Kerala Syllabus Class 10 Physics Model Question Paper Set 1

Practicing Physics Question Paper Class 10 Kerala Syllabus Set 1 English Medium helps identify strengths and weaknesses in a subject.

Physics Class 10 Kerala Syllabus Model Question Paper Set 1

General Instructions:

1. The first 15 minutes is the cool off time. You may – use the time to read and plan your answers.
2. Answer the questions only after reading the instructions and questions thoroughly.
3. Questions with marks series 1, 2, 3 and 4 are categorized as sections A, B, C and D respectively.
4. Five questions are given in each section. Answer any four from each section.
5. Answer each question by keeping the time.

Time: 1½ Hours
Total Score: 40 Marks

Section – A

I. Answer any FOUR questions from 1 to 5. Each question carries 1 score. [4 x 1 = 4]

Question 1
How many 10Ω resistors will connect parallel to get an effective resistance which is equal to the effective resistance when 5 resistors each of 5Ω connecting parallel to each other.
Answer:
10

Question 2.
Find the odd one from the following.
\(\frac { NS }{ NP }\) < 1, \(\frac { Vs }{ Vp }\) > 1, \(\frac { Is }{ Ip }\) < 1. Also write the reason for that.
Answer:
\(\frac { NS }{ NP }\) < 1 This indicates step down transformer. All others indicate step up transformer.

Question 3.
Which is the incorrect statement about diamond?
a) High refrective index.
b) Velocity of light is more.
c) The optical density is more.
d) More possibility to occur total internal reflection.
Answer:
The velocity of light is more.

Question 4.
Using the relation from the first word pair, complete the second.
Presbyopia : Convex lens
For-sightedness : ………………..
Answer:
Convex lens

Question 5.
Which of the following fossil fuel obtained from the earth is in high quantity?
(petroleum, natural gas, biogas, coal)
Answer:
Coal

II. Answer any FOUR questions from 6 to 10. Each question carries 2 score. (4 × 2 = 8)

Question 6.
a) Which substance is to be added to domestic LPG as an indicator to detect gas leakage?
b) What precautions are to be taken to avoid accidents due to LPG leakage?
Answer:
a. Ethyl mercaptan

b. (1) Examine the rubber tube in regular intervals and ensure that it does not have a leakage.
(ii)Turn on the knob of the stove only after the regulator is turned on

Question 7.
Correct the underlined part of the following sentences. if there is any error (2)
a. All measurements are taken from focus
b. Magnification of an image produced by a pline mirror is +1.
c. The image formed on the rear view mirror hence develops a feeling that the vehicle distance.
Answer:
a. Origin
b. True
c. The image formed on the rear view mirror is very small in size

Question 8.
Write the uses of the following devices
a. Multimeter
b. Insulation tape
Answer:
a. Multimeter – It is used to measure current, voltage and resis- 1 tance. It also helps to check weather various elements in an electronic circuit are functioning properly.

b. Insulation tape – when connecting the wires or connecting it with a device; this is used to provide insulation in those parts where it has been damaged.

Question 9.
Match the items correctly

Answer:
First graph – AC generator
Second graph – Battery
Third graph – DC generator

Question 10.
Explain how moving coil loudspeaker regenerate the original sound?
Answer:
The electrical pulses from the microphone are strengthened using an amplifier and sent through the voice coil of a loud speaker. The voice coil, which is placed in the magnetic field, moves to and fro rapidly in accordance with the electric pulses. These movements make the diaphragm vibrate. there by reproducing sound.

III. Answer any FOUR question from 11 to 15. Each question carries 3 score. (4 × 3 = 12)

Question 11.
Some statements related to LED bulbs are given below. Identify to LED relates each statement?
a) Part which emit light from the bulb
b) Board’ on which LED’s are fixed.
c) Metal plate that fixes it to the holder.
d) Part which gives DC output.
e) Part that connects bulbs to the holder.
f) Arrangement for absorbing heat from base.
Answer:
a. Diffuser cup
b. Printed circuit board / LED chip board.
c. Base plate
d. Power supply board.
e. Base unit
f. Heat sink

Question 12.
Total internal reflection occurs when a light incident from a medium of high optical density to a medium of low optical density at an angle of incidence greater than critical angle.
a) What do you mean by critical angle?
b) What is the critical angle of water?
c) Whether total internal reflection occur when light passes from glass to air at an angle of incidence of 28°? What is the reason?
Answer:
a. When a ray of light passes from a medium of greater optical density to that of lower optical density, the angle of incidence at which the angle of refraction becomes 90° is the critical angle.
b.48.6°
c. No, because the critical angle of glass is 42°.

