Kerala Syllabus Class 5 Maths Chapter 10 Solutions Rectangle Math

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SCERT Class 5 Maths Chapter 10 Solutions Rectangle Math

Class 5 Maths Chapter 10 Rectangle Math Questions and Answers Kerala State Syllabus

Rectangle Math Class 5 Questions and Answers Kerala Syllabus

Question 1.
Calculate the areas of the rectangle with lengths of sides as below:
i) 6 centimetres, 3 centimetres
ii) 12 centimetres, 5 centimetres
iii) 10 centimetres, 10 centimetres
iv) 8 metres, 5 metres
v) 11 metres, 7 metres
Answer:
i) Area = 6 × 3 = 18 square centimetres
ii) Area = 12 × 5 = 60 square centimetres
iii) Area = 10 × 10 = 100 square centimetres
iv) Area = 8 × 5 = 40 square metres
v) Area = 11 × 7 = 77 square metres

Question 2.
Draw rectangles of area and perimeter as below:
i) 12 square centimetres, 14 centimetres
Answer:
12 square centimetres, 14 centimetres
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 17
Sides = 3 centimetres, 4 centimetres
Area = 3 × 4
= 12 square centimetres

Perimeter =(3 + 4) × 2
= 7 × 2
= 14 centimetres

ii) 12 square centimetres, 16 centimetres
Answer:
12 square centimetres, 16 centimetres
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 18
Sides = 2 centimetres, 6 centimetres
Area =2×6 = 12 square centimetres
Perimeter =(2 + 6)×2 = 8×2 = 16 centimetres

iii) 12 square centimetres, 26 centimetres
Answer:
12 square centimetres, 26 centimetres
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 19
Sides =12 centimetres, 1 centimetres
Area =12×1 = 12 square centimetres
Perimeter = (12 + 1) × 2 = 13 ×2
= 26 centimetres

iv) 5 square centimetres, 12 centimetres
Answer:
5 square centimetres, 12 centimetres
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 20
Sides = 5 centimetres, 1 centimetres
Area = 5 × 1
= 5 square centimetres

Perimeter = (5 + 1) × 2
= 6 × 2
= 12 centimetres

v) 8 square centimetres, 12 centimetres
Answer:
8 square centimetres, 12 centimetres
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 21
Sides = 4 centimetres, 2 centimetres
Area = 4 × 2
= 8 square centimetres
Perimeter =(4 + 2) × 2
= 6 × 2
= 12 centimetres

vi) 9 square centimetres, 12 centimetres
Answer:
9 square centimetres, 12 centimetres
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 22
Sides = 3 centimetres, 3 centimetres
Area = 3 × 3 = 9 square centimetres
Perimeter = (3 + 3) × 2
= 6 × 2
= 12 centimetres

Kerala Syllabus Class 5 Maths Chapter 10 Solutions Rectangle Math

Question 3.
Now compute the perimeter and area of each of the shapes below:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 30
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 31
Perimeter = 4 + 6 + 1 + 1 + 2 + 1 + 1 + 4
= 20 centimeter
Area of the complete rectangle = 4 × 6
= 24 square centimeter

Area of Ist part = 2 × 1 = 2 square centimeter
Area of IIndpart = 2 × 1 = 2 square centimeter
Total Area = 24 – (2 + 2) = 20 square centimeter

Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 32
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 33
Perimeter = 4 + 5 + 4 + 2 + 1 + 1 + 1 + 2 = 20 centimeter
Area of large rectangle = 5 × 4 = 20 square centimeter
Area of small square = 1 × 1 = 1 square centimeter
Total Area = 20 – 1= 19 square centimeter

Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 34
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 35
Let’s make it as 2 part
Perimeter of Ist part = 2 × (4 + 1)
= 2 × 5 = 10 centimeter
Perimeter of IInd part = 2 × (5 + 1)
= 2 × 6 = 12 centimeter
Total Perimeter =10 + 12 = 22 centimeter
Area of Ist part = 4 × 1 = 4 square centimeter
Area of IInd part = 5 × 1 = 5 square centimeter
Total Area = 5 + 4 = 9 square centimeter

Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 36
Answer:
Let’s join the two sides. So we get 4 rectangles.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 37
Area of Ist part = 5 × 1 = 5 square centimeter
Area of IInd part = 4 × 1 = 4 square centimeter
Area of IIIrd part = 3 × 1 = 3 square centimeter
Area of IVth part = 4 × 1 = 4 square centimeter
Total Area = 5 + 4 + 3 + 4 = 16 square centimeter

Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 38
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 39
Each side is 2 cm.
So the perimeter will be = 2 × 12 = 24 centimeter
Area of Ist part = 2 × 2 = 4 square centimeter
Area of IInd part = 2 × 6 = 12 square centimeter
Area of IIIrd part = 2 × 2 = 4 square centimeter
Total Area = 4 + 12 + 4 = 20 square centimeter

Intext Questions And Answers

Question 1.
Find the widths and heights of all rectangles like this.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 3
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 4

Question 2.
Write the perimeters of the rectangles in the table below.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 6
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 7

Question 3.
Now we can add areas also in our table:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 11
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 12
The area of large rectangles (for example playground, rooms in a building etc) are measured in terms of a square of side 1 metre. So,
The area of a square of sides 1 metre is said to be 1 square metres.

