With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 1 help improve accuracy.
Kerala Syllabus 5th Standard Maths Question Paper Set 1
Time : 2 Hrs 15 Min
Instructions:
- First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
- Answer all six questions. Answer all the sub questions.
- Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).
Question 1.
(a) Ziad and Meera are making numbers with digit cards. These are the cards they have:
407856
(i) What is the largest number they can make with these cards?
Answer:
876540
(ii) And the smallest?
Answer:
405678
(b) The table gives the distances of the planets from the sun.
| Planets | Distance (km) |
| Mercury | 57909175 |
| Venus | 108200000 |
| Earth | 149600011 |
| Mars | 227940000 |
| Jupiter | 778333000 |
| Saturn | 142940000 |
| Uranus | 149600011 |
| Neptune | 2870990000 |
(i) What is the distance of the earth from the sun?
(ii) What is the distance of Jupiter from the sun?
(iii) What is the distance from the sun to its farthest planet?
Answer:
(i) Distance of the Earth from the Sun = 149,600,011 km
(ii) Distance of Jupiter from the Sun = 778,333,000 km
(iii) Farthest planet is Neptune = 287,099,000 km
Question 2.
Look at the numbers given below.
38, 46, 62, 35, 36, 106
(a) Which of these numbers leaves a remainder when divided by 2 ?
Answer:
35
(b) The sum of two of the above numbers does not leave remainder when divided by 5. Which are those numbers?
Answer:
38, 62 are the two numbers 38 + 62 100
(c) Which of the above numbers leaves a remainder of 2 when divided by 5 or 10 ?
Answer:
62
(d) Which of the above number does not leave a remainder when divided by 4 ?
Answer:
36
(e) Which of the following is equal to 48 + 4?
(i) (4 ÷ 4) + (8 ÷ 4)
(ii) (40 ÷ 4) + (4 ÷ 4)
(iii) (24 ÷ 8) + (24 ÷ 8)
(iv) (40 ÷ 4)+ (8 ÷ 4)
Answer:
(iv) (40 ÷ 4)+ (8 ÷ 4)
Question 3.
‘53427 ‘ is a five digit number made without repeating its digits.
(a) Which is the smallest five digit number that can be made using all the above digits?
Answer:
Smallest five digit number = 23457
(b) What is the digit in the ones place of the largest five digit number made using these digits?
Answer:
Largest five digit number = 75432
Digit in ones place = 2
(c) Which is the correct statement about the difference between the largest and the smallest five digit number that can be made using all these digits?
(i) More than 50000.
(ii) Less than 50000.
(iii) 7 is in the ones place.
(iv) Between 60000 and 70000.
Answer:
Difference between the largest and smallest five digit number ‘
= 75432 – 23457 = 51975
The correct statement is:
(i) More than 50000.
(d) Write a five digit palindromic number using the digits 5, 3 and 4
Answer:
Five digit palindromic number = 53435
(e) How many four digit numbers can be made using the digits 0, 1, 2 and 3 with 0 in the hundreds place?
Answer:
Digits are 0, 1, 2 and 3.
Choices for thousand place is = 1,2,3 = 3 choices
Here 0 is in the hundreds place.
Tens place = remaining 2 digits = 2 choices
Ones place = remaining 1 digit = 1 choice
The number of four digit numbers = 3 × 1 × 2 × 1 = 6
Question 4 has two questions (4 A and 4 B). Answer any one.
Question 4.
A See the numbers given below.
1632482, 1537821, 350421, 358212
(a) If these numbers are written from largest to smallest, what will be the last number?
Answer:
Last number = 350421
(b) The sum of two of these numbers is 1982903. Which are those numbers?
Answer:
Sum of two numbers =1982903 1632482 + 350421 = 1982903
The two numbers are 1632482, 350421
(c) What is the difference between the largest number and the smallest number?
Answer:
Difference between the largest and smallest number is
1632482 – 350421 = 1282061
(d) Some statements regarding the largest number is given below.
(i) The number is less than 1 million.
(ii) The number is greater than 1 million.
(iii) The number is between 5 lakh and 10 lakh.
(iv) The number is between 10 lakh and 20 lakh.
Choose the correct statement:
(A) (i) and (iv) are true
(B) (ii) and (iii) are true
(C) (i) and (iii) are true
(D) (ii) and (iv) are true
Answer:
Correct statement = (D) (ii) and (iv) are true
OR
B. (a) What are the possible remainders on dividing a number by 4 ?
Answer:
Possible remainders when dividing by 4 is: 0, 1, 2, 3.
(b) 3, 7, 11,… are the numbers that leave the remainder 3 when divided by 4 . Write the next four numbers in this pattern.
Answer:
Pattern: 3, 7, 11,…
Next four numbers = 15, 19, 23, 27.
(c) If you continue writing like this, will 100 be in this pattern, Why?
Answer:
No.
Because 100 = 4 = 25, remainder is 0.
In this pattern the remainder is 3.
(d) Write 169 as certain times 8 and a remainder.
Answer:
169 as certain times 8 and a remainder.
169 = 8 × 21 + 1
Question 5.
Write each of the numbers as certain times 8 and a remainder
(a) 9
(b) 98
(c) 987
Answer:
The number can be written in certain times of 8 and a reminder as:
(a) 9 = (8 × 1) + 1
(b) 98 = (8 × 12) + 2
(c) 987 = (8 × 123) + 3
(i) Can you guess how 9876 is written like this? Check your guess by actual division.
Answer:
That is, 9876 divided by 8 gives quotient 1234, remainder 4. Thus, we can write 9876 as:
9876 = (8 × 1234) + 4
(ii) Write out this number pattern.
Answer:
(8 × 1) + 1 = 9
(8 × 12) + 2 = 98
(8 × 123) + 3 = 987
(8 × 1234) + 4 = 9876
(8 × 12345) + 5 = 98765
Question 6 has two questions (6 A and 6 B). Answer any one.
Question 6.
A. The graph below shows the number of girls and boys in classes 1 – 7 in a school:
(i) Which class has more boys than girls? What is the difference?
(ii) In which class is the difference between the number of girls and boys the most? In which class is this the least?
(iii) How many girls are there in all these classes together?
(iv) What is the total number of students?
Answer:
(i) Class 3, Difference = 75 – 70 = 5
(ii) Difference between the number of girls and boys the most = Class 1
Difference between the number of girls and boys the least Class 2, 3 and 6
(iii) Total number of girls in all these classes
= 65 + 65 + 70 + 70 + 100 + 115 + 95 = 580
Total number of students = 1100
OR
B. Compute the perimeter and area of each of the shapes below.
Answer:
Each side is 2 cm. So the perimeter will be = 2 × 12 = 24 centimeter
Area of Ist part = 2 × 2 = 4 square centimeter
Area of IInd part = 2 × 6=12 square centimeter
Area of IIIrd part = 2 × 2=4 square centimeter
Total Area = 4+ 12 + 4 = 20 square centimeter