Class 5

For exam preparation, 5th Standard English Question Paper Kerala Syllabus Set 2 provide useful practice.

Kerala Syllabus 5th Standard English Model Question Paper Set 2

Instructions:

1. 15 minutes cool-off time is allotted for reading and understanding the activities.
2. Answer all the activities.
3. Internal choice is provided for activities 3 and 5. Answer either A or B.

Question 1.
Reading Comprehension – Read the poem and answer the following questions:

I guess you think you know this story.
You don’t. The real one’s much more gory.
The phoney one, the one you know,
Was cooked up years and years ago,
And made to sound all soft and sappy
just to keep the children happy.

Mind you, they got the first bit right,
The bit where, in the dead of night,
The Ugly Sisters, jewels and all,
Departed for the Palace Ball,
While darling little Cinderella
Was locked up in a slimy cellar,
Where rats who wanted things to eat,
Began to nibble at her feet.

Note:
phoney – not true, not genuine
sappy – over-sentimental
nibble – take small bites

a) What does the writer think about your knowledge of the story? The writer thinks:
i) You know the true story.
ii) You don’t know the true story.
iii) You don’t want to know the true story.
iv) All the people know the true story.
Answer:
ii) You don’t know the true story.

b) When the Ugly Sisters departed for the dance in the palace:
i) Cinderella was happy.
ii) Cinderella played with the rats in the cellar.
iii) Cinderella cooked in the kitchen.
iv) Cinderella was locked up in the cellar.
Answer:
iv) Cinderella was locked up in the cellar.

c) The phoney story you know was made up:
i) soon after the Ugly Sisters left for the dance.
ii) very many years ago.
iii) just before the Ugly Sisters left for the dance.
iv) by the people in the palace.
Answer:
ii) very many years ago.

d) Why the phoney story was cooked up?
i) To make the Ugly Sisters happy
ii) To make Cinderella happy.
iii) To keep the poet happy.
iv) To make the children happy.
Answer:
iv) To make the children happy.

Question 2.
Editing – Read and edit the following.
My school is very near my home. Even then by father a) take me to the school in (b) her car. My father works as a clerk (c) on a government office. His office is some five d) kilometre away e) by home.
Answer:
a) takes
b) his
c) in
d) kilometres
e) from

Question 3.
Thoughts – Attempt any one activity from the following:
(A) In “Salt inhis Shoes” we see Michael putting salt in his shoes to grow taller, but fie does not succeed. He felt unhappy. His Daddy asked him why he wanted to be taller. Michel said if he were taller he could help his team to win. Daddy then said that Michael was already a great player. He added that he had everything in him to make him a winner. Practice, determination and giving his best are more important than being a little taller. They are the qualities that make a person a winner.

Write down the thoughts of Michael.
When writing, think of the following:
• What was his mother’s advice?
• Why was he unhappy?
• What advice did his Daddy give him and what was the result?
Answer:
I want to be taller because I want my team to win in the basketball game. But Mark, who plays for the opposite team, is much taller than I and he makes fun of me saying that I am too short. I felt so sad. 1 asked my mother how to get taller. She said I should put salt in my shoes. I tried that for 2 months, but I haven’t grown even an inch. I felt so sad and I was gloomy. So my mother sent Daddy to me to talk to me. Daddy told me that it was not the height of a player that mattered in a game. He told me I was already a great player.

He added that I had everything in me to be a winner. Being taller might help me to play a little better. But it is practice, determination and giving my best that are more important than being a little taller. I know my father is right and I take his advice seriously. In the next game I will win and show Mark that it is not how tall you are but how determined you are that decides the winner in a game.

(B) In “The Honey Mango Tree” we see how the mango tree helped in uniting Rasheed and Asma as husband and wife. When giving the sliced ripe mangoes to Basheer, Rasheed recollects his first meeting with Asma.
Write down the thoughts of Rasheed.
When writing, think of the following:
• What made Rasheed go to Asma’s house?
• How did the withering sapling grow into big tree?
• What significance does the honey mango tree have in their life?
Answer:
It is this mango tree that caused Asma and me to get married. Therefore this mango tree is very special in my life. When I was a bachelor, I had come to this place to visit my young brother who was a police inspector. In the evening I went for a walk. I saw an old man lying under a tree. He was sick and old and groaning in pain. He wanted some water. I saw a young woman sitting outside her house across the road. I went to her and asked for some water and told her about the old man.

She came with me to see the old man. When I gave the pitcher of water for him to drink, he first went and poured half the water on a withered mango sapling. Then he drank the remaining water. He told us his name was Yusuf Sidhik and he was a fakir. He died soon and we buried him in the local graveyard. The girl told me her name was Asma. Asma continued to look after the sapling and it grew well and started producing mangoes. I married Asma and we got a son whom we named Yusuf Sidhik. This mango tree is really our honey mango tree.

Question 4.
Riddle –
ACROSS
2. A standard unit of length (5)
4. The opposite of “hot.” (4)

DOWN
1. A large plant with a trunk and leaves.
3. Very high in height.
5. Something you drink.

Answer:
ACROSS
2. METER
4. COLD
DOWN
1. TREE
3. TALL
5. WATER

Question 5.
Conversation – Attempt any. one activity from the following:
(A) The art class was finished. But Vashti remained sitting on her chair. Her paper was blank. The teacher looked at the blank paper and said that she was supposed to draw a polar bear in a storm. Vashti said she didn’t know how to draw. Her teacher smiled and told her to make a mark and see where it takes her. Vashti took her marker and made a dot on the paper.
Write the conversation between her teacher and Vashti. Write at least 4 exchanges.
Answer:
Teacher : Vashti, your paper is blank. Why are you not drawing the polar bear in the storm which I asked you to draw?
Vashti : Madam, I am not at all good at drawing. I do not know how to draw a polar bear in a storm.
Teacher : But you should have tried.
Vashti : I don’t even know how to begin that picture.
Teacher : Vashti: Not everyone is good at drawing. But you can try, can’t you?
Vashti : Madam, I am sorry. I don’t have the slightest idea of what to do.
Teacher : Alright. I am not forcing you to draw the polar bear in a storm. But you take your marker and make a mark on the paper. You can do that, can’t you? You make the mark and see where it takes you.
Vashti : I will do that, Madam.

OR
(B) One day Bill and his friend Meg visited his Granddad’s farm. Granddad asked them to peel the ears of com and help him sow the seeds. Then they were asked to feed the animals. After that they went with Granddad to collect hay for the cows. He told them he had a collection of bees and they should not disturb them. Write the conversation between Granddad and Bill. Write at least 4 exchanges.
Answer:
Granddad : Bill, welcome to my farm. Who is this girl with you?
Bill: Granddad, she is Meg, my close friend. We study in the same class.
Granddad : Good. First of all, let me show you round my farm. Maybe you can also help me.
Bill : Sure, Granddad. We will do whatever we can to help you.
Granddad : Okay. Let’s go and collect some hay for the cows. These cows give us a lot of milk and they are very precious to me. My major income is from the milk I sell.
Bill : The cows look very healthy. Okay, Granddad let’s go to collect the hay.
Granddad : Bill and Meg, be careful as you walk here and do things. I have a collection of bees. Make sure that you don’t disturb them. If you disturb them they will sting you and that can be very dangerous.
Bill : We will be careful not to disturb the bees.
Granddad : Okay, let’s go then!

Question 6.
Picture Story –  Events of a story are given below. Develop the events into a story.

a) Crow thirsty.
b) Finds ajar with water
c) Jar not full. Crow can’t get the water
d) Picks stones and drops in the jar
e) Water level rises.
f) Crow drinks water; happy.
Answer:

A Thirsty Crow

Once, a crow was feeling very thirsty. She was looking here and there to find some water. After a long search she found ajar with some water in it. The water level in the jar was very low and the beaks of the crow could not reach the water. She began to think. She saw some small stones lying near the jar. An idea came to her mind. She picked up the stones one by one and dropped them in the jar. As the stones fell into the jar, the water level started rising up. Finally the crow could drink the water and she went away happily.

The moral of the story: Where there’s a will, there’s a way.

For exam preparation, 5th Standard English Question Paper Kerala Syllabus Set 3 provide useful practice.

Kerala Syllabus 5th Standard English Model Question Paper Set 3

Instructions:

1. 15 minutes cool-off time is allotted for reading and understanding the activities.
2. Answer all the activities.
3. Internal choice is provided for activities 3 and 5. Answer either A or B.

Question 1.
Reading Comprehension – Read the poem and answer the following questions:

In a field one summer’s day,
A Grasshopper was hopping away.
He sang and danced with all his might,
For summer warmth was his delight.

But nearby, an Ant worked hard,
Gathering food, his yard to guard.
He stored away each grain with care,
Preparing for winter’s icy stare.

The Grasshopper mocked the Ant’s toil,
“Why work so hard on this fertile soil?
Come sing and dance, enjoy the sun,
There’s time enough when winter’s begun.”

a) What w as the grasshopper doing one summer’s day?
i) He was sitting on the branch of a tree and watching things.
ii) Fie was singing and dancing.
iii) He was fighti ng with the Ant.
iv) He was crying.
Answer:
ii) Fie was singing and dancing.

b) What was the Ant doing?
i) He was laughing at the grasshopper.
ii) He was working hard, storing away grains with great care.
iii) He was watching the singing and dancing of the grasshopper.
iv) He was busily eating food.
Answer:
ii) He was working hard, storing away grains with great care.

c) Why did the Grasshopper make fun of the Ant?
i) He thought the Ant was foolish in working so hard on such a delightful day.
ii) He thought the Ant is not intelligent.
iii) The ant was so small.
iv) The Ant did not join him in the singing and dancing.
Answer:
i) He thought the Ant was foolish in working so hard on such a delightful day.

d) What is the moral of the poem? Say it in a sentence of your own.
Answer:
The moral of the poem is we should prepare ourselves for tomorrow against possible adversities.

