Class 6

Parents often use SCERT Kerala Syllabus 6th Standard English Textbook Solutions Unit 4 Chapter 3 The Story of Dalda 13 Textual Questions and Answers Activities Notes Pdf Download to assist their kids with homework.

Class 6 English The Story of Dalda 13 Activities Question Answer

The Story of Dalda 13 Class 6 Questions and Answers

The Story of Dalda 13 Questions and Answers

Question 1.
Why did Vyarawalla’s family move from place to place?
വ്യാരവല്ലയുടെ കുടുംബം സ്ഥലം മാറി മാറി താമസിച്ചത് എന്തുകൊണ്ട്?
Answer:
Vyarawalla’s family moved from place to place because her father was a theatre artist and he had to move to different places for performances.
വ്യാരവല്ലയുടെ പിതാവ് ഒരു നാടകകലാകാരനായതിനാലും പ്രകടനങ്ങൾക്കായി വ്യത്യസ്ത സ്ഥലങ്ങളിലേക്ക് താമസം മാറേണ്ടി വന്നതിനാലും അവരുടെ കുടുംബം സ്ഥലം മാറി മാറി താമസിച്ചു.

Question 2.
What was Vyarawalla’s first assignment as a photographer?
ഫോട്ടോഗ്രാഫർ എന്ന നിലയിൽ വ്യാരവല്ലയുടെ ആദ്യ പ്രവർത്തി എന്തായിരുന്നു
Answer:
Vyarawalla’s first assignment as a photographer was to take snaps at a picnic when she was still at college.
ഫോട്ടോഗ്രാഫർ എന്ന നിലയിൽ വ്യാരവല്ലയുടെ ആദ്യ പ്രവർത്തി കോളേജിൽ പഠിക്കുമ്പോൾ ഒരു പിക്നിക്കിൽ ഫോട്ടോകൾ എടുക്കുക എന്നതായിരുന്നു.

Question 3.
Why were Vyarawalla’s early photographs published in her husband’s name? വ്യാരവല്ലയുടെ ആദ്യകാല ഫോട്ടോഗ്രാഫുകൾ ഭർത്താവിന്റെ പേരിൽ പ്രസിദ്ധീകരിച്ചത് എന്തുകൊണ്ട്?
Answer:
Vyarawalla’s early photographs were published in her husband’s name because at that time she was unknown and a woman.
വ്യാരവല്ലയുടെ ആദ്യകാല ഫോട്ടോഗ്രാഫുകൾ ഭർത്താവിന്റെ പേരിൽ പ്രസിദ്ധീകരിച്ചത് ആ സമയത്ത് അവർ അജ്ഞാതയും ഒരു സ്ത്രീയും ആയിരുന്നതിനാലാണ്.

Question 4.
Why didn’t people in Delhi take her seriously?
ഡൽഹിയിലെ ആളുകൾ എന്തുകൊണ്ട് അവരെ ഗൗരവമായി എടുത്തില്ല?
Answer:
People in Delhi didn’t take her seriously because they had never seen a woman photographer.
When she was roaming on a bicycle with a camera hanging on her shoulders, they thought she was just fooling around or was showing off.
ഡൽഹിയിലെ ആളുകൾ അവരെ ഗൗരവമായി എടുത്തില്ല, കാരണം അവർ ഒരിക്കലും ഒരു വനിതാ ഫോട്ടോഗ്രാഫറെ കണ്ടിട്ടില്ല. തോളിൽ ക്യാമറ തൂക്കി സൈക്കിളിൽ സഞ്ചരിക്കുമ്പോൾ, അവർ വെറുതെ വിഡ്ഢികളാക്കുകയോ പൊങ്ങച്ചം കാണിക്കുകയോ ചെയ്യുകയാണെന്ന് അവർ കരുതി.