Question 4.
What is the perimeter of this rectangle?
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 13
Answer:
Adding the lengths of sides one by one
Perimeter = 7 + 4 + 7 + 4 = 22 centimetres
Otherwise, let’s take the sides of same lengths together,and calculate the perimeter as twice 7 and 4.
(7 × 2) + (4 × 2) = 14 + 8 = 22 centimetres
We can calculate the perimeter in one more method.
Twice 7 and twice 4 is twice 11. Therefore,
(7 × 2) + (4 × 2) = (7 + 4) × 2
= 11 × 2
= 22 cm

Kerala Syllabus Class 5 Maths Chapter 10 Solutions Rectangle Math

Question 5.
Can you calculate the perimeter of a rectangle of sides 1 Ocm and 5cm in a similar way?
Answer:
Perimeter = (10 × 2) + (5 × 2)
= (10 + 5) × 2
= 15 × 2
= 30 cm
The perimeter of a rectangle is twice the sum of its sides.

Question 6.
Using this, can’t you mentally calculate the perimeters of the rectangles with lengths of sides as below?
i) 6 centimetres, 3 centimetres
ii) 13 centimetres, 7 centimetres
iii) 6 centimetres, 6 centimetres
iv) 25 metres, 15 metres
v) 34 metres, 16 metres
Answer:
i) Perimeter = (6 × 2) + (3 × 2)
= (6 + 3) × 2
= 9 × 2
= 18 centimetres

ii) Perimeter = (13 × 2) + (7 × 2)
= (13 + 7) × 2
= 20 × 2
= 40 centimetres

iii) Perimeter = (6 × 2) + (6 × 2)
= (6 + 6) × 2
= 12 × 2
= 24 centimetres

iv) Perimeter= (25 × 2) + (15 × 2)
= (25 + 15) × 2
= 40 × 2
= 80 metres

v) Perimeter= (34 × 2) + (16 × 2)
= (34 + 16) × 2
= 50 × 2
= 100 metres

Question 7.
Can you now calculate the area of the rectangle given below?
Answer:
Area = 6 × 2 = 12 square centimeters

Question 8.
How many squares of side 1 centimeter can we arrange along the bottom side?
Answer:
We can add 6 squares of 1 centimeter.

Question 9.
How many such rows can be stacked inside the rectangle?
Answer:
2 rows can be stacked.

Question 10.
How many squares in all?
Answer:
12 squares
The area of a rectangle is the product of the lengths of its sides.

Class 5 Maths Chapter 10 Kerala Syllabus Rectangle Math Questions and Answers

Question 1.
Find out the area of the figure given below.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 40
Answer:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 41
Let’s extend the top left comer, so we get a complete square with sides 8 cm.
Area of the large square = 8 × 8 = 64 square centimeters
After joining the two sides we will get a small rectangle with sides 3 cm and 2 cm.
To find the area of the shape, we take the area of the big rectangle and subtract the area of the smaller rectangle from it.
Area of the small rectangle = 3 × 2 = 6 square centimeters
Area of the figure = 64 – 6 = 58 square centimeters

Question 2.
Find the area and perimeter for the following figures.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 42
Answer:
Perimeter =(8 + 3) × 2 = 22 centimeter
Area = 8 × 3 = 24 square centimeter

Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 43
Answer:
Perimeter = (6 + 2) × 2 = 16 centimeter
Area = 6 × 2 = 12 square centimeter

Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 44
Answer:
Perimeter = (5 + 2) × 2 = 14 centimeter
Area = 5 × 2 = 10 square centimeter

Kerala Syllabus Class 5 Maths Chapter 10 Solutions Rectangle Math

Question 3.
What is the area of a rectangle of length 7 meter and width 3 meter?
Answer:
Area = 7 × 3 = 21 square meter

Question 4.
Find the area of the colored part in the figure.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 45
Answer:
Area of large rectangle = 14 × 7 = 98 square centimeter
Area of small rectangle = 5 × 1 = 5 square centimeter
Therefore the area of shaded part = 98 – 5 = 93 square centimeter

Question 5.
A rectangle plot of length 23 metres and width 14 metres is selected to cultivate Pea, Potato and Tomato as given below.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 46
a) Pea is cultivated in a square plot with sides 14 metres. Find its area.
b) Find the length of the Potato cultivated plot in metres? If its area is 72 square metres, find its width.
c) Find the area where Tomato is cultivated?
Answer:
a) Area where Pea cultivated = 14 × 14 = 196 square metre
b) Area 72 square metre is given Length = 23 – 14 = 9-metre
Width = \(\frac{72}{9}\) = 8 metre
c) Length = 9 metre
Width = 14 – 8 = 6 metre
Area = 9 × 6 = 54 square metre

Class 5 Maths Chapter 10 Notes Kerala Syllabus Rectangle Math

In this chapter, we are going to study about two important concepts in mathematics: Perimeter and Area. These ideas will help you learn how to measure different shapes and how much space they take up.

  • The length around a shape is called perimeter.
  • The perimeter of a rectangle is twice the sum of its sides.
  • Area is the amount of space inside a shape.
  • The area of the rectangle is the product of the lengths of its sides.
  • If the lengths of the sides are in centimetres, the area is in square centimetres, and if the lengths of the sides are in metres, then the area is in square metres.

Squares And Rectangles
We can make rectangles by joining small squares. For example see the picture given below:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 1
Here all the squares have sides of 1 centimetre.
Can you write the width and height of all the rectangles in the picture?
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 2
Here the width of the rectangle is 3 centimetres and height is 2 centimetres.

Measuring Boundaries
If we paste colored threads along the edges of each rectangle, what is the length of the thread required to paste around the first rectangle?
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 5
It takes 1 centimeter for the left and right edges and 6 centimetres for the top and bottom edges.
So, 1 + 1 + 6 + 6 = 14 centimetres

The length, taken around the rectangle, is called its perimeter.
Thus, the perimeter of the above rectangle is 14 centimetres.

Kerala Syllabus Class 5 Maths Chapter 10 Solutions Rectangle Math

Measuring Insides
Let’s consider the two rectangles given below:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 8
The perimeter of both rectangle is 14 centimetres. Here the left rectangle has 6 small squares, while the right rectangle has 12 small squares, which means the space inside rectangles will vary if two 14 centimetre long strings are cut in different ways to make the edges.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 9
So we can say that the rectangle in the right side is more spread out.
The measure of the spread is called area.
Just as we measure lengths using fi×ed lengths such as centimetre and metre, we measure areas using predetermined squares.
For example,
The area of a square of sides 1 centimetre is said to be 1 square centimetre.
If two such squares joined then area is 2 square centimetres, three of them joined together is said to have area 3 square centimetres and so on.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 10

Calculate
How can we compute the area of this rectangle?
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 14
For this, we have to calculate the number of small squares of side 1 centimetre that can fit inside it.
Let’s see how many squares we can put in the bottom side:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 15
See here we can add 7 squares in the bottom. Likewise how many such rows can we stack inside the rectangle? *
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 16
There are 4 rows of 7 squares each.
4 × 7 = 28 squares in total.
So, the area is 28 square centimetres.

  • If the lengths of the sides are in centimetres, the area is in square centimeters.
  • If the lengths of the sides are in metres, the area is in square meters.

Some Other Shapes
See the figure which is made up of eerkkil bits:
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 23
Can you guess how many pieces of eerkkil are needed to make this?
The length of each side is also given. Then adding up all we get,
5 + 4 + 2 + 2 + 3 + 2 = 18
So to create this, cut an 18 cm long piece of eerkkil and cut it into six pieces using the lengths given. Let’s try another method to make this:

Make a rectangle with sides 4 cm and 5 cm
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 24
Mark 2 cm in the top and 3 cm in the right sides of the rectangle. And cut out the pieces.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 25
Replace the removed bits as shown, so we get the first figure.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 26
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 27
The rectangle and this figure has the same perimeter.
Let’s cut out this figure in a sheet of paper. Now how can we find the area?
See, here we can consider this as two rectangles joined together.
Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 28
To find the area,
Add the areas of two rectangles:
(4 × 2) + (2 × 3)
= 8 + 6
= 14 square centimetres

Another method:

  • To create this shape, we start by cutting out a big rectangle
  • Then we cut a small rectangle out of it.

Kerala Syllabus Class 7 Maths Chapter 10 Solutions Rectangle Math 29

To find the area of the shape, we take the area of the big rectangle and subtract the area of the smaller rectangle from it.
(4 × 5) – (2 × 3) = 20 – 6 = 14 square centimetres
When we remove the small rectangle from the big one, the area got smaller, but the perimeter stayed the same.

Kerala Syllabus Class 5 Maths Chapter 10 Solutions Rectangle Math

  • The length around a shape is called perimeter.
  • The perimeter of a rectangle is twice the sum of its sides.
  • Area is the amount of space inside a shape.
  • The area of the rectangle is the product of the lengths of its sides.
  • If the lengths of the sides are in centimetres, the area is in square centimetres, and if the lengths of the sides are in metres, then the area is in square metres.

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