With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 4 help improve accuracy.
Kerala Syllabus 5th Standard Maths Question Paper Set 4
Time : 2 Hrs 15 Min
Instructions:
- First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
- Answer all six questions. Answer all the sub questions.
- Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).
Question 1.
(a) What are the possible remainders on dividing a number by 4? Write the pattern of numbers leaving the same remainder for each of these.
Answer:
4 = (4 × 1) + 0
5 = (4 × 1)+ 1
6 = (4 × 1) + 2
7 = (4 × 1) + 3
8 = (4 × 2) + 0
9 = (4 × 2) + 1
10 = (4 × 2) + 2
11 = (4 × 2) + 3
(b) Which of the following numbers will leave remainder 0 when divided by 4 ?
(i) 7, 11, 15
(ii) 8, 12, 20
(iii) 5, 9, 13
(iv) 10, 14, 18
Answer:
(ii) 8, 12, 20
Question 2.
(a) Answer the following based on fractions:
Answer:
A rectangle with \(\frac{2}{6}\) shaded.
(b) Draw a rectangle divided into six equal parts and shade \(\frac{2}{6}\).
Answer:
\(\frac{4}{8}=\frac{2}{4}=\frac{1}{2}\)
(c) Write two fractions equivalent to \(\frac{4}{8}\).
Answer:
\(\frac{12}{16}=\frac{3}{4}\)
(d) Simplify \(\frac{12}{16}\).
Answer:
1\(\frac{2}{3}=\frac{5}{3}\)
(e) Write 1\(\frac{2}{3}\) as an improper fraction.
Answer:
A circle with \(\frac{6}{8}\) shaded.
(f) Divide a circle into eight parts and shade three-fourths of it.
Answer:
Three-fourth = \(\frac{3 \times 2}{4 \times 2}=\frac{6}{8}\)
Question 3.
Draw the following pictures:
Answer:
Draw two circles. Extend the line to the right till it meets the circle on the right. With this point as centre, draw another circle of the same radius.
Join all four points where the circle in the middle is cut by the other two.
With one of the six points on the middle circle as centre and without changing the radius used till now, draw a piece of a circle within the middle circle, as given below:
Take three more points as centres and draw pieces of circle.
Erase the parts outside the middle circle, we get the required figure.
Question 4 has two questions (4 A and 4 B). Answer any one.
Question 4.
A (a). Convert the following improper fractions to mixed numbers:
(i) \(\frac{13}{4}\)
(ii) \(\frac{17}{5}\)
Answer:
(i) \(\frac{13}{2}\) = 3\(\frac{1}{4}\)
(ii) \(\frac{17}{5}\) = 3\(\frac{2}{5}\)
(b) Write these mixed numbers as improper fractions:
(i) Three and one-third.
(ii) Five and two-fifths.
Answer:
(i) Three and one-third = \(\frac{1}{2}\)
(ii) Five and two-fifths = \(\frac{1}{2}\)
(c) If a ribbon 2 meters long is cut into 7 equal pieces, what is the length of one piece? Write your answer as a fraction.
Answer:
2m divided into 7 parts = \(\frac{2}{7}\) m Per piece
(d) Which of the following statements are correct?
(i) \(\frac{4}{8}\) and \(\frac{1}{2}\) are equivalent fractions.
(ii) Simplifying \(\frac{12}{16}\) gives \(\frac{3}{4}\).
(iii) The mixed fraction 1\(\frac{2}{3}\) is equal to \(\frac{7}{3}\).
(iv) Shading 2 out of 6 equal parts of a rectangle represents \(\frac{1}{2}\).
(a) i, ii, iii are correct
(b) ii, iii, iv are correct
(c) i, iii, iv are correct
(d) i, ii, iv are correct
Answer:
(a) i, ii, iii are correct
OR
B. Solve the following:
(a) A chocolate bar is divided into 12 equal parts. If 9 parts are eaten, what fraction is left?
Answer:
Fraction left = 1 – \(\frac{9}{12}=\frac{3}{12}=\frac{1}{4}\)
(b) Convert \(\frac{15}{8}\) into a mixed number.
Answer:
\(\frac{15}{8}\) = 1\(\frac{7}{8}\)
(c) Divide 2 liters of water equally into 5 bottles. How much water is in each bottle?
Answer:
2 ÷ 5 = 0.4 liters per bottle
(d) A cake is cut into 16 equal slices, and 10 are eaten. Write the fraction eaten and simplify it.
Answer:
Fraction eaten = \(\frac{10}{6}=\frac{5}{8}\)
(e) (i) \(\frac{2}{4}, \frac{3}{6}\) and \(\frac{4}{8}\) all represent the same value.
(ii) Multiplying numerator and denominator of a fraction by the same number does not change its value.
(iii) \(\frac{5}{10}\) and \(\frac{1}{2}\) are equivalent fractions.
(iv) \(\frac{7}{3}\) and \(\frac{1}{3}\) are equivalent fractions.
(a) i, ii, iii are correct
(b) ii, iii, iv are correct
(c) i, ii, iv are correct
(d) i, ii, iii, iv are correct
Answer:
(a) i, ii, iii are correct
Question 5.
Compute the perimeter and area of each of the shapes below:
Answer:
Lets join the two sides. So we get 4 rectangles.
Perimeter = 5 + 5 + 1 + 4 + 1 + 3 + 1 + 3 + 1 + 4 + 1 + 5 = 34 centimeter
Area of Ist part = 5 × 1 = 5 square centimeter
Area of IInd part = 4 × 1 = 4 square centimeter
Area of IIIrd part = 3 × 1 = 3 square centimeter
Area of IVth part = 4 × 1 = 4 square centimeter
Total Area = 5 + 4 + 3 + 4 = 16 square centimeter 6 A.
Question 6 has two questions (6 A and 6 B). Answer any one.
Question 6.
A Write answers to the questions related to the measurements given below.
(a) If one centimetre divided into 10 equal parts, what is the length of one part?
Answer:
1 millimeter
(b) How many millimetres are there in 8 centimetre and 7 millimetre.
Answer:
87 millimeter
(c) Write 4 millimeters in centimeter
Answer:
0.4 cm or \(\frac{4}{10}\) cm
(d) How much is part of a metre?
Answer:
1 cm
(e) 2 metre = ……… centimetre
Answer:
213 cm
OR
B. Rewrite the table in the ascending order.
| DISTRICT | POPULATION |
| Kottayam | 1974551 |
| Alappuzha | 2127789 |
| Pathanamthita | 1197412 |
| Kollam | 2635375 |
| Thiruvananthapuram | 3301427 |
Answer:
| DISTRICT | POPULATION |
| Pathanamthita | 1197412 |
| Kottayam | 1974551 |
| Alappuzha | 2127789 |
| Kollam | 2635375 |
| Thiruvananthapuram | 3301427 |