Practicing Physics Question Paper Class 10 Kerala Syllabus Set 2 English Medium helps identify strengths and weaknesses in a subject.
Physics Class 10 Kerala Syllabus Model Question Paper Set 2
Time: 11/2 Hours
Total Score: 40
Instructions:
- The first 15 minutes is cool-off time. This time is meant for reading the questions and planning your answers.
- This question paper includes 18 questions in sections A, B, C, D.
- Questions 5, 11, 13, 14 and 18 contain choices.
- You need to answer only one of the options provided for each of these choice-based questions.
Section – A
I. Write down the correct answer by choosing from the given options for questions 1 to 4. Each question carries 1 score.(4 × 1 = 4)
Question 1.
Study the following diagrams in which the path of a ray of light passing through a glass prism as traced by four students P, Q, R ans S is shown:
The student who has traced the path correctly is
a) P
b) Q
c) R
d) S
Answer:
b) Q
Question 2.
Choose the correct statement regarding the magnetic polarity of a current carrying solenoid and write it down.
a) If the current in one end of the solenoid is clockwise, then that end is north pole.
b) If the current in one end of the solenoid is clockwise, then that end is south pole.
c) If the current in one end of the solenoid is anticlockwise, then that end is south pole.
d) None of the above.
Answer:
b) If the current in one end of the solenoid is clockwise, then that end is south pole.
Question 3.
Statement: A heater A operating at 230 V draws 2 A current ,its power obtained is 460 W.
Reason: The power can be calculated as the product of voltage and current.
a) Statement and reason are correct; the reason explains the statement.
b) Statement and reason are correct; however, the reason does not explain the statement.
c) both the statement and the reason are incorrect.
d) Statement is incorrect; reason is correct
Answer:
a) Statement and reason are correct; the reason explains the statement.
Question 4.
Choose the correct statements regarding the wheel and axle system
i) The mechanical advantage is greater than one.
ii) The work done by the effort and the work done by the load are equal.
iii) The mechanical advantage is less than one.
iv) The radius of the wheel is greater than the radius of the axle.
Which of the following is correct?
a) i, ii, iii are correct
b) i, ii, iv are correct
c) ii, iii, iv are correct
d) i, iii, iv are correct
Answer:
b) i, ii, iv are correct
Section – B
II. Write clown the answers to the questions 5 to 11. Questions 5 and 11 have choices. Each question carries 2 score. (7 × 2 = 14)
Question 5.
A) What is the necessity of reducing carbon footprint?(Write any two points)
Answer:
- It helps slow down climate change by lowering greenhouse gas emissions.
- Reduces the occurrence of severe weather phenomena like droughts and floods.
- Helps in preserving natural habitats for plants and animals and limiting pollution
- Decreased emissions lead to cleaner air and water, which enhances public health by lowering respiratory and other illnesses.
OR
B) We know that the sun is the basis of all energy on the earth.
a) Name a device that utilise solar energy
b) To reduce electricity consumption in our houses, we can maximise the use of sunlight during the day. Write any two ways for it.
Answer:
a)
• Solar water heater
• Solar cooker
• Solar fumace(any one)
b)
• By opening the windows and drapes, rooms can be made brighter without the use of artificial lighting.
• To maximize daylight, we should choose locations for work or study next to windows.
• Mirrors and light-colored walls can improve the room’s ability to reflect sunlight. .
Question 6.
What are the radiations that are seen on either side of visible light in the electromagnetic spectrum. Write one use of the radiation with a shorter wavelength than visible light.
Answer:
Radiation seen in the electromagnetic spectrum on both sides of visible light are UV radiation and infrared radiation. Ultraviolet radiation has a shorter wavelength than visible light.
Use : UV radiation produces vitamin D
Question 7.
Analyse the figure.
An object is placed between F and 2F
a) Copy the diagram and complete to show the image formation.
b) Where must be the object be placed to get a real image of same size as that of the object.
Answer:
a)
b) At 2F
Question 8.
Fill in the blanks of the table suitably.
| Device | Energy change | Effect of electricity |
| Electric bulb | (a) | Lighting effect |
| (b) | Electrical energy is converted to heat energy | (c) |
| Mixie | (d) | Mechanical effect |
Answer:
(a)-Electrical energy,
(b)-Electric Iron,
(c)-Heating effect,
(d)-Electric energy to mechanical energy
Question 9.
State the Motor principle. If the directions of current in the conductor and the magnetic field are the same, in which way will the conductor move?
Answer:
A current carrying conductor which is free to move, placed in a magnetic field, exhibits a tendency to deflect. This is motor principle. If the current in the conductor and the magnetic field are the same, the conductor will not move.
Question 10.
Write a short note on MCB.
Answer:
MCB is a device used in branch circuits instead of safety fuse. When there is excessive current in a circuit due to short circuit or overload, the MCB automatically operates and disconnects the circuit ie., it trips. After resolving the circuit problem, the MCB switch can be turned on to restore the circuit to its original state. MCB works by utilising the magnetic effect and heating effect of electricity.
Question 11.
A.What is a third-order lever, and how does it differ from other levers?
Answer:
In a third-order lever, the effort is applied between the fulcrum and the load. The load arm is longer than the effort arm, resulting in a mechanical advantage less than 1, meaning more effort is required.
Example: A pair of tweezers, fishing rod
OR
B. Classify the following into those with a mechanical advantage greater than 1 and those less than 1: Nutcracker, fishing rod, lemon squeezer, bottle opener, broom, wheelbarrow, forceps, tongs.
Answer:
| Mechanical advantage greater than 1 | Mechanical advantage less than 1 |
| Nutcracker | fishing rod |
| lemon squeezer | forceps |
| bottle opener | tongs |
| wheelbarrow | broom |
Section – C
III. Write down the answers to questions 12 to 17. Questions 13 and 14 have choices. Each question carries 3 score. (6 × 3 = 18)
Question 12.
