With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 3 help improve accuracy.
Kerala Syllabus 5th Standard Maths Question Paper Set 3
Time : 2 Hrs 15 Min
Instructions:
- First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
- Answer all six questions. Answer all the sub questions.
- Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).
Question 1.
(a) Write \(\\frac{3}{6}\) as an equivalent fraction.
Answer:
\(\frac{3}{6}=\frac{1}{2}\)
(b) If a circle is divided into 10 parts and 4 are shaded, how many more parts need to be shaded to make it \(\frac{3}{5}\) of the circle?
Answer:
\(\frac{4}{10}=\frac{2}{5}\) parts are already shaded.
Additional parts to be shaded: \(\frac{1}{2}\)
(c) Simplify \(\frac{8}{12}\) to its lowest terms.
Answer:
\(\frac{8}{12}=\frac{2}{3}\)
(d) Write \(\frac{9}{8}\) as a mixed number.
Answer:
\(\frac{9}{8}\) = 1\(\frac{1}{8}\)
Question 2.
(a) Draw a circle of radius 3 centimetres and draw the pattern given below on it.
Answer:
(b) Given below are circles of radius 3 centimetres and 1 centimetre. What is the length of the line drawn by joining the centres of the two circles?
(A) 2 centimetres
(B) 4 centimetres
(C) 6 centimetres
(D) 8 centimetres
Answer:
(B) 4 centimetres
Question 3.
(a) Which is the fiftieth odd number?
Answer:
The fiftieth odd number can be found by multiplying 50 by 2 and then subtracting 1, SO”1 odd number
= (50 × 2) – 1 = 100 – 1 = 99
(b) What is the sum of the odd numbers from 1 to this number?
Answer:
The sum of odd numbers from 1 to 99
= 50 × 50 = 2500
(c) Rewrite each of the products below as the product of a number by itself:
(i) 9 × 16
(ii) 16 × 36
(iii) 36 × 49
(iv) 49 × 64
(v) 81 × 25
Answer:
(i) 9 × 16 = (3 × 4)(3 × 4)
(ii) 16 × 36 = (4 × 6)(4 × 6)
(iii) 36 × 49 = (6 × 7)(6 × 7)
(iv) 49 × 64 = (7 × 8)(7 × 8)
(v) 81 × 25 = (9 × 5)(9 × 5)
Question 4 has two questions (4 A and 4 B). Answer any one.
Question 4.
A. (a) The school store needs 1825 notebooks. How many packs of 25 notebooks are to be bought?
Answer:
(b) What are the numbers which leave remainder 0 on division by 2 ? And those that leave remainder 1 ?
Answer:
2 = (2 × 1) + 0
4 = (2 × 2) + 0
6 = (2 × 3) + 0
8 = (2 × 4) + 0
Thus, the numbers are 2, 4, 6, 8,10 ….
That is, the multiple of 2 which leave remainder 0 on division by 2.
3 = (2 × 1)+ 1
5 = (2 × 2) + 1
7 = (2 × 3) + 1
9 = (2 × 4) + 1
Thus, the numbers are 3, 5, 7, 9………….
(c) Which of the following statements are true about division?
i. Division is the process of repeated addition.
ii. Any number can be expressed as (Divisor × Quotient) + Remainder.
iii. The remainder is always smaller than the divisor.
iv. If the remainder is 0, the number is exactly divisible.
(a) ii, iii, iv are correct
(b) i, ii, iii are correct
(c) i, iii, iv are correct
(d) i, ii, iii, iv are correct
Answer:
(c) i, iii, iv are correct
OR
B. Write the decimal forms of:
(a) 3 meters and 45 centimeters.
(b) 7 liters and 125 milliliters.
(c) 5 kilograms and 275 grams.
(d) 12 millimeters.
(e) A length of 1 meter 15 centimeters and 6 millimeters.
Answer:
(a) 3 m 45 cm = 3.45 m
(b) 7L 125 mL = 7.125 L
(c) 5 kg 275 g = 5.275 kg
(d) 12 mm = 1.2 cm
(e) 1 m 15 cm 6 mm = 1.156m
Question 5.
(a) A train scheduled to leave at 20:50 is delayed by 35 minutes. At what time does it leave? Write the answer in both 24-hour and AM/PM formats.
Answer:
Scheduled time: 20 : 50 + 35 minutes = 21 : 25
AM/PM format: 9 : 25 PM.
(b) If a train journey starts at 19:25 and ends at 03:40 the next day, calculate the total duration of the journey.
Answer:
Total journey time:
03:40 (next day) – 19: 25 (previous day) = 8 hours and 15 minutes.
(c) If a person cycles 3.5 kilometers in 30 minutes, what is their speed in kilometers per hour?
Answer:
Speed: Distance = 3.5 km, Time = 0.5 hours.
Speed = \(\frac{3.5}{0.5}\) = 7 km/h.
Question 6 has two questions (6 A and 6 B). Answer any one.
Question 6.
A. The amount allotted to certain sectors in the Annual budget of a Grama Panchayat is given in the table.
| Sector | Amount |
| Health | 5825000 |
| Agriculture | 12045750 |
| Drinking water | 960428 |
| Road Development | 10520310 |
| Education | 3295246 |
(a) For which sector is the least amount allotted?
(b) Which are the sectors for which more than one crore is allotted?
(c) For which sector an amount between 50 lakhs and 60 lakhs is allotted?
(d) Write an amount less than 10 million from the table?
(e) Which of the following is the correct statement regarding the total amount allotted for all the areas given in the table?
Total allotted amount:
(A) Between one crore and two crore.
(B) Between two crore and three crore.
(C) Between three crore and four crore.
Answer:
(a) Drinking water
(b) Agriculture, Road development
(c) Health
(d) 5825000
(e) Total amount = 5825000 + 12045750 + 960428 + 10520310 + 3295246 = 32646734
Option (C) Between three crore and four crore
OR
B (a) How many four digit numbers can be formed using all the digits 6, 7, 8 and 9 ?
(b) How many numbers will be there with 7 in the one’s place?
(c) Among the numbers formed using all the digits 6, 7, 8 and 9 how many odd numbers are there?
(d) How many four digits numbers can be formed using all the digits and 0 ?
(e) Find the number according to the hints given below.
- Digits and 5 are used to form the number.
- The number is between 40000 and 50000.
- It is an odd number.
- The digit in the hundredth place of the number is ‘O’.
- The number formed by three middle digits, is between 600 and 700
(A) 48065
(B) 86045
(C) 46058
(D) 46085
Answer:
(a) 24
(b) 6
(c) 12
(d) 18
(e) (D) 46085