With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 5 help improve accuracy.
Kerala Syllabus 5th Standard Maths Question Paper Set 5
Time : 2 Hrs 15 Min
Instructions:
- First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
- Answer all six questions. Answer all the sub questions.
- Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).
Question 1.
(a) The picture given below is prepared by 5th std students of Govt. UPS Punnassery using number cards.
(i) Which of the following is the largest number that can be made using all the digits in the figure?
Answer:
Largest number = 9876420
(ii) Write the smallest number using these digits.
Answer:
Smallest number = 2046789
(b) Write the number according to the place value.
(i) 8 lakh 3 ten thousand 6 thousand 7 hundred 3 tens and 2 ones.
Answer:
836732
(ii) Which among the following represents seven lakh two thousand four hundred and thirty two?
(a) 72432
(b) 720432
(c) 702432
(d) 724320
Answer:
(b) 702432
Question 2.
(a) Look at the following calculations: .
4 = 1 + 2 + 1
9 = 1 + 2 + 3 + 2 + 2
16 = 1 + 2 + 3 + 4 + 2 + 1
(i) How do we write 49 as a sum like this?
Answer:
49 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 6 + 5 + 4 + 3 + 2 + 1
(ii) How about 81?
Answer:
81 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
(iii) Can you write 121 as such a sum?
Answer:
121 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
(b) (i) How many odd numbers like 1, 3, 5 are to be added to get 123 ?
Answer:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 = 123
12 odd numbers are needed to get 123.
(ii) Which is the last odd number added in this?
Answer:
23 is the last odd number added in this.
(c) Which of the following statements are correct about the sum of odd numbers?
(i) 1 + 3 + 5 = 9, which is a square number.
(ii) The sum of the first 10 odd numbers is 100.
(iii) The sum of the first n odd numbers equals n<sup>2</sup>.
(iv) Adding even numbers also gives a perfect square.
(a) i, ii, iii are correct
(b) ii, iii, iv are correct
(c) i, iii are correct
(d) i, ii, iii, iv are correct
Answer:
(c) i, iii are correct
Question 3.
Write each of the numbers as certain times 9 and a remainder
(a) 11
(b) 111
(c) 1111
Answer:
The number can be written in certain times of 9 and a reminder as:
(a) 11 = (9 × 1) + 2
(b) 111 = (9 × 12)+ 3
(c) 1111 = (9 × 123) + 4
(i) Can you guess how 1111 is written like this? Check your guess by actual division.
Answer:
(ii) Write out this number pattern.
Answer:
(9 × 1) + 2 = 11
(9 × 12) + 3 = 111
(9 × 123) + 4 = 1111
(9 × 1234) + 5 = 11111
(9 × 12345) + 6= 111111
(9 × 123456) + 7 = 1111111
Question 4 has two questions (4 A and 4 B). Answer any one.
Question 4.
[A] (a) State ‘T‘ for True and ‘F‘ for False:
(i) 33 metres 50 centimetres is equal to 3350 centimetres.
Answer:
True
(ii) 5 kilograms 250 grams is equal to 2300 grams.
Answer:
False
(iii) 8150 millilitres is equal to 8050 millilitres.
Answer:
False
(iv) 4000 millilitres is equal to 4 litres.
Answer:
True
(v) 7 kilograms is equal to 8000 grams.
Answer:
False
(b) Complete the following table.
| Measure | Fractional form | Decimal form |
| 25 kilometres 836 metres | __________ kilometres | _______ kilometres |
| 9 litres 375 millilitres | _________ litres | _______ litres |
| 13 metres 38 centimetres | _________ metres | _______ metres |
| 2 kilograms 800 grams | _________ kilograms | _______ kilograms |
| 12 centimetres 3 millimetres | _________ centimetres | _______ centimetres |
| 525 millilitres | ________ litres | ________ litres |
| 250 grams | _________ kilograms | _______ kilograms |
Answer:
Question 4.
[B] Find out the area of the figure given below.
Answer:
Let’s extend the top left comer, so we get a complete square with sides 8 cm.
Area of the large square = 8 × 8 = 64 square centimeters
After joining the two sides we will get a small rectangle with sides 3 cm and 2 cm.
To find the area of the shape, we take the area of the big rectangle and subtract the area of the smaller rectangle from it.
Area of the small rectangle = 3 × 2 = 6 square centimeters
Area of the figure = 64 – 6 = 58 square centimeters
Question 5.
A picture of a clock is given.
(a) What are the hands on this clock?
Answer:
Second hand, minute hand, hour hand
(b) Which hand turns the fastest?
Answer:
Second hand
(c) How long does it take for the minute hand to rotate once?
Answer:
1 hour
(d) What time is it on the clock, in the picture?
Answer:
7:15
(e) Draw a picture of a clock and mark the time as half past eight.
Answer:
Question 6 has two questions (6A and 6 B). Answer any one.
Question 6.
[A] (a) Check whether the first is a multiple of the second: 7, 91
Answer:
This shows 91 = 13 × 7
That is, 91 is a multiple of 7.
(b) Now find the quotients below by removing common factors:
(i) 630 ÷ 126
(ii) 420 ÷ 105
Answer:
(i) 630 = 2 × 9
126 = 2 × 9 × 7
Common factors: 2, 9, 7
Thus, 630 ÷ 126 = 5
(ii) 420 = 4 × 3 × 5 × 7
105 = 3 × 5 × 7
Common factors: 3, 5, 7
Thus, 420 ÷ 105=4
OR
[B] The graph below shows the units of electricity consumed during various months of a year:
(i) In which months was the maximum electricity used?
Answer:
The maximum electricity consumption , occurred in March and April, each.
(ii) In which months was it the minimum?
Answer:
The minimum electricity consumption occurred in September, October, November, and December
(iii) What is the difference between the maximum and minimum?
Answer:
Maximum unit of electricity consumed = 340
Minimum unit of electricity consumed = 290
The difference between the maximum and minimum = 340 – 290 = 50 units
(iv) Are there any months in which the same units of electricity was used?
Answer:
Yes, September, October, November and December.
(v) What is the total number of uftits used in this whole year?
Answer:
310 + 340 + 330 + 300 + 290 + 290 = 1860
The total electricity used in the whole year = 1860 × 2 = 3720 unit