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Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 10 Functions

Plus One Functions One Mark Questions and Answers

Question 1.
The process of dividing big programs into small programs are called __________.
Answer:
Modularization

Question 2.
The big programs are divided into smaller programs. This smaller programs are called __________.
Answer:
Functions

Question 3.
The execution of the program begins at __________ function.
Answer:
main function

Question 4.
One of the following is not involved in the creation and usage of a user defined function.
(a) Define a function
(b) Declare a function
(c) invoke a function
(d) None of these
Answer:
(d) None of these

Question 5.
The default data type returned by a function is ________.
(a) float
(b) double
(c) int
(d) char
Answer:
(c) int

Question 6.
After the execution of a function, it is returned back to the main function by executing _________ keyword.
Answer:
return

Question 7.
Supplying data to a function from the called func-tion by using _________.
Answer:
parameters (arguments)

Question 8.
_________ keyword is used to give a value back to the called function.
Answer:
return.

Question 9.
_________ key word is used to specify a function returns nothing.
Answer:
void

Question 10.
One of the following is not necessary in the function declaration. What is it?
(a) name of the function
(b) return type
(c) number and type of arguments
(d) name of the parameters
Answer:
(d) name of the parameters

Question 11.
A function declaration is also called _________.
Answer:
prototype

Question 12.
Consider the following declaration
int sum(int a , int b)
{
return a+b;
}
From the following which is the valid function call.
(a) n = sum(10)
(b) n = sum(10,20)
(c) n = sum(10,20,30)
(d) n = sum()
Answer:
(b) n = sum(10,20)

Question 13.
The ability to access a variable or a function from some where in a program is called ________.
Answer:
scope

Question 14.
A variable or a function declared within a function is have ______ scope.
Answer:
local

Question 15.
A variable or a function declared out side of all the functions is have __________ scope.
Answer:
global

Question 16.
State True/False

1. A local variable exist till the end of the program
2. A global variable destroyed when the sub function terminates

Answer:

1. False
2. False

Question 17.
consider the following declaration
int x;
void main()
{
……..
}
Here x is a _____ variable.
Answer:
global

Question 18.
consider the following declaration
void main()
{
int x;
}
Here x is a _______ variable
Answer:
local

Question 19.
__________ parameter is used when the function call does not supply a value for parameters
Answer:
default

Question 20.
The parameter used to call a function is called ____________.
Answer:
Actual parameter

Question 21.
The parameters appear in a function definition are ___________.
Answer:
formal parameters

Question 22.
After the distribution of answer scripts, the teacher gives the Photostat copy of the mark list to the students to check the marks. If the students make any change that do not affect the original mark list. There is a similar situation to pass the arguments to a function. What is this method?
(a) call by value
(b) call by reference
(c) call by address
(d) none of these
Answer:
(a) call by value

Question 23.
Your class teacher gives you the original mark list to check the mark. If you make any change it will affect the original mark list. There is a similar situation to pass the arguments to a function. What is this method?
(a) call by value
(b) call by reference
(c) call by function
(d) none of these
Answer:
(b) call by reference

Question 24.
Consider the following function declaration
int sum(int,a, int b)
{
Body
}
Here the arguments are passed by __________.
Answer:
call by value method

Question 25.
Consider the following function declaration
int sum(int &a, int &b)
{
Body
}
Here the arguments are passed by __________.
Answer:
call by reference method

Question 26.
A function calls it self is known as ____________.
Answer:
recursive function

Question 27.
Varun wants to copy a string by using strcpy() function. From the following which header file is used for this?
(a) cstdio
(b) cmath
(c) cstring
(d) cctype
Answer:
(c) cstring

Question 28.
__________ is a named group of statements to perform a job/task and returns a value.
Answer:
Function

Question 29.
In his C++ program Ajith wants to accept a lengthy text of more than one line. Which function in C++ can be used in this situation.
Answer:
gets() function can be used to accept a lengthy text.

Question 30.
A function can call itself for many times and return a result. What is the name given to such a function? (MARCH-2016)
Answer:
Recursive function

Question 31.
How many values can a C++ function return? (SCERT SAMPLE-I) (1)
Answer:
One Value

Question 32.
A function may require data to perform the task assigned to it. Which is the component of function prototype that serves this purpose? (SCERT SAMPLE – II) (1)
Answer:
Arguments (Parameters)

Question 33.
“Arguments used in call statement are formal arguments”. State true or false. (SAY-2016) (1)
Answer:
False

Question 34.
Name the built-in function to check whether a character is alphanumeric or not. (MARCH-2017)
Answer:
pisalnum()

Plus One Functions Two Mark Questions and Answers

Question 1.
How does C++ support modularity in programming C++
Answer:
The process of converting big programs into smaller programs is known as modularisation. This small programs are called modules or sub programs or functions. C++ supports modularity in programming called functions.

Question 2.
Consider the following code snippet
charch;
cout << “Enter an alphabet”;
cin>>ch;
cout<<toupper (ch);
What is the output of the above code? Give a sample output.
If the above code is used in a computer that has no cctype file, how will you modify the code to get the same output?
Answer:
It reads a character and convert it into upper case.
eg:
Enter an alphabet: a
The output is A.
If a computer has no cctype header file the code is as follows,
char ch;
cout<< “Enter an alphabet”;
cin»ch;
if (ch >= 97 && ch<<122)
cout<<ch – 32;

Question 3.
The following assignment statement will generate a compilation error.
char str[20];
str = “Computer”
Write a correct C++ statement to perform the same task
Answer:
char str[20] = “Computer”;

OR

char str[20];
strcpy(str,”Computer”); (The header file <string.h> should be included)

Question 4.
float area(const float pi = 3.1415, const float r)
{
r = 10;
return pi*r;
}
Is there any problem? If yes what is it?
Answer:
There is an error. The error is ‘r’ is a constant V must be initialised and cannot be changed during execution.

Question 5.
Match the following

a. strcmp()	1. cctype
b. tolower()	2. iomanip
c. sqrt()	3. iomanip
d. abort()	4. cstdlib
e. setw()	5. cmath

Answer:
a. 3
b. 1
c. 5
d. 4
e. 2

Question 6.
What are the jobs of a return statement in a program?
Answer:
In the case of a sub function a return statement helps to terminate the sub function and return back to the main function or called function. But in the case of a main function it terminates the program.

Question 7.
How to invoke a function in C++ program?
Answer:
function can be called or invoked by providing the name of the function followed by the arguments in parenthesis.
eg: sum(m,n);

Question 8.
Briefly explain constant arguments
Answer:
By using the keyword const we can make argument (parameter) of a function as a constant argument. The value of the const argument cannot be modified within the function.

Question 9.
Short notes on header files
Answer:
A header file is a prestored file that helps to use some operators and functions. To write C++ pro-grams the header files are must. Following are the header files
alloc
iostream
iomanip
cstdio
cctype
cmath
cstring
The syntax for including a header file is as follows
#include<name of the header file>
eg: #include<iostream>

Question 10.
Identify the appropriate header files for the following.

1. setw()
2. cout
3. toupper()
4. exit()
5. strcpy()

Answer:

1. setw() – iomanip.h
2. cout – iostream
3. toupper() – cstring
4. exit() – process
5. strcpy() – cstring

Question 11.
Construct the function prototypes for the following functions.

1. The function Display() accepts one argument of type double and does not return any value.
2. Total () accepts two arguments of type int, float respectively and returns a float type value. (MARCH-2015) (2)

Answer:

1. void Display(double);
2. float Total(int, float);

Question 12.
Explain two types of variable according to its scope and life. (SAY-2015) (2)
Answer:
Scope and life of variables and functions
1. Local scope:
A variable declared inside a block can be used only in the block. It cannot be used any other block.
eg:
#include<iostream>
using namespace std;
int sum(int n1 ,int n2)
{
int s;
s = n1 + n2;
return (s);
}
int main()
{
int n1 ,n2;
cout<<“Enter 2 numbers cin>>n1>>n2;
cout<<“The sum is “<<sum(n1 ,n2);
}
Here the variable s is declared inside the function sum and has local scope;

2. Global scope:
A variable declared outside of all blocks can be used any where in the program.
#include<iostream>
using namespace std;
int s;
int sum(int n1,int n2)
{
s = n1 + n2;
return(s);
}
int main()
{
int n1 ,n2;
cout<<“Enter 2 numbers cin>>n1>>n2;
cout<<“The sum is “<<sum(n1,n2);
}
Here the variable s is declared out side of all functions and we can use variable s any where in the program.

Question 13.
There is a way to pass more than one value to the calling function from the called function. Explain how? (SCERT SAMPLE – I) (2)
Answer:
Methods of calling functions
Two types call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example
#include<iostream.h>
#include<conio.h> void
swap(int a, int b)
{
int temp;
temp = a;
a = b;
b = temp;
}
main()
{
clrscr();
int a,b;
cout<<“Enter values for a and b:-“;
cin>>a>>b;
cout<<“The values before swap a =”<<a<<“ and
b =”<<b;
swap(a,b);
cout<<“\nThe values before swap a =”<<a«“ and
b =”<<b;
getch();
}

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example
#include<iostream.h>
#include<conio.h>
void swap(int &a, int &b)
{
int temp;
temp = a;
a = b;
b = temp;
}
main()
{
clrscrO;
int a,b;
cout<<“Enter values for a and b:- “; cin>>a>>b;
cout<<“The values before swap a =”<<a<<“ and
b=”<<b;
swap(a,b);
cout<<“\nThe values before swap a =”<<a<<“ and
b =”<<b;
getch();
}

Question 14.
A
Answer:
int sum (int N, int Start_No) .
{
int i, S = 0;
for (i = Start_No; i < = N + Start_No; i++)
S = S + i;
reurn S;
}

Question 15.
Differentiate between the string functions strcmp() and strcmpi(). (SAY-2016) (2)
Answer:
strcmp(): It is used to compare two strings and returns an integer.
Syntax:
strcmp(string1,string2)

• if it is 0 both strings are equal.
• if it is greater than 0(i.e. +ve) stringl is greater than string2
• if it is less than 0(i.e. -ve) string2 is greater than string1

strcmpi():
It is same as strcmp() but it is not case sensitive. That means uppercase and lowercase are treated as same.
eg: “ANDREA” and “Andrea” and “andrea” these are same.

Question 16.
Read the function definition given below. Predict the output, if the function is called as convert (7). (MARCH-2017) (2)
void convert (int n)
{
if (n>1)
convert (n/2);
cout<<n%2;
}
Answer:
The out put is 111. convert() is a recursive function.

Plus One Functions Three Mark Questions and Answers

Question 1.
Consider the following function declaration with optional (default) arguments and state legal or illegal and give the reasons

1. int sum(int x = 10, int y, int z)
2. int sum(int x = 10, int y = 20, int z)
3. int sum(int x = 10, int y = 20, int z = 30)
4. int sum(int x, int y = 20, int z)
5. int sum(int x, int y = 20, int z = 30)
6. inf sum(int x, int y, int z = 30)
7. int sum(int x = 10, int y, int z = 30)

Answer:
There is a rule to make an argument as default argument,i.e., to set an argument with a value that must be in the order from right to left. All the arguments in the right side of an argument must be set first to make an argument as a default argument.

1. illegal, because y and z are not have values
2. illegal, because z has no value
3. legal
4. illegal, because z has no value
5. legal
6. legal
7. illegal, because x has a value but y has no value

Question 2.
A list of C++ built-in functions are given. Classify them based on the usage and prepare a table with proper group names.

Answer:

Question 3.
Read the following program
#include<iostream>
using namespace std;
int main()
{
cout<<sum(2,3);
}
int sum(int x, int y)
{return (x + y);}
On compilation on the program, an error will be displayed. Identify and explain the reason. How can you rectify the problem
Answer:
The compilation of the program starts from the first line arid next line and so on( i.e. line by line). While compiling the line cout<<sum(2,3); The compiler does not understand the word sum(2,3) because it is not declared yet hence the error prototype required. To rectify this problem there are two methods

First method:
Give the function definition just before the main function as follows.
#include<iostream>
using namespace std;
int sum(intx, int y)
{return (x + y);}
int main()
{
cout<<sum(2,3);
}

Second Method:
Give the function declaration(prototype only) in the main function as follows.
#include<iostream>
using namespace std;
int main()
{
int sum(int.int);
cout<<sum(2,3);
}
int sum(int x, int y)
{return (x + y);}

Question 4.
Considering the following function definition.
{
for (int f = 1; n>0; n-)
f = f*n;
return f;
}
void main()
{
int a = 5, ans;
ans = fact (a);
cout<< a << “! = ” << ans;
}
The expected, desired output is 5! = 120
What will be the actual output of the program? It is not the same as above, why? What modification are required in the program to get the desired output.
Answer:
The output is 0! = 120
Because the address of variable ’a’ is given to the variable ‘n’ of the function fact(call by reference method). So the function changes its value (i.e. n-) to 0. Hence the result.
To get the desired result call the function as call by value method in this method the copy of the value of the variable ‘a’ is given to the function. So the actual value of ‘a’ will not changed. So instead of int fact(int &n) just write int fact(int n), i.e., no need of & symbol.

Question 5.
A function is defined as follows
int sum (int a, int b = 2)
{return (a + b);}
Check whether each of the following function calls is correct or wrong, Justify your answer

1. cout << sum (2,3);
2. cout << sum( 2) ;
3. cout << sum();

Answer:
Here the function is declared with one optional argument. So the function call with minimum one argument is compulsory.

1. It is valid. Here a becomes 2 and b becomes 3.
2. It is also valid . Here a becomes 2 and b takes the default value 2.
3. It is not a valid call. One argument is compulsory.

Question 6.
The factorial of a number, say N is the product of first N natural numbers. Thus, factorial of 5 can be obtained by taking the product of 5 and factorial of 4. Similarly factorial of 4 be found out by taking the product of 4 and factorial of 3. At last the factorial of 1 is 1 itself.

Which technique is applicable to find the factorial of a number in this fashion? Write a C++ function to implement this technique. Also explain the working of the function by giving the number 5 as input.
Answer:
A function calls itself is known as recursion.
#include<iostream>
using namespace std;
int fac(int);
int main()
{
int n;
cout<<“enter a number”;
cin>>n;
cout<<fac(n);
}
int fac(int n)
{
if (n == 1) return (1);
else
return (n × fac(n – 1));
}
The working of this program is as follows If the value of n is 5 then it calls the function as fa. The function returns value 5 × fac(4), That means this function calls the function again and returns 5 ×4 × fac(3). This process continues until the value n = 1. So the result is 5 × 4 × 3 × 2 × 1 = 120.

Question 7.
How do two functions exchange data between them? Compare the two methods of data transfer from calling function to called function
Answer:
There are two methods they are call by value and call by reference
1. call by value:
In call by value method, a copy of the actual parameters are passed to the formal parameters. If the function makes any change it will not affect the original value.

2. call by reference:
In call by reference method, the reference of the actual parameters are passed to the formal parameters. If the function makes any change it will affect the original value.

Question 8.
Read the following program
#include<iostream>
using namespace std;
int a = 0;
int main()
{
int showval(int);
cout<< a; a++;
cout << showval (a);
cout<< a;
}
int showval(int x)
{
int a = 5;
return (a + x);
}
Write down the value displayed by the output of the above program with suitable explanation. What are the inferences drawn regarding the scope of variables?
Answer:
The output is 061.
Global variable: A variable declared out side of all functions it is known as global variable.
Local variable: A variable declared inside of a function it is known as local variable.
If a variable declared inside a function(main or other) with the same name of a global variable. The function uses the value of local variable and does not use the value of the global variable.

Here int a = 0 is a global variable. In the main function the global variable ‘a’ is used. There is no local variable so the value of ‘a’, 0 is displayed. The statement ‘a++’ makes the value of ‘a’ is 1. It calls the function showval with argument ‘a = T.

The argument ‘x’ will get this value i.e. ‘x = 1 But in the function showval there is a local variable ‘a’ its value is 5 is used. So this function returns 6 and it will be displayed. After this the value 1 of the global variable ‘a’ will be displayed. Hence the result 061.

Question 9.
The following are function calling statements. Some of them will be executed, while some other generate compilation error. Write down your opinion on each of them with proper justification Function

1. har ch =
2. sqrt(25);
3. strcat (“Computer”, “Program”);
4. double num = pow(2,3,5)
5. putchar(getchar());

Answer:

1. getch get a character from the console(keyboard) but does not echo to the screen. So we can’t read a character from the console.
2. It returns the square root of 25.
3. It concatenates Program to computer, i.e. we will get a string “computer program”
4. The function pow should contains only two arguments. But here it contains 3 arguments so it is an error. We can write this function as follows Double num = pow(pow(2,3),5)
5. It reads a character from the console and display it on the screen.

Question 10.
Write down the operation performed by the following statements.

1. int l = strlen(“Computer Program”);
2. char ch[ ] = tolower(“My School”);
3. cout <<(strcmp(“High”, “Low”)>0 ? toupper(“High”):tolower(“Low”));

Answer:

1. The built in function strlen find the length of the string i.e. 16 and assigns it to the variable I.
2. This is an error because tolower is a character function.
3. This is also an error because tolower and toupper are character functions.

Question 11.
A line of given length with a particular character is to be displayed. For example, ********** js a line with ten asterisks (*). Define a function to achieve this output.
Answer:

Question 12.
Read the following function
int fib(int n)
{
if (n<3)
return 1;
else
return (fib(n – 1) + fib(n – 2));
}

1. What is the speciality of this function
2. How does it work?
3. What will be the output of the following code?

Answer:

1. This function is a recursive function. That means the function calls itself.
2. It works as follows
   • if i = 1, The function fib calls with value 1. i.e. fib(1) returns 1
   • if i = 2, The function fib calls with value 2. i.e. fib(2) returns 1
   • if i = 3, The function fib calls with value 3. i.e. fib(3) returns fib(2) + fib(1) i.e. it calls the function again.
     So the result is 1 + 1 = 2
   • if i = 4, The function fib calls with value 4. i.e. fib(4) returns fib(3) + fib(2) i.e. it calls the function again.
     So the result is 2 + 1 = 3
3. The output will be as follows 1 1 2 3

Question 13.
Explain scope rules of functions and variables in a C++ program
Answer:
Local variable or function:
A variable or function declared inside a function is called local variable or function. This cannot be accessed by the out-side of the function.
eg:
main()
{
int k; // local variable
cout<<sum(a,b); // local function
}

Global variable or function:
A variable or function declared out side of a function is called global variable or function. This can be accessed by any statements.
eg:
int k; // global variable
int sum(int a, int b); // global function
main()
{
}

Question 14.
Briefly explain default arguments Default arguments.
Answer:
A default value can be set for a parameter (argument) of a function. When the user does not give a value the function will take the default value. An important thing remember,is an argument cannot have a default value unless all arguments on its right side must have default value.
Functions with valid default arguments are given below

• float area(int x, int y, int z = 30);
• float area(int x, int y = 20, int z = 30);
• float area(int x = 10, int y = 20, int z = 30);

Functions with invalid default arguments are given below

• float area(int x = 10, int y, int z);
• float area(int x, int y = 20, int z);
• float area(int x = 10, int y = 20, int z);

Question 15.
How to pass an array to function.
Answer:
By using call by reference method we can send an array as argument. We have to send only the array name and its data type. The array name holds the starting address and will access the subsequent elements of an array.
The following example shows this

Question 16.
How to pass a structure to a function.
Answer:
A structure can be passed as argument to a function either call by value or call by reference method. An example is given below to read name and age of a structure and pass it to a function.

Question 17.
Write a program to read a character and check whether it is alphabet or not. If it is an alphabet check whether it is upper case or lower case?
Answer:

Question 18.
Write a program to read 2 strings and join them 2 string.
Answer:

Question 19.
Write a program to read 2 strings and compare it 2 string.
Answer:

Question 20.
Write a program to read a string and display the number of alphabets and digits and special characters.
Answer:

Question 21.
Write a program to perform the following opera-tions on a string

1. Length of a string
2. Search a character
3. Display the string

Answer:

Question 22.
Write short notes about conversion functions.
Answer:
The header file stdlib.h is used for conversion functions.Following are the important conversion functions
1. itoa():
It is used to convert an integer into a string.
eg:
int n = 100;
charstr[20];
itoa(n,str,10);

2. Itoa():
It is used to convert an long into a string.
eg:
long n = 1002345L
char str[20];
ltoa(n,str,10);

3. atoi():
It is used to convert a string into integer
eg:
int n;
str[] = “123”
n = atoi(str);

4. atoll():
It is used to convert a string into long
eg:
long n;
str[] = “123456”
n = atol(str);

Question 23.

1. Predict the output of both programs.
2. Justify your predictions.

Answer:
1. A. Output
value = 40

B. output
value = 0

2. In the first case (A) the argument x is passed by reference method. So the changes made in the function reflects in main()

In the second case (B) the argument x is passed by value method. So the changes made in the function will not reflect in main()

Question 24.
Consider the following C++ function.
int recfact(int x)
{
if(x == 0)
return 1;
else
return x * recfact(x – 1);
}

1. What type of function is this? Explain. (2 Scores)
2. What is the output of the above function when x = 5

Answer:

1. recursive function. The abilty of a function to call itself is called recursion. A function is said to be recursive if a statement in the body of the function calls itself.
2. Output 120

Question 25.
void initialise()
{
int k = 10;
}
int main()
{
int a, b;
float marks;
a = 20;
cout<<“First value =”<< a;
initialise();
b = k + a;
cout<<“New value =”<<b;
}

1. Identify the error in the above code and explain its reasons.
2. Correct the errors.

Answer:

1. K is a local variable in the function initialize 0. It is not accessible in main()
2. Making the variable K as global we can correct the error.

Question 26.
Write a program to read 2 strings and join them using string function.
Answer:
#include<iostream>
#include<cstring>
#include<cstdio>
using namespace std;
int main()
{
char str1 [50],str2[50],str[100];
cout<<“Enter a string:”; gets(strl);
cout<<“Enter another string:”; gets(str2);
strcat(str,str1);
strcat(str,str2);
cout<<“The concatenated string is”<<str;
}

Question 27.
Consider the following code.
#include<iostream>
#include<cstdlib>
using namespace std;
int main()
{
char str1 [] = “123”,str2[] = “45”;
int a,b;
a = atoi(str1);
b = atoi(str2);
cout<<a + b;
}
What will be the output and give the reason?
Answer:
The output is 123 + 45 = 168. Here the conversion function atoi is used to convert the string “123” into integer 123 and “45” into integer 45 so the result.

Question 28.
Name the different methods used for passing arguments to a function. Write the difference between them with examples. (MARCH-2015)
Answer:
Methods of calling functions:
Two types call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 29.
Write a C++ program to display the simple interest using function. (SAY-2015) (3)
Answer:
include < iostream>
using namespace std;
float Simplelnt (float p, int n, float r)
{
return (p*n*r/100);
}
int main()
{
float p, r, SI;
int n;
cout<<“Enter values for p,n,r:”; cin>>p>>n>>r;
SI = Simplelnt (p,n,r); cout<<“simple interest is”<<SI;
}

Question 30.
Write a function’s definition of the above type to find the sum of matural numbers from 1 to N. (Hint: If the value of N is 5, the answer will be 1 + 2 + 3 + 4 + 5 = 15). (MARCH – 2016) (3)
Answer:
int sum (int n)
{
if (n == 0)
return 0;
else
return (n + sum (n – 1));
}

Question 31.
A program requires functions for adding 2 numbers, 3 numbers and 4 numbers, How can you provide a solution by writing a single functio0n? (SCERT SAMPLE -1) (3)
Answer:
It can be solved by writing function with default values.
eg: int add (int n1, int n2, int n3 = 0, int n4 = 0)
{
return (n1 + n2 + n3 + n4);
}
This function can be invoked by the following function calling
1. add (5,2);
2. add (5,2,7);
3. add (5,2,7,10);

The 1. Call returns 5 + 2 = 7
2. Call returns 5 + 2 + 7 = 14
3. Call returns 5 + 2 + 7 + 10 = 24

Question 32.
Explain the difference between call-by-value method and call-by-reference method with the help of examples. (SCERT SAMPLE – II) (3)
Answer:
Methods of calling functions:
Two types call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the ’ function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 33.
Explain recursive functions with the help of a suitable example. (SAY-2016) (3)
Answer:
A function calls itself is called recursive function.
#include<iostream>
using namespace std;
void convert(int n)
{
if(n>1)
convert(n/2);
cout<<n % 2;
}
int main()
{
convert(7);
}
Here the function convert is a recursive function, that means it calls itself and output of the above program is 111.

Question 34.
Name the built-in function to check whether a character is alphanumeric or not. (MARCH-2017) (3)
Answer:
isalnum()

Question 35
Briefly explain the three components in the structure of a C++ program. (MARCH-2017) (3)
Answer:
1. Preprocessor directives:
A C++ program starts with the preprocessor directive i.e., # .include, #define, #undef, etc, are such a preprocessor directives. By using #include we can link the header files that are needed to use the functions. By using #define we can define some constants.
eg: #define x 100. Here the value of x becomes 100 and cannot be changed in the program. No semicolon is needed.

2. Header files:
A header file is a pre stored file that helps to use some operators and functions. To write C++ programs the header files are must. Following are the header files iostream

• iomanip
• cstdio
• cctype
• cmath
• cstring

The syntax for including a header file is as follows
#include<name of the header file>
eg: #include<iostream>

3. The main function:
The main function is the first function which is invoked at the time of execution and the program ends within main(). The other functions are invoke from main().

Question 36.
Explain the difference between call by value method and call by reference method with the help of examples. (MARCH-2017) (3)
Answer:
Two types are call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change wilt not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Plus One Functions Five Mark Questions and Answers

Question 1.
Short notes about character functions and string functions
Answer:
A. Character functions:
1. isalnum():
t is used to check whether a character is alphabet or digit. It returns a non zero value if it is an alphabet or digit otherwise it returns zero.

2. isalpha():
It is used to check whether a character is alphabet or not. It returns a non zero value if it is an alphabet otherwise it returns zero.

3. isdigit():
It is used to check whether a character is digit or not. It returns a non zero value if it is digit otherwise it returns zero.

4. islower():
It is used to check whether a character is lower case alphabet or not. It returns a non zero value if it is a lowercase alphabet otherwise it returns zero.

5. isupper():
It is used to check whether a character is upper case alphabet or not. It returns a non zero value if it is an upper case alphabet otherwise it returns zero.

6. tolower():
It is used to convert the alphabet into lower case

7. toupper():
It is used to convert the alphabet into upper case

B. String functions:

1. strcpy():
This function is used to copy one string into another

2. strcat():
This function is used to concatenate(join) second string into first string

3. strlen():
This function is used to find the length of a string.

4. strcmp():
This function is used to compare 2 strings. If the first string is less than second string then it returns a negative value. If the first string is equal to the second string then it returns a value zero and if the first string is greater than the second string then it returns a positive value.

Question 2.
Write functions to perform the following operations

1. sqrt()
2. power of 2 numbers
3. sin
4. cos

Answer:

Question 3.
Write a C++ program to display the roots of quadratic equation. (SAY-2015) (5)
Answer:
#include<iostream>
#include<cmath>

Question 4.
Explain ‘Call by Value’ and ‘Call by Reference’ methods of function calling with the help of a suitable example. (SAY-2016)
Answer:
Two types are call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 5.
Define network topology. Explain any four network topologies in detail. (SAY-2016)
Answer:
Network topologies:
Physical or logical arrangement of computers on a network is called structure or topology. It is the geometrical arrangement of computers in a network. The major topologies developed are star, bus, ring, tree and mesh

1. Star Topology:
A star topology has a server all other computers are connected to it. If computer A wants to transmit a message to computer B. Then computer A first transmit the message to the server then the server retransmits the message to the computer B.

That means all the messages are transmitted through the server. Advantages are add or remove workstations to a star network is easy and the failure of a workstation will not effect the other. The disadvantage is that if the server fails the entire network will fail.

2. Bus Topology:
Here all the computers are attached to a single cable called bus. Here one computer transmits all other computers listen. Therefore it is called broadcast bus. The transmission from any station will travel in both the direction. The connected computers can hear the message and check whether it is for them or not.

Advantages are add or remove computer is very easy. It requires less cable length and the installation cost is less. Disadvantage is fault detection is very difficult because of no central computer.

3. Ring Topology:
Here all the computers are connected in the shape of a ring and it is a closed loop. Here also there is no central computer. Here a computer transmits a message, which is tagged along with its destination computer’s address. The message travels in one direction and each node check

whether the message is for them. If not, it passes to the next node. FIt requires only short cable length. If a single node fails, at least a portion of the network will fail. To add a node is very difficult.

4. Hybrid Topology:
It is a combination of any two or more network topologies. Tree topology and mesh topology can be considered as hybrid topology.
(a) Tree Topology:
The structure of a tree topology is the shape of an inverted tree with a central node and branches as nodes. It is a variation of bus topology. The data transmission takes place in the way as in bus topology. The disadvantage is that if one node fails, the entire portion will fail.

(b) Mesh Topology:
In this topology each node is connected to more than one node. It is just like a mesh (net). There are multiple paths between computers. If one path fails, we can transmit data through another path.

Students can Download Chapter 2 Animal Kingdom Questions and Answers, Plus One zoology Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examination

Kerala Plus One Zoology Chapter Wise Questions and Answers Chapter 2 Animal Kingdom

Plus One Animal Kingdom One Mark Questions and Answers

Question 1.
Fill in the blanks.

Answer:
i) B – Nereis
ii) B – Ctenoplanna
C – Ctenophora
iii) A – radula

Question 2.
Write any two members of the Phylum Aschelminthes which are found parasitic on Human beings.
Answer:

1. Ascaris (Roundworm)
2. Wuchereria (Filaria worm)

Question 3.
In some animal groups, the body is found divided into compartments with at least some organs/ organ repeated. This characteristic feature is named
(a) Segmentation
(b) Metamerism
(c) Metagenesis
(d) Metamorphosis
Answer:
(b) Metamerism

Question 4.
Given below are types of cells present in some animals. Each one is specialized to perform a single specific function except
(a) Choanocytes
(b) Interstitial cells
(c) Gastrodermal cells
(d) Nematocytes
Answer:
(b) Interstitial cells

Question 5.
Which one of the following sets of animals share a four chambered heart?
(a) Amphibian, Reptiles, Birds
(b) Crocodiles, Birds, Mammals
(c) Crocodiles, Lizards, Turtles
(d) Lizards, Mammals, Birds
Answer:
(b) Crocodiles, Birds, Mammals

Question 6.
Which of the following pairs of animals has non glandular skin.
(a) Snake and Frog
(b) Chameleon and Turtle
(c) Frog and Pigeon
(d) Crocodile and Tiger.
Answer:
(c) Frog and Pigeon

Question 7.
Birds and mammals share one of the following characteristics as a common feature.
(a) Pigmented skin
(b) Alimentary canal with some modification
(c) Viviparity
(d) Warm blooded nature
Answer:
(d) Warm blooded nature

Question 8.
Note the relationship between the first two words and find a suitable word for the fourth place,

1. Coelenterata: radial symmetry, platyhelminthes, _______
2. Lizard: Poikilothermous, crow, _________

Answer:

1. bilaterally symmetrical
2. Homoiothermous

Question 9.

1. Annelida: Parapodia :: __________ : Comb plates
2. _________: Water vascular system :: Coelenterata : cnidoblast

Answer:

1. Ctenophora
2. Echinodermata

Question 10.
Malpighian tubule is the excretory organ of which phylum?
(a) Phylum porifera
(b) Phylum arthropoda
(c) Phylum Coelenterata
(d) Phylum mollusca
Answer:
(b) Phylum Arthropoda

Question 11.
A chordate animal having flame cells as the excretory organ.
Answer:
Amphioxus

Question 12.
From the pictures given below, find out the poikilothermic animals.

Answer:
B and D are poikilothermic animals.

Question 13.
Segmentation in the body is first observed in which of the following:
(a) Platyhelminthes
(b) Aschelminthes
(c) Annelida
(d) Arthropoda
Answer:
(c) Annelida

Question 14.
Shark has to swim continuously, otherwise, it will sink down. Give reason.
Answer:
Due to absence of air bladder.

Plus One Animal Kingdom Two Mark Questions and Answers

Question 1.
Arrange the phylum in order.
Arthropoda → Platyhelminthes → Porifera → Ctenophora → Cnidaria → Mollusca → Annelida → Echinodermata → Aschelminthesip
Answer:

• Presence of milk producing mammary gland.
• Presence of hair on skin.
• External ear or pinnae is present.
• Different types of teeth are present in the jaw.

Question 2.
Complete the blanks.

Character	Phylum
a. Body is flat
b. Body has similar segments
c. Body has jointed appendages
d. Body is round

Answer:

Character	Phylum
a. Body is flat	Platyhelminthes
b. Body has similar segments	Annelida
c. Body has jointed appendages	Arthropoda
d. Body is round	Aschelminthes

Question 3.
Triploblastic animals are more complex than diploblastic animals. Do you agree with this statement? Justify.
Answer:
Triploblastic animals have more cell layers so they have the possibility of greater degree of cellular specialisation.

Question 4.
All vertebrates are chordates but all chordates are not vertebrates. Justify.
Answer:
Notochord is present in all vertebrates but vertebral column is present only in vertebrates and not in all chordates.

Question 5.
Copy and complete the table.

Chondrichthyes	Osteichthyes
a _____________	Seen in all water forms
b. Endoskeleton is cartilage	_____________
c _______________	Body covered by cycloid scales
d ______________	Mouth is terminal

Answer:

Chondrichthyes	Osteichthyes
a. Marine form	Seen in all water forms
b. Endoskeleton is cartilage	Endoskeleton is bony.
c. Body is covered by placoid scale	Body covered by cycloid scales
d. Mouth is ventral	Mouth is terminal

Question 6.
Arrange the phylum in order.
Arthropoda → Platyhelminthes → Porifera → Ctenophora → Cnidaria → Mollusca → Annelida → Echinodermata → Aschelminthes
Answer:
Porifera → Cnidaria → Ctenophora→ Platyhelminthes → Aschelminthes → Annelida → Arthropoda → Mollusca → Echinodermata

Question 7.
Categorise and classify the following organisms and arrange them in a table with separate columns and provide appropriate headings.
Exocoetus, Physalia, Ascaris, Apis, Locusta, Corvus, Pita, Hydra, Sepia, Ancylostoma.
Answer:

Question 8.

1. Identify the phylum which exhibit metagenesis or alternation of generation.
2. What is meant by alternation of generation?

Answer:

1. Cnidaria
2. Alternation of sexual and asexual forms of organism: ie., Polyp asexually produce medusa, medusa sexually product polyp.

Question 9.
Name the following.

1. Phylum in which flatworms are included
2. Excretory organs of Annelids.
3. Largest phylum.
4. An oviparous mammal.

Answer:

1. Platyhelminthes
2. Nephridia
3. Arthropoda
4. Platypus

Question 10.
Apis, Prawn, Locust, Spider
Following animals have different habit and habitat. But they have many common characters.

1. Mention the common characters.
2. Identify their phylum.

Answer:

1. Joint footed animals
   • Metameric segmentation
   • Chitinous exoskeleton
2. Arthropoda

Question 11.
A list of animals are given below. Arrange them according to increase in complexity of organization. Scorpion, Earthworm, Liver fluke, Pigeon, Seaanemon, Sycon, Elephant, Anabas.
Answer:
Sycon, Seaanemon, Liver fluke, Earthworm, Scor¬pion, Anabas, Pegeon, Elephant.

Question 12.
Nithin is Studying in Std. XI. He collected some specimens during the field trip conducted by the Science Club of his School. Help Nithin to Classify the Animal in respective Phylum.
Prawn, Slug worm, Butterfly, Pila, Grass Hopper, Crab
Answer:

Arthropoda	Mollusca
Prawn	Slugworm
Butterfly	Pila
Grass hopper
Crab

Question 13.
During a field trip Raju has collected some organisms with the following characters. Help him to identify the phyla of those organisms.

1. Metamerically segmented body.
2. Body covered with calcareous shell.
3. Dorso-ventrally flattened leaf like body.
4. Body divided into head, thorax and abdomen.

Answer:

1. Annelida
2. Mollusca
3. Platyhelminthes
4. Arthropoda

Question 14.
Categorise the following fishes into Osteichthyes and Chondrichthyes?

1. Exocoetus
2. Trygon

Answer:

1. Exocoetus – Oesteichthyes
2. Trygon – Chondrichthyes

Question 15.
Arrange the following terms in two columns correctly. Malpighian tubules, radula, metamerism, Bioluminescence, choanocytes, nematocytes, Phylum-coelenterate, phylum-Arthropoda, phylum- ctnophora, phylum-Mollusca, Phylum-Porifera.
Answer:

Malpighian	Phylum – Arthropoda
Radula	Phylum – Mollusca
Metamerism	Phylum – Annelida
Bioluminescence	Phylum – Ctenophora
Choanocytes	Phylum – Porifera
Nematocytes	Phylum – Coelenterata

Question 16.
Match the following

Bidders canal	Earthworm
Typhlosole	Catla
Air bladder	Shark
Placoid scale	frog

Answer:

Bidders canal	frog
Typhlosole	Earthworm
Air bladder	Catla
Placoid scale	Shark

Question 17.
Observe the given organisms

1. Place these animals in proper phylum.
2. Segmentation in the body is first observed in which of the above phylum?

Answer:

1.  i) Arthropoda,
   ii) Porifera,
   ii) Annelida
2. Annelida

Question 18.
Observe the table given below and fill the blank columns A, B, C and from the animals given in brackets. (Ascaris, Starfish, Fasciola, Earthworm)

Answer:

Question 19.
1. Identify the animal given below.

2. Write one well marked property of the above animal.
Answer:

1. Pleurobrachia
2. Bioluminescence is well marked property of pleurobrachia

Question 20.
Representatives of some vertebrate classes are introducing themselves. Write down the name of the class in which they belong.

1. My gills are covered by operculum. I have bony endoskeleton.
2. I give birth to young ones. My body is covered by hair.
3. My skin is glandular? Have trilocular heart.
4. I live only in marine water. My endoskeleton is made up of cartilage.

Answer:

1. Osteichthyes
2. Mammalia
3. Amphibia
4. Chondrichthyes

Question 21.
During classroom discussion a student said that sponges are more complex than cnidarians. Do you agree with him. Justify.
Answer:
NO. Sponges are asymmetrical and body is formed of loose aggregate of cells. Cells are not organised to from tissues and organs. Cnidarians are radially symmetrical and tissue grade of organisation. So cnidarians are more complex than sponges.

Question 22.
Due to the absence of air bladder, fishes belonging to the class Chondrichthyes have to swim constantly. How important is the presence of air bladder in these fishes?
Answer:
Due to the absence of air bladder in chondrichthyes, they have to swim constantly to avoid sinking. If air bladder is present which regulates buoyancy.

Question 23.
Match the column A, B &C in the table given below:

Answer:

Question 24.
Identify the phylum whose larvae are bilaterally symmetrical, but adults are radially symmetrical.

1. Annelida
2. Arthropoda
3. Mollusca
4. Echinodermata

Mention two salient features of the phylum.
Answer:
4. Echinodermata
Salient features Presence of Echinodermata:

• Water vascular system
• Spiny bodies, Endoskeleton of Calcareous ossicles

Question 25.
Write the name of phylum.

1. Diploblastic, tissue grade of organisation, radially symmetrical, polymorphic animals.
2. Soft bodied, Unsegmented, Bilaterally symmetrical animals with open type circulation.
3. Triploblastic, bilaterally symmetrical, true coelomic animals with metamerism, closed circulation.
4. Triploblastic, chitinous exoskeleton and open circulation.

Answer:

1. Cnidaria
2. Mollusca
3. Annelida
4. Arthropoda

Question 26.
Observe the table given below and fill the blank columns a, b, c, and d from the animals given in brackets.

(Hydra, Shark, Spongilla, Obelia)
Answer:
(a) Hydra/Obelia
(b) Shark
(c) Spongilla
(d) Hydra/Obelia

Question 27.
Copy and complete the table.

Answer:

Question 28.
You are provided with two fishes Catla (Bony fish) and Shark (Cartilagenous fish). Prepare a table showing difference in:
(a) Position of mouth
(b) Air bladder
(c) Scales
(d) Fertilization
Answer:

Calta (Bony fish)	Shark (Cartilaginous fish)
(a) Mouth is terminal	Mouth is ventral
(b) Air bladder present	Air bladder absent
(c) Cycloid scales	Placoid scales
(d) External Fertilization	Internal Fertilization

Question 29.
Prepare a list of some animals that are found parasitic on human beings.
Answer:
Tapeworm (Taenia), Ascaris (Roundworm), Wuchereria (Filaria worm), Ancylostoma(Hookworm)

Question 30.

1. Identify the 2 forms of Cnidarians.
2. Mention any 2 difference between them.

Answer:

1. A – polyp
   B – medusa
2. Polyp: Asexual, sessile, mouth upwards Medusa: Sexual, Free swimming, Mouth downwards

Plus One Animal Kingdom Three Mark Questions and Answers

Question 1.
Classify the given organisms and arrange them in the order of their phylum.
Limulus, Corvus, Spongilla, Ascaris, Physalia, Nereis, Catla, Sepia, Echinus, Taenia, Pleurobrachia, Tiger, Viper, Toad.
Answer:

Non chordata	Chordata
Limulus – Arthropoda	Corvus
Spongilla – Porifera	Catla
Ascaris – Aschelminthes	Tiger
Physalia – Cnidaria	Viper
Nereis-Annelida	Toad
Sepia – Mollusca
Echinus – Echinodermata
Taenia – Platyhelminthes
Pleurobrachia – Ctenophora

Question 2.
Match the following.

(a) Operculum	i. Ctenophora
(b) Parapodia	ii. Mollusca
(c) Scales	iii. Porifera
(d) Comb plates	iv. Reptilia
(e) Radula	v. Annelida
(f) Hairs	vi. Cyclostomata
(g) Choanocytes	vii. Mammalia
(h) Gill slits	viii. Osteichthyes

Answer:

(a) Operculum	viii. Osteichthyes
(b) Parapodia	v. Annelida
(c) Scales	iv. Reptilia
(d) Comb plates	i. Ctenophora
(e) Radula	ii. Mollusca
(f) Hairs	vii. Mammalia
(g) Choanocytes	iii. Porifera
(h) Gill slits	vi. Cyclostomata

Question 3.
Observe the diagram

1. Identify the phylum of this hypothetical organism.
2. List out the features that helps in identifying it.
3. Write about the fate of notochord in Urochordata, Cephalochordata and Chordata.

Answer:

1. Chordata
2. Notochord, Dorsal nerve cord, Pharyngeal gill slits, Post anal tail
3. In Urochordatarfiotochond is present only in larval tail. In Cephalochondata, notochord extends from head to tail region is persistent throughout their life. In vertebrata, the notochord is replaced by a cartilagenous or bony vertebral column in the adults.

Question 4.
Select the following items into their appropriate phylum.
Radula, Parapodia, Comb plate, Nephridia, Choanocytes, Flame cells.
Answer:

• Radula – Mollusca
• Parapodia – Annelida
• Comb plate – Ctenophora
• Nephridia – Annelida
• Choanocytes – Porifera
• Flame cells – Platyhelminthes

Question 5.

(a) Fill and complete the chart given below.

(b) Write any two fundamental characters of the phylum chordata.
(c) Classify Tetrapoda into classes:
Answer:
Male accessory ducts store and transport the sperms from testis to the outside through urethra. Male accessory glands secrete seminal Plasma, Which is rich in fructose, citrate, prostaglandins and certain enzymes. The secretion of cowper’s glands lubricate the penis.

Question 6.
Write down the functions of the following (any two) structures and assign their phyla.

1. Radula
2. Flame cells
3. Parapodia

Answer:

1. Radula: File like rasping organ for feeding.
   Phylum: Mollusca
2. Flame cells: Osmoregulation and excretion
   Phylum: Platyhelminthes
3. Parapodia: help in swimming
   Phylum: Annelida

Question 7.
1. Identify the organism A and B.

2. Which features of these organism enable you to identify them?
Answer:

1. A-Tapeworm
   B – Earthworm
2. Features of these organism:
   • Tapeworm: Scolex is present, suckers and hooks are present. No true segmentation.
   • Earthworm: True segmentation, Absence of Scolex, hook and suckers, Clitellum is present.

Question 8.

1. Which of the following animals exhibit metagenesis? (Ascaris Obelia Earthworm Crab)
2. To which phylum does it belong?
3. Write any two features of the phylum.

Answer:

1. Obelia
2. Cnidaria
3. Two features of the phylum:
   • Presence of Cnidoblasts
   • Cnidarians exhibit two basic forms called polyp and medusa.

Question 9.
Pick out the appropriate one from the term given within bracket and put against the corresponding phylum.

1. Porifera
2. Coelenterata
3. Platyhelminthes
4. Annelida
5. Arthropoda
6. Mollusca
7. Echinodermata
8. Chordata

(Hirudin, Flame cell, Choanocytes, Cnidoblast, Jointed legs, Radula, Notochord and Dermal Ossicles)
Answer:

1. Porifera – Choanocytes
2. Coelenterata – Cnidoblast
3. Platyhelminthes – Flame cells
4. Annelida – Hirudin
5. Arthropoda – Jointed legs
6. Mollusca – Radula
7. Echinodermata -Dermal ossicles
8. Chordata – Notochord

Question 10.

 

1. Identify the organism (A) and (B) and which class do they belong?
2. On which basis do you classify these animals?

(Hint: Write any 2 Identifying characters)
Answer:

1. Organism in (A) and (B)
   • A – Bony fish – Osteichthyes
   • B – Cartilagenous fish – Chondrichthyes

2.

Osteichthyes	Chondrichthyes
Mouth is terminal	Mouth is ventral
Operculum is present	Operculum absent

Question 11.
From a fish market, you got a fish, on a close watching you friend says it is a cartilaginous fish.

1. Which characters helped him to identify it as a cartilaginous fish, (any four characters.)
2. Name the class it belongs.

Answer:

1. Characters:
   • a – Gillslits are separate and without operculum
   • b – Placoidscale
   • c – Mouth is located ventrally
   • d – heterocercal caudal fin
2. Chondrichthyes

Question 12.
Presence or absence of a cavity between the body wall and the gut wall is very important in classification.

 

1. Identify the different types of body cavities.
2. Give examples to each

Answer:

1. Different types of Body Cavities:
   • a – Coelomate
   • b – Pseudocoelomate
   • c – Acoelomate
2. Examples:
   • Coelomate – Chordates
   • Pseudocoelomate – Aschelminthes
   • Acoelomate – Platyhelminthes

Question 13.
From the following general characters find out corresponding/Class with an Example

1. Exclusively marine, triploblastic, spines on the skin, radially symmetrical in the adult and bilaterally symmetrical in the larval stage.
2. Marine, they migrate towards freshwater for spawning, then their larvae return to ocean after metamorphosis.
3. Triploblastic, bilaterally symmetrical, coelomate and metamerically segmented animals.

Answer:

1. Echinodermata
   • eg: Starfish
2. Class – Cyclostomata
   • eg: Petromyzon
3. Annelida
   • eg: Earthworm

Question 14.
Arrange the following points in a two-column table and give suitable heading for each column.

1. Notochord present
2. Post anal tail absent
3. Pharynx Perforated by gill slits
4. Notochord absent
5. Posts anal tail present
6. Gill slits are absent

Answer:

Chordata	Non Chordata
Notochord present	Post anal tail present
Pharynx perforated by gill slits	Notochord absent
Post anal tail present	Gill slits absent

Question 15.
Observe the figure and answer the questions.

1. Identify the structure.
2. Name the phylum which possess this structure.
3. How this structure help the organism?

Answer:

1. Cnidoblastornematocyst
2. Cnidaria
3. Capture of Prey
   • Defense organ.

Question 16.
Note the relationship between first two words and suggest suitable words for the 4th place.

1. Planaria: Flartfe cells: Earthworm: _________
2. Jaw present: Gnathostomata:: Jaw absent: ___________

Answer:

1. Nephridia
2. Agnatha

Question 17.
Give reasons for the following.

1. Respiratory and circulatory system are absent in parasitic platyhelminthes and Aschelminthes.
2. Arthropods are the most successful invertebrate.
3. Body of endoparasites are covered with cuticle.

Answer:

1. Parasitic Plalyhelminthes and Aschelminthes lives in anaerobic condition. So respiratory and circulatory systems are absent in these parasitic forms.
2. Arthropods are most successful, because of the presence of unique chitinous cuticle.
3. In these parasites, the cuticle helps in escaping from the action of digestive enzymes.

Question 18.
Arthropodes are organisms with chitinous exoskeleton. Suppose exoskeleton is absent in arthropods. List the difficulties arthropodes has to face.
Answer:

1. Their body will be dried up due to evaporation
2. They couldn’t escape from predators.
3. They couldn’t live in all environments.

Question 19.
Suppose during your field visit for collection from a rocky seashore you have got some live specimens such as sea urchin, sea cucumber, sea anemone. Is it possible to keep them on an aquarium in your school. Give reasons for your answer.
Answer:
No. It is not possible.
Marine animals cannot live on freshwater because it leads to endosmosis and death occurs.

Question 20.

1. Why nematocysts are more concentrated on the oral end and tentacles of cnidarians?
2. What are the difficulties that coelenterate have to face if nematocysts were absent in body.

Answer:

1. Nematocysts are concerned with defence and offence. Tentacles are usually used for defence, offence and food collection. Hence nematocysts are more concentrated in the oral end.
2. The major difficulties cnidarians has to face in the absence of nematocysts are for food collection and escaping from enemies.

Question 21.

1. Which of the following show the body cavity of earthworm?
2. Identify the names of germlayers ‘a’ and ’b’.

 

Answer:

1. Figure C is the body cavity of earthworm. Because it is a true coelom
2. The names of germlayers
   • a-ectoderm
   • b-endQderm

Question 22.
Identify the characters listed below and put (✓) mark on appropriate places

Answer:

Question 23.

1. Identify the organisms.
2. Which feature of these organisms enable you to identify them?

Answer:

1. The organisms:
   • A-Tape worm
   • B – Ascaris
   • C – Earthworm
2. Features:
   • Tapeworm – Body is dorso-ventrally flattened and segmented.
   • Ascaris – Body is cylindrical and vermiform
   • Earthworm – Body is divided into similar segments and clitellum is present.

Question 24.
During a classroom discussion a student said that sponges are more complex than cnidarians. Do you agree with him. Jusftfy.
Answer:
1. Sponges: Cellular grade of organisation and cell aggregate body plan.

2. Cnidarians: Tissue level of organisation and blind sac body plan. So Cnidarians are more complex than sponges.

Question 25.
While comparing the digestive system of a roundworm and flatworm, a boy noted some differences. List out the differences.
Answer:
1. Flatworms: Digestive system incomplete, has only a single opening, ingestion and egestion occurs through the same opening.

2. Round worm: Complete digestive system, it has both mouth and anus. A muscular pharynx is also present in their digestive system.

Question 26.

1. Identify the invertebrate whose mouth is on ventral or lower side and anus is on dorsal or upper side.
2. Mention the phylum.
3. Comment on its General characters.

Answer:

1. Starfish
2. Echinodermata
3. Its General characters are:
   • Water vascular system
   • Tube feet
   • Coelomate
   • Spiny body

Question 27.
Match the following.

Answer:

• Arthropoda – Bombyx – Joint footed animals
• Annelida – Earthworm – Little rings
• Echinodermata – Antedon – Spiny bodies animals
• Mollusca – Pila – Soft bodies animals

Question 28.
Animals showing metameric segmentation are included under annelida. Body of tapeworm has numerous segments, but the animal is not included under annelida. How will you account for it?
Answer:
Tapeworm show false segmentation. In true segmentation number of segments is fixed and age of the segments are all same.

Question 29.
Complete the given flow chart showing the flow of water through canal system in sponges.

Answer:

Question 30.
Mention a single word for the following.

1. Sexes are not separate.
2. Body wall with three layers.
3. File like rasping organs in Mollusca.
4. Segmentation of animal body.
5. The property of a living organism to emit light.
6. Alternation of generation in Cnidarians.

Answer:

1. Hermaphrodite
2. Triploblastic
3. Radula
4. Metamerism
5. Bioluminescence
6. Metagenesis

Question 31.
The birds are well adapted for flying.

1. Write the general characters of Aves.
2. Give some of the flight adaptations seen in birds.

Answer:

1. General characters of Aves:
   • Presence of feathers
   • Presence of beak
   • Forelimbs are modified into wings.
   • Warm blooded
   • Respiration by lungs with air sacs.
   • Oviparous
2. Flight adaptations:
   • Forelimbs are modified into wings
   • Long bones are hollow with air cavities (Pneumatic)
   • Air sacs connected to lungs supplement respiration
   • Constant body temperature

Plus One Animal Kingdom NCERT Questions and Answers

Question 1.
What is the difference between direct and indirect development?
Answer:
1. Direct Development:
In direct development the young animal resembles an adult. There is no intermediate stage.

2. Indirect Development:
In indirect development there is intermediate stage, like larval stage. For example, frog before being developed into adult passthrough a tadpole stage. This is the case of indirect development.

Question 2.
What are the peculiar features that you find in parasitic platyhelminthes?
Answer:
In parasitic platyhelminthes hooks and suckers are present. Suckers help the parasite, in sucking the blood from the host.

Question 3.
What are the reasons that you can think of for the arthropods to constitute the largest group of the animal kingdom?
Answer:
Arthropods are the first phylum to have well developed systems to carry out different activities. There is distinct system for respiration, locomotion and reproduction. Their survival capacity is great because of elaborate system. This has helped them survive in diverse conditions. They can live in water, on land and in air.

This can be one of the reasons why arthropods are the largest group among the animal kingdom. Another reason is their early development compared to animals of higher phylum.

Question 4.
Water vascular system is the characteristic of which group of the following:
(a) Porifera
(b) Ctenophora
(c) Echinodermata
(d) Chordata
Answer:
(c) Echinodermata

Question 5.
“All vertebrates are chordates but all chordates are not vertebrates”. Justify the statement.
Answer:
All chordates have notochord present in some stage of life.
The difference between vertebrates and nonvertebrates is as follows:
In vertebrates the notochord is present in the embryonic stage. This is replaced by a vertebral column during the adult stages.

Question 6.
How important is the presence of air bladder in Pisces?
Answer:
Presence of air-bladder in Pisces helps in buoyancy. This means that members of pisces don’t have to keep on swimming to remain floating.

Question 7.
What are the modifications that are observed in birds that help them fly?
Answer:
Following modification in birds help them fly:

1. Pneumatic or hollow bones make for a light weight skeleton.
2. Fore limbs are modified into wings to assist in flight.
3. Excertion of urine and faeces is through single opening facilitating weight reduction.
4. Aerodynamic body helps in flying.

Question 8.
Could the number of eggs or young ones produced by an oviparous and viviparous mother be equal? Why?
Answer:
Usually number of eggs produced by oviparous mothers is greater than number of young ones produced by viviparous mothers. The main reason for this is the need of resources required for development of the embryo.
In oviparous the major part of development of the embryo takes place outside the uterus. This makes lesser burden on the mother.

On the other hand in viviparous animals the development takes place inside the uterus so lesser number of young ones can be successfully incubated. Moreover, once eggs are outside they are at risk of getting eaten by some predator because of their immobility, so need of more eggs is there to ensure continuity of progeny.

Plus One Animal Kingdom Multiple Choice Questions and Answers

Question 1.
Calcareous skeleton is found in
(a) echinoderms
(b) some sponges
(c) mollusca
(d) all the above
Answer:
(d) all the above

Question 2.
Which cannot be the character of cnidaria
(a) musculoepithelial cells
(b) gastrovascular cavity
(c) nerve cells and process
(d) organ grade organization
Answer:
(d) organ grade organization

Question 3.
A non-matching set in the following is
(a) sepia – cuttle fish
(b) octopus – devilfish
(c) limulus – king crab
(d) ancylostoma – pinworm
Answer:
(d) ancylostoma – pinworm

Question 4.
A character common to Echinoderms and chordates
(a) marine
(b) benthonic
(c) deuterostome
(d) none of the above
Answer:
(c) deuterostome

Question 5.
Largest animal in the world that feed on smallest plankton is the
(a) dolphin
(b) killer whale
(c) blue whale
(d) sea cow
Answer:
(c) blue whale

Question 6.
Which is common to amphibian, reptelia and fishes
(a) nucleated RBC
(b) dermal scales
(c) poikelothermic condition
(d) both a and d
Answer:
(d) both a and d

Question 7.
Which of the following has pseudocoelomate tube within a tube body plan
(a) hydra
(b) planaria
(c) ascaris
(d) pheretima
Answer:
(c) ascaris

Question 8.
Ink gland associated with alimentary canal is found in
(a) sepia
(b) earthworm
(c) starfish
(d) cockroach
Answer:
(a) sepia

Question 9.
Which is common to all tetrapods
(a) epidermal scales
(b) red coloured blood
(c) 12 pairs of cranial nerve
(d) ureotelism
Answer:
(b) red coloured blood

Question 10.
Which one of the following is not a characteristic of phylum annelida?
(a) closed circulatory system
(b) segmentation
(c) pseudocoelom
(d) ventral nerve cord
Answer:
(c) pseudocoelom

Question 11.
Respiratory pigment of mollusc is
(a) haemocyanin
(b) haemoglobin
(c) haemoerythrin
(d) both a and b
Answer:
(a) haemocyanin

Question 12.
Select the character that can be attributed to chondrithytes
(a) persistened notochord
(b) placoid scales
(c) poikelothermic body
(d) all the above
Answer:
(d) all the above

Question 13.
The central cavity of sponge is called
(a) spongocoel
(b) coelocentron
(c) canal system
(d) spongilla
Answer:
(c) canal system

Question 14.
Flame cell are excretory organ of
(a) hydra
(b) cockroach
(c) planaria
(d) frog
Answer:
(c) planaria

Question 15.
Pneumatic skeleton is a feature of
(a) amphibians
(b) reptiles
(c) fishes
(d) birds
Answer:
(d) birds

Question 16.
The number of gills present in osteichthyes is
(a) 2 pairs
(b) 6-15 pairs
(c) 5 pairs
(d) 4 pairs
Answer:
(d) 4 pairs

Students can Download Chapter 3 Structural Organisation in Animals Questions and Answers, Plus One zoology Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Zoology Chapter Wise Questions and Answers Chapter 3 Structural Organisation in Animals

Plus One Structural Organisation in Animals One Mark Questions and Answers

Question 1.
Which one of the following types of cell is involved in making of the inner walls of large blood vessels?
(a) Cuboidal epithelium
(b) Columnar epithelium
(c) Squamous epithelium
(d) stratified epithelium
Answer:
(c) Squamous epithelium

Question 2.
To which one of the following categories does adipose tissue belong?
(a) Epithelial
(b) Connective
(c) Muscular
(d) Neural
Answer:
(b) Connective

Question 3.
Which one of the following is not a connective tissue?
(a) Bone
(b) Cartilage
(c) Blood
(d) Muscles
Answer:
(d) Muscles

Question 4.
Which one of the following statements is true for cockroach?
(a) The number of ovarioles in each ovary are ten.
(b) The larval stage is called caterpillar
(c) Anal styles are absent in females
(d) They are ureotelic
Answer:
(c) Anal styles are absent in females

Question 5.
Match the following with reference to Cockroach and choose the correct option.

A. Phallomere	i. Chain of developing ova
B. Gonopore	ii. Bundles of sperm
C. Spermatophore	iii. Opening of the ejaculatory dust
D. Ovarioles	iv. The external genitalia

(a) A – iii, B – iv, C – ii, D – i
(b) A – iv, B – iii, C – ii, D – i
(c) A – iv, B – ii, C – iii, D – i
(d) A – ii, B – iv, C – iii, D – i
Answer:
(b) A – iv, B – iii, C – ii, D – i

Question 6.
Complete the following sentences:

1. The most common species of frog found in India is
2. Blood Vascular system of cockroach is

Answer:

1. Ranatigrina
2. Open

Question 7.
Name the respiratory organs of insects.
Answer:
Trachea

Question 8.
Note the relationship between the first two words and suggests a suitable word.

1.  Dendrons: Dendrites
   Axon: _________
2. Mast cells: Histamine
   Fibroblast: ________

Answer:

1. Myelin sheath
2. Fibres

Question 9.

1. Which among the following is the bone cell _____________.
   (Leucocyte, Chondrocyte, Osteocyte, Thrombocyte)
2. In earthworm, segments 14-16 are covered by a prominent dark band of glandular tissue called __________. (Setae, Clitellum, Typlosol, None of these)

Answer:

1. Osteocyte
2. Clitellum

Question 10.
‘Neuroglia make up more than one half the volume of neural tissue in our body’. Write the function of neuroglial cells.
Answer:
Neuroglia cells protect and support neurons in our neural system.

Question 11.
From the following segments, find out the segments in which, Clitellum is situated in a mature earthworm.
(a) 12-16
(b) 14 -16
(c) 10-14
(d) 16-18
Answer:
(b) 14 -16

Question 12.
Name the cells present in areolar tissue.
Answer:
Fibroblasts, Macrophages, Mast cells

Question 13.
_____________ make up more than one half the volume of neural tissue in our body.
Answer:
Neuroglia

Question 14.
Given below are different types of epithelial tissues. Find out the tissue that are present in the tubular parts of nephrons in kidneys.
Answer:
Cuboidal

Question 15.
Heart is made of
1. Epithelial tissue and Muscular tissue.
2. Muscular tissue and neural tissue.
3. Musculartissue and connective tissue.
4. All the four types of tissues.
Answer:
4. All the four types of tissues.

Question 16.
Write the cellular components of blood.
Answer:
Red blood cells (RBC), White blood cells (WBC) and platelets.

Question 17.
In earthworm, setae are absent in the segments.
(a) First and last
(b) Clitellum only
(c) First, last and clitellum
(d) Peristomium and Clitellum
Answer:
(c) First, last and Clitellum.

Question 18.
Intestine of earthworm contain a special organ which help in absorption. Identify the organ.
Answer:
Typhlosole

Question 19.
Name the structures which help in locomotion in Earthworm.
Answer:
Setae

Question 20.
In cockroach the fertilized eggs are encased in capsule called __________
Answer:
Oothecae

Plus One Structural Organisation in Animals Two Mark Questions and Answers

Question 1.
Regarding the blood vascular system of frog, some statements are given below. Check whether these are True or False and make corrections if necessary.

1. Open type.
2. Sinus venosus join the right atrium.
3. RBC is non-nucleated.
4. Circulation is achieved by the pumping action of the heart.

Answer:

1. False – Closed type
2. True
3. False – RBC is nucleated
4. True

Question 2.
You are given two cockroaches and the teacher asked to display the mouthparts of male cockroach.

1. How will you identify the male cockroach
2. Name the mouthparts of cockroach.

Answer:

1. In males styles are present and the abdomen is narrow and V shaped. In females abdomen is broad and anal styles are absent.
2. Labrum, mandibles, Hypopharynx, maxilla and Labium.

Question 3.
Give one word for the following.

1. Tissue attach one bone to another.
2. The structures protect and support neurons in neural system.

Answer:

1. Ligaments
2. Neuroglial cell

Question 4.
Match the following.

A	B
Cuboidal epithelium	Fallopian tube
Squamous epithelium	Ducts of glands
Columnar epithelium	alveoli
Ciliated epithelium	intestine

Answer:

A	B
Cuboidal epithelium	Ducts of glands
Squamous epithelium	alveoli
Columnar epithelium	intestine
Ciliated epithelium	Fallopian tube

Question 5.
Copy the diagram and label the numbered parts.

Answer:

1. Pharynx
2. Gizzard
3. Intestinal caecum
4. Typhlosole

Question 6.
Observe the diagram

1. Name the above connective tissue. Where they found in our body?
2. Name any two principle cell found in it.

Answer:

1. Areolar connective tissue, present beneath the skin.
2. Fibroblast and macrophage

Question 7.
Observe the pool of connective tissues carefully. Classify them under three headings.

Answer:

Question 8.
Anatomical structures of 3 animals are given below. Identify the 3 animals and arrange the structures into 3 separate groups.  (Typhlosole, Malpighian tubules, Blood glands, Cloaca, Phallic gland, Kidney, Collateral Gland)
Answer:

Question 9.
Copy the diagram and label the numbered parts.

Answer:

1. Testis
2. Vasa efferentia
3. Fat bodies
4. Urino genital duct

Question 10.
Match the following.

Column A	Column B
Haemocoelom	Frog
Typhlosole	Frog
Cloaca	Earthworm
Pseudocoelom	Cockroach

Answer:

Column A	Column B
Haemocoelom	Cockroach
Earthworm	Earthworm
Cloaca	Frog
Pseudocoelom	Ascaris

Question 11.
Name the labeled parts A, B in the diagram given below

Answer:
A. Chondocyte

B. Collagen fibers

Question 12.
Circulating fluid of cockroach is colourless.

1. Name the circulating fluid.
2. Name the cell concerned in it.

Answer:

1. hemolymph
2. hemocytes

Question 13.
Match the following:

A	B
Intestinal mucosa	Skeletal muscle
Biceps muscle	Smooth muscle
Tendon	Brush bordered columnar epithelium
Intestinal muscle	Connective tissue

Answer:

A	B
Intestinal mucosa	Brush bordered columnar epithelium
Biceps muscle	Skeletal muscle
Tendon	Connective tissue
Intestinal muscle	Smooth muscle

Question 14.
Give one word for the following.

1. Tissue specialised to store fats.
2. Tissue contains fibroblasts, macrophages and mast cells.
3. Tissue attach skeletal muscles to bones.

Answer:

1. Adipose tissue
2. Areolar tissue
3. Tendons

Question 15.
You are given permanent slides of a bone and cartilage. How will you identify them using a microscope.
Answer:

1. Bone: Presence of Haversian system.
   Presence of Haversian canal in the centre.
2. Cartilage: Matrix contain spaces called lacunae.
   Lacunae contain chondrocyte.

Question 16.
Frogs maintain ecological balance. As a biological student do you agree with this statement? Why?
Answer:
Frogs maintain ecological balance because they serve as an important link of food chain and food web in the ecosystem.

Question 17.
Ratheesh mounted the mouthparts of cockroach in the following manner. If there is any error, correct it.

Answer:
A) Labium
B) Labrum
C) Mandibles
D) Hypopharynx
E) Maxilla.

Question 18.
Observe the diagram given below and label the parts
A, B, C, D.

Answer:
A – Liver
B – Stomach
C – Intestine
D – Rectum

Question 19.
While viewing the fallopian tube through CT scan we can find large number of cilia.

1. Identify the tissue present in the fallopian tube.
2. Mention the function of cilia.

Answer:

1. Ciliated epithelium
2. Ovum is moved by the help of cilia.

Question 20.
‘An earthworm respires through skin and excretes through nephridia’ Rewrite the above sentence beginning with ‘A cockroach ………………..’ making appropriate
changes.
Answer:
A cockroach respires through trachea and excretes through malpighian tubules.

Question 21.
Match the following

i	ii
Hypopharynx	Food grinding
Nephridium	Food absorption
Gizzard	Bone cell
Typhlosole	Phallomere
Osteocyte	Tongue
Genitalia	Earthworm
	Frog

Answer:

i	ii
Hypopharynx	Tongue
Nephridium	Earthworm
Gizzard	Food grinding
Typhlosole	Food absorption
Osteocyte	Bone cell
Genitalia	Phallomere

Question 22.
Identify the diagram and label the part marked A.

Answer:
Frog female reproductive system Part A is Oviduct

Question 23.
Observe the given diagram.

1. Identify X and Y.
2. Write any two characters of X and Y.

Answer:

1. X – Striated muscle
   Y – Cardiac muscle
2. Striated muscle – Skeletal muscle, voluntary muscle, striations present Cardiac muscle – Muscles of heart, branched muscle fibres, intercalated disc.

Question 24.
Observe the table given below and fill in the blanks from the list given below:
(Pancreas, Liver, Salivary gland, Tear gland, Adrenal gland, Thyroid gland)

Answer:

Question 25.
There are some physiological similarities between typhlosole and villi. Substantiate your answer.
Answer:
Both typhlosole and villi are part of intestine of earthworm and human beings respectively. Typhlosole and villi increase the effective area of absorption in the intestine.

Question 26.
Observe the given diagrams.

1. Identify A and B.
2. Write any one function of each.

Answer:

1. A – Non-striated muscle (smooth muscle)
   B – Ciliated epithelium
2. A – Found in the wall of internal organs and concerned with the movement of these organs. B – Ciliated epithelium is to move particles or mucus in a specific direction over the epithelium.

Question 27.
Write the significance of

1. Blood
2. Neuroglia

Answer:

1. Blood – The main circulating fluid that help in the transport of various substances.
2. Neuroglia – Protect and support neurons. Neuroglia make up more than one half the volume of neural tissue in our body.

Question 28.
Classify the given terms into three columns and give appropriate headings.
Striated, heart muscle, intercalated disc, biceps, visceral organs, no striation.
Answer:

Question 29.
Where do you find the following structures in human body.

1. Chondrocytes
2. Axon
3. Osteocytes
4. Plasma

Answer:

1. Cartilage
2. Neuron
3. Bone
4. Blood

Question 30.
Write the suitable world for the 4^th place.

1. Muscle to bone – Tendon; Bone to Bone – _____________
2. Bone – osteocytes; Cartilage – __________
3. Cardiac Muscle – Involuntary; Striated Muscle – __________
4. Contractile cell – Muscle; Excitable cell – ______________

Answer:

1. Ligament
2. Chondrocytes
3. Voluntary
4. Neuron

Question 31.
Give an account on Nephridia of earthworm.
Answer:
Excretory organs in earthworm is nephridia. There are three types:

1. Septal nephridia: Present on both the sides of intersegmental septa of segments 5 to the last that open into intestine.

2. Integumentary nephridia: attached to lining of the body wall of segment 3 to the last that open on the body surface.

3. Pharyngeal nephridia: present as three paired tufts in the 4^th, 5^th, and 6^th segments.

Question 32.
Flow chart showing flow of food through the alimentary canal of an earthworm given. Correct the flow chart if there is any mistake.
Mouth→Pharynx → Stomach → intestine → Gizzard → Oesophagus.
Answer:
Mouth → Pharynx → Oesophagus → Gizzard → Stomach → Intestine

Question 33.
Match the following.

Bidder’s canal	Cockroach
Labium	Earthworm
Typhlosole	Frog

Answer:

Bidder’s canal	Frog
Labium	Cockroach
Typhlosole	Earthworm

Question 34.
You are given an earthworm for dissection, how will you identify its anterior, posterior, dorsal and ventral sides.
Answer:
The dorsal surface of the body is marked by a dark median mid dorsal line along the longitudinal axis of the body. The ventral surface is distinguished by the presence of genital openings. Anterior end consists of the mouth and the prostomium. The posterior end is slightly rounded.

Question 35.
Blood cell of earthworm lack hemoglobin. But blood of earthworm is red in colour. How do you account for it?
Answer:
Blood cell of earth worm lack hemoglobin. But blood of earthworm is red in colour because hemoglobin is dissolved in blood plasma.

Question 36.
Match the related items from B and C with Column A.

Answer:

Question 37.
Copy and complete the animals on the table and the excretory organs.

Animals	Excretory organs
Earthworm	_______________
________________	Malpighian tubules
Frog	________________

Answer:

Animals	Excretory organs
Earthworm	Nephridia
Coackroach	Malpighian tubules
Frog	Kidney

Question 38.
Identify the animals from the hints given below.

1. Invertebrate, Burrowing in moist soil, Nephridia, Genital pore.
2. Chordata, Amphibian, Kidney, Cloaca
3. Invertebrate, Insecta, Malpighian tubules, gonapophysis.

Answer:

1. Earthworm
2. Frog
3. Cockroach

Question 39.
Identify the statements as True or False.

1. First segment of earthworm is Prostomium.
2. Peristomium contain mouth.
3. Clitellum is on segments 14-16.
4. Earthworm has only a single female genital aperture.

Answer:

1. False (First segment is peristomium)
2. True
3. True
4. Tare

Question 40.
Earthworm feeds on humus, which contain large amount of humic acid.

1. How does the earthworm neutralises the humic acid?
2. Name the region of alimentary canal where humic acid is neutralised.

Answer:

1. Calciferous gland, present in the stomach, neutralise the humic and present in humus.
2. In stomach.

Question 41.
Write a note on typhlosole.
Answer:
The special structure present in the intestine of earthworm between 26-35 segment is called typhlosole. It is an internal median fold of dorsal wall of intestine. Typhlosole increases the effective area of absorption in the intestine.

Question 42.
Blood glands are important in earthworm. Give reason.
Answer:
Blood glands are present on the 4^th, 5^th and 6^th segments of earthworm. They produce blood cells and hemoglobin which is dissolved in blood plasma.

Question 43.
Earthworm is a hermaphrodite animal. Where are its sex organs situated?
Answer:
Two pairs of testes present in the 10^th and 11^th segments. One pair of ovaries is attached at the inter-segmental septum of the 12^th and 13^th segment.

Question 44.
Earthworms are known as ‘Friends of farmers’. Give reason.
Answer:
Earthworms are known as ‘friends of farmers’ because they make burrows in the soil and make it porous which helps in respiration and penetration of the developing plant roots. The process of increasing fertility of soil by the earthworm is called vermicomposting. They are also used as bait in the game fishing.

Question 45.
Write the missing word in 4^th place.

1. Dorsally – Tergites; Ventrally – ……………
2. Earthworm – Nephridia; Cockroach – …………….

Answer:

1. Stern items
2. Malpighian tubules

Question 46.
Cockroach show sexual dimorphism. Write any two morphological differences between male and female cockroaches.
Answer:

1. In females, the 7^th sternum is boat-shaped and there is presence of a brood pouch.
2. In males, there is presence of anal style and genital pore in the 9^th segment.

Question 47
While dissecting a cockroach to display its digestive system, a student observed certain thick white tubules. Teacher explained it as part of respiratory system.

1. Name the tubules.
2. Draw a flow chart showing the flow of air through this system.

Answer:

1. Tracheal tubules
2. Spiracle → Trachea → Tracheoles → Tissue

Question 48.

1. Identify the diagram given below.
2. Label the parts a to e.

answer:

1. Digestive system of cockroach
2. parts from a to e
   • a – Oesophagus
   • b – Crop
   • c – Hepatic caeca
   • d – Mesentrorr
   • e – Malpighian tubules

Question 49.
Blood of cockroach is colourless. Give reason.
Answer:
Blood of cockroach is composed of colourless plasma and hemocytes. No respiratory pigments present in the blood of cockroach. So blood is colourless.

Question 50.
Cockroach is uricotelic animal. Give reason.
Answer:
Cockroach excrete nitrogenous waste in the form of uric acid. So cockroach is known as uricotelic animal.

Question 51.
Name the four structure helps in excretion in cockroaches.
Answer:

1. Malpighian tubule
2. fat body
3. nephrocytes
4. urecose gland.

Question 52.
If the head of cockroach is cut off, it will still alive for as long as one week. Give reason.
Answer:
The head of cockroach holds a bit of a nervous system while the rest is situated along the ventral part of its body. So, if the head of cockroach is cut off it will still live for long as one week.

Question 53.
Name the sensory organs of cockroaches.
Answer:
Antennae, Compound eyes, anal cerci, maxillary palps, Labial palps.

Question 54.
Compound eyes are more effective than vertebrate eye. Give reason.
Answer:
Each compound eyes in cockroach consists of about 200 ommatidia. With the help of several ommatidia, a cockroach can receive several images of an object. This kind of vision is known as mosaic vision. Compound eye is more effective than vertebrate eye because it can detect the movement of other animals more easily and efficiently.

Question 55.
Frog show sexual dimorphism. Write the morphological difference present only in male frog.
Answer:

1. Presence of vocal sacs
2. Presence of copulatory pad on the 1^st digit of the forelimb.

Question 56.
Prepare a flow chart showing the flow of food in the alimentary canal of frog. Compare it with alimentary canal of cockroach.
Answer:
1. In frog:
Mouth → oesophagus → stomach → Intestine → Rectus → Cloacal aperture

2. In coackroach:
Mouth → Oesophagus → Crop → Gizzard → Mesentron → ileum → Colon → Rectum → Anus

Question 57.
Cloaca is a common opening of 3 tubes or tracts.

1. Name the tracts which opens to cloaca.
2. Name the animal which possess cloaca.

Answer:

1. Tracts which opens to cloaca
   • Alimentary canal
   • Urinary canal
   • Reproductive tract
2. Frog

Question 58.
Name the portal systems found in frog

1. Between liver and intestine.
2. Between kidney and lower parts of the body.

Answer:

1. Hepatic portal system
2. Renal portal system

Question 59.

1. Frog is ureotelic animal. How?
2. Name the different parts of the excretory system- off rog.

Answer:

1. Frog excrete nitrogenous waste in the form of urea. So they are called ureotelic animal,
2. A pair of kidneys, ureters, cloaca and urinary bladder.

Question 60.
Answer in one word.

1. Covering of eyes in frog.
2. Number of cranial nerves in frog.
3. Membranous covering of Heart of frog.
4. Brain of frog is enclosed in a bony structure named ____________
5. Larval stage of frog.

Answer:

1. Nictitating membrane
2. Ten pairs
3. Pericardium
4. Cranium
5. Tadpole

Question 61.
Frogs are beneficial for mankind. Justify.
Answer:
Frogs are beneficial for mankind because they eat insects and protect the crop. Frogs maintain ecological balance because these serve as an important link of food chain and food web in the ecosystem. In some countries the muscular legs of frog are used as food by man.

Plus One Structural Organisation in Animals Three Mark Questions and Answers

Question 1.
Compare the circulatory system and blood of frog with that of an earthworm.
Answer:
In Frog blood circulatory system is closed type. Frog have a lymphatic system also. Heart is three chambered – two atria and one ventricle. Blood is composed of plasma and cells. The blood cells are RBC, WBC and platelets. RBC’s are nucleated and contain red coloured pigment namely hemoglobin. In earthworm blood circulatory system is closed type.

Blood glands are present on the 4^th, 5^th and 6^th segments. They produce blood cells and hemoglobin. Hemoglobin is dissolved in the plasma. Blood cells are phagocytic in nature.

Question 2.
The mounting of mouthparts of cockroach are given below. If there is any error, correct it.

Answer:
a. Labrum
b. Mandible
c. Hypopharynx
d. Maxilla
e. Labium

Question 3.
Answer in one word or one line.

1. Give the common name of Periplaneta Americana.
2. How many spermathecae are found in earthworm?
3. What is the position of a ovaries in cockroach?
4. How many segments are present in the abdomen of cockroach.
5. Where do you find Malpighian tubules?
6. Development through nymphal stage.

Answer:

1. Cockroach
2. 4 pairs of spermathecae are located 6^th – 9^th segments.
3. 2^nd – 6^th abdominal segments
4. 10 segments
5. At the junction of midgut and hindgut.
6. Paurometabolous

Question 4.
“All glands in our body do not have ducts of their own.” Do you agree with this statement.

1. Justify your answer using example.
2. Name three types of cell junctions in the epithelium.

Answer:

1. No. There are two types of glands in our body. Exocrine gland and Endocrine gland.
   • Exocrine gland – ducted gland
     • eg: Salivary gland
   • Endocrine gland – ductless gland
     • eg: Thyroid gland
2. Three types of junctions:
   • Tight junction
   • Adhering junction
   • Gap junction

Question 5.
Observe the following diagram carefully.

1. Identify and compare two diagrams.
2. Mention its location and function.

Answer:

1. A – squamous epithelium
   B – Columnar epithelium
2. Its locations and functions are
   • Both squamous and columnar epithelium are simple epithelium. Squamous epithelium is made up of a single thin layer of flattened cells with irregular boundaries. The columnar epithelium is composed of a single layer of tall and slender cells.
   • Squamous epithelium is found in the walls of blood vessels and air sacs of lungs and are involved in the functions like forming a diffusion boundary.
     Columnar epithelium is found in the lining of stomach and intestine and help in secretion and absorption.

Question 6.
Compare the excretory System in Cockroach and Frog.
Answer:
1. Cockroach:
Excretion is performed by malpighian tubules. They absorb nitrogenous waste products and convert them into uric acid which is excreted out through the hind gut. Therefore, cockroach is called Uricotelic. In addition, the fat body nephrocytes and urecose gland also help in excretion.

2. Frog:
Excretory system consists of a pair of kidneys. Ureter, Urinary bladder and cloaca. Excretory wastes are carried by blood into the kidney where it is separated and excreted. The frog excrete urea and thus a ureotelic animal.

Question 7.
Mention the mode of respiration in a frog while it is

1. In water
2. On land
3. When under aestivation or hibernation.

Answer:

1. Gills
2. Lungs
3. Skin (cutaneous respiration)

Question 8.
Arrange the columns A, B, and C in the table below and match them properly.

Answer:

Question 9.
Give reasons.

1. Simple epithelium functions as lining for the body cavities, ducts, tubes etc. where as compound epithelium is protective in function.
2. Cockroach does not possess respiratory pigment.
3. Frog in ureotelic where as tadpole is ammonotelic.

Answer:

1. Simple epithelium is composed of a single layer of cells. The compound epithelium consists of two or more cell layers and has protective function.
2. Cockroach respiratory organ is trachea. These tracheal tubules carry oxygen from the air to all the parts of their body. So they does not require any respirations pigment.
3. Ammonotelism demands an excess of water in the body. Tadpole is aquatic and there is availability of large amount of water. So tadpole is ammonotelic. Whereas Ureotelism requires only a moderate quantity of water. Frog is semiaquatic. So frog is ureotelic.

Plus One Structural Organisation in Animals NCERT Questions and Answers

Question 1.
Answer in one word or one line:

1. Give the common name of Periplanata americana.
2. How many spermathecae are found in earthworm?
3. What is the position of ovaries in cockroach?
4. How many segments are present in the abdomen of cockroach?
5. Where do you find Malpighian tubules?

Answer:

1. Cockroach
2. 4 pair of spermathecae are found in earthworm
3. 2 large ovaries are found lying laterally in the 2^nd to the abdominal segment.
4. The abdomen of cockroach consists of 10 segments.
5. Malpighian tubules are the main excretory organs of the cockroach.

Question 2.
Answer the following:

1. What is the function of nephridia?
2. How many types of nephridia are found in earthworm based on their location?

Answer:

1. Nephridia is the excretory organ of the earthworm or pheretima.
2. There are three types of nephridia in the earthworm:
   • septal nephridia, present on both the sides of intersegmental septa of segment 15 to the last that open into intestine,
   • integumentary nephridia, attached to lining of the body wall of segment 3 to the last that open on the body surface and pharyngeal nephridia, present as three paired tufts in the 4^th, 5^th and the segments.

Question 3.
Distinguish between the following:

1. Prostomium and peristomium
2. Septal nephridium and pharyngeal nephridium

Answer:

1. Prostomium is the frontmost part of the earth-worm. This is not called a true segment as it doesn’t contain typical organs of an annelida. Peristomium is from where the true segment of the earthworm body starts.
2. Septal nephridia, present on both the sides of intersegmental septa of segment 15 to the last that open into intestine.

Pharyngeal nephridia, present as three paired tufts in the 4^th, 5^th and 6^th segments Both are same structurally and functionally.

Question 4.
What are the cellular components of blood?
Answer:
Red Blood Cells and White Blood Cells are the cellular components of the blood.

Question 5.
What are the following and where do you find them in animal body?

1. Chondriocytes
2. Axons
3. Ciliated epithelium

Answer:

1. Chondriocytes are cells of cartilage.
2. Axons it is the tail like structure of a neuron
3. Ciliated epithelium is found in the inner lining of bronchioles, Cilia help trap and clear dust and foreign particles.

Question 6.
Distinguish between

1. Simple epithelium and compound epithelium
2. Cardiac muscle and striated muscle
3. Dense regular and dense irregular connective tissues
4. Adipose and blood tissue
5. Simple gland and compound gland

Answer:

1. Simple epithelium is composed of one layer of cells, while compound epithelium is composed of more than one layer of cells.

2. Cardiac muscles are present in the cells of heat only. They have contractile property which helps in the pumping action of the heart. Striated muscles are present near articulatory joints. Their role is to facilitate movement of organs like hands and feet.

3. Dense Connective Tissue. Fibres and fibroblasts are compactly packed in the dense connective tissues. Orientation of fibres show a regular or irregular pattern and are called dense regular and dense irregular tissues. In the dense regular connective tissues, collagen fibres are present in rows between may parallel bundles of fibres.

Tendons, which attach skeletal muscles to bones and ligments which attach one bone to another are examples of this tissue. Dense irregular connective tissue has fibroblasts and many fibres (mostly collagen) that are oriented differently. This tissue is present in the skin.

4. Adipose tissue is a type of loose connective tissue located mainly beneath the skin. The cells of this tissue are specialised to store fats. The excess of nutrients which are not used immediately are converted into fats and are stored in this tissue. Blood is a fluid connective tissue. The main function of blood is to transport gases, nutrients and easte products in the body.

5. Simple gland is composed of single cell, while compound gland is composed of multiple cells.

Question 7.
Mark the odd one in each series:

1. Areolar tissue, blood, neuron, tendon
2. RBC, WBC, platelets, cartilage
3. Exocrine, endocrine, salivary gland, ligament
4. Maxilla, mandible, labrum, antennae
5. Protonema, mesothorax, metathorax, coxa

Answer:

1. Neuron is not a connective tissue
2. Cartilage is not part of blood
3. Ligament is not part of gland
4. Antennae is not a masticating part of cockroach
5. Protonema is thread like chain of cells, all others are about morphological structure of cockroach.

Plus One Structural Organisation in Animals Multiple Choice Questions and Answers

Question 1.
Carotene pigment is found in the cells of
(a) dermis
(b) epidermis
(c) adipose cell
(d) Both (b) and (c)
Answer:
(d) Both (b) and (c)

Question 2.
The lining of intestine and kidneys in human is
(a) keratinised
(b) brush bordered
(c) ciliated
(d) None of these
Answer:
(b) brush bordered

Question 3.
The type of cell junction, which facilitates cell to cell communication is
(a) tight junction
(b) adhering junction
(c) gap junction
(d) desmosomes
(e) brush borders
Answer:
(c) gap junction

Question 4.
Keratinised dead layer of skin is made up of
(a) stratified squamous
(b) simple cuboidal
(c) simple columnar
(d) stratified columnar
Answer:
(a) stratified squamous

Question 5.
Endothelium of blood vessels is made up of
(a) simple cuboidal epithelium
(b) simple squamous epithelium
(c) simple columnar epithelium
(d) simple non-ciliated columnar
Answer:
(b) simple squamous epithelium

Question 6.
In which one of the following preparations are you likely to come across cell junctions most frequently?
(a) Ciliated epithelium
(b) Thrombocyte
(c) Tendon
(d) Hyaline cartilage
Answer:
(a) Ciliated epithelium

Question 7.
Bowman’s glands are located in the
(a) proximal end of uriniferous tubules
(b) anterior pituitary
(c) female reproductive system of cockroach
(d) olfactory epithelium of our nose
Answer:
(d) olfactory epithelium of our nose

Question 8.
Compound squamous epithelium is found in
(a) stomach
(b) intestine
(c) trachea
(d) pharynx
Answer:
(d) pharynx

Question 9.
Find out the wrongly matched pair.
(a) Squamous epithelium – Skin of frog
(b) Columnar epithelium – Peritoneum of body cavity
(c) Ciliated epithelium – Bronchioles
(d) Stratified squamous – Oesophagus epithelium
(e) Glandular epithelium Salivary gland
Answer:
(b) Columnar epithelium – Peritoneum of body cavity

Question 10.
The type of tissue lining the nasal passage, bronchioles and fallopian tubes is
(a) columnar ciliated epithelium
(b) cuboidal epithelium
(c) neurosensory epithelium
(d) germinal epithelium
(e) stratified columnar epithelium
Answer:
(a) columnar ciliated epithelium

Question 11.
The nasal chamber of rabbit has three thin twisted bony plates called conchae. They are lined by
(a) striated cuboidal epithelium
(b) simple cuboidal epithelium
(c) simple squamous epithelium
(d) simple ciliated columnar epithelium
Answer:
(d) simple ciliated columnar epithelium

Question 12.
The cavities of alveoli of lungs are lined by
(a) cuboidal epithelium
(b) columnar epithelium
(c) stratified cuboidal epithelium
(d) squamous epithelium
Answer:
(d) squamous epithelium

Question 13.
The type of epithelial cells, which line the inner surface of fallopian tubes, bronchioles and small bronchi, are known as
(a) squamous epithelium
(b) columnar epithelium
(c) ciliated epithelium
(d) cubical epithelium
Answer:
(c) ciliated epithelium

Question 14.
Agranulocytes are
(a) lymphocytes and monocytes
(b) eosinophils and basophils
(c) lymphocytes and eosinophils
(d) basophils and monocytes
Answer:
(a) lymphocytes and monocytes

Question 15.
________ acts as a shock absorber to cushion when tibia and femur came together.
(a) Ligament
(b) Cartilage
(c) Tendon
(d) Disc
Answer:
(b) Cartilage

Question 16.
Erythropoiesis starts in
(a) kidney
(b) liver
(c) spleen
(d) red bone marrow
Answer:
(b) liver

Question 17.
Largest single mass of lymphatic tissue in the body is
(a) lung
(b) spleen
(c) liver
(d) kidney
Answer:
(b) spleen

Question 18.
Hypochronic microcytic anaemia and leucopenia are caused by the deficiency of respectively.
(a) pyridoxine and riboflavin
(b) pyridoxine and folacin
(c) biotin and folacin
(d) biotin and cyanocobalamin
Answer:
(b) pyridoxine and folacin

Students can Download Chapter 1 Sets Questions and Answers, Plus One Maths Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Maths Chapter Wise Questions and Answers Chapter 1 Sets

Plus One Maths Sets Three Mark Questions and Answers

Question 1.
There are 200 individuals with a skin disorder, 120 had been exposed to the chemical A, 50 to chemical B and 30 to both chemical A and B, Find the number of individuals exposed to

1. Chemical A but not chemical B. (1)
2. Chemical B but not.chemical C. (1)
3. Chemical A or chemical B. (1)

Answer:
1. Given; n(U) = 200; n(A) = 120;
n(B) = 50; n(A∩B) = 30
n (Chemical A but not chemical B)
= n(A ∩ B’) = n(A) – n(A ∩ B) = 120 – 30 = 90

2. n (Chemical B but not chemical A)
= n(A’ ∩ B) = n(B) – n(A ∩ B) = 50 – 30 = 20

3. n (Chemical A or chemical B)
= n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
= 120 + 50 – 30 = 140.

Question 2.
In a survey of 400 students in a school, 100 were listed as taking apple juice, 150 as taking orange juice and 75 were listed as taking both apple as well as orange juice. Find how many students were taking neither apple juice nor orange juice.
Answer:
Let A – Apple juice; O – Orange juice be the sets.
Given; n(U) = 400; n(A) = 100;
n(O) = 150; n(A ∩ O) = 75
n (neither apple juice nor orange juice)
= n(A’ ∩ O’) = n((A ∪ O)’)
= n(U) – n(A ∪ O)
= 400 – [n(A) + n(O) – n(A ∩ O)]
= 400 – [100 + 150 – 75] = 400 – 175 = 225.

Question 3.
In a committee, 50 people speak French, 20 speak Spanish and 10 speak both Spanish and French. How many speaks at least one of these two languages?
Answer:
Let F – French; S – Spanish be the sets.
Given; n(F) = 50; n(S) = 20;w(F ∩ S) = 10
n (speaks at least one of these two languages)
= n(F ∪ S) = n(F) + n(S) – n(F ∩ S)
= 50 + 20 – 10 = 60.

Question 4.
In a group of 65 people, 40 like cricket, 10 like both cricket and tennis, how many like tennis only and not cricket? How many like tennis?
Answer:
Let C – Cricket; T – Tennis be the sets.
Given;
n(C’ ∪ T) = 65; n(C) = 40; n(C ∩ T) = 10
n(C ∪ T) = n(C) + n(T) – n(C ∩ T)
⇒ 65 = 40 + n(T) – 10 ⇒ n(T) = 35
n (tennis only and not cricket)
= n(T ∪ C’) = n(T) – n(T ∩ C) = 35 – 10 = 25.

Question 5.
Let A and B be two sets such that n( A) = 20, n(A ∪ B) = 42, n(A ∩ B) = 4. Find

1. n(B) (1)
2. n(B – A) (1)
3. n(A – B) (1)

Answer:

1. n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
   ⇒ 42 = 20 + n(B) – 4 ⇒ n(B) = 26
2. n(B – A) = n(B) – n(A ∩ B) = 26 – 4 = 22
3. n(A – B) = n(A) – n(A ∩ B) = 20 – 4 = 16.

Question 6.
A = {x: x is a natural number less than 8}

1. Write in roster form. (1)
2. Write a subset of A containing all even numbers in A. (1)
3. Which of the following could not be the number of elements of power set of a set [2, 8, 10, 16]? (1)

Answer:

1. A = {1, 2, 3, 4, 5, 6, 7}
2. {2, 4, 6} or {2, 4, 6, 7}
3. 10. (since other are powers of 2.)

Plus One Maths Sets Four Mark Questions and Answers

Question 1.
Observe the Venn diagram.

1. Write in roster form. (1)
2. Verify that (A – B) ∪ (A ∩ B) = A (2)
3. Find (A ∩ B)’ (1)

Answer:

1. A = {1, 3, 4, 8} ; B = {2, 3, 5}
2. A – B = {1, 4, 8}; A ∩ B = {3}
   ⇒ (A – B) ∪ (A ∩ B) = {1, 3, 4, 8}
   Hence; (A – B) ∪ (A ∩ B) = A
3. (A ∩ B)’ = {1, 2, 4, 5, 6, 7, 8, 9}

Plus One Maths Sets Practice Problems Questions and Answers

Question 1.
Write the following sets in roster form.

1. A = {x: x xis an integer and -3 < x < 7}
2. B = {x: x ∈ N; x ≤ 6}
3. C = {x : x is a vowel in English alphabet}
4. D = {x : x is a two-digit natural number such that the sum of its digits is 8}
5. E = {x: x ∈ Z; \(-\frac{1}{2}<x<\frac{9}{2}\)}

Answer:

1. A = {-2, -1, 0, 1, 2, 3, 4, 5, 6}
2. B = {1, 2, 3, 4, 5, 6}
3. C = {a, e, i, o, u}
4. D = {17, 71, 26, 62, 35, 53}
5. E = {1, 2, 3, 4}

Question 2.
Write the following sets in Set builder form.

1. A = {3, 6, 9, 12}
2. B = {2, 4, 8, 16, 32}
3. C = \(\left\{\frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \frac{5}{6}, \frac{6}{7}\right\}\)
4. D = {5, 25, 125, 625}
5. E = {2, 4, 6……..} (1 score each)

Answer:

1. A = {x: x = 3n, n ∈ N, n< 4 }
2. B = {x: x = 2ⁿ; n ∈ N; n < 5 }
3. C = {x: x = \(\frac{n}{n+1}\); n ∈ N, n ≤ 6}
4. D = {x: x = 5ⁿ; n ∈ N, n ≤ 4 }
5. E = {x: x is an even number}

Question 3.
Write the following in interval form.

1. {x: x∈ R, -4 < x ≤ 6}
2. {x: x∈ R, 0 ≤ x < 7 }
3. {x: x∈ R, 3 ≤ x ≤ 4 } (1 score each)

Answer:

1. (-4, 6]
2. [0, 7)
3. [3, 4]

Question 4.
Write the following in set builder form.

1. [0, 10]
2. [-2, 7)
3. (3, 4)

Answer:

1. {x: x∈ R, 0 ≤ x ≤ 10 }
2. { x: x ∈ R, -2 ≤ x < 7 }
3. {x: x ∈ R, 3 < x < 4 }

Question 5.
Find Set A, B and Universal set U (1 score each)

Answer:
A = {e, f, d}; B = {a, b, c, d} and U = {a, b, c, d, e, f, g, h}

Question 6.
Write all subset of the following

1. {1, 2}
2. {a, b, c}
3. Φ (1 score each)

Answer:

1. Φ, {1}, {2}, {1, 2}
2. Φ, {a}, {b}, {c} ,{a, b}, {a, c}, {b, c}, {a, b, c}
3. Φ

Question 7.
Let A = {1, 2, {3, 4}, s, d, θ} , Which of the following statements are true/false and why?

1. 3 ∈ A
2. {1, {3, 4}} ∈ A
3. {1, 2, 3} ⊂ A
4. Φ ∈ A
5. 1 ⊂ A (1 score each)

Answer:

1. False
2. True
3. False
4. False
5. False

Question 8.
If A = {1, 2, 4, 6, 7, 8}; B = {2, 5, 7, 9, 10} and C = {4 , 5, 9, 10}. Find

1. A ∪ B
2. B ∪ C
3. A ∪ C
4. A ∩ B
5. B ∩ C
6. A∪ B ∪ C
7. A ∩ B ∩ C
8. (A ∩ B) ∪ (C ∩ A) (1 score each)

Answer:

1. A ∪ B = {1, 2, 4, 5, 6, 7, 8, 9, 10}
2. B ∪ C = {2, 4, 5, 7, 9, 10}
3. A ∪ C = {1, 2, 4, 5, 6, 7, 8, 9, 10}
4. A ∩ B = {2, 7}
5. B ∩ C = {5, 9, 10}
6. A ∪ B ∪ C = {1, 2, 4, 5, 6, 7, 8, 9, 10}
7. A ∩ B ∩ C = Φ
8. (A ∩ B) ∪ (C ∩ A) = {2, 7} u {4} = {2, 4, 7}

Question 9.
If A = {2, 4, 6, 7, 8, 12}; B = {2, 7, 9, 10} and C = {5, 9, 10, 12}. Find

1. A – B
2. B – C
3. A – C
4. B – A
5. C – A
6. (A ∪ B) – C
7. A – {B ∩ C)
8. (A ∩ B) – (C ∩ A) (1 score each)

Answer:

1. A – B = {4, 6, 8, 12}
2. B – C = {2, 7}
3. A – C = {2, 4, 6, 7, 8}
4. B – A = {9, 10}
5. C – A = {5, 9, 10}
6. (A ∪ B) – C = {2, 4, 6, 7, 8, 9, 10, 12} – {5, 9, 10, 12} = {2, 4, 6, 7, 8}.
7. A – (B ∩ C) = {2, 4, 6, 7, 8, 12} – {9, 10} = {2, 4, 6, 7, 8, 12}
8. (A ∩ B) – (C ∩ A) = {2, 7} – {12} = {2, 7}

Question 10.
If U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}; A = {2, 7, 9, 10} B = {5, 9, 10, 12} and C = {1, 4, 5, 7, 11}. Find

1. A’
2. B’
3. A’ – C
4. (B – A)’
5. B’ ∩ C’
6. (A ∪ B)’
7. A’ ∩ B’ (1 score each)

Answer:

1. A’ = { 1, 3, 4, 5, 6, 8, 11, 12}
2. B’ = { 1, 2, 3, 4, 6, 7, 8, 11}
3. A’ – C = {1, 3, 4, 5, 6, 8, 11, 12} – {2, 3, 6, 8, 9, 10, 12} = {1, 4, 5, 11}
4. (B – A)’ = {5, 12}’ = {1, 2, 3, 4, 6, 7, 8, 9, 10, 11}
5. B’ ∩ C’ = {1, 2, 3, 4, 6, 7, 8, 11} – {2, 3, 6, 8, 9, 10, 12} = {2, 3, 6, 8}
6. (A ∪ B)’ = {2, 5, 7, 9, 10, 12}’ = {1, 3, 4, 6, 8, 11}
7. A’ ∩ B’ = {1, 3, 4, 5, 6, 8, 11, 12} ∩ {1, 2, 3, 4, 6, 7, 8, 11} = {1, 3, 4, 6, 8, 11}

Question 11.
If X and Y are two sets such that X ∪ Y has 50 elements, X has 28 elements and Y has 32 elements, how many elements does X ∩ Y have?
Answer:
Given; n(X ∪ Y) = 50; n(X) = 28; n(Y) = 32
n(X ∪ Y) = n(X) + n(Y) – n(X ∩ Y)
⇒ 50 = 28 + 32 – n(X ∩ Y)
⇒ n(X ∩ Y) = 60 – 50 = 10

Students can Download Chapter 9 Mechanical Properties of Solids Questions and Answers, Plus One Physics Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Physics Chapter Wise Questions and Answers Chapter 9 Mechanical Properties of Solids

Plus One Physics Mechanical Properties of Solids One Mark Questions and Answers

Question 1.
If longitudinal strain fora wire is 0.03 and its poisson’s ratio is 0.5, then its lateral strain is
(a) 0.003
(b) 0.0075
(c) 0.015
(d) 0.4
Answer:
(c) 0.015
Poisson’s ratio σ = \(\frac { Lateral\quad strain }{ Longitudina\quad strain } \)
Lateral strain = Longitudinal strain × σ
= 0.03 × 0.5 = 0.015.

Question 2.
Between steel and diamond, which is more elastic?
Answer:
Steel.

Question 3.
What is the value of Y for a perfectly elastic body?
Answer:
Infinity.

Question 4.
Young’s modulus of the wire depends on
(a) length of the wire
(b) diameter of the wire
(c) material of the wire
(d) mass hanging from the wire
Answer:
(c) material of the wire
Young’s modulus of wire depends only on the nature of the material of the wire.

Question 5.
Two solid spheres of the same material have the same radius but one is hollow while the other is solid. Both spheres are heated to same temperature. Then
(a) the solid sphere expands more
(b) the hollow sphere expands more
(c) expansion is same for both
(d) nothing can be solid about their relative expansion if their masses are not given
Answer:
(c) expansion is same for both.

Question 6.
For most materials the Young’s modulus is n times the rigidity modulus, where n is
(a) 2
(b) 3
(c) 4
(d) 5
Answer:
(b) 3
For most materials, the modulus of rigidity, η is one third of the Young’s modulus, Y.
η = \(\frac{1}{3}\)Y or Y = 3η
∴ n = 3.

Question 7.
The stress required to double the length of a wire of Young’s modulus Y is
(a) Y/2
(b) 2Y
(c) Y
(d) 4Y
Answer:
(c) Let L be the length of a wire.
If the length of a wire is doubled, the longitudinal strain will be

Young’s modulus Y = \(\frac{\text { Stress }}{\text { Strain }}\)
∴ Y = Stress (∵ Strain = 1).

Question 8.
What is the bulk modulus of a perfectly rigid body?
Answer:
Infinity

Question 9.
What is shear modulus of liquid?
Answer:
Zero

Question 10.
What is rigidity modulus of liquid?
Answer:
Zero.

Question 11.
Identify the type of modulus in twisting of cylinder.
Answer:
Shear modulus

Question 12.
Why work is required to be done to stretch a wire?
Answer:
Work is required to be done against the inter molecular forces of attraction.

Question 13.
Name the material which is famous for a large elastic after effect.
Answer:
Glass

Plus One Physics Mechanical Properties of Solids Two Mark Questions and Answers

Question 1.
Find stress required to double the length of a wire of Young’s modulus Y
Answer:
Let L be the length of a wire.
If the length of a wire is doubled, the longitudinal strain will be

Young’s modulus Y = \(\frac{\text { Stress }}{\text { Strain }}\)
∴ Y = Stress (∵ Strain = 1).

Question 2.
When wire is bent back and forth, it becomes hot. Why?
Answer:
When wire is bent back and forth, the deformations are beyond elastic limit. A part of work done is converted in to heat energy. Hence wire becomes hot.

Plus One Physics Mechanical Properties of Solids Three Mark Questions and Answers

Question 1.
The stress strain graph of two bodies A and B are given in the figure

1. Which of the material has greater youngs modulus?
2. Which of the two material is preferable to be used as a rope in a crane?
3. Redraw the graph and mark the regions in the graphs where the elastic force is strictly conservative

Answer:
1. Youngs modulus, Y = \(\frac{\text { Stress }}{\text { Strain }}\)
The slope of above graph gives youngs modulus. The body A has larger slope. Hence youngs modulus of ‘A ‘is greater than ‘B’.

2. The fracture point is greater for A. Hence A is stronger. Due to high strength, the material A is used as rope in a crane.

3.

Up to the point C, the elastic force is strictly conservative.

Question 2.
Hook’s law is said to be that fundamental law in elasticity.

1. State Hook’s law of Elasticity.
2. Name the different types of modulus of elasticity with their equations.

Answer:
1. For small deformations, the stress and strain are proportional to each other, ie: stress ∝ strain stress = k × strain. Where k is the proportionality constant and is known as modulus of elasticity.

2.

Plus One Physics Mechanical Properties of Solids Four Mark Questions and Answers

Question 1.
When an external force deforms a solid, internal restoring forces are developed in the body giving rise to stress and strain.

1. Define stress and strain.
2. Draw the stress-strain diagram and mark the positions of elastic limit and the regions of elastic and plastic behaviors.

Answer:
1. Stress: It is the restoring force developed per unit area of cross section.
Strain: The ratio of change in dimension to original dimension is called strain.

2.

Plus One Physics Mechanical Properties of Solids Five Mark Questions and Answers

Question 1.

1. Distinguish between perfectly plastic and perfectly elastic materials.
2. What is the quantity obtained from the slope of a stress-strain graph and what is the area under the curve?
3. Two wires have their lengths in the ratio 1:3 and radii in the ratio 2:1. What will be the ratio of elongations for the same linear stress?

Answer:
1. When deforming forces are applied on a body its volume or shape will change. On removing the deforming forces it regains its original size and shape. It is called elastic body.

On removing the deforming forces. The body which cannot retain the original shape and size is called plastic body.

2. Modulus of elasticity. Area under stress strain graph gives workdone.

3. we know l₁: l₂, 1 : 3
r₂ : r₁, 2 : 1

Question 2.
The modulus of elasticity of rubber is higher than that of steel.

1. Do you agree with this statement? Why?
2. Give your explanation.
3. Prove that the elastic potential energy density of a stretched wire is half the product of stress and strain.

Answer:
1. No

2. Y = \(\frac{F l}{A \Delta l}\)
∆l is higher for rubber than steel. Hence youngs modulus is smaller for rubber than steel.

3. Workdone in stretching a wire.
= \(\frac{1}{2}\) × stretching force × extension
= \(\frac{1}{2}\) Fe
Let ‘a’ be the area of cross section and ‘L’ the length of the wire. The volume ‘aL’
Workdone for a volume ‘aL’ = \(\frac{1}{2}\)
Workdone per unit volume

Question 3.
We have common experience that a thin thread breakes if pulled at its ends. Also a thin metallic wire, when pulled at the ends elongates and then contracts, when released.

1. What do you mean by elasticity?
2. Draw a the stress-strain graph of a metal and mark elastic limit, plastic region, and fracture point.
3. A lift is tied with thick iron wires and its mass is 1000kg. What should be the minimum diameter of the wire if the maximum acceleration of the lift is 1.2 m/s² and maximum safe stress of the wire is 1.4 × 10⁸ N/m² (g = 9.8m/s²)

Answer:
1. Elasticity of a body is the property of the body by virtue of which the body gains its original shape and size when the deforming force is removed.

2. Stress strain curve

3. When the lift goes upward with as acceleration a, then tension in the wires,
T = m (g + a)
= 1000(9.8 + 1.2)
= 11000N
Let r be the minimum radius of the wire
Then maximum stress = \(\frac{T}{\pi r^{2}}\)
But the maximum stress the wire can withstand = 1.4 × 10⁸

r = 0.005m
∴ diameter = 0.01m.

Question 4.
The property of material bodies to regain its original size on the remaoval of deforming force is called elasticity.

1. What are the values of
   • Young’s modulus for a perfectly rigid body
   • Rigidity modulus of a liquid
2. Why do we prefer steel to copper in the manufacture of spring?
3. How much should the pressure on a littre of water be changed to compress it by 0.10%?
   (B = 2.2 × 10⁹N/m²)

Answer:
1. The values:

• infinity
• Zero

2. Young’s modulus of steel is more than that of copper. Hence steel is more elastic than copper.

3.

Plus One Physics Mechanical Properties of Solids NCERT Questions and Answers

Question 1.
A steel wire of length 4.7m and cross sectional area 3 × 10^-5m² stretches by the same amount as a copper wire of length 3.5m and cross sectional area of 4 × 10^-5m² under a given load. What is the ratio of the Young’s modulus of steel to that of copper?
Answer:
For steel
l₁ = 4.7m, a₁ = 3 × 10^-5m²
If F newton is the stretching force and ∆l metre the extension in each case, then


For copper
l₂ = 3.5m, a₂ = 4 × 10^-5m²

Dividing (1) by (2), we get

Question 2.
Following figure shows the strain-stress curve for a given material. What are

1. Young’s modulus and
2. approximate yield strength for this material?

Answer:
1. It is clear from the graph that for a stress of 150 × 10⁶Nm^-2, the strain is 0.002
∴ Young’s modulus of the material

= 7.5 × 10¹⁰Nm^-2.

2. It is clear from the graph that A corresponds to the yield point. So, the approximate yield strength of them material is 300 × 10⁶Nm^-2 or 3 × 10⁸Nm^-2.

Question 3.
The edge of an aluminium cube is 10cm long. One face of the cube is firmly fixed to a vertical wal. A mass of 100kg is then attached to the opposite face of the cube. The shear modulus of aluminium is 25GPa. What is the vertical deflection of this face?
Answer:

3.92 × 10^-7m
≃ 4 × 10^-7m.

Question 4.
A steel cable with a radius 1.5cm supports a chair lift. If the maximum stress is not to exceed 10⁸Nm^-2, what is the maximum load the cable can support?
Answer:
Maximum load = Maximum Stress × Cross sectional area
= 10⁸Nm^-2 × \(\frac{22}{7}\) × (1.5 × 10^-2)^-2N
= 7.07 × 10⁴N.

Question 5.
Compute the fractional change in volume of a glass slab when subjected to a hydraulic pressure of 10atm.
Answer:
Given : Bulk modulus of elasticity of glass
= 37 × 10⁹Nm² and 1 atm
= 1.013 × 10⁵Pa
p = 10 atm = 10 × 1.013 × 10⁵Pa
Fractional change in volume = Volumetric strain

Question 6.
Determine the volume of contraction of a solid copper tube 10cm on an edge, when subjected to a hydraulic pressure of 7 × 10⁶Pa. Bulk modulus of copper =140 × 10⁹Pa.
Answer:
V = L³ = (10cm)³ = (0.1m)³
p = 7 × 10⁶Pa, K = 140 × 10⁹Pa

Students can Download Chapter 8 Arrays Questions and Answers, Plus One Computer Science Chapter Wise Questions and Answers helps you to revise the complete Kerala State Syllabus and score more marks in your examinations.

Kerala Plus One Computer Science Chapter Wise Questions and Answers Chapter 8 Arrays

Plus One Arrays One Mark Questions and Answers

Question 1.
From the following which is not true for an array.
(a) It is easy to represent and manipulate array variable
(b) Array uses a compact memory structure
(c) Readability of program will be increased
(d) Array elements are dissimilar elements
Answer:
(d) Array elements are dissimilar elements

Question 2.
Consider the following declaration.
int mark(50) Is it valid? If no give the correct declaration
Answer:
It is not valid. The correct declaration is as follows, int mark[50]. Use square brackets instead of parenthesis

Question 3.
Consider the following declaration.
int mark[200]
The index of the last element is ________.
Answer:
199

Question 4.
Consider the following declaration int mark[200]. The index of the first element is ________.
Answer:
0

Question 5.
Consider the following int age[4] = {15,16,17,18};
From the following which type of initialisation is this.
(a) direct assignment
(b) along with variable declaration
(c) multiple assignment
(d) None of these
Answer:
(b) along with variable declaration

Question 6.
From the following which is used to read and display array elements.
(a) loops
(b) if
(c) switch
(d) if else ladder
Answer:
(a) loops

Question 7.
Write down the corresponding memory consumption in bytes

1. int age[10] = ——-
2. charname[10] = ——-
3. int age[10][10]= ——–

Answer:

1. 2 × 10 = 20 bytbs (2 bytes for one integer)
2. 1 × 10 = 10 (one byte for each character)
3. 2 × 10 ×10 = 200 (2 × (100 elements))

Question 8.
A two dimensional array is having ________ number of subscript
(a) one
(b) two
(c) three
(d) none of these
Answer:
(b) two

Question 9.
Consider the following
int age[10][10];
In this array how many elements will contain.
Answer:
10 × 10 = 100 elements

Question 10.
Consider the following int age[4] = {12, 13, 14};
cout<<age[3];
What will be the output?
(а) 14
(b) 12
(c) 13
(d) 0
Answer:
(d) 0

Question 11.
The elements of 2 dimensional array can be read using _________ loop.
Answer:
nested loop

Question 12.
________ is the process of reading/visiting elements of an array.
Answer:
traversal

Question 13.
Anjali wants to read the 10 marks that already stored in an array and find the total. This process is known as ________.
(a) insertion
(b) deletion
(c) traversal
(d) linear search
Answer:
(c) traversal

Question 14.
Mani wants to check a number from 100 numbers already stored in an array. This process is called ___________.
(a) insertion
(b) deletion
(c) searching
(d) None of these
Answer:
(c) searching

Question 15.
Divide and conquer method used in ____________ search.
Answer:
binary

Question 16.
“Each element of the array is composed with value to be searched from the beginning of the array”. This method is adopted by _____________ search.
Answer:
linear search

Question 17.
____________ search requires a sorted array as input.
Answer:
binary search

Question 18.
___________ searching is slower for larger array.
Answer:
linear searching

Question 19.
____________ is a simple sorting algorithm.
(a) bubble sort
(b) selection sort
(c) linear search
(d) binary search
Answer:
(a) bubble sort

Question 20.
Adjacent elements are checked and inter changed in _____________ sort.
Answer:
bubble sort

Question 21.
The array is divided into sorted part and unsorted part in ____________ sort.
selection.

Question 22.
The elements of an array of size ten are numbered from _____ to _______.
Answer:
0 to 9

Question 23.
Element mark[6] is which element of the array?
(a) The sixth
(b) the seventh
(c) the eighth
(d) impossible to tell
Answer:
(b) the seventh

Question 24.
When a multidimensional array is accessed, each array index is ________.
(a) Separated by column.
(b) Surrounded by brackets and separated by commas.
(c) Separated by commas and surrounded by brackets.
(d) Surrounded by brackets,
Answer:
(d) surrounded by brackets

Question 25.
You have used a 2D array with the Name Mat representing a matrix. Write the C++ expression to access the 3rd element in the 2nd row.
Answer:
mat[1] [2];

Question 26.
Write a C++ statement that defines a string variable called ‘name’ that can hold a string of upto 20 characters.
Answer:
char name[21j;

Question 27.
Given some array declaration. Pick the odd man out.
Float a[+40], int num[0-10], double [50], char name[50], amount[20] of float.
Answer:
char name[50]. It is a valid array decalaration the remaining are not valid.

Question 28.
__________ is a collection of elements with same datatype.
Answer:
Array

Question 29.
int num[10];
The above C++ statement declares an array named num that can store maximum ________ integer numbers. (SEP-2015 (IMP) (1)
(а) 9
(b) 10
(c) N
(d) none of these
Answer:
(b) 10

Question 30.
Declare a two dimensional array to store the elements of a matrix with order 3 × 5. (MARCH-2016) (1)
Answer:
int m[3] [5]; or float m[3] [5]

Question 31.
_________ search method is an example for ‘divide and conquer method’. (SEP-2016) (1)
Answer:
Binary

Question 32.
Read the following C++ statement:
int AR[10]
How many bytes will be allocated for this array? (1)
Answer:
To store an integer 4 bytes needed so AR[10] needs 10 × 4 = 40 bytes

Question 33.
Find the value of score [4] based on the following declaration statement. int score [5] = {988,87,92,79,85}; (MARCH-2017) (1)
Answer:

Hence (158)₁₀ = (9E)₁₆

Plus One Arrays Two Mark Questions and Answers

Question 1.
Whether the statement char text[] = “COMPUTER”; is True/False? Justify.
Answer:
It is a single dimensional array. If the user doesn’t specify the size the operating system allocates the number of characters + one (for null character for text) bytes of memory. So here OS allocates 9 bytes of memory.

Question 2.
Given a word ” Mathematics”. How will you locate this word in a standard dictionary. What are the steps used for this purpose
Answer:
In the standard dictionary the words are arranged in sorted order so binary search method is more suitable to find the word “MATHEMATICS”.

Question 3.
How can you find out the word “MATHEMATICS” from a text book. Which is the most convenient method? Justify your answer.
Answer:
In a text book the words are not arranged in sorted order so linear search method is convenient.

Question 4.
Consider the statement char str[] = “PROGRAM” What will be stored in last location of this array. Justify.
Answer:
The last location is the null character(\0) because each string must be appedend by a null character.

Question 5.
Explain different array operations in detail.
Answer:

1. Traversal: All the elements of an array is visited and processed is called traversal
2. Search: Check whether the given element is present or not
3. Sorting: Arranging elements in an order is called sorting

Question 6.
Read the following C++ statement: int MAT[5][4];

1. How many bytes will be allocated for this array?
2. Suppose MAT[4][4] is a 2D array that contains the elements of a square matrix. Write C++ statements to find the’ sum of all the elements in the array. (MARCH – 2015) (1)

Answer:

Question 7.
Declare an array of size 5 and intitialize it with the numbers 8, 7, 2, 4 and 6. (MARCH-2016) (2)
Answer:
int n[5] = {8, 7, 2, 4, 6};

Question 8.
Predict the output of the following C++ program.
#include <iostream.h>
int main()
{
int array[] = {1, 2, 4, 6,7,5};
for (int n =1; n<=5; n++)
array [n] = array [n – 1 ];
for (n = 0; n <= 5; n++)
cout<< array [n];
return 0;
}
Answer:
1, 1, 1, 1, 1, 1

Question 9.
Suppose M[5][5] is a 2D array that contains the elements of a square matrix. Write C++ statements to find the sum of the diagonal elements. (SCERT SAMPLE – II) (2)
Answer:
for (i = 0; i < 5, i++)
for (j = 0; j < 5; j++)
if (i == j)
S = S + M[i][j];

Question 10.

1. Write C++ program for sorting a list of numbers using Bubble Sort Method. (2)
2. Write the different passes of sorting the following numbers using Bubble Sort.
   32, 21, 9, 17, 5

Answer:
1. Example for Bubble sort is given below

2. Bubble sort (ascending order):
Consider the first 2 elements of the numbers and compare it. 32 is greater than 21 then interchange both of them. Then the numbers are
21, 32, 9, 17, 5
Next compare 32 and 9. Here 32 is greater so interchange both of them. Then the numbers are
21, 9, 32, 17, 5
Next compare 32 and 7. Then interchange and the numbers are
21, 9, 17, 32, 5
Next compare 32 and 5. Then interchange and the numbers are
21, 9, 17, 5, 32.
After the first phase the largest number is on the right side. Similarly do the remaining. At last we will get the result as follows.
5, 9, 17, 21, 32

Question 11.
Suppose M[5] [5] is a 2D array that contains the elements of a square matrix. Write C++ statements to find the sum of the diagonal elements. (MARCH-2017)
Answer:

Plus One Arrays Three Questions and Answers

Question 1.
Suppose you are given Total mark of 50 students in a class

1. How will you store these values using ordinary variable?
2. Is there any other efficient way to store these values? Give reason.

Answer:
We have to declare 50 variables individually to store total marks of 50 students. It is a laborious work. Hence we use array, it is an efficient way to declare 50 variables. With a single variable name we can store multiple elements.
eg: int mark[50]. Here we can store 50 marks. The first mark is in mark[0], second is in mark[1]…. etc the fiftieth mark is in mark[49],

Question 2.
Four friends are in a queue for watching a movie. How can you locate a particular person from that queue? Write all the steps sequentially.
Answer:
Locate a particular person from a queue can be carried out by using two ways.
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is returned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.

Question 3.
Total mark of 50 students in a class are given in an array. A bonus of 10 marks is awarded to all of them. Write the program code for making such a modification.
Answer:

Question 4.
In School Assembly, try to arrange all the students in your class according to the increasing order of their heights separately for male/female students. Smallest one will be in front and tallest one at the last position. Write sequential steps for doing this, in two different methods.
Answer:
Arranging elements from smallest to largest (ascending) or largest to smallest(descending) is called sorting. There are two sorting methods
1. Bubble sort:
It is a simple sorting method. In this sorting considering two adjacent elements if it is out of order, the elements are interchanged. After the first iteration the largest(in the case of ascending sorting) or smallest(in the case of descending sorting) will be the end of the array. This process continues.

2. Selection sort:
In selection sort the array is divided into two parts, the sorted part and unsorted part. First smallest element in the unsorted part is searched and exchanged with the first element. Now there is 2 parts sorted part and unsorted part. This process continues.

Question 5.
Using the concept obtained from algorithms in question number (9), write complete program for the two types of sorting.
Answer:

Question 6.
Collect the heights of 12 students from your class in which 7 students are male and others are female students. Suppose these male and female students be seated in two separate benches and you are given a place which is used for sitting these 12 students in linear form. How will you combine and make them sit without mixing male/female students. Write a program for the same.
Answer:

Question 7.
Collect the heights of 12 students from your class in which 7 students are male and others are female students. Suppose you are given the heights according to a sorted order separately for male/female students. How will you combine these group according to the same order in linear form. Write a program for the same.
Answer:

Question 8.
Write the program code for counting the number of vowels from your school name.
Answer:

Question 9.
Write the program code for counting the number of words from the given string.” Directorate of Higher Secondary Examination”
Answer:

Question 10.
Given a word like “ECNALUBMA” Write the program code for arranging it in into a meaningful word.
Answer:

Question 11.
Explain the needs for arrays Array
Answer:
Array is collection of same type of elements. With the same name we can store more elements. The elements are distinguished by using its index or subscript. To store 50 marks of 50 students we have to declare 50 variables, it is a laborious work.

Hence the need for arrays arise. By using array this is very easy as follows int mark[50]. Here the index of first element is 0, then 1, 2, 3, etc upto 49.

Question 12.
Explain different types of arrays.
Answer:
There are two tyes of array
1. Single dimensional:
It contains only one index or subscript. The index starts from 0 and ends with size-1.
eg: int n[50];
char name[10];

2. Multi-dimensional:
It contains more than one index or subscript. The two dimensional array contains two indices, one for rows and another for columns. The row index starts from 0 and end at row size-1 and column index starts at 0 and ends at colunn size-1.
eg: int n[10][10] can store 10 × 10 = 100 elements. The index of the first element is n[0][0] and index of the 100th element is n[9][9],

Question 13.
Write a program to read the 5 marks of a students and display the marks and total
Answer:

Question 14.
Write a program to read 3 marks of 5 students and find the total and display it.
Answer:

Question 15.
Differentiate linear search and binary search
Answer:
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is re¬turned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.

Question 16.
Differentiate bubble sort and selection sort.
Answer:
1. Bubble sort:
It is a simple sorting method. In this sorting considering two adjascent elements if it is out of order, the elements are interchanged. After the first iteration the largest(in the case of ascending sorting) or smallest (in the case of descending sorting) will be the end of the array. This process continues.

2. Selection sort:
In selection sort the array is divided into two parts, the sorted part and unsorted part. First smallest element in the unsorted part is searched and exchanged with the first element. Now there is 2 parts sorted part and unsorted part. This process continues.

Question 17.
Write a program to read a string and a character and find the character by using linear search.
Answer:

Question 18.
Write a program to read marks of 10 students and read a mark and check whether it is in the array or not using binary search
Answer:

Question 19.
Write a program reverse a string without using a function.
Answer:

Question 20.
Write a program to read a string and find the no. of vowels .consonents and special characters.
Answer:

Question 21.
Given a word “COMPUTER”, write a C++ program to reverse the word without using any string functions.
Answer:
#include<iostream>
using namespace std;
int main(()
{
char a[9] = “COMPUTER”;
inti;
for (i=8; i>=0; i- -)
{
cout<<a[i];
}
}

Question 22.
Write a program to accept marks of 10 students and find out the largest and smallest mark from the list.

OR

C++ program to store the scores of 10 batsmen of a school cricket team and find the largest and smallest score.
Answer:

Question 23.
Write the names of two searching methods in arrays. Prepare a chart that shows the comparisons of two searching methods. (MARCH-2015)
Answer:
It is the process of finding the position of the given element.
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is returned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.

Question 24.
Write a C++ program to illustrate array traversal. (SAY-2015 (IMP) (3)
Answer:
#include<iostream>
using namespace std;
int main()
{
int i, mark[50];
for(i=0;i<50; i++)
{
cout<<“Enter mark “<<i + 1<<“: cirt>>mark[i];
}
cout<<“\nThe mark of 50 students after adding bonus mark 10 is given below \n”; for(i=0;i<50; i++)
cout<<mark[i] + 10<<endl;
}

Question 25.
Define an array. Also write an algorithm for searching an element in the array using any one method that you are familiar with. (MARCH-2016) (3)
Answer:
An array is a collection of elements with same data type. The index of first element is 0 (zero) and the index of last element is size -1. There are 2 methods linear search and binary search.

Searching: It is the process of finding the position of the given element.
1. Linear search:
In this method each element of the array is compared with the element to be searched starting from the first element. If it finds the position of the element in the array is returned.

2. Binary search:
It uses a technique called divide and conquer method. It can be performed only on sorted arrays. First we check the element with the middle element. There are 3 possibilities. The first possibility is the searched element is the middle element then search can be finished.

The second possibility is the element is less than the middle value so the upper bound is the middle element. The third possibility is the element is greater than the middle value so the lower bound is the middle element. Repeat this process.8.3 Two dimensional (2D) arrays.

Some occasions we have to store 6 different marks of 50 students. For this we use 2D arrays. An array with two subscripts is used, eg. int mark[r][c]; Here r is the row and c is the column.

Question 26.

1. Finding sum of all elements in an array is an example of _________ operation.
2. If 24, 45, 98, 56, 76, 24, 15 are the elements of an array, illustrate the working of selection sort for arranging the elements in descending order. (SCERT SAMPLE -1) (3)

Answer:
1. Traversal

2. In selection sort the array is divided into two parts the sorted part and unsorted part. First smallest elemant in the unsorted part in searched and exchanged with the first elemant now there is 2 parts sorted part and unsorted part. This process continues.

Question 27.
Read the following C++ statement:

1. How many bytes will be allocated for this array?
2. Write algorithm to sort this array using bubble sort method. (SCERT SAMPLE – II) (3)

Answer:
1. To store an integer 4 bytes needed so AR[10] needs 10 × 4 = 40 bytes.

2. Sorting – Arranging elements of an array in an order(ascending or descending).
(a) Bubble sort:
It is a simple sorting method. In this sorting considering two adjascent elements if it is out of order, the elements are interchanged. After the first iteration the largest(in the case of ascending sorting) or smallest(in the case of descending sorting) will be the end of the array. This process continues.

(b) Selection sort:
In selection sort the array is divided into two parts, the sorted part and unsorted part. First smallest element in the unsorted part is searched and exchanged with the first element. Now there is 2 parts sorted part and unsorted part. This process continues.

Question 28.
Explain ‘Call by Value’ and ‘Call by Reference’ methods of function calling with the help of a suitable example. (SEP-2016) (3)
Answer:
Two types are call by value and call by reference.
1. Call by value:
In call by value method the copy of the original value is passed to the function, if the function makes any change will not affect the original value.
Example

2. Call by reference:
In call by reference method the address of the original value is passed to the function, if the function makes any change will affect the original value.
Example

Question 29.
What is an array? Write C++ program to declare and use a single dimensional array for storing the computer science marks of all students in your
class. (SEP-2016) (3)
Answer:
An array is a collection of elements with same data type or with the same name we can store many elements, the first or second or third etc can be distinguished by using the index(subscript). The first element’s index is 0, the second elements index is 1, and so on.

Question 30.
Write an algorithm for arranging elements of an array in ascending order using bubble sort. (MARCH-2017) (3)
Answer:

Plus One Arrays Five Mark Questions and Answers

Question 1.
Write a program to perform matrix addition, multiplication, subtraction.
Answer: