With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 2 help improve accuracy.
Kerala Syllabus 5th Standard Maths Question Paper Set 2
Time : 2 Hrs 15 Min
Instructions:
- First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
- Answer all six questions. Answer all the sub questions.
- Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).
Question 1.
The bar graph below represents the books read by students of class 5.
Answer the following questions.
a) The students of which class reads less books?
Answer:
5B
b) Total how many books read by 5th standard students altogether.
Answer:
5A= 10
5B = 5
5C = 20
5D = 30
Total = 65
c) Which divisions students together read 50 books.
Answer:
5C = 20
5D = 30
Total = 50
Question 2.
The prices of cars bought by Ramu, Raju, Gopu and Saju are given below: Ramu- Rs. 449180 Raju- Rs. 448991 Gopu-Rs. 440894 Saju-Rs. 448911
a) Who bought the car with the highest price? How much?
Answer:
Ramu = 449180
b) Write the highest price in words
Answer:
Four lakh forty-nine thousand one hundred and eighty.
c) Who bought the car with the lowest price? How much?
Answer:
Gopu- Rs. 44089
Question 3.
A rectangle plot of length 23 metres and width 14 metres is selected to cultivate Pea, Potato and Tomato as given below.
a) Pea is cultivated in a square plot with sides 14 metres. Find its area.
Answer:
Area where Pea cultivated
= 14 × 14= 196 square metre
b) Find the length of the Potato cultivated plot in metres? If its area is 72 square metres, find its width.
Answer:
Area 72 square metres is given
Length = 2314 = 9 metre
Width = 8 metre
c) Find the area where the Tomato is cultivated?
Answer:
Length = 9 metre
Width = 148 = 6 metre
Area = 9 × 6 = 54 square metre
Question 4 has two questions (4 A and 4 B). Answer anyone.
Question 4.
A. a) 3 litres is equal to
I. 1000 millilitres
II. 2000 millilitres
III. 3000 millilitres
IV. 6000 millilitres
Answer:
III. 3000 millilitres
b) Fill in the blanks:
I. 200 grams = ______ Kilogram
II. 0.850 kilograms = ______ Grams
Answer:
I. 0.2 Kilograms
II. 850 Grams
B. a) How do we write 3.275 kilograms in fractional form?
Answer:
3.275 kilograms = 3\(\frac{275}{100}\) kilograms
b) How do we write this in kilograms and grams?
Answer:
3 kilograms and 275 grams
c) How do we write this in grams alone?
Answer:
1 kilogram = 1000 grams
So, 3 kilograms = 3000 grams
3.275 kilograms = 3275 grams.
Question 5.
Sidharth has a cake. He cuts it into 10 equal parts. He gave 2 parts to Naman, 3 parts to Nidhi, 1 part to Seema and the remaining four parts he kept for himself. Find:
i) What fraction of the cake did he give to Naman?
ii) What fraction of the cake did he give to Nidhi?
iii) What fraction of the cake, he give to Seema?
Answer:
Number of cakes = 1
Number of parts = 10
Each part is \(\frac{1}{10}\)
i) Sidharth gave 2 parts to Naman.
Fraction of cake with Naman
= 2 × \(\frac{1}{10}\) = \(\frac{2}{10}\)
ii) Sidharth gave 3 parts to Nidhi.
Fraction of cake with Nidhi
= 3 × \(\frac{1}{10}\) = \(\frac{3}{10}\)
iii) Sidharth gave 1 part to Seema.
Fraction of cake with Seema = \(\frac{1}{10}\)
Question 6 has two questions (6A and 6B). Answer any one.
Question 6.
A. Look at the following calculations:
1 + 3 = 4
4 + 5 = 9
9 + 7 = 16.
Continue this to compute the squares up to 100.
Answer:
16 + 9 = 25
25 + 11 = 36
36 + 13 = 49
49 + 15 = 64
64 + 17 = 81
81 + 19 = 100
OR
B. A number multiplied by 24 gave 1560.
(i) What will be the product if the next number is multiplied by 24?
(ii) What will be the product if the number just before this is multiplied by 24?
Answer:
(i) If we look at the number just after our original number, we can find the new product by simply adding 24 to 1560:
1560 + 24 = 1584.
So, when the next number is multiplied by 24, we get 1584
(ii) Now, let’s, look at the number just before our original number. To find this new product, we subtract 24 from 1560:
1560 – 24 = 1536.
So, when the previous number is multiplied by 24, we get 1536