Question 5.
How did Vyarawalla get the pseudonym Dalda 13?
വ്യാരവല്ലയ്ക്ക് ഡാൽഡ 13 എന്ന ഓമനപ്പേര് എങ്ങനെ ലഭിച്ചു
Answer:
Vyarawalla got the pseudonym Dalda 13 because she bought a car in Delhi and its registration number of was DLD 13. Soon people began to call her Dalda 13.
ഡൽഹിയിൽ നിന്ന് ഒരു കാർ വാങ്ങിയതിനാലും അതിന്റെ രജിസ്ട്രേഷൻ നമ്പർ DLD 13 ആയതിനാലുമാണ് വ്യാരവല്ലയ്ക്ക് ഡാൽഡ 13 എന്ന ഓമനപ്പേര് ലഭിച്ചത്. താമസിയാതെ ആളു കൾ അവളെ ഡാൽഡ 13 എന്ന് വിളിക്കാൻ തുടങ്ങി.

Question 6.
What was her complaint against younger generation of photographers?
യുവതലമുറയിലെ ഫോട്ടോഗ്രാഫർമാർക്കെതിരായ അവരുടെ പരാതി എന്തായിരുന്നു?
Answer:
Her complaint against younger generation of photographers was that they disturbed people’s privacy for publicity and fame. She did not like this attitude of theirs.
പേരിനും പ്രശസ്തിക്കും വേണ്ടി ആളുകളുടെ സ്വകാര്യതയെ അവർ തടസ്സപ്പെടുത്തുന്നു എന്ന തായിരുന്നു യുവതലമുറയിലെ ഫോട്ടോഗ്രാഫർമാർക്കെതിരായ അവരുടെ പരാതി. അവരുടെ ഈ മനോഭാവം അവൾക്ക് ഇഷ്ടപ്പെട്ടില്ല.

The Story of Dalda 13 Activities

The Story of Dalda 13 Class 6 Question Answer – Activity 1

Maya, a journalist, collected a few details about Homai Vyarawalla. Prepare a write up based on the hints given:

Homai Vyarawalla was India’s first woman photojournalist. ………….…………………
………………………………………………………………………………………………………………………
………………………………………………………………………………………………………………………
………………………………………………………………………………………………………………………
Answer:
Homai Vyarawalla was India’s first woman photojournalist. She was born at Navsari in Gujarat in 1913. Her father was a theatre artist and the family moved from place to place for performances. These travels were the first inspiration for the photographer in her. Her family later moved to Mumbai. Vyarawalla’s first assignment as a photographer was to take snaps at a picnic when she was still in college. In 1942, she moved to Delhi to join the British Information Services as its photographer.

When she bought a car in Delhi, it got the registration number DLD 13. Soon she began to be called Dalda 13, which became her pseudonym. Many of her photographs were published under the name Dalda 13.

Vyarawalla has hundreds of striking news photographs to her credit. Her lens captured Mahatma Gandhi, Jawaharlal Nehru and several other important personalities in politics and culture. She also talked with foreign dignitaries like Ho Chi Minh and Marshall Georgy Zhukov and took their photographs.

In 1998 she was honoured with the Chameli Devi Jain Award for Outstanding Woman Media-person. In 2010, the Information and Broadcasting Ministry honoured her with the Lifetime Achievement Award. In 2011, she got Padma Vibhushan, India’s second highest civilian honour.

Homai Vyarawalla passed away in 2012. She continues to be a role model for women photographers in India.

Class 6 English The Story of Dalda 13 Activities Pdf- Activity 2

Look at the photo of Kiran and his cat given on p. 120. Read the caption and the description. Now, let us go on a fun photo adventure at home, like Homai Vyarawalla, who took beautiful pictures of everyday life. Arrange your pictures into an album.

Pick a memorable photo from the album and write a short description. Keep the following questions in mind when writing the description.
Can you describe the scene?
Why is the moment important to you?
How did this moment make you feel?

Answer:

A SNAPSHOT OF MY DAY

A Quiet Moment with My Cat
In this photo, I am sitting at the table while my cat enjoys her favourite food. The sunlight coming through the window makes the moment look warm and peaceful. Kichu is happily eating, and I am smiling as I watch her.

This moment is important to me because it shows the love and bond I share with my pet. Taking care of her makes me feel proud and responsible. When I look at this photo, I feel calm and happy, remembering how content we both were.