Question 2.
Editing – Read and edit the following
When I (a) am going to school, I saw (b) a elephant. It was huge and it was eating a big (c) banch of bananas. There (d) was many people standing (e) araund and watching it.
Answer:
a) was
b) an
c) bunch
d) were
e) around

Question 3.
Thoughts – Attempt any one activity from the following:
(A) In “The Giving Tree” we see how the Tree is making sacrifices to help the boy in the different stages of his life. The boy has now grown old and he is tired and we see him resting on the stump of the tree.

Write down the thoughts of the old man. In the writing, include the following:
• How did the boy enjoy the company of the tree when he was small boy?
• How did the tree help the young man to buy the things he needed?
• How did the tree help him to build a house and a boat, and become a stump?
Answer:
I am very grateful to this tree. She has been helping me throughout my life. When I was a small boy she gave me leaves to make crowns. She gave me her shade to sleep when I was tired after playing. She allowed me to swing on her branches. When I needed money, she gave me her fruits to sell and get money. She gave me her branches to build my house and then she gave me her trunk to make a boat. Now she is just a stump and even now I am sitting on it and resting. All her life she helped me and she even gave me her life. She has never demanded anything in return. It is such a great sacrifice she has made and I will never forget her.

OR
(B) In “The Little Engine That Could” we find that her wheels do not turn. The clown and the animals climbed out of their cars. They tried to push the Little rain. But she could not move.

What would be the thoughts of the Little Train then? Use the following hints.
• Was the Little Train happy that she did not have to work again?
• What were the things she was carrying?
• About whom did the Little Train think then and what was her reaction?
Answer:
Oh My God! My wheels are not moving. What will I do now? My compartments are full of good things for boys and girls. There are all kinds of animals – giraffes with long necks, teddy bears with no necks and even a baby elephant. There are all kinds of dolls – dolls with blues eyes and yellow hair; dolls with brown eyes and brown hair; and the funniest toy clown you ever saw. There are toy trucks, airplanes, and boats. There are pictures books, games and drums to play. I am also carrying good things to eat – big round oranges; fat, red apples; long, yellow bananas. There is fresh cold milk. There are lollypops to eat after dinner. How happy the boys and girls would be to see me. If I don’t reach the other side of the mountain, the boys and girls waiting there will have nothing to eat and nothing to play with. How sad they will be! Oh God, help me to find a way to move forward and take the things to the eagerly waiting boys and girls.

Question 4.
Riddle
Across
1. You write or draw on this. (5)
5. A piece of furniture where you sit and eat. (5)

Down
2. A comfortable seat in a living room. (4)
3. Name of the furniture in the dining room used for placing food (5)
4. We use this to write; it can be sharpened. (6 letters)

Answer:
Across
1. Paper
5. Chair

Down
2. SOFA
3. TABLE
4. PENCIL

Question 5.
Conversation – Attempt anyone of the following:
(A)

Write down the conversation between Chester and his mother. Write at least 4 exchanges.
Answer:
Chester : Mother, I don’t want to go to school. I can’t stay away from you. Why do you send me away from the comfort of my home?

Mother : My dear son, in the school you will be more happy. There you will have a lot of friends and toys to play with.

Chester : You are just bluffing me, mother. In the school they will ask me to sit in the class room and study arithmetic, reading and writing. If I don’t study they will beat me. My friend Sohan said that to me.

Mother : Son, you can’t always do the things you like. Going to school may look scary at first. But soon you will love it and you get new friends and play with them.

Chester : But, mother, I won’t be able to eat whenever I want. Sohan told me they have a fixed time for lunch. You can’t eat before or after that.

Mother : Son, you have to leam to be disciplined. As you grow you don’t eat whenever you like. You have to leam to control your desires.

Chester : Why should I control my desires? I want to be free to do the things I like, at the time I like.

Mother : Only small babies can do that. As we grow we have to leam to control ourselves. You have to leam many things and then only you can become a successful person. You are growing up.

(B) When Arya was 8, she wanted to be Kalpana Chawla. She made herself an orange space suit and wore it day and night. When her mother asked her if she does not feel hot in that suit, Arya told her that an astronaut had to get used to that suit.

Write down the conversation between Arya and her mother. Write at least 4 exchanges.
Answer:
Mother : Arya, what is wrong with you? Why are you wearing that orange space suit day and night?

Arya : Nothing wrong with me Mama. I told you I want to be an astronaut like Kalpana Chawla. Astronauts have to wear the space suit all the time.

Mother : Don’t you feel hot in that suit?

Arya : No,- Mama. I feel quite happy because I know one day I will be an astronaut.

Mother : Arya, you are only 8 years old now. First you have to be a grown-up girl and then only you can train and become an astronaut.

Arya : I am training for that Mama.

Mother : When you were 4 years old, you wanted to be Rosamma, the trapeze artist. You wanted to fly from swing to swing. And you were swinging all the time, saying you were practising to be a trapeze artist. Now you say you want to be an astronaut like Kalpana Chawla. I am sure after some years you will say you want to be something else.

Arya : I will not change my mind. I am sure I want to be an astronaut.

Mother : I am not so sure, from what I have seen so far!

Question 6.
Picture Story – Events of a story are given below. Develop the events into a story.
A Fox and a Crow with a Slice of Cheese

a) Crow with a piece of cheese sits on a branch.
b) Fox wants to have that cheese.
c) Praises crow saying it is a great singer; asks it to sing.
d) Crow opens its mouth to sing.
e) Cheese falls down.
f) Fox gets the Cheese.
Answer:

A Fox and a Crow with a Slice of Cheese

Once, a crow got a big slice of fine cheese. She flew with it holding it between her beaks. She then sat on the branch a tree. A fox was sitting under the tree. When he saw the cheese, he became greedy. He wanted to get it. He wanted to play a trick to get it. He told the crow: You are so beautiful and your singing is great. I love your singing. Can you please sing a song now? The crow was flattered. It opened its mouth to sing and the cheese fell down. The fox caught the cheese as it was falling down and ran away with it.

With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 2 Malayalam Medium help improve accuracy.

Kerala Syllabus Class 5 Maths Model Question Paper Set 2 Malayalam Medium

സമയം: 2 മണിക്കൂർ 15 മിനിറ്റ്

നിർദേശങ്ങൾ

• ആകെ സമയത്തിന്റെ ആദ്യത്തെ 15 മിനിറ്റ് സമാശ്വാസ സമയമാണ്. ഈ സമയം ചോദ്യങ്ങൾ വായിച്ചു മനസ്സിലാക്കാനും ഉത്തരങ്ങൾ ആസൂത്രണം ചെയ്യാനും ഉപയോഗിക്കുക.
• 6 ചോദ്യങ്ങൾക്ക് ഉത്തരം എഴുതണം. ചോദ്യങ്ങളിലെ ഉപചോദ്യങ്ങൾക്കെല്ലാം ഉത്തരം എഴുതണം
• 4, 6 എന്നിവയിൽ ഓരോന്നിലും 2 ചോദ്യങ്ങൾ വീതം ഉണ്ട്. അതിൽ ഒന്നു മാത്രം എഴുതിയാൽ മതി.

Question 1.
(a) \(\\frac{3}{6}\) നു തുല്യമായ ഒരു ഭിന്നസംഖ്യ എഴുതുക.
Answer:
\(\frac{3}{6}=\frac{1}{2}\)

(b) ഒരു വൃത്തം 10 ഭാഗങ്ങളായി വിഭജിച്ചിരിക്കുന്നു. അതിൽ 4 ഭാഗങ്ങൾ നിറം കൊടുത്തിട്ടുണ്ട്. വൃത്തത്തിന്റെ \(\frac{3}{5}\) ഭാഗം നിറം കൊടുക്കാൻ ഇനി എത്ര ഭാഗങ്ങൾ കൂടി നിറം കൊടുക്കണം?
Answer:
\(\frac{4}{10}=\frac{2}{5}\) ഭാഗം നിറം കൊടുത്തിട്ടുണ്ട്.

അധികം നിറം കൊടുക്കേണ്ട ഭാഗങ്ങൾ: \(\frac{3}{5}=\frac{6}{10}\)

(c) \(\frac{8}{12}\) എന്ന സംഖ്യയെ അതിന്റെ ലഘു രൂപത്തിൽ എഴുതുക.
Answer:
\(\frac{8}{12}=\frac{2}{3}\)

(d) \(\frac{9}{8}\) നെ മിശ്രഭിന്നത്തിൽ എഴുതുക.
Answer:
\(\frac{9}{8}\) = 1\(\frac{1}{8}\)

Question 2.
(a) 3 സെന്റിമീറ്റർ ആരമുള്ള ഒരു വൃത്തം വരച്ച് അതിൽ താഴെ കൊടുത്തിരിക്കുന്ന മാതൃക വരയ്ക്കുക.

Answer:

(b) 3 സെന്റിമീറ്ററും 1 സെന്റിമീറ്ററും ആരമുള്ള രണ്ടു വൃത്തങ്ങൾ താഴെ കൊടുത്തിരിക്കുന്നു. രണ്ട് വൃത്തങ്ങളുടെയും കേന്ദ്രങ്ങൾ യോജിപ്പിച്ച് വരയ്ക്കുന്ന വരയുടെ നീളം എന്താണ്?

(A) 2 സെന്റിമീറ്റർ
(B) 4 സെന്റിമീറ്റർ
(C) 6 സെന്റിമീറ്റർ
(D) 8 സെന്റിമീറ്റർ
Answer:
(B) 4 സെന്റിമീറ്റർ

Question 3.
(a) അമ്പതാമത്തെ ഒറ്റസംഖ്യ ഏതാണ് ?
Answer:
അമ്പതാമത്തെ ഒറ്റ സംഖ്യ കണ്ടെത്താൻ,
അമ്പതാമത്തെ ഇരട്ട സംഖ്യ കണ്ടെത്തി അതിൽനിന്നും ഒന്ന് കുറച്ചാൽ മതി.
അമ്പതാമത്തെ ഇരട്ട സംഖ്യ = (50 × 2) = 100
അമ്പതാമത്തെ ഒറ്റ സംഖ്യ = (100 – 1) = 99

(b) 1 മുതൽ ഈ സംഖ്യ വരെയുള്ള ഒറ്റസംഖ്യകളുടെ തുക എന്താണ് ?
Answer:
1 മുതൽ ഈ സംഖ്യ വരെയുള്ള ഒറ്റസംഖ്യ കളുടെ തുക = 50 × 50 = 2500

(c) ചുവടെയുള്ള ഓരോ ഗുണനത്തെയും ഒരു സംഖ്യയെ അതുകൊണ്ടുതന്നെ ഗുണിക്കുന്ന രീതിയിൽ മാറ്റിയെഴുതുക.
(i) 9 × 16
(ii) 16 × 36
(iii) 36 × 49
(iv) 49 × 64
(v) 81 × 25
Answer:
(i) 9 × 16 = (3 × 4) × (3 × 4) = 12 × 12
(ii) 16 × 36 = (4 × 6) × (4 × 6) = 24 × 24
(iii) 36 × 49 = (6 × 7) × (6 × 7) = 42 × 42
(iv) 49 × 64 = (7 × 8) × (7 × 8) = 56 × 56
(v) 81 × 25 = (9 × 5) × (9 × 5) = 45 × 45

നാലാമത്തെ ചോദ്യത്തിൽ രണ്ട് ചോദ്യങ്ങളുണ്ട് (4A യും B യും) ഇതിൽ ഒന്നിന് മാത്രം ഉത്തരം എഴുതിയാൽ മതി.

Question 4.
(a) സ്കൂൾ സ്റ്റോറിലേക്ക് 1825 നോട്ടുപുസ്തകങ്ങൾ വാങ്ങണം. 25 പുസ്തകം വീതമുള്ള എത്ര കെട്ടുകൾ വാങ്ങണം?
Answer:

(b) 2 കൊണ്ടു ഹരിക്കുമ്പോൾ ശിഷ്ടം വരുന്ന സംഖ്യകൾ ഏതൊക്കെയാണ്? 1 ശിഷ്ടം വരുന്ന സംഖ്യകളോ?
Answer:
2 = (2 × 1) + 0
4 = (2 × 2) + 0
6 = (2 × 3) + 0
8 = (2 × 4) + 0
ആയതിനാൽ, 2 കൊണ്ടു ഹരിക്കുമ്പോൾ ശിഷ്ടം വരുന്ന സംഖ്യകൾ = 2, 4, 6, 8, 10 ….
3 = (2 × 1) + 1
5 = (2 × 2) + 1
7 = (2 × 3) + 1
9= (2 × 4) + 1
ആയതിനാൽ, 2 കൊണ്ടു ഹരിക്കുമ്പോൾ 1 ശിഷ്ടം വരുന്ന സംഖ്യകൾ = 3, 5, 7, 9 …

(c) ഹരണത്തെക്കുറിച്ച് താഴെ പറയുന്ന പ്രസ്താവനകളിൽ ഏതാണ് ശരി?
(i) ഹരണമെന്നത് സംഖ്യയുടെ ആവർത്തിച്ചുകൂട്ടുന്ന പ്രക്രിയയാണ്
(ii) ഏതൊരു സംഖ്യയെയും (ഹാരണം × ഗുണിതം) + ശിഷ്ടം എന്ന് പ്രകടിപ്പിക്കാം.
(iii) ശിഷ്ടം എപ്പോഴും ഹരണത്തേക്കാൾ ചെറുതായിരിക്കും.
(iv) ശിഷ്ടം 0 ആണെങ്കിൽ, സംഖ്യ കൃത്യമായി ഹരിക്കാവുന്നതാണ്.
(A) ii, iii, iv ശരിയാണ്
(B) i, ii, iii ശരിയാണ്
(C) i, iii, iv ശരിയാണ്
(D) i, ii, iii, iv ശരിയാണ്
Answer:
(A) ii, iii, iv ശരിയാണ്

OR

B. ഇവയുടെ ദശാംശ രൂപങ്ങൾ എഴുതുക.
(a) 3 മീറ്റർ 45 സെന്റിമീറ്റർ
(b) 7 ലിറ്റർ 125 മില്ലിലിറ്റർ
(c) 5 കിലോഗ്രാം 275 ഗ്രാം
(d) 12 മില്ലിമീറ്റർ
(e) 1 മീറ്റർ 15 സെന്റിമീറ്റർ 6 മില്ലിമീറ്റർ നീളം
Answer:
(a). 3 മീ 45 സെമീ = 3.45
(b). 7 മീ 125 സെമീ = 7.125 മീ
(c). 5 കിലോഗ്രാം 275 ഗ്രാം = 5.275 കിലോഗ്രാം
(d). 12 മി.മി. = 1.2 സെമീ
(e). 1 × 15 സെമീ × 6 സെമീ = 1.156

Question 5.
(a) 20:50ന് പുറപ്പെടേണ്ടിയിരുന്ന ഒരു ട്രെയിൻ 35 മിനിറ്റ് വൈകി. അത് ഏത് സമയത്താണ് പുറപ്പെടുന്നത്? 24 മണിക്കൂർ രീതിയിലും AM/PM രീതിയിലും എഴുതുക.
Answer:
നിശ്ചിയിച്ച സമയം : 20 : 50 + 35 മിനിറ്റ്
= 21 : 25
AM/PM രീതിയിൽ : 9 : 25 PM.

(b) ഒരു ട്രെയിൻ യാത്ര 19:25ന് തുടങ്ങി, അടുത്ത ദിവസം 03:40ന് അവസാനിക്കുന്നു. യാത്രയുടെ ആകെ ദൈർഘ്യം കണ്ടുപിടിക്കൂ.
Answer:
ആകെ യാത്രാസമയം:
03:40 (അടുത്ത ദിവസം) – 19: 25
(പിറ്റെദിവസം) = 8 മണിക്കൂർ 15 മിനിറ്റ്

(c) ഒരാൾ 30 മിനിറ്റിൽ 3.5 കിലോമീറ്റർ സൈക്കിൾ ഓടിച്ചാൽ, അദ്ദേഹത്തിന്റെ വേഗം മണിക്കൂറിൽ എത കിലോമീറ്റർ?
Answer:
ദൂരം 3.5 km,
സമയം = 30 മിനിറ്റ് = 0.5 മണിക്കൂർ
വേഗം = \(\frac{3.5}{0.5}\) = 7 കിലോമീറ്റർ/മണിക്കൂർ

ആറാമത്തെ ചോദ്യത്തിൽ രണ്ട് ചോദ്യങ്ങളുണ്ട് (6A യും 6 B യും). ഇതിൽ ഒന്നിന് മാത്രം ഉത്തരം എഴുതിയാൽ മതി.

Question 6.
(A) ഒരു ഗ്രാമപഞ്ചായത്തിന്റെ വാർഷിക ബജറ്റിൽ ചില മേഖലകൾക്ക് അനുവദിച്ച തുക പട്ടികയിൽ നൽകിയിരിക്കുന്നു.

മേഖല	തുക
1 ആരോഗ്യം	5825000
2 കൃഷി	12045750
3 കുടിവെള്ളം	960428
4 റോഡ് വികസനം	10520310
5 വിദ്യാഭ്യാസം	3295246

(a) ഏത് മേഖലയ്ക്കാണ് ഏറ്റവും കുറഞ്ഞ തുക അനുവദിച്ചിരിക്കുന്നത്?
(b) ഒരു കോടിയിൽ കൂടുതൽ അനുവദിച്ചിരിക്കുന്ന മേഖലകൾ ഏതൊക്കെയാണ്?
(c) 50 ലക്ഷത്തിനും 60 ലക്ഷത്തിനും ഇടയിൽ തുക ലഭിച്ച മേഖല ഏതാണ്?
(d) പട്ടികയിൽ നിന്ന് 1 കോടി രൂപയിൽ കുറവ് വരുന്ന ഒരു തുക എഴുതുക.
(e) പട്ടികയിൽ കൊടുത്തിരിക്കുന്ന മുഴുവൻ മേഖലകൾക്കും വകയിരുത്തിയ മൊത്തം തുകയെക്കുറിച്ചുള്ള ശരിയായ പ്രസ്താവന ഏതാണെന്ന് കണ്ടെത്തുക:
(A) 1 കോടിക്കും 2 കോടിക്കും ഇടയിൽ
(B) 2 കോടിക്കും 3 കോടിക്കും ഇടയിൽ
(C) 3 കോടിക്കും 4 കോടിക്കും ഇടയിൽ
(D) 4 കോടിയിൽ കൂടുതലായി
Answer:
(a) കുടിവെളളം
(b) കൃഷി, റോഡ് വികസനം
(c) ആരോഗ്യം
(d) 5825000
(e) മൊത്തം തുക = 5825000 + 12045750 + 960428 + 10520310 + 3295246
(C) 3 കോടിക്കും 4 കോടിക്കും ഇടിയിൽ

OR

(a) 6, 7, 8, 9 എന്നീ അക്കങ്ങളെല്ലാം ഉപയോഗിച്ച് എത്ര നാലക്ക സംഖ്യകൾ നിർമ്മിക്കാൻ കഴിയും?
Answer:

24

(b) ഒന്നാം സ്ഥാനത്ത് 7 വരുന്ന എത്ര സംഖ്യകൾ ഉണ്ടാകും?
Answer:
6

(c) 6, 7, 8, 9 എന്നീ അക്കങ്ങളെല്ലാം ഉപയോഗിച്ച് നിർമ്മിക്കുന്ന സംഖ്യകളിൽ എത്ര ഒറ്റ സംഖ്യകൾ ഉണ്ടാകും?
Answer:
12

(d) 6, 7, 8, 0 എന്നീ അക്കങ്ങൾ ഉപയോഗിച്ച് എത്ര നാലക്ക സംഖ്യകൾ ഉണ്ടാക്കാം?
Answer:
18

(e) താഴെ കൊടുത്തിരിക്കുന്ന സൂചനകൾ പ്രകാരം സംഖ്യ കണ്ടെത്തുക:
അക്കങ്ങൾ 0, 4, 6, 8, 5 ഉപയോഗിച്ച് സംഖ്യ ഉണ്ടാക്കണം.
ആ സംഖ്യ 40000നും 50000നും ഇടയിലാണ്.
അത് ഒരു ഒറ്റ സംഖ്യയാണ്.
സംഖ്യയിലെ നൂറുന്റെ സ്ഥാനത്ത് ‘0’ വേണം.
മദ്ധ്യത്തിലുള്ള മൂന്ന് അക്കങ്ങൾ ചേർന്ന് ഉണ്ടാകുന്ന സംഖ്യ 600നും 700നും ഇടയിൽ ആയിരിക്കണം.
(A) 48065
(B) 86045
(C) 46058
(D) 46085
Answer:
(D) 46085

With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 1 Malayalam Medium help improve accuracy.

Kerala Syllabus Class 5 Maths Model Question Paper Set 1 Malayalam Medium

സമയം: 2 മണിക്കൂർ 15 മിനിറ്റ്

നിർദേശങ്ങൾ

• ആകെ സമയത്തിന്റെ ആദ്യത്തെ 15 മിനിറ്റ് സമാശ്വാസ സമയമാണ്. ഈ സമയം ചോദ്യങ്ങൾ വായിച്ചു മനസ്സിലാക്കാനും ഉത്തരങ്ങൾ ആസൂത്രണം ചെയ്യാനും ഉപയോഗിക്കുക.
• 6 ചോദ്യങ്ങൾക്ക് ഉത്തരം എഴുതണം. ചോദ്യങ്ങളിലെ ഉപചോദ്യങ്ങൾക്കെല്ലാം ഉത്തരം എഴുതണം
• 4, 6 എന്നിവയിൽ ഓരോന്നിലും 2 ചോദ്യങ്ങൾ വീതം ഉണ്ട്. അതിൽ ഒന്നു മാത്രം എഴുതിയാൽ മതി.

Question 1.
a) സിയാദും മീരയും അക്കങ്ങളുടെ കാർഡുകൾ ഉപയോഗിച്ച് നമ്പറുകൾ ഉണ്ടാക്കി. അവരുടെ കൈവശമുള്ള കാർഡുകൾ ഇവയാണ്:
407856
I. കാർഡുകൾ ഉപയോഗിച്ച് ഉണ്ടാക്കാവുന്ന ഏറ്റവും വലിയ നമ്പർ ഏത്?
Answer:
876540

II. ഏറ്റവും ചെറിയ നമ്പറോ ?
Answer:
405678

b) താഴെക്കൊടുത്തിട്ടുള്ള പട്ടികയിൽ സൂര്യനിൽ നിന്നുള്ള ഗ്രഹങ്ങളുടെ ദൂരങ്ങൾ നൽകിയിരിക്കുന്നു.

ഗ്രഹങ്ങൾ	ദൂരം (കി.മീ)
ബുധൻ	57909175
ശുക്രൻ	108200000
ഭൂമി	149600011
ചൊവ്വ	227940000
വ്യാഴം	778333000
ശനി	142940000
യുറാനസ്	149600011
നെപ്റ്റ്യൂൺ	2870990000

(i) സൂര്യനിൽ നിന്ന് ഭൂമിയിലേക്കുള്ള ദൂരം എത്രയാണ്?
Answer:
സൂര്യനിൽ നിന്ന് ഭൂമിയിലേക്കുള്ള ദൂരം 14,96,00,011 കി.മീ.

(ii) സൂര്യനിൽ നിന്ന് വ്യാഴത്തിലേക്കുള്ള ദൂരം എത്രയാണ്?
Answer:
സൂര്യനിൽ നിന്ന് വ്യാഴത്തിലേക്കുള്ള ദൂരം 77,83,33,000 കി.മീ.

(iii) സൂര്യനിൽ നിന്ന് ഏറ്റവും അകലെയുള്ള ഗ്രഹത്തിലേക്കുള്ള ദൂരം എത്രയാണ്?
Answer:
ഏറ്റവും അകലെയുള്ള ഗ്രഹം നെപ്റ്റ്യൂൺ ആണ് = 2,87,09,90,000 കി.മീ.

Question 2.
താഴെക്കൊടുത്തിട്ടുള്ള സംഖ്യകൾ ശ്രദ്ധിക്കുക. 38, 46, 62, 35, 36, 106
(a) ഈ സംഖ്യകളിൽ ഏതിനെ രണ്ടുകൊണ്ട് ഹരിക്കുമ്പോൾ ശിഷ്ടം വരും?
Answer:
35

(b) മുകളിലുള്ള രണ്ട് സംഖ്യകളുടെ തുകയെ 5 കൊണ്ട് ഹരിക്കുമ്പോൾ ശിഷ്ടം വരുന്നില്ല. ആ സംഖ്യകൾ ഏതെല്ലാമാണ്?
Answer:
38, 62
\(\frac{38+62}{5}=\frac{100}{5}\) = 20
ഹരിക്കുമ്പോൾ ശിഷ്ടം വരുന്നില്ല.

(c) ഈ സംഖ്യകളിൽ ഏതിനെ 5 കൊണ്ടോ 10 കൊണ്ടോ ഹരിക്കുമ്പോൾ 2 ശിഷ്ടം വരും?
Answer:
62

(d) ഈ സംഖ്യകളിൽ ഏതിനെ 4 കൊണ്ട് ഹരിക്കുമ്പോൾ ശിഷ്ടം വരുന്നില്ല?
Answer:
36

(e) താഴെക്കൊടുത്തിട്ടുള്ളവയിൽ ഏതാണ് 48 ÷ 4ന് തുല്യമായത്?
(i) (4 ÷ 4) + (8 ÷ 4)
(ii) (40 ÷ 4) + (4 ÷ 4)
(iii) (24 ÷ 8) + (24 ÷ 8)
(iv) (40 ÷ 4) + (8 ÷ 4)
Answer:
(iv) (40 ÷ 4) + (8 ÷ 4)

Question 3.
53427 എന്നത് അക്കങ്ങൾ ആവർത്തിക്കാതെ ഉണ്ടാക്കിയ ഒരു അഞ്ചക്ക സംഖ്യയാണ്.
(a) ഈ അക്കങ്ങൾ ഉപയോഗിച്ച് ഉണ്ടാക്കാൻ കഴിയുന്ന ഏറ്റവും ചെറിയ അഞ്ചക്ക സംഖ്യ ഏതാണ്?
Answer:
ഏറ്റവും ചെറിയ അഞ്ചക്ക സംഖ്യ = 23457

(b) ഈ അക്കങ്ങൾ ഉപയോഗിച്ച് ഉണ്ടാക്കുന്ന ഏറ്റവും വലി വലിയ അഞ്ചക്ക സംഖ്യയുടെ ഒറ്റയുടെ സ്ഥാനത്തെ അക്കം ഏതാണ്?
Answer:
ഏറ്റവും വലിയ അഞ്ചക്ക സംഖ്യ = 75432
ഒറ്റകളുടെ സ്ഥാനത്തെ അക്കം = 2

(c) ഈ അക്കങ്ങൾ ഉപയോഗിച്ച് ഉണ്ടാക്കാൻ കഴിയുന്ന ഏറ്റവും വലിയ അഞ്ചക്ക സംഖ്യയും ഏറ്റവും ചെറിയ അഞ്ചക്ക സംഖ്യയും തമ്മിലുള്ള വ്യത്യാസത്തെക്കുറിച്ച് ശരിയായ പ്രസ്താവന ഏതാണ്?
(i) 50000-ത്തിൽ കൂടുതൽ.
(ii) 50000-ത്തിൽ കുറവ്.
(iii) ഒറ്റയുടെ സ്ഥാനത്ത് 7 ആണ്.
(iv) 60000-ത്തിനും 70000-ത്തിനും ഇടയിലാണ്.
Answer:
ഏറ്റവും വലിയതും ഏറ്റവും ചെറിയതുമായ അഞ്ചക്ക സംഖ്യകൾ തമ്മിലുള്ള വ്യത്യാസം = 75432 – 23457 = 51975
ശരിയായ പ്രസ്താവന: (i) 50000ലധികം

(d) 5, 3, 4 എന്നീ അക്കങ്ങൾ ഉപയോഗിച്ച് ഒരു അഞ്ചക്ക പാലിൻഡ്രോമിക് സംഖ്യ എഴുതുക.
Answer:
5, 3, 4 ഉപയോഗിച്ച് ഉണ്ടാക്കാവുന്ന അഞ്ചക്ക പാലിൻഡ്രോം സംഖ്യ = 53435

(e) പൂജ്യം നൂറുകളുടെ സ്ഥാനത്ത് വരുന്ന, 0, 1, 2, 3 എന്നീ അക്കങ്ങൾ ഉപയോഗിച്ച് എത്ര നാലക്ക സംഖ്യകൾ ഉണ്ടാക്കാം?
Answer:
അക്കങ്ങൾ 0, 1, 2, 3 ഉപയോഗിച്ച് ഉണ്ടാ ക്കാവുന്ന നാലക്ക സംഖ്യകൾ.
ആയിരങ്ങളുടെ സ്ഥാനത്തേക്കുള്ള ചോയ് സുകൾ = 1, 2, 3 → 3 ചോയ്സുകൾ
ഇവിടെ 0 നൂറുകളുടെ സ്ഥാനത്താണ്.
പത്തിന്റെ സ്ഥാനം = ശേഷിക്കുന്ന 2 അക്കങ്ങൾ → 2 ചോയ്സുകൾ
ഒറ്റകളുടെ സ്ഥാനം = ശേഷിക്കുന്ന 1 അക്കം → 1 ചോയ്സ്
അതുകൊണ്ട്, നാലക്ക സംഖ്യകളുടെ എണ്ണം = 3 × 1 × 2 × 1 = 3

നാലാമത്തെ ചോദ്യത്തിൽ രണ്ട് ചോദ്യങ്ങളുണ്ട് (4 A യും 4 B യും) ഇതിൽ ഒന്നിന് മാത്രം ഉത്തരം എഴുതി യാൽ മതി.

Question 4.
A. താഴെ കൊടുത്തിരിക്കുന്ന സംഖ്യകൾ നോക്കൂ:
1632482, 1537821, 350421, 358212
(a) ഈ സംഖ്യകൾ വലുതിൽ നിന്നും ചെറുതിലേക്ക് ക്രമീകരിച്ചാൽ, അവസാനത്തേത് ഏതാണ്?
Answer:
അവസാന സംഖ്യ = 350421

(b) ഇവയിൽ രണ്ട് സംഖ്യകളുടെ മൊത്തം 1982903 ആണ്. ആ സംഖ്യകൾ ഏതാണ്?
Answer:
രണ്ട് സംഖ്യകളുടെ മൊത്തം = 1982903
1632482 + 350421 = 1982903
അതിനാൽ ആ രണ്ട് സംഖ്യകൾ
= 1632482, 350421

(c) ഏറ്റവും വലിയ സംഖ്യയും ഏറ്റവും ചെറിയ സംഖ്യയും തമ്മിലുള്ള വ്യത്യാസം എത്ര?
Answer:
ഏറ്റവും വലിയ സംഖ്യയും ഏറ്റവും ചെറിയ സംഖ്യയും തമ്മിലുള്ള വ്യത്യാസം 1632482 – 350421 = 1282061

(d) ഏറ്റവും വലിയ സംഖ്യയെക്കുറിച്ച് ചില പ്രസ്താവനകൾ താഴെ കൊടുത്തിരിക്കുന്നു.
(i) സംഖ്യ 1 ലക്ഷം കുറവാണ്.
(ii) സംഖ്യ 1 ലക്ഷം കൂടുതലാണ്.
(iii) സംഖ്യ 5 ലക്ഷത്തിനും 10 ലക്ഷത്തിനും ഇടയിലാണ്.
(iv) സംഖ്യ 10 ലക്ഷത്തിനും 20 ലക്ഷത്തിനും ഇടയിലാണ്.
ശരിയായ പ്രസ്താവന തിരഞ്ഞെടുക്കുക.
(A) (i) ഉം (iv) ശരിയാണ്
(C) (ii) ഉം (iii) ശരിയാണ്
(B) (ii) ഉം (iii) ശരിയാണ്
(D) (ii) ഉം (iv) ശരിയാണ്
Answer:
ശരിയായ പ്രസ്താവന = (D) (ii)ഉം (iv) ശരിയാണ്

OR

B. (a) ഒരു സംഖ്യയെ 4 കൊണ്ട് ഹരിക്കുമ്പോൾ കിട്ടാവുന്ന ശിഷ്ടങ്ങൾ എന്തൊക്കെയാണ്?
Answer:
ഒരു സംഖ്യയെ 4 കൊണ്ട് ഹരിക്കുമ്പോൾ കിട്ടാവുന്ന ശിഷ്ടങ്ങൾ: 0, 1, 2, 3.

(b) 3, 7, 11, … എന്നിവയെ 4 കൊണ്ട് ഹരിക്കുമ്പോൾ 3 ശിഷ്ടം വരുന്ന സംഖ്യകളാണ്. ഈ ശ്രേണിയിലെ അടുത്ത നാല് സംഖ്യകൾ എഴുതുക.
Answer:
ശ്രേണി 3, 7, 11, … അടുത്ത നാല് സംഖ്യകൾ
= 15, 19, 23, 27.

(c) നിങ്ങൾ ഇങ്ങനെ എഴുതിക്കൊണ്ടിരുന്നാൽ, 100 ഈ ശ്രേണിയിൽ ഉണ്ടാകുമോ?
Answer:
ഇല്ല. കാരണം,, ശിഷ്ടം ) ആണ്. എന്നാൽ, ഈ ശ്രേണിയിലെ സംഖ്യകളെ 4 കൊണ്ട് ഹരിക്കുമ്പോൾ ശിഷ്ടം 3 ആണ്.

(d) 169-നെ 8 ന്റെ ഒരു നിശ്ചിത തവണയും ഒരു ശിഷ്ടവും ആക്കി എഴുതുക.
Answer:
169 -നെ 8 കൊണ്ട് ഹരിച്ചാൽ
169 = 8 × 21 + 1

Question 5.
a) ഓരോ സംഖ്യയും 8-ന്റെ ഒരു ഗുണിതവും ഒരു ശിഷ്ടവും ആയി എഴുതുക.
(a) 9
(b) 98
(c) 987
Answer:
(a) 9 = (8 × 1) + 1
(b) 98 = (8 × 12) + 2
(c) 987 = (8 × 123) + 3

b) (i) 9876 എന്ന സംഖ്യയെ ഈ രീതിയിൽ എങ്ങനെ എഴുതാൻ കഴിയുമെന്ന് നിങ്ങൾക്ക് ഊഹിക്കാൻ കഴിയുമോ? നിങ്ങളുടെ ഊഹം യഥാർത്ഥത്തിൽ ഹിച്ച് ശരിയാണോ എന്ന് പരിശോധിക്കുക.
Answer:

(ii) ഈ സംഖ്യാ പാറ്റേൺ എഴുതുക.
Answer:
(8 × 1) + 1 = 9
(8 × 12) + 2 = 98
(8 × 123) + 3 = 987
(8 × 1234) + 4 = 9876
(8 × 12345) + 5 = 98765

ആറാമത്തെ ചോദ്യത്തിൽ രണ്ട് ചോദ്യങ്ങളുണ്ട് (6 A യും 6 B യും) ഇതിൽ ഒന്നിന് മാത്രം ഉത്തരം എഴുതി യാൽ മതി.

Question 6.
A. താഴെ കാണുന്ന ഗ്രാഫ് ഒരു സ്കൂളിലെ 1 മുതൽ 7 വരെയുള്ള ക്ലാസ്സുകളിലെ പെൺകുട്ടികളു ടെയും ആൺകുട്ടികളുടെയും എണ്ണം കാണി ക്കുന്നു..

(i) ഏത് ക്ലാസ്സിലാണ് പെൺകുട്ടികളേക്കാൾ കൂടു തൽ ആൺകുട്ടികൾ ഉള്ളത്? എണ്ണത്തിലുള്ള വ്യത്യാസം എത്രയാണ്?
Answer:
മൂന്നാം ക്ലാസ്സ്, വ്യത്യാസം = 75 – 70 = 5

(ii) ഏത് ക്ലാസ്സിലാണ് പെൺകുട്ടികളുടെയും ആൺ കുട്ടികളുടെയും എണ്ണം തമ്മിലുള്ള വ്യത്യാസം ഏറ്റവും കൂടുതൽ ഏത് ക്ലാസ്സിലാണ് ഇത് ഏറ്റവും കുറവ്?
Answer:
പെൺകുട്ടികളുടെയും ആൺകുട്ടികളുടെയും എണ്ണത്തിൽ ഏറ്റവും കൂടുതൽ വ്യത്യാസ മുള്ളത് ഒന്നാം ക്ലാസ്സിലാണ്. ഏറ്റവും കുറഞ്ഞ വ്യത്യാസമുള്ളത് ക്ലാസ് 2, 3, 6 എന്നിവയി ലാണ്. 9)

(iii) ഈ ക്ലാസ്സുകളിലെല്ലാം കൂടി ആകെ എത്ര പെൺകുട്ടികളുണ്ട്?
Answer:
ഈ ക്ലാസ്സുകളിലെല്ലാം കൂടി ആകെ പെൺ കുട്ടികളുടെ എണ്ണം = 580

(iv) ആകെ എത്ര വിദ്യാർത്ഥികളുണ്ട്?
Answer:
ആകെ വിദ്യാർത്ഥികളുടെ എണ്ണം = 1100

OR

B. താഴെ നൽകിയിട്ടുള്ള ഓരോ രൂപത്തിന്റെയും ചുറ്റളവും പരപ്പളവും (വിസ്തീർണ്ണം) കണ്ട ത്തുക:

Answer:

ഓരോ വശവും 2 സെന്റീമീറ്ററാണ്. അതിനാൽ ചുറ്റളവ് = 2 × 12 = 24 സെന്റീമീറ്റർ
ഒന്നാമത്തെ ഭാഗത്തിന്റെ വിസ്തീർണ്ണം = 2 × 2 = 4 ചതുരശ്ര സെന്റീമീറ്റർ
രണ്ടാം ഭാഗത്തിന്റെ വിസ്തീർണ്ണം = 2 × 6 = 12 ചതുരശ്ര സെന്റിമീറ്റർ
മൂന്നാം ഭാഗത്തിന്റെ വിസ്തീർണ്ണം = 2 × 2 = ചതുരശ്ര സെന്റിമീറ്റർ
ആകെ വിസ്തീർണ്ണം = 4 + 12 + 4 = 20 ചതുരശ്ര സെന്റിമീറ്റർ

With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 1 help improve accuracy.

Kerala Syllabus 5th Standard Maths Question Paper Set 1

Time : 2 Hrs 15 Min

Instructions:

• First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
• Answer all six questions. Answer all the sub questions.
• Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).

Question 1.
(a) Ziad and Meera are making numbers with digit cards. These are the cards they have:
407856
(i) What is the largest number they can make with these cards?
Answer:
876540

(ii) And the smallest?
Answer:
405678

(b) The table gives the distances of the planets from the sun.