Answers to the questions based on the figure given below.
a) Which colour deviates the most and the least due to dispersion?
b) Which colour has the shortest wavelength and which one has the longest wavelength?
c) As the wavelength increases deviation (increases/decreases)
Answer:
a) Violet undergoes most deviation.Red undergoes least deviation.
b) Violet has the shortest wavelength. Red has the longest wavelength.
c) As the wavelength increases the deviation decreases.
Question 13.
A. An electric heater operating at 230 V draws 2 A current.
a) What is the resistance of the heater?
b) Calculate the heat produced when this heater operates for 10 minutes.
c) What is the power of this appliance?
Answer:
OR
B. An electric heater has a resistance of 690 Q and is designed to operate at 230 V.
a) What are the characteristics of a good heating coil?
b) Calculate the heat energy produced by this heater when it works for 30 minutes.
Answer:
Resistance, R = 690 Ω, time,
t=3O minute = 30 × 60 = 1800s
Voltage, V = 230V
(a) Characteristics of a good heating coil are
- High oxidation resistance
- Ability to remain in red hot condition fora long time.
- High melting point
- High resistivity
(b) Heat generated,
\(\mathrm{H}=\frac{V^2 t}{R}=\frac{230^2 \times 1800}{690}=138000 \mathrm{~J}\)
Question 14.
A. Choose the correct answer from the brackets.
a) What type of electricity is generated in the armature of a DC generator?
(AC, DC, current at constant voltage, none of these)
b) At what voltage is electricity generated in power stations in India?
(11 kV, 11 V, 110 V, 230 V)
c) What is the voltage of electricity supplied for household use in our state?
(230 V, 230 kV, 11 kV, 11 V)
Answer:
a) Type ofelectricity in DC generator armature: AC
b) Voltage generated in power stations in India: 11 kV
c) Voltage supplied for household use: 230 V
Question 14.
B. Look at the picture given below.
Identify the device and explain how it ensures safety?
Answer:
The device is a three pin plug . In a three pin plug ,one of the three pins are Connected to live, one to neutral and one to earth wire. The earth pin in a three-pin plug is longer and thicker, making it the first to make contact and the last to break when inserted into or pulled out of a socket. Its middle slit ensures a tight fit. The earth pin E makes contact with the earth line. The appliance’s body is attached to this pin.
In the instance when the body makes any kind of electrical contact, the earth wire conducts electricity to the earth. Current is increased as it travels to the ground through a low resistance circuit. The circuit breaks as a result of the fuse wire’s increased generation of heat. This ensures both the instrument’s and the user’s safety.
Question 15.
a) Name the two main parts of a compound microscope?
b) Differentiate between a refracting telescope and a compound microscope? How does magnification work in both devices?
Answer:
a) The two main parts of a compound microscope are objective and eyepiece,
b) A refracting telescope is used to view distant objects (like stars), while a compound microscope is used to view very small objects (like cells). Both devices use two lenses: one to form the image (objective lens) and another to magnify it
(eyepiece lens). However, the telescope magnifies distant objects, while the microscope magnifies tiny, close objects.
Question 16.
a) What happens to the air column around the paper cone when the voice coil vibrates?
b) Does the voice coil vibrate if DC reaches the voice coil?
c) Name an another device that works on the same principle?
Answer:
a) Air column also vibrates. As a result, sound is produced.
b) No. Because there is no flux change occurring.
c) Electric motor
Question 17.
Match appropriately.
| Lever | A | B |
| First order | Load is always more than the effort | Fulcrum comes in between effort and load |
| Second order | Load can be equal to, lesser or greater than the effort | Effort comes in between fulcrum and load |
| Third order | Load is always less than the effort | Load comes in between effort and fulcrum |
Answer:
| Lever | A | B |
| First order | Load can be equal to, lesser or greater than the effort | Fulcrum comes in between effort and load |
| Second order | Load is always more than the effort | Load comes in between effort and fulcrum |
| Third order | Load is always less than the effort | Effort comes in between fulcrum and load |
Section – D
18th question has a choice. Answer any one of the two questions. Each question carries 4 score. (4 × 1 = 4)
Question 18.
A. Below is a picture of hacksaw blades of various lengths fixed on a wooden board.
a) Which blade vibrates in the same w’ay as the blade of C is excited?
b) Why do the two blades vibrate in the same way?
c) What is the vibration of the other blades known as?
d) What happens to the amplitude of vibrations when the natural frequency of an object matches the frequency of the external forcing object?
Answer:
a) F
b) The natural frequency of both is equal because of resonance.
c) Forced Vibration
d) If the natural frequency of the forcing object and that of the forced object are equal, the objects are said to be in resonance. The objects undergoing resonance will vibrate with maximum amplitude.
B. (a)
A person standing at A claps his hands. Is there any chance for occurence of echo?
b) The echo of fire cracker (kathina) is heard after 1 s by the person who burst it. How far is the reflecting surface from the person hearing the echo?
Answer:
a) Yes, can hear echo. Because the wall W, is 18m away from the source. Minimum distance to hear echo is 17.5 m.
b) Let d be the distance to the reflecting surface. Then the total distance travelled by the sound to the’ reflecting surface and back will be 2d.
Speed of sound = \(\frac{Total dis tance travelled }{time}\)
\(v=\frac{2 d}{t}\)
\(\mathrm{d}=\frac{(\mathrm{v} \times \mathrm{t})}{2}=\frac{(350 \times 1) \mathrm{m}}{2}=175 \mathrm{~m}\)
The reflecting surface will be 175 m away.