Parents often use SCERT Kerala Syllabus 6th Standard English Textbook Solutions Unit 4 Chapter 1 The Why – Why Girl Textual Questions and Answers Activities Notes Pdf Download to assist their kids with homework.

Class 6 English The Why – Why Girl Activities Question Answer

The Why – Why Girl Class 6 Questions and Answers

6th Standard English Unit 4 Question Answer

The Doorway
On 16 June 1963, Valentina Tereshkova made history by becoming the first woman in space.

On 16 June 1963, Valentina Tereshkova made history by becoming the first woman in space. She was born in 1937.
The Spaceship: VOSTOK 6
Completed 48 orbits of the Earth: 20,11,680 km in two days, 22 hours and 50 minutes.
1963 ജൂൺ 16 ന്, വാലന്റീന തെരേഷ്കോവ ബഹിരാകാശത്തെത്തിയ ആദ്യ വനിതയായി ചരിത്രം സൃഷ്ടിച്ചു.
1937 ൽ അവർ ജനിച്ചു.
സ്പേസ്ഷിപ്പ് : വോസ്റ്റോക്ക് 6
ഭൂമിയുടെ 48 ഭ്രമണപഥങ്ങൾ രണ്ട് ദിവസം 22 മണിക്കൂർ, 50 മിനിറ്റ് കൊണ്ട് പൂർത്തിയാക്കി, 20, 110, 680 കിലോമീറ്റർ താണ്ടി.

A bird cannot fly with one wing only. Human spaceflight cannot develop any further without the active participation of women.
Valentina Tereshkova
ഒരു പക്ഷിക്ക് ഒരു ചിറകുകൊണ്ട് മാത്രം പറക്കാൻ കഴിയില്ല. സ്ത്രീകളുടെ സജീവപങ്കാളിത്ത മില്ലാതെ മനുഷ്യബഹിരാകാശ യാത്രക്ക് കൂടുതൽ വികസിക്കാൻ കഴിയില്ല.
വാലന്റീന തെരേഷ് കോവ

Question 1.
In which year was Valentina Tereshkova born?
വാലന്റീന തെരഷ്കോവ ഏത് വർഷത്തിലാണ് ജനിച്ചത്?
Answer:
Valentina Tereshkova born in the year 1937.
വാലന്റീന തെരഷ്കോവ 1937 ൽ ജനിച്ചു.

Question 2.
What was her achievement?
അവരുടെ നേട്ടം എന്താണ്?
Answer:
Her achievement was that she was the first woman in space.
ബഹിരാകാശത്തെത്തിയ ആദ്യ വനിത എന്നതായിരുന്നു അവരുടെ നേട്ടം.

Question 3.
What was the name of her spaceship?
അവരുടെ ബഹിരാകാശ കപ്പലിന്റെ പേരെന്തായിരുന്നു?
Answer:
The name of her spaceship was VOSTOK 6.
അവരുടെ ബഹിരാകാശ കപ്പലിന്റെ പേര് VOSTOK 6 എന്നായിരുന്നു.

Question 4.
What did Valentina Tereshkova mean by saying, ‘A bird cannot fly with one wing only’ ?
ഒരു പക്ഷിക്ക് ഒരു ചിറകുകൊണ്ട് മാത്രം പറക്കാൻ കഴിയില്ല” എന്ന് പറഞ്ഞതിലൂടെ വാലന്റീന തെരേഷ്കോവ എന്താണ് ഉദ്ദേശിച്ചത്?
Answer:
By saying, “A bird can’t fly with one wing only” Valentina Tereshkova meant that her achievement was not the result of only her effort but also the efforts of many others.
” ഒരു പക്ഷിക്ക് ഒരു ചിറകുകൊണ്ട് മാത്രം പറക്കാൻ കഴിയില്ല” എന്ന് പറഞ്ഞതിലൂടെ വാലന്റീന തെരേ ഷ്കോവ ഉദ്ദേശിച്ചത് അവരുടെ നേട്ടം അവരുടെ പരിശ്രമത്തിന്റെ മാത്രമല്ല, മറ്റ് പലരുടെയും പരിശ്രമ ത്തിന്റെയും ഫലമാണെന്നാണ്. സ്ത്രീകളെ മാറ്റിനിർത്തി ബഹിരാകാശ യാത്രകൾ വികസിപ്പിക്കാൻ പറ്റുകയില്ല എന്നാണ്.

