ (n – 2) 180° = 6300°
∴ n – 2 = \(\frac{6300}{180}\) = 35
∴ n = 35 + 2 = 37
Question 10.
If \(\frac{3}{5}\) of a number is 4 more than \(\frac{1}{5}\) of the number, then what is the number?
Answer:
\(\frac{3}{5} \times \frac{1}{5}\) x + 4
\(\frac{2}{5}\)x = 4
x = 4 x \(\frac{5}{2}=\frac{20}{2}\) = 10
Question 11.
Kiran deposited 15000 rupees in a bank which pays interest compound quarterly. The annual rate of interest compounded quarterly. The annual rate of interest is 6%. How much would he get back after 9 months?
Answer:
15000(1 + \(\frac{1.5}{100}\))<sup>3</sup>
= 15000 × \(\frac{101.5}{100} \times \frac{101.5}{100}\)
= Rs. 15685.18
Question 12.
(a) x² – y² = (x + y)(____)
(b) 75² – 25² = 100 × ____
(c) 105² – 100² = ____
Answer:
(a) x² – y² = (x + y)(x – y)
(b) 75² – 25² = 100 × 50
(c) 105² – 100² = 205 × 5 = 1025
Answer any 5 questions from 13 to 18. Each question carries 4 scores. (5 × 4 = 20)
Question 13.
Draw the quadrilateral with the given measures as shown below.
Answer:
Draw 7cm first, Mark 80°, then draw arcs 6 cm, 5, cm, 4 cm respectively using compass then complete the figure.
Question 14.
Rearrange the table by finding and matching equal value to column A in column B and column C.
| A | B | C |
| 8 + (-3) | 2 | -2 × 3 |
| 7-(-5) | -10 | 36 + 3 |
| -8 × 5 | 12 | 10 × -4 |
| -18 -3 | 5 | -6 – (-8) |
| -2 – (-4) | -6 | 8 – 3 |
Answer:
| A | B | C |
| 8 + (-3) | 5 | 8 – 3 |
| 7 – (-5) | 12 | 36 ÷ 3 |
| -8 × 5 | -40 | 10 × -4 |
| -18 ÷ 3 | -6 | -2 × 3 |
| -2 – (-4) | 2 | -6 – (-8) |
Question 15.
The scores of 30 students in a test are given below.
21, 32, 5, 12, 36, 24, 31, 15, 27, 34
44, 39, 37, 25, 7, 20, 23, 12, 9, 40
46, 42, 28, 16, 47, 27, 37, 18, 49, 26
(a) Prepare a frequency table as shown below.
| Score | Tally | Number of Students |
| 0-10 10-20 ………. ………. |
||
| Total |
Answer:
(b) How many students scored more than 30?
Answer:
7 + 6 = 13
(c) In which class more students lie?
Answer:
20 – 30
Question 16.
Find the area of the parallelogram in the figure.
Answer:
Area of ∆ABF = \(\frac{1}{2}\) × 6 × 3 = 9 cm²
AB = \(\sqrt{6^2+3^2}\)
= \(\sqrt{36+9}=\sqrt{45}\)
\(\frac{1}{2}\) × AB × h = 9
\(\frac{1}{2}\) × \(\sqrt{45}\) × h = 9
h = \(\frac{9 \times 2}{\sqrt{45}}=\frac{18}{\sqrt{45}}\)
Area of ABCD = \(\sqrt{45} \times \frac{18}{\sqrt{45}}\) =18 cm²
[or Area of Parallelogram ABCD = Area of the rectangle = 6 × 3 = 18]
Question 17.
Observe the picture and answer the questions given below.
(a) How many students are there in 8 C class?
(b) In which class is the most number of students?
(c) In which class is the least number of students?
(d) In which class has 50 number of students?
Answer:
(a) 40
(b) 8A
(c) 8E
(d) 8D
Question 18.
In the figure the four comers of the quadrilateral ABCD is on the circle. Such quadrilaterals are known as cyclic quadrilaterials. The opposite angles of such quadrilaterals are supplimentary. That means in the figure ∠A + ∠C = 180°. Now answer the following.
(a) ∠A = 110° then ∠C = ____
(b) ∠PBC = 90° then ∠D = ____
(c) Which is the cyclic quadrilateral given below. (Trapezium, Parallelogram, Rhombus, Rectangle)
(d) If ∠PBC = x° then ∠D = ____
Answer:
(a) ∠C = 180 – 110 = 70°
(b) ∠PBC = 90° ∴ ∠ABC = 90°
∴ ∠D = 180 – 90 = 90°
(c) Rectangle
(d) ∠PBC = x°, ∠ABC = 180 – x°
∴ ∠D = x°