Practicing Physics Question Paper Class 10 Kerala Syllabus Set 2 English Medium helps identify strengths and weaknesses in a subject.
Physics Class 10 Kerala Syllabus Model Question Paper Set 2
General Instructions:
- The first 15 minutes is the cool off time. You may – use the time to read and plan your answers.
- Answer the questions only after reading the instructions and questions thoroughly.
- Questions with marks series 1, 2, 3 and 4 are categorized as sections A, B, C and D respectively.
- Five questions are given in each section. Answer any four from each section.
- Answer each question by keeping the time.
Time: 1½ Hours
Total Score: 40 Marks
Section – A
I. Answer any FOUR questions from 1 to 5. Each question carries 1 score. [4 x 1 = 4]
Question 1.
Choose the odd one and write the reason for your answer.
(Base unit. Diffuser cup, Heat sink compound, Power supply board)
Answer:
Heat sink compound. It is a component used for making LED 1 bulbs. All others are parts of LED bulbs
Question 2.
What is the frequency of AC produced in our country for distribution?
(100 Hz, 11 kV, 11000 V, 50 Hz)
Answer:
50 Hz
Question 3.
Using the relation in the first pair, complete the second pair.
focal length : metre
Power of lens : ………..
Answer:
Dioptre
Question 4.
Which part of eye that can be transplanted for donation?
answer:
Cornea
Question 5.
What is the name of the system which converts nuclear energy into electrical energy?
Answer:
Nuclear reactor
II. Answer any FOUR questions from 6 to 10. Each question carries 2 score. (4 × 2 = 8)
Question 6.
a. Which are the fuels that are commonly used in thermal power station?
b. Explain the energy change taking place here.
Answer:
a. coal, naphtha, lignite
b. chemical energy → heat energy → mechanical energy → electrical energy
Question 7.
The angle between two plane mirrors → and the number of images formed, n are tabulated below.
angle θ | number of images formed (n) |
45 | 7 |
60 | a |
90 | b |
120 | 2 |
a. Complete the table.
b. Using the table, fnd the relation between 0 and n
Answer:
a) a = 5, b = 5
b) n = \(\frac { 360 }{ 6 }\) – 1
Question 8.
a.Which are the factors that depend on the direction of electric current produced by the electromagnetic induction?
b. What is the law that connects these two?
Answer:
a. (i) Direction of magnetic field
(ii) Direction of motion of conductor
b. Fleming’s right hand rule.
Question 9.
What are the precautions to be taken to avoid electric shock during the following situations?
a. When inserting plug pins into socket.
b. When maintenance work is being carried out at home.
c. While operating electric devices.
d Connecting adapters of cable TV
Answer:
a. Do only after switching off.
b. Ensure that the main switch and ELCB are switched off.
c. Hands never wet, wear rubber footwear
d. Do not touch the interior parts of the adapter.
Question 10.
Correct the following statements if there is any error.
a Fleming’s left hand rule helps to find the direction of magnetic field around a current carrying conductor.
b. The direction of magnetic field in a solenoid is from north pole to south pole
Answer:
a. Right hand thumb rule helps to find the direction of magneticeld around a current carrying conductor.
b. The direction of magnetic field in a solenoid is from south pole to north pole.
III. Answer any FOUR question from 11 to 15. Each question carries 3 score. (4 × 3 = 12)
Question 11.
a. Find the highest and lowest effective resistances of a circuit connecting 8 resistors each of resistance 4 Ω?
b. Find the minimum number of resistors each of resistance 4 Ω to get an effective resistance of 13 Ω?
Answer:
a. Highest resistance = 4 × 8 = 32 Ω
Lowest resistance = \(\frac { r }{ n }\) – \(\frac { 4 }{ 8 }\) – \(\frac { 1 }{ 2 }\) Ω
Question 12.
With the help of the following figure answer the questions given below.
a. Which medium has greater optical density?
b. Which medium has greater refractive index?
c. Write the name of a medium which can be medium X?
Answer:
a. Medium x
b. Medium x
c. Diamond
Question 13.
“Far point” and “Near point are two terms associated with vision.
a. What do you mean by near point?
b. What is the far point of our eye?
c. What is the defect of eye due to the increase in distance to the near point?
Answer:
a. Near point is the nearest point at which the object can be seen distinctly.
b. At infinity
c. Presbyopia
Question 14.
In the misty mornings, we can see the path of light coming through the trees.
a. Which phenomenon is behind this? Explain.
b. What does the intensity of scattering depends?
Answer:
a. Tyndal effect – When light rays pass through a colloidal fluid or suspension, the tiny particles get illuminated due to scattering. Because of this, the path of light is made visible. This phenomenon is Tyndal effect.
b) Size of colloidal particles
Question 15.
Geo thermal power plants are not possible in Kerala.
a. Why is it said that not possible in Kerala?
b. Which is the energy source used here?
c. Which type of energy produced here?
Answer:
a. There is no hotspot in the underground of Kerala.
b. High temperature in Magma.
c. Electrical energy
IV. Answer any FOUR questions from 16 to 20. Each question carries 4 score. (4 × 4 = 16)
Question 16.
The magnification of an image produced by a lens is between-1 to 0.
a. Which type of lens is this?
b. Draw the ray diagram of image formation?
c. Where will be the position of object when the magnification became.-1
Answer:
Question 17.
Classify the following statements as “related to step up transformer” and “related to step down transformer”
\(\frac { Ns }{ Np }\) < 1, \(\frac { ls }{ lp }\) < 1, \(\frac { lp }{ ls }\) > 1, \(\frac { Vp }{ Vs }\) < 1
lp < ls, Vs > Vp, \(\frac { Vs }{ Vp }\) > 1, \(\frac { Np }{ Ns }\) < 1
Answer:
Step of transformer | Step down transformer |
\(\frac { ls }{ lp }\), Vs > Vp | \(\frac { Ns }{ Np }\) < 1, \(\frac { lp }{ ls }\) > 1 |
\(\frac { Vs }{ Vp }\) > 1, \(\frac { Np }{ Ns }\) | \(\frac { Vp }{ Vs }\) < 1, lp < ls |
Question 18.
Complete the missing parts in the following table.
Mirror and position of object. | Features of image | Situations used |
Plane mirror | …………(a)……………… | To view face |
……(b)………… | Small,erect and virtual image | Rear view mirror |
Source of light at the focus of concave mirror. | Parallel rays of light | ……………(c)…………. |
Between Fand P of a concave mirror. | …………(d)……………….. | To examine the throat by ENTdoctors |
Answer:
a. Erect, virtual and same size of the object
b. Convex mirror
c. Reflector in head lights
d. Erect,larger and virtual image.
Question 19.
a. Which is the device shown in the figure?
b. Write the energy transformation take place here.
c. Which are the moving parts in this device?
d. Which principle is used in this device?
Answer:
a. Moving coil loudspeaker
b. Electrical energy into sound energy
c. Voice coil and diaphragm
d. Motor principle
Question 20.
Observe the following figure and answer the questions
a. Calculate the resistances of bulbs A and B in the circuit.
b. Calculate the intensity of current through these bulbs
c. Which bulb glows with more intensity?
d. Write any two advantages when connecting these bulbs parallel.
Answer:
Resistance of A
P = \(\frac{v^2}{P}\)
R = \(\frac{v^2}{P}\) – \(\frac{12 \times 12}{2}\) = 72
Resistance of B,
R = \(\frac{v^2}{P}\) = \(\frac{12 \times 12}{3}\) = 48
b) Effective resistance in the circuit, R = R1 +R2
R = 72 +48 = 120 Ω
I = \(\frac { V }{ R }\) = \(\frac { 12 }{ 120 }\) = \(\frac { 1 }{ 10 }\)A
c) Bulb A
d) i) Each bulb glows with the power marked.
ii) Each bulb can be controlled by using separate switches.