Question 5.
Have you heard of other women who have inspiring achievements like her? Name a few.
അവരെപ്പോലെ പ്രചോദനാത്മകമായ നേട്ടങ്ങൾ കൈവരിച്ച മറ്റ് സ്ത്രീകളെ കുറിച്ച് നിങ്ങൾ കേട്ടി ട്ടുണ്ടോ? കുറച്ച് പേരുടെ പേരുകൾ പറയു.
Answer:
Yes, I have heard of other women who have inspiring achievements like her.
ഉവ്വ്, കേട്ടിട്ടുണ്ട്, അവരെപ്പോലെ പ്രചോദനാത്മകമായ നേട്ടങ്ങൾ ഞാൻ കേട്ടിട്ടുണ്ട്.
Some of them are:
Sally Ride, the first American woman in space.
അവരിൽ ചിലർ:
ബഹിരാകാശത്തെ ആദ്യത്തെ അമേരിക്കൻ വനിത സാലി റൈഡ്.

Mae Jemison, the first African American woman in space
ബഹിരാകാശത്തെ ആദ്യത്തെ ആഫ്രിക്കൻ അമേരിക്കൻ വനിത മേ ജെമിസൺ

Peggy Whitson, the first female commander of the International Space Station.
അന്താരാഷ്ട്ര ബഹിരാകാശ നിലയത്തിന്റെ ആദ്യ വനിതാ കമാന്ററായ പെഗ്ഗി വിറ്റ്സൺ.

Cosmonaut Svetlana Savitskaya, the first to perform a spacewalk;
ആദ്യമായി ബഹിരാകാശ നടത്തിയ ബഹിരാകാശ സഞ്ചാരി സാന സാവിറ്റ്സ്കായ

Ellen Ochoa, the first Hispanic woman in space;
ബഹിരാകാശത്തെ ആദ്യത്തെ ഹിസ്പാനിക് വനിത എല്ലെൻ ഒച്ചോവ

Kalpana Chawla, the Indian-American astronaut and aerospace engineer who was the first woman of Indian origin to fly to space.
ബഹിരാകാശത്തേക്ക് പറന്ന ആദ്യ ഇന്ത്യൻ വംശജയായ ഇന്ത്യൻ – അമേരിക്കൻ ബഹിരാകാശ സഞ്ചാ രിയും എയ്റോസ്പേസ് എഞ്ചിനീയറുമായ കൽപന ചൗള

Sunita Williams, who spent 608 days, 19 minutes in space.
608 ദിവസവും 19 മിനിറ്റും ബഹിരാകാശത്ത് ചെലവഴിച്ച സുനിത വില്യംസ്.

The Why – Why Girl Questions and Answers

Question 1.
Why did the narrator stop Moyna from catching a snake?
മൊയെ പാമ്പിനെ പിടിക്കുന്നതിൽ നിന്ന് കഥാകാരി തടഞ്ഞത് എന്തുകൊണ്ടാണ്?
Answer:
The narrator stopped Moyna from catching a snake because the snake Moyna was chasing was a cobra, a venomous snake.
മൊ പിന്തുടരുന്ന പാമ്പ് ഒരു വിഷപ്പാമ്പായതിനാലാണ് കഥാകാരി മൊയെ പാമ്പിനെ പിടിക്കുന്നതിൽ നിന്ന് തടഞ്ഞത്.

Question 2.
What was the Samiti meant for?
സമിതി എന്തിനായിരുന്നു രൂപീകരിച്ചത്?
Answer:
The Samiti was meant for people to come and learn reading and writing and simply to sing and dance together.
ആളുകൾ വന്ന് വായിക്കാനും എഴുതാനും പഠിക്കാനും ഒരുമിച്ച് പാടാനും നൃത്തം ചെയ്യാനും വേണ്ടിയായിരുന്നു സമിതി രൂപീകരിച്ചത്.

Question 3.
What does Moyna do for her family?
മായ തന്റെ കുടുംബത്തിനായി എന്താണ് ചെയ്യുന്നത് ?
Answer:
Moyna does many things for her family. She brings the goats home, collects firewood, fetches water and lays traps for the birds.
മൊന്ന് തന്റെ കുടുംബത്തിനായി നിരവധി കാര്യങ്ങൾ ചെയ്യുന്നു. അവൾ ആടുകളെ വീട്ടി ലേക്ക് കൊണ്ടുവരുന്നു. വിറക് ശേഖരിക്കുന്നു. വെള്ളം കൊണ്ടുവരുന്നു. പക്ഷികൾക്കായി കെണി
യൊരുക്കുന്നു.

Question 4.
Why did the postmaster call Moyna the why-why girl?
പോസ്റ്റ് മാസ്റ്റർ മൊയെ എന്തുകൊണ്ടാണ് “വൈ-വൈ” പെൺകുട്ടി എന്ന് വിളിക്കു ന്നത്?
Answer:
The postmaster called Moyna the why-why girl because she asked so many questions, starting with ‘why”?
‘എന്തുകൊണ്ട്’ എന്ന് തുടങ്ങുന്ന നിരവധി ചോദ്യങ്ങൾ ചോദിച്ചതിനാലാണ് പോസ്റ്റ് മാസ്റ്റർ മൊയയെ “എന്തുകൊണ്ട് – എന്തുകൊണ്ട് പെൺകുട്ടി” എന്ന് വിളിച്ചത്.

Question 5.
Why did Moyna decide to learn to read?
എന്തുകൊണ്ടാണ് മൊയ് വായിക്കാൻ പഠിക്കാൻ തീരുമാനിച്ചത്?
Answer:
Moyna decided to learn to read to find answers to her questions.
തന്റെ ചോദ്യങ്ങൾക്ക് ഉത്തരം കണ്ടെത്താനാണ് മൊയ് വായിക്കാൻ പഠിക്കാൻ തീരുമാനിച്ചത്.

Question 6.
Why do stars look smaller than the sun?
നക്ഷത്രങ്ങൾ സൂര്യനേക്കാൾ ചെറുതായി കാണപ്പെടുന്നത് എന്തുകൊണ്ട്
Answer:
Stars look smaller than the sun because they are far away from us whereas the sun looks bigger as it is nearer.
നക്ഷത്രങ്ങൾ സൂര്യനേക്കാൾ ചെറുതായി കാണപ്പെടുന്നത് അവ നമ്മിൽ നിന്ന് വളരെ അകലെ യായതിനാലും സൂര്യൻ നമ്മുടെ അടുത്തായതുകൊണ്ട് വലുതായി കാണപ്പെടുന്നതിനാലുമാണ്.

Question 7.
How do we know that Moyna was speaking like a teacher?
മായ ഒരു അധ്യാപികയെപ്പോലെയാണ് സംസാരിച്ചതെന്ന് നമുക്ക് എങ്ങനെ അറിയാം?
Answer:
We know that Moyna was speaking like a teacher because she was telling her little sister and elder brother to plant trees, wash their hands before they eat, and attend the classes at the Samiti.
മൊ ഒരു അധ്യാപികയെപ്പോലെയാണ് സംസാരിച്ചതെന്ന് നമുക്കറിയാം. കാരണം അവൾ തന്റെ അനുജത്തിയോടും ജ്യേഷ്ഠനോടും മരങ്ങൾ നടാനും, ഭക്ഷണം കഴിക്കുന്നതിന് മുമ്പ് കൈ കഴുകാനും, സമിതിയിലെ ക്ലാസുകളിൽ പങ്കെടുക്കാനും പറഞ്ഞു.

Question 8.
How did Moyna motivate children?
മൊ കുട്ടികളെ എങ്ങനെ പ്രചോദിപ്പിച്ചു
Answer:
Moyna motivated children by asking them not to be lazy and ask her questions like why mosquitoes should be destroyed and why the pole star is always in the northern sky. മടിയന്മാരാകരുതെന്നും, കൊതുകുകളെ എന്തുകൊണ്ട് നശിപ്പിക്കണം, ധ്രുവനക്ഷത്രം എല്ലാ പോഴും വടക്കൻ ആകാശത്ത് എന്തുകൊണ്ടാണ് കാണപ്പെടുന്നത് എന്നതുപോലുള്ള ചോദ്യ ങ്ങൾ ചോദിക്കണമെന്നും മൊയ കുട്ടികളോട് ചോദിച്ചുകൊണ്ട് അവരെ പ്രചോദിപ്പിച്ചു.

The Why – Why Girl Activities

The Why – Why Girl Class 6 Question Answer – Activity 1

Look at the following questions raised by Moyna:
Why shouldn’t I catch a cobra?
Why do we live in a leaf hut?
Why can’t we eat rice twice a day?
Like Moyna, you too might have a number of “why” questions” in your mind. Frame some ‘why’ questions on the themes given on p. 102. One question is given on each theme. Here are two more questions on each. You may add more.

1. Nature: Why is the ocean blue?
Why don’t we see the moon and the stars during the day time?
Why do we have different seasons?

2. Technology: Why do we use headphones?
Why is it dangerous to watch TV for long periods continuously?
Why don’t we use solar energy more in our homes?

3. Food: Why is it not good to eat too many chocolates?
Why do people say that fast foods are dangerous for health?
Why can’t we eat things like chicken and meat for all our meals?

4. Health: Why should we wash our hands before eating?
Why can’t we fill our stomachs with the kinds of food we like?
Why are exercises necessary to be healthy?

5. Social life: Why do we celebrate festivals?
Why do we invite relatives and friends for weddings and such things?
Why do we greet people when we meet them?

Class 6 English The Why – Why Girl Activities Pdf- Activity 2

Can you think of a few meaningful “why” questions to match the responses given in the pictures below? Write them in the space provided.

1. Why are you late?
2. Why are you so happy today?
3. Why did not you answer the last question in the homework?
4. Why should we eat healthy food?
5. Why are you not writing?
6. Why are you sad?

The Why – Why Girl Class 6 Questions and Answers Pdf – Activity 3

Read this sentence from the story:
Many stars are bigger than the sun.
We use different words to compare things. Here, we are comparing the stars and the sun using the word ‘bigger’.

Now, read the following sentences:
A rabbit is fast.
A deer is faster than a rabbit.
A cheetah is the fastest of all.

Look at the information given below.

We see that their ages are different.
a) Eric is young. (positive) – Single thing, no comparison.
b) Alex is younger than Loris. (comparative) – comparing two things.
c) Eric is the youngest of all. (superlative) – comparing more than two things. EXAM POINT

To make comparisons we add ‘er’ and ‘est’ to most adjectives :
rich richer – richest
poor – poorer – poorest
high-higher – highest

But if the word is long like ‘beautiful, important, intelligent’ we add more and most to make their comparatives and superlatives. Thus we have:
beautiful – more beautiful – most beautiful
important – more important – most important
intelligent – more intelligent – most intelligent

a) Now, look at the information about Alex, Eric and Loris. Write about their height and strength, making a comparison.
_________________________________________
_________________________________________
_________________________________________
Answer:
Eric is tall, Alex is taller and Loris is the tallest.
Eric is strong, Alex is stronger and Loris is the strongest.

b) Make five sentences by comparing the features and qualities of Alex, Eric and Loris.
e.g. Loris is taller than Eric.
Answer:
i) Loris is young, Alex is younger and Eric is the youngest.
ii) Eric is tall, Alex is taller and Loris is the tallest.
iii) Eric is strong, Alex is stronger and Loris is the strongest.
iv) Loris is creative, Alex is more creative, and Eric is the most creative.
v) Loris is confident, Eric is more confident and Alex is the most confident.

c) Look at the pictures below and fill in the spaces.

Answer:

Class 6 English The Why – Why Girl Question Answer – Activity 4

Moyna became a teacher at the Samiti after studying in the village school. The Samiti is planning to celebrate “Tribal Pride Day”. They have decided to felicitate Moyna on her achievement.
Here is a notice by the Samiti. Read it.

Your school is planning a special programme to felicitate your friend on her amazing achievement at the National Athletic meet. Imagine you are in charge of organizing the event. Draft a notice to invite people to the programme.
_________________________________________
_________________________________________
_________________________________________
_________________________________________
Answer:

Std 6 English The Why – Why Girl Question Answer – Activity 5

Read the following sentences from the story.

Why do you read books before you go to sleep?
Because books have the answers to your ‘why’s!

Moyna went to the library to get answers for all her ‘why’s. Moyna used to prepare notes of the books she read. Here is an example. Read it.

Now, search for an interesting book in your library, read it and prepare a short note to be presented at the School English Club.
_________________________________________
_________________________________________
_________________________________________
_________________________________________
_________________________________________
Answer:

The Why – Why Girl Questions and Answers – Activity 6

Moyna, the curious girl from our story, keeps a diary to record her adventures and thoughts. A part of it gets wet in the rain and can’t be read. Help Moyna restore the last part.

Answer:
MOYNA’S DIARY

22/11/2025

Dear Diary,

Today was a fun day. It appeared that it might rain, but I still wanted to go outside. When I went to the riverside I saw a boy crying. I went to him and asked him why he was crying. First he was unwilling to talk to me. But then he said that he had lost his golden chain. His parents would be so angry when they found out the loss. I consoled him by saying I will also help him in the search for his lost golden chain. He said he had it when he came to the riverbank. He was running with some boys and playing some games. I joined him in the search. I then found it lying near a bench. I picked it up and gave it to him. He was overjoyed and thanked me profusely for my help.
I will never forget his joyful face on my finding his lost golden chain.

Activity 7

One day, Moyna’s teacher took the class for a nature walk and the children were very happy. Look at the picture carefully and describe what you see and what you feel about it.

Answer:
In the picture I see a teacher taking her students for a nature walk. They all seem t be very happy and excited. I see the teacher pointing to at something, perhaps some birds, sitting on the branch of a tree. There are many trees around and they are tall. I can see different types of flowers on the ground. Some of them are yellow and some are white. Together they make the place very beautiful. The hills beyond the small lake look majestic. On the whole the picture presents a beautiful scene of nature.

Activity 8

Write a short description of the given picture. You may consider the following points while writing the description.

Answer:
The theme of the picture is village life. We can see a flowing river and its banks. Some people are crossing the river in about. Their houses are on the other side of the river. On the banks of the river there are coconut trees. We can see birds flying about. We can see a woman washing things in the river water. There are some ducks in the stream. The woman walking on the left bank of the stream seems to be going to collect water. The bird sitting on the trunk of the tree on the left bank seems to be looking for worms to eat. It is a fine picture of village life.

Parents often use SCERT Kerala Syllabus 6th Standard English Textbook Solutions Unit 4 Chapter 2 The Heart of a Woman Textual Questions and Answers Activities Notes Pdf Download to assist their kids with homework.

Class 6 English The Heart of a Woman Activities Question Answer

The Heart of a Woman Class 6 Questions and Answers

The Heart of a Woman Questions and Answers

Question 1.
How does “the heart of a woman” fly at the beginning of the poem?
കവിതയുടെ തുടക്കത്തിൽ “ഒരു സ്ത്രീയുടെ ഹൃദയം എങ്ങനെയാണ് പറക്കുന്നത്?
Answer:
At the beginning of the poem “the heart of a woman” flies like a bird flying alone, softly and restlessly.
കവിതയുടെ തുടക്കത്തിൽ “ഒരു സ്ത്രീയുടെ ഹൃദയം “ഒറ്റയ്ക്ക് പറക്കുന്ന പക്ഷിയെപ്പോലെ, മൃദുവായും അസ്വസ്ഥമായും പറക്കുