Practicing with Class 8 Maths Question Paper Pdf Kerala Syllabus and Annual Exam Question Paper 2022-23 will help students prepare effectively for their upcoming exams.
Class 8 Maths Annual Exam Question Paper 2022-23 Kerala Syllabus
Time : 1½ Hours
Score : 40
Write any 4 questions from 1 to 5. Each question carries 2 scores. (4 × 2 = 8)
Question 1.
In the figure, PQ = PR, ∠Q = 30°
(a) ∠R =
(b) ∠P =
Answer:
(a) ∠R = 30° (Since PQ = PR, ∠Q = ∠R)
(b) ∠P = (180 – (30 + 30) = 180 – 60 = 120°
Question 2.
2 is added to 3 times of a number gives 17. Find the number.
Answer:
17 – 2 = 15
Number = \(\frac{15}{3}\) = 5
Or
3x + 2 = 17
3x = 17 – 2 = 15
Question 3.
In the figure, ∠A = 70°, ∠D = 110°, ∠C = 80°
(a) ∠ABC =
(b) ∠CBE =
Answer:
Since ABCD is a Quadrilateral
(a) ∠ABC = 360 – (110 + 80 + 70) = 100°
(b) ∠CBE + ∠ABC = 180°
∠CBE = 180 – 100 = 80°
Question 4.
The number of girls and boys in a class are in the ratio 2:3. Total number of students is 50.
(a) What is the number of girls?
Answer:
G : B = 2 : 3
Number of girls = 50 × \(\frac{2}{5}\)
= 20
(b) What is the number of boys?
Answer:
Number of boys = 50 × \(\frac{3}{5}\)
= 30
Question 5.
(a) -3 × 4 = ___
(b) 5 – (-2) = ___
Answer:
(a) -3 × 4 = -12
(b) 5 – (-2) = 7
Answer any 4 Questions from 6 to 11. Each question carries 3 scores. (4 × 3 = 12)
Question 6.
Fill in the blanks
(a) a² – b² = ___ × (a – b)
(b) 100² – 99² = ___ × 1
(c) (a + 1)² – 1² = (a + 2) × ___
Answer:
a) a² – b² = (a + b) × (a – b)
(b) 100² – 99² = 199 × 1
(c) (a + 1)² – 1² = (a + 2) × a
Question 7.
The perimeter of a triangle is 36 centimetres and the sides are in the ratio 2:3:4. Find length of its sides.
Answer:
Length of the sides are
36 × \(\frac{2}{9}\) = 8 cm
36 × \(\frac{3}{9}\) = 12 cm
36 × \(\frac{4}{9}\) = 16 cm
Question 8.
In the figure, ABCD is a rectangle.
AB = 8 centimetres, AD = 4 centimetres, PB = QD =3 centimetres
(a) Find the area of the rectangle ABCD.
Answer:
Area of ABCD = AB × AD
= 8 × 4 = 32 cm²
(b) What is the length of AP?
Answer:
AP = AB – PB = 8 – 3 = 5 cm
(c) What is the area of parallelogram APCQ?
Answer:
Area oof APCD = 5 × 4 = 20 cm²
Question 9.
If x = 3y = -7,then find
(a) x + y = ___
(b) x – y = ___
(c) (x + y)(x – y) = ___
Answer:
(a) x + y = 3 + (-7)
= -4
(b) x – y = 3 – (-7)
= 3 + 7
= 10
(c) (x + y)(x – y) = -4 × 10
= -40
Question 10.
The scores of 25 students in a mathematics test are given below.
20, 12, 15, 35, 26, 32, 28, 24,
0, 14, 8, 40, 29, 30, 36, 34,
22, 23, 11, 10, 41, 47, 42, 35, 38
Make a frequency table as given below.
Answer:
Question 11.
In the figure ABCD is a trapezium.
AB = 6 centimetres, BC = 5 centimetres, CD = 3 centimetres, AD = 4 centimetres and
∠A = ∠D = 90°
(a) Find the sum of the parallel sides of the trapezium
(b) Find the area of the trapezium.
Answer:
(a) Sum of parallel sides of ABCD
= AB + CD = 6 +3 = 9 cm
(b) Area of ABCD = \(\frac{1}{2}\) × 4 × 9
= 18cm²
Answer any 5 Questions from 12 to 18. Each question carries 4 scores. (5 × 4 = 20)
Question 12.
Three equal rhombuses are drawn as shown below. Draw the figure with given measurements.
Answer:
Question 13.
Electricity consumption of 30 families in a locality are given in the table below. Draw a histogram.
| Electricity Consumption | Number of families |
| 100 – 200 | 5 |
| 200 – 300 | 7 |
| 300 – 400 | 8 |
| 400 – 500 | 6 |
| 500 – 600 | 4 |
Answer:
Question 14.
Anu deposited Rs. 10000 in a bank com-pounding interest at 10% per annum. After two years, she deposited another Rs. 10000. How much amount will Anu get at the end of third year?
Answer:
10000(1 + \(\frac{10}{100}\))<sup>2</sup>
= 10000 × \(\frac{110}{100} \times \frac{110}{100}\)
= 12100
Anu deposite of again 10000 rupees so the principal amount becomes
= 12100 + 10000
= 22100
So the amount of the end of third year
Question 15.
The perimeter of a rectangle is 48 centimetres. The ratio between the length and breadth is 5:3,
(a) Length + breadth =
Answer:
Length + breadth = \(\frac{48}{2}\) = 24 cm
(b) Calculate the length and breadth.
Answer:
Length: breadth =5:3
∴ Length = 24 × \(\frac{5}{8}\) = 15cm
Breadth = 24 × \(\frac{3}{8}\) = 9cm
(c) If the breadth is increased by 1 centimetre, then find the ratio between length and breadth
Answer:
If the breadth is increased by 1 cm means
New breadth = 9 + 1 = 10 cm
Length : breadth =15: 10 = 3: 2
Question 16.
Draw a quadrilateral with the measurements shown in the figure.
Answer:
Question 17.
x = -5, y = -6, z = 4
(a) x – y = ___
(b) (x – y)z = ___
(c) Check whether (x – y) z and xz – yz are equal or not.
Answer:
(a) x – y = -5 – (-6)
= -5 + 6
= 6 – 5
= 1
(b) (x – y)z = 1 × 4 = 4
(c) xz = -5 × 4 = -20
yz = -6 × 4 = -24
xz – yz = -20 – (-24)
= -20 + 24
= 4 (x – y) z
= xz – yz
Question 18.
Read and understand the mathematical concept given below and answer the following questions.
2² + 1² = 3² – 2 × (2 × 1)
3² + 2² = 5² – 2 × (3 × 2)
4² + 3² = 7² – 2 × (4 × 3)
Sum of the squares of two numbers is equal to the difference between the square of the sum of the numbers and twice their product.
(a) Write the next line.
(b) 8² + 7² = 15² – 2 × (___)
(c) 20² + 10² = ___ -2 × (___)
(d) a² + b² = ___
Answer:
(a) 5² + 4² = 9² – 2 × (5 × 4)
(b) 8² + 7² = 15² – 2 × (8 × 7)
(c) 20² + 10² = 30² – 2 × (20 × 10)
(d) a² + b² = (a + b)² – 2ab