Planets	Distance (km)
Mercury	57909175
Venus	108200000
Earth	149600011
Mars	227940000
Jupiter	778333000
Saturn	142940000
Uranus	149600011
Neptune	2870990000

(i) What is the distance of the earth from the sun?
(ii) What is the distance of Jupiter from the sun?
(iii) What is the distance from the sun to its farthest planet?
Answer:
(i) Distance of the Earth from the Sun = 149,600,011 km
(ii) Distance of Jupiter from the Sun = 778,333,000 km
(iii) Farthest planet is Neptune = 287,099,000 km

Question 2.
Look at the numbers given below.
38, 46, 62, 35, 36, 106
(a) Which of these numbers leaves a remainder when divided by 2 ?
Answer:
35

(b) The sum of two of the above numbers does not leave remainder when divided by 5. Which are those numbers?
Answer:
38, 62 are the two numbers 38 + 62 100

(c) Which of the above numbers leaves a remainder of 2 when divided by 5 or 10 ?
Answer:
62

(d) Which of the above number does not leave a remainder when divided by 4 ?
Answer:
36

(e) Which of the following is equal to 48 + 4?
(i) (4 ÷ 4) + (8 ÷ 4)
(ii) (40 ÷ 4) + (4 ÷ 4)
(iii) (24 ÷ 8) + (24 ÷ 8)
(iv) (40 ÷ 4)+ (8 ÷ 4)
Answer:
(iv) (40 ÷ 4)+ (8 ÷ 4)

Question 3.
‘53427 ‘ is a five digit number made without repeating its digits.
(a) Which is the smallest five digit number that can be made using all the above digits?
Answer:
Smallest five digit number = 23457

(b) What is the digit in the ones place of the largest five digit number made using these digits?
Answer:
Largest five digit number = 75432
Digit in ones place = 2

(c) Which is the correct statement about the difference between the largest and the smallest five digit number that can be made using all these digits?
(i) More than 50000.
(ii) Less than 50000.
(iii) 7 is in the ones place.
(iv) Between 60000 and 70000.
Answer:
Difference between the largest and smallest five digit number ‘
= 75432 – 23457 = 51975

The correct statement is:
(i) More than 50000.

(d) Write a five digit palindromic number using the digits 5, 3 and 4
Answer:
Five digit palindromic number = 53435

(e) How many four digit numbers can be made using the digits 0, 1, 2 and 3 with 0 in the hundreds place?
Answer:
Digits are 0, 1, 2 and 3.
Choices for thousand place is = 1,2,3 = 3 choices
Here 0 is in the hundreds place.
Tens place = remaining 2 digits = 2 choices
Ones place = remaining 1 digit = 1 choice
The number of four digit numbers = 3 × 1 × 2 × 1 = 6

Question 4 has two questions (4 A and 4 B). Answer any one.

Question 4.
A See the numbers given below.
1632482, 1537821, 350421, 358212
(a) If these numbers are written from largest to smallest, what will be the last number?
Answer:
Last number = 350421

(b) The sum of two of these numbers is 1982903. Which are those numbers?
Answer:
Sum of two numbers =1982903 1632482 + 350421 = 1982903
The two numbers are 1632482, 350421

(c) What is the difference between the largest number and the smallest number?
Answer:
Difference between the largest and smallest number is
1632482 – 350421 = 1282061

(d) Some statements regarding the largest number is given below.
(i) The number is less than 1 million.
(ii) The number is greater than 1 million.
(iii) The number is between 5 lakh and 10 lakh.
(iv) The number is between 10 lakh and 20 lakh.
Choose the correct statement:
(A) (i) and (iv) are true
(B) (ii) and (iii) are true
(C) (i) and (iii) are true
(D) (ii) and (iv) are true
Answer:
Correct statement = (D) (ii) and (iv) are true

OR

B. (a) What are the possible remainders on dividing a number by 4 ?
Answer:
Possible remainders when dividing by 4 is: 0, 1, 2, 3.

(b) 3, 7, 11,… are the numbers that leave the remainder 3 when divided by 4 . Write the next four numbers in this pattern.
Answer:
Pattern: 3, 7, 11,…
Next four numbers = 15, 19, 23, 27.

(c) If you continue writing like this, will 100 be in this pattern, Why?
Answer:
No.
Because 100 = 4 = 25, remainder is 0.
In this pattern the remainder is 3.

(d) Write 169 as certain times 8 and a remainder.
Answer:
169 as certain times 8 and a remainder.
169 = 8 × 21 + 1

Question 5.
Write each of the numbers as certain times 8 and a remainder
(a) 9
(b) 98
(c) 987
Answer:
The number can be written in certain times of 8 and a reminder as:
(a) 9 = (8 × 1) + 1
(b) 98 = (8 × 12) + 2
(c) 987 = (8 × 123) + 3

(i) Can you guess how 9876 is written like this? Check your guess by actual division.
Answer:

That is, 9876 divided by 8 gives quotient 1234, remainder 4. Thus, we can write 9876 as:
9876 = (8 × 1234) + 4

(ii) Write out this number pattern.
Answer:
(8 × 1) + 1 = 9
(8 × 12) + 2 = 98
(8 × 123) + 3 = 987
(8 × 1234) + 4 = 9876
(8 × 12345) + 5 = 98765

Question 6 has two questions (6 A and 6 B). Answer any one.

Question 6.
A. The graph below shows the number of girls and boys in classes 1 – 7 in a school:

(i) Which class has more boys than girls? What is the difference?
(ii) In which class is the difference between the number of girls and boys the most? In which class is this the least?
(iii) How many girls are there in all these classes together?
(iv) What is the total number of students?
Answer:
(i) Class 3, Difference = 75 – 70 = 5

(ii) Difference between the number of girls and boys the most = Class 1
Difference between the number of girls and boys the least Class 2, 3 and 6

(iii) Total number of girls in all these classes
= 65 + 65 + 70 + 70 + 100 + 115 + 95 = 580
Total number of students = 1100

OR

B. Compute the perimeter and area of each of the shapes below.

Answer:

Each side is 2 cm. So the perimeter will be = 2 × 12 = 24 centimeter
Area of Ist part = 2 × 2 = 4 square centimeter
Area of IInd part = 2 × 6=12 square centimeter
Area of IIIrd part = 2 × 2=4 square centimeter
Total Area = 4+ 12 + 4 = 20 square centimeter

With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 2 help improve accuracy.

Kerala Syllabus 5th Standard Maths Question Paper Set 2

Time : 2 Hrs 15 Min

Instructions:

• First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
• Answer all six questions. Answer all the sub questions.
• Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).

Question 1.
The bar graph below represents the books read by students of class 5.

Answer the following questions.
a) The students of which class reads less books?
Answer:
5B

b) Total how many books read by 5th standard students altogether.
Answer:
5A= 10
5B = 5
5C = 20
5D = 30
Total = 65

c) Which divisions students together read 50 books.
Answer:
5C = 20
5D = 30
Total = 50

Question 2.
The prices of cars bought by Ramu, Raju, Gopu and Saju are given below: Ramu- Rs. 449180 Raju- Rs. 448991 Gopu-Rs. 440894 Saju-Rs. 448911
a) Who bought the car with the highest price? How much?
Answer:
Ramu = 449180

b) Write the highest price in words
Answer:
Four lakh forty-nine thousand one hundred and eighty.

c) Who bought the car with the lowest price? How much?
Answer:
Gopu- Rs. 44089

Question 3.
A rectangle plot of length 23 metres and width 14 metres is selected to cultivate Pea, Potato and Tomato as given below.

a) Pea is cultivated in a square plot with sides 14 metres. Find its area.
Answer:
Area where Pea cultivated
= 14 × 14= 196 square metre

b) Find the length of the Potato cultivated plot in metres? If its area is 72 square metres, find its width.
Answer:
Area 72 square metres is given
Length = 2314 = 9 metre
Width = 8 metre

c) Find the area where the Tomato is cultivated?
Answer:
Length = 9 metre
Width = 148 = 6 metre
Area = 9 × 6 = 54 square metre

Question 4 has two questions (4 A and 4 B). Answer anyone.

Question 4.
A. a) 3 litres is equal to
I. 1000 millilitres
II. 2000 millilitres
III. 3000 millilitres
IV. 6000 millilitres
Answer:
III. 3000 millilitres

b) Fill in the blanks:
I. 200 grams = ______ Kilogram
II. 0.850 kilograms = ______ Grams
Answer:
I. 0.2 Kilograms
II. 850 Grams

B. a) How do we write 3.275 kilograms in fractional form?
Answer:
3.275 kilograms = 3\(\frac{275}{100}\) kilograms

b) How do we write this in kilograms and grams?
Answer:
3 kilograms and 275 grams

c) How do we write this in grams alone?
Answer:
1 kilogram = 1000 grams
So, 3 kilograms = 3000 grams
3.275 kilograms = 3275 grams.

Question 5.
Sidharth has a cake. He cuts it into 10 equal parts. He gave 2 parts to Naman, 3 parts to Nidhi, 1 part to Seema and the remaining four parts he kept for himself. Find:
i) What fraction of the cake did he give to Naman?
ii) What fraction of the cake did he give to Nidhi?
iii) What fraction of the cake, he give to Seema?
Answer:
Number of cakes = 1
Number of parts = 10
Each part is \(\frac{1}{10}\)

i) Sidharth gave 2 parts to Naman.
Fraction of cake with Naman
= 2 × \(\frac{1}{10}\) = \(\frac{2}{10}\)

ii) Sidharth gave 3 parts to Nidhi.
Fraction of cake with Nidhi
= 3 × \(\frac{1}{10}\) = \(\frac{3}{10}\)

iii) Sidharth gave 1 part to Seema.
Fraction of cake with Seema = \(\frac{1}{10}\)

Question 6 has two questions (6A and 6B). Answer any one.

Question 6.
A. Look at the following calculations:
1 + 3 = 4
4 + 5 = 9
9 + 7 = 16.
Continue this to compute the squares up to 100.
Answer:
16 + 9 = 25
25 + 11 = 36
36 + 13 = 49
49 + 15 = 64
64 + 17 = 81
81 + 19 = 100

OR

B. A number multiplied by 24 gave 1560.
(i) What will be the product if the next number is multiplied by 24?
(ii) What will be the product if the number just before this is multiplied by 24?
Answer:
(i) If we look at the number just after our original number, we can find the new product by simply adding 24 to 1560:
1560 + 24 = 1584.
So, when the next number is multiplied by 24, we get 1584

(ii) Now, let’s, look at the number just before our original number. To find this new product, we subtract 24 from 1560:
1560 – 24 = 1536.
So, when the previous number is multiplied by 24, we get 1536

With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 3 help improve accuracy.

Kerala Syllabus 5th Standard Maths Question Paper Set 3

Time : 2 Hrs 15 Min

Instructions:

• First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
• Answer all six questions. Answer all the sub questions.
• Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).

Question 1.
(a) Write \(\\frac{3}{6}\) as an equivalent fraction.
Answer:
\(\frac{3}{6}=\frac{1}{2}\)

(b) If a circle is divided into 10 parts and 4 are shaded, how many more parts need to be shaded to make it \(\frac{3}{5}\) of the circle?
Answer:
\(\frac{4}{10}=\frac{2}{5}\) parts are already shaded.

Additional parts to be shaded: \(\frac{1}{2}\)

(c) Simplify \(\frac{8}{12}\) to its lowest terms.
Answer:
\(\frac{8}{12}=\frac{2}{3}\)

(d) Write \(\frac{9}{8}\) as a mixed number.
Answer:
\(\frac{9}{8}\) = 1\(\frac{1}{8}\)

Question 2.
(a) Draw a circle of radius 3 centimetres and draw the pattern given below on it.

Answer:

(b) Given below are circles of radius 3 centimetres and 1 centimetre. What is the length of the line drawn by joining the centres of the two circles?
(A) 2 centimetres
(B) 4 centimetres
(C) 6 centimetres
(D) 8 centimetres

Answer:
(B) 4 centimetres

Question 3.
(a) Which is the fiftieth odd number?
Answer:
The fiftieth odd number can be found by multiplying 50 by 2 and then subtracting 1, SO”1 odd number
= (50 × 2) – 1 = 100 – 1 = 99

(b) What is the sum of the odd numbers from 1 to this number?
Answer:
The sum of odd numbers from 1 to 99
= 50 × 50 = 2500

(c) Rewrite each of the products below as the product of a number by itself:
(i) 9 × 16
(ii) 16 × 36
(iii) 36 × 49
(iv) 49 × 64
(v) 81 × 25
Answer:
(i) 9 × 16 = (3 × 4)(3 × 4)
(ii) 16 × 36 = (4 × 6)(4 × 6)
(iii) 36 × 49 = (6 × 7)(6 × 7)
(iv) 49 × 64 = (7 × 8)(7 × 8)
(v) 81 × 25 = (9 × 5)(9 × 5)

Question 4 has two questions (4 A and 4 B). Answer any one.

Question 4.
A. (a) The school store needs 1825 notebooks. How many packs of 25 notebooks are to be bought?
Answer:

(b) What are the numbers which leave remainder 0 on division by 2 ? And those that leave remainder 1 ?
Answer:
2 = (2 × 1) + 0
4 = (2 × 2) + 0
6 = (2 × 3) + 0
8 = (2 × 4) + 0
Thus, the numbers are 2, 4, 6, 8,10 ….
That is, the multiple of 2 which leave remainder 0 on division by 2.
3 = (2 × 1)+ 1
5 = (2 × 2) + 1
7 = (2 × 3) + 1
9 = (2 × 4) + 1
Thus, the numbers are 3, 5, 7, 9………….

(c) Which of the following statements are true about division?
i. Division is the process of repeated addition.
ii. Any number can be expressed as (Divisor × Quotient) + Remainder.
iii. The remainder is always smaller than the divisor.
iv. If the remainder is 0, the number is exactly divisible.
(a) ii, iii, iv are correct
(b) i, ii, iii are correct
(c) i, iii, iv are correct
(d) i, ii, iii, iv are correct
Answer:
(c) i, iii, iv are correct

OR

B. Write the decimal forms of:
(a) 3 meters and 45 centimeters.
(b) 7 liters and 125 milliliters.
(c) 5 kilograms and 275 grams.
(d) 12 millimeters.
(e) A length of 1 meter 15 centimeters and 6 millimeters.
Answer:
(a) 3 m 45 cm = 3.45 m
(b) 7L 125 mL = 7.125 L
(c) 5 kg 275 g = 5.275 kg
(d) 12 mm = 1.2 cm
(e) 1 m 15 cm 6 mm = 1.156m

Question 5.
(a) A train scheduled to leave at 20:50 is delayed by 35 minutes. At what time does it leave? Write the answer in both 24-hour and AM/PM formats.
Answer:
Scheduled time: 20 : 50 + 35 minutes = 21 : 25
AM/PM format: 9 : 25 PM.

(b) If a train journey starts at 19:25 and ends at 03:40 the next day, calculate the total duration of the journey.
Answer:
Total journey time:
03:40 (next day) – 19: 25 (previous day) = 8 hours and 15 minutes.

(c) If a person cycles 3.5 kilometers in 30 minutes, what is their speed in kilometers per hour?
Answer:
Speed: Distance = 3.5 km, Time = 0.5 hours.
Speed = \(\frac{3.5}{0.5}\) = 7 km/h.

Question 6 has two questions (6 A and 6 B). Answer any one.

Question 6.
A. The amount allotted to certain sectors in the Annual budget of a Grama Panchayat is given in the table.

Sector	Amount
Health	5825000
Agriculture	12045750
Drinking water	960428
Road Development	10520310
Education	3295246

(a) For which sector is the least amount allotted?
(b) Which are the sectors for which more than one crore is allotted?
(c) For which sector an amount between 50 lakhs and 60 lakhs is allotted?
(d) Write an amount less than 10 million from the table?
(e) Which of the following is the correct statement regarding the total amount allotted for all the areas given in the table?
Total allotted amount:
(A) Between one crore and two crore.
(B) Between two crore and three crore.
(C) Between three crore and four crore.
Answer:
(a) Drinking water
(b) Agriculture, Road development
(c) Health
(d) 5825000
(e) Total amount = 5825000 + 12045750 + 960428 + 10520310 + 3295246 = 32646734
Option (C) Between three crore and four crore

OR

B (a) How many four digit numbers can be formed using all the digits 6, 7, 8 and 9 ?
(b) How many numbers will be there with 7 in the one’s place?
(c) Among the numbers formed using all the digits 6, 7, 8 and 9 how many odd numbers are there?
(d) How many four digits numbers can be formed using all the digits and 0 ?

(e) Find the number according to the hints given below.

• Digits and 5 are used to form the number.
• The number is between 40000 and 50000.
• It is an odd number.
• The digit in the hundredth place of the number is ‘O’.
• The number formed by three middle digits, is between 600 and 700

(A) 48065
(B) 86045
(C) 46058
(D) 46085
Answer:

(a) 24
(b) 6
(c) 12
(d) 18
(e) (D) 46085

With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 4 help improve accuracy.

Kerala Syllabus 5th Standard Maths Question Paper Set 4

Time : 2 Hrs 15 Min

Instructions:

• First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
• Answer all six questions. Answer all the sub questions.
• Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).

Question 1.
(a) What are the possible remainders on dividing a number by 4? Write the pattern of numbers leaving the same remainder for each of these.
Answer:
4 = (4 × 1) + 0
5 = (4 × 1)+ 1
6 = (4 × 1) + 2
7 = (4 × 1) + 3
8 = (4 × 2) + 0
9 = (4 × 2) + 1
10 = (4 × 2) + 2
11 = (4 × 2) + 3

(b) Which of the following numbers will leave remainder 0 when divided by 4 ?
(i) 7, 11, 15
(ii) 8, 12, 20
(iii) 5, 9, 13
(iv) 10, 14, 18
Answer:
(ii) 8, 12, 20

Question 2.
(a) Answer the following based on fractions:
Answer:
A rectangle with \(\frac{2}{6}\) shaded.

(b) Draw a rectangle divided into six equal parts and shade \(\frac{2}{6}\).
Answer:
\(\frac{4}{8}=\frac{2}{4}=\frac{1}{2}\)

(c) Write two fractions equivalent to \(\frac{4}{8}\).
Answer:
\(\frac{12}{16}=\frac{3}{4}\)

(d) Simplify \(\frac{12}{16}\).
Answer:
1\(\frac{2}{3}=\frac{5}{3}\)

(e) Write 1\(\frac{2}{3}\) as an improper fraction.
Answer:
A circle with \(\frac{6}{8}\) shaded.

(f) Divide a circle into eight parts and shade three-fourths of it.
Answer:
Three-fourth = \(\frac{3 \times 2}{4 \times 2}=\frac{6}{8}\)

Question 3.
Draw the following pictures:

Answer:
Draw two circles. Extend the line to the right till it meets the circle on the right. With this point as centre, draw another circle of the same radius.

Join all four points where the circle in the middle is cut by the other two.

With one of the six points on the middle circle as centre and without changing the radius used till now, draw a piece of a circle within the middle circle, as given below:

Take three more points as centres and draw pieces of circle.

Erase the parts outside the middle circle, we get the required figure.

Question 4 has two questions (4 A and 4 B). Answer any one.

Question 4.
A (a). Convert the following improper fractions to mixed numbers:
(i) \(\frac{13}{4}\)
(ii) \(\frac{17}{5}\)
Answer:
(i) \(\frac{13}{2}\) = 3\(\frac{1}{4}\)
(ii) \(\frac{17}{5}\) = 3\(\frac{2}{5}\)

(b) Write these mixed numbers as improper fractions:
(i) Three and one-third.
(ii) Five and two-fifths.
Answer:
(i) Three and one-third = \(\frac{1}{2}\)
(ii) Five and two-fifths = \(\frac{1}{2}\)

(c) If a ribbon 2 meters long is cut into 7 equal pieces, what is the length of one piece? Write your answer as a fraction.
Answer:
2m divided into 7 parts = \(\frac{2}{7}\) m Per piece

(d) Which of the following statements are correct?
(i) \(\frac{4}{8}\) and \(\frac{1}{2}\) are equivalent fractions.
(ii) Simplifying \(\frac{12}{16}\) gives \(\frac{3}{4}\).
(iii) The mixed fraction 1\(\frac{2}{3}\) is equal to \(\frac{7}{3}\).
(iv) Shading 2 out of 6 equal parts of a rectangle represents \(\frac{1}{2}\).
(a) i, ii, iii are correct
(b) ii, iii, iv are correct
(c) i, iii, iv are correct
(d) i, ii, iv are correct
Answer:
(a) i, ii, iii are correct

OR

B. Solve the following:
(a) A chocolate bar is divided into 12 equal parts. If 9 parts are eaten, what fraction is left?
Answer:
Fraction left = 1 – \(\frac{9}{12}=\frac{3}{12}=\frac{1}{4}\)

(b) Convert \(\frac{15}{8}\) into a mixed number.
Answer:
\(\frac{15}{8}\) = 1\(\frac{7}{8}\)

(c) Divide 2 liters of water equally into 5 bottles. How much water is in each bottle?
Answer:
2 ÷ 5 = 0.4 liters per bottle

(d) A cake is cut into 16 equal slices, and 10 are eaten. Write the fraction eaten and simplify it.
Answer:
Fraction eaten = \(\frac{10}{6}=\frac{5}{8}\)

(e) (i) \(\frac{2}{4}, \frac{3}{6}\) and \(\frac{4}{8}\) all represent the same value.
(ii) Multiplying numerator and denominator of a fraction by the same number does not change its value.
(iii) \(\frac{5}{10}\) and \(\frac{1}{2}\) are equivalent fractions.
(iv) \(\frac{7}{3}\) and \(\frac{1}{3}\) are equivalent fractions.
(a) i, ii, iii are correct
(b) ii, iii, iv are correct
(c) i, ii, iv are correct
(d) i, ii, iii, iv are correct
Answer:
(a) i, ii, iii are correct

Question 5.
Compute the perimeter and area of each of the shapes below:

Answer:
Lets join the two sides. So we get 4 rectangles.

Perimeter = 5 + 5 + 1 + 4 + 1 + 3 + 1 + 3 + 1 + 4 + 1 + 5 = 34 centimeter
Area of Ist part = 5 × 1 = 5 square centimeter
Area of IInd part = 4 × 1 = 4 square centimeter
Area of IIIrd part = 3 × 1 = 3 square centimeter
Area of IVth part = 4 × 1 = 4 square centimeter
Total Area = 5 + 4 + 3 + 4 = 16 square centimeter 6 A.

Question 6 has two questions (6 A and 6 B). Answer any one.

Question 6.
A Write answers to the questions related to the measurements given below.
(a) If one centimetre divided into 10 equal parts, what is the length of one part?
Answer:
1 millimeter

(b) How many millimetres are there in 8 centimetre and 7 millimetre.
Answer:
87 millimeter

(c) Write 4 millimeters in centimeter
Answer:
0.4 cm or \(\frac{4}{10}\) cm

(d) How much is part of a metre?
Answer:
1 cm

(e) 2 metre = ……… centimetre
Answer:
213 cm

OR

B. Rewrite the table in the ascending order.

DISTRICT	POPULATION
Kottayam	1974551
Alappuzha	2127789
Pathanamthita	1197412
Kollam	2635375
Thiruvananthapuram	3301427

Answer:

DISTRICT	POPULATION
Pathanamthita	1197412
Kottayam	1974551
Alappuzha	2127789
Kollam	2635375
Thiruvananthapuram	3301427

With regular practice, Std 5 Maths Question Paper Kerala Syllabus Set 5 help improve accuracy.

Kerala Syllabus 5th Standard Maths Question Paper Set 5

Time : 2 Hrs 15 Min

Instructions:

• First 15 minutes is allotted as cool-off time. Read the questions carefully and plan the answers during this time.
• Answer all six questions. Answer all the sub questions.
• Two questions are there in Question 4 and 6. Attempt any one of them. (4A or 4 B and 6A or 6B).

Question 1.
(a) The picture given below is prepared by 5th std students of Govt. UPS Punnassery using number cards.

(i) Which of the following is the largest number that can be made using all the digits in the figure?
Answer:
Largest number = 9876420

(ii) Write the smallest number using these digits.
Answer:
Smallest number = 2046789

(b) Write the number according to the place value.
(i) 8 lakh 3 ten thousand 6 thousand 7 hundred 3 tens and 2 ones.
Answer:
836732

(ii) Which among the following represents seven lakh two thousand four hundred and thirty two?
(a) 72432
(b) 720432
(c) 702432
(d) 724320
Answer:
(b) 702432

Question 2.
(a) Look at the following calculations: .
4 = 1 + 2 + 1
9 = 1 + 2 + 3 + 2 + 2
16 = 1 + 2 + 3 + 4 + 2 + 1
(i) How do we write 49 as a sum like this?
Answer:
49 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 6 + 5 + 4 + 3 + 2 + 1

(ii) How about 81?
Answer:
81 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1

(iii) Can you write 121 as such a sum?
Answer:
121 = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1

(b) (i) How many odd numbers like 1, 3, 5 are to be added to get 123 ?
Answer:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 = 123
12 odd numbers are needed to get 123.

(ii) Which is the last odd number added in this?
Answer:
23 is the last odd number added in this.

(c) Which of the following statements are correct about the sum of odd numbers?
(i) 1 + 3 + 5 = 9, which is a square number.
(ii) The sum of the first 10 odd numbers is 100.
(iii) The sum of the first n odd numbers equals n².
(iv) Adding even numbers also gives a perfect square.
(a) i, ii, iii are correct
(b) ii, iii, iv are correct
(c) i, iii are correct
(d) i, ii, iii, iv are correct
Answer:
(c) i, iii are correct

Question 3.
Write each of the numbers as certain times 9 and a remainder
(a) 11
(b) 111
(c) 1111
Answer:
The number can be written in certain times of 9 and a reminder as:
(a) 11 = (9 × 1) + 2
(b) 111 = (9 × 12)+ 3
(c) 1111 = (9 × 123) + 4

(i) Can you guess how 1111 is written like this? Check your guess by actual division.
Answer:

(ii) Write out this number pattern.
Answer:
(9 × 1) + 2 = 11
(9 × 12) + 3 = 111
(9 × 123) + 4 = 1111
(9 × 1234) + 5 = 11111
(9 × 12345) + 6= 111111
(9 × 123456) + 7 = 1111111

Question 4 has two questions (4 A and 4 B). Answer any one.

Question 4.
[A] (a) State ‘T‘ for True and ‘F‘ for False:
(i) 33 metres 50 centimetres is equal to 3350 centimetres.
Answer:
True

(ii) 5 kilograms 250 grams is equal to 2300 grams.
Answer:
False

(iii) 8150 millilitres is equal to 8050 millilitres.
Answer:
False

(iv) 4000 millilitres is equal to 4 litres.
Answer:
True

(v) 7 kilograms is equal to 8000 grams.
Answer:
False

(b) Complete the following table.

Measure	Fractional form	Decimal form
25 kilometres 836 metres	__________ kilometres	_______ kilometres
9 litres 375 millilitres	_________ litres	_______ litres
13 metres 38 centimetres	_________ metres	_______ metres
2 kilograms 800 grams	_________ kilograms	_______ kilograms
12 centimetres 3 millimetres	_________ centimetres	_______ centimetres
525 millilitres	________ litres	________ litres
250 grams	_________ kilograms	_______ kilograms

Answer:

Question 4.
[B] Find out the area of the figure given below.

Answer:

Let’s extend the top left comer, so we get a complete square with sides 8 cm.
Area of the large square = 8 × 8 = 64 square centimeters
After joining the two sides we will get a small rectangle with sides 3 cm and 2 cm.
To find the area of the shape, we take the area of the big rectangle and subtract the area of the smaller rectangle from it.
Area of the small rectangle = 3 × 2 = 6 square centimeters
Area of the figure = 64 – 6 = 58 square centimeters

Question 5.

A picture of a clock is given.
(a) What are the hands on this clock?
Answer:
Second hand, minute hand, hour hand

(b) Which hand turns the fastest?
Answer:
Second hand

(c) How long does it take for the minute hand to rotate once?
Answer:
1 hour

(d) What time is it on the clock, in the picture?
Answer:
7:15

(e) Draw a picture of a clock and mark the time as half past eight.
Answer:

Question 6 has two questions (6A and 6 B). Answer any one.

Question 6.
[A] (a) Check whether the first is a multiple of the second: 7, 91
Answer:

This shows 91 = 13 × 7
That is, 91 is a multiple of 7.

(b) Now find the quotients below by removing common factors:
(i) 630 ÷ 126
(ii) 420 ÷ 105
Answer:
(i) 630 = 2 × 9
126 = 2 × 9 × 7
Common factors: 2, 9, 7
Thus, 630 ÷ 126 = 5

(ii) 420 = 4 × 3 × 5 × 7
105 = 3 × 5 × 7
Common factors: 3, 5, 7
Thus, 420 ÷ 105=4

OR

[B] The graph below shows the units of electricity consumed during various months of a year:

(i) In which months was the maximum electricity used?
Answer:
The maximum electricity consumption , occurred in March and April, each.

(ii) In which months was it the minimum?
Answer:
The minimum electricity consumption occurred in September, October, November, and December

(iii) What is the difference between the maximum and minimum?
Answer:
Maximum unit of electricity consumed = 340
Minimum unit of electricity consumed = 290
The difference between the maximum and minimum = 340 – 290 = 50 units

(iv) Are there any months in which the same units of electricity was used?
Answer:
Yes, September, October, November and December.

(v) What is the total number of uftits used in this whole year?
Answer:
310 + 340 + 330 + 300 + 290 + 290 = 1860
The total electricity used in the whole year = 1860 × 2 = 3720 unit

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