Question 13.
Dispersion of light caused by the water droplets in the atmosphere causes rainbow.
a) In which time the rainbow is seen in the west? What is its shape?
b) Write the situation in which rainbow is seen as a circle?
c) What is the colour seen at the outer edge of the rainbow?
Answer:
a. In the morning, in arc shape
b. When viewed from aeroplane
c. Red

Question 14.
You may seen that elders used to read newspaper by holding it away from them.
a) By which defect of eye they do so?
b) What will be the reason behind this defect?
c) What is the remedy for this defect?
Answer:
a. Presbyopia
b. Due to the diminishing ability of ciliary muscles.
c. Using a convex lens of suitable power.

Question 15.
Energy crisis is the consequence of increase in demand and decrease in availability of energy. What can be done for reducing energy crisis? Write any three.
Answer:

• Maximum utilisation of solar energy.
• Minimising the wastage of water.
• Making use of public transportation as far as possible.

IV. Answer any FOUR questions from 16 to 20. Each question carries 4 score. (4 × 4 = 16)

Question 16.

Find the answer using the New Carlesian Sign Convention (4 × 1⁄2 = 2)
a) Distance to the object, u
b) Distance to the image v
c) Height of the object h
d) Height of the image h
e) Magnification, m
Answer:
a. u = -25 cm
b. v = +100 cm
C. h₀ = +1cm
d. h₁ = -4cm
e. Magnification, m = \(\frac{h_1}{h_0}\)
m = \(\frac { 4cm }{ +1 cm }\)
m = -4

Question 17.
An object is placed infront of a concave mirror at a distance of 8cm from the mirror of focal length 5cm.
a) Where will be the image formed?
b) Calculate the magnification of the image?
c) Draw the ray diagram of image formation.
Answer:
f = -5 cm, u = -8cm
a) \(\frac { l }{ f }\) = \(\frac { 1 }{ u }\) + \(\frac { 1 }{ v }\); \(\frac { 1 }{ v }\) = \(\frac { 1 }{ 6 }\) – \(\frac { 1 }{ 4 }\)
v = \(\frac { uf }{ u-f }\) = \(\frac{(-8) \times(-5)}{(-8) \cdot(-5)}\) = \(\frac{8 \times 5}{-3}\)
v = -13.33 cm

b) m = \(\frac { v }{ u }\) = \(\left(\frac{-13.33}{.8}\right)\) = 1.67

Question 18.

a) What are the situations when the bulb glows in this arrangement?
b) Whether the bulb glows if the switch is kept in on position? Why?
c) Can you suggest a method for glowing the bulb continuously?
d) Suggest any 2 methods to increase the voltage of the bulb.
Answer:
a. When switch turned ON and OFF.
b. No, because there is no variation in magnetic flux
c. Connect AC source replacing battery.
d. (i) Increase the number of turns in secondary.
(ii) Increase the voltage in primary.

Question 19.
Observe the following figure. Current is allowed to pass through the coil PQ.

a) How will be the flow of electrons through the coil?
b) Which is the direction of magnetic field in the coil?
(From outward to inward / from inward to outward).
c) Name the law that helps to find this
d) How will the strength of magnetic field produced here be increased?
Answer:
a. From Q to P
b. From outward to inward.
c. Right hand thumb rule – Imagine you are holding a current carrying conductor with the right hand in such a way that the thumb points in the direction of current. The direction in which the other fingers encircle the conductor gives the direction of the magnetic field.
d. (i) Increase the number of turns of the coil.
(ii) Increase the voltage of current.

Question 20.
Some informations related to two heaters are given below.
Heater A
V = 230 V, R = 1150 Ω
Heater B
V = 230 V, R = 460 Ω
a. Find the quantity of heat produced if they are made to work for 5 minute each?
b. Calculate the current through these devices.
C. How do the resistors bring about a change in the heat produced?
Answer:
Heater A
V = 230V, R = 1150, t = 5 minute
H = \(\frac { V2 }{ R }\) × t = \(\frac{230 \times 230}{1150}\) × 5 × 60 = 13800J

Heater B
V = 230V, R = 460, t = 5 minute
H = \(\frac { V2 }{ R }\) × t = \(\frac{230 \times 230}{460}\) × 5 × 60 = 34500J

b) Heater A
I = \(\frac { V }{ R }\) = \(\frac { 230 }{ 1150 }\) = 0.2A

Heater B
I = \(\frac { V }{ R }\) = \(\frac { 230 }{ 460 }\) = 0.5A

c) As resistance decreases intensity of electric current increases. Therefore according to the equation, H=12Rt the heat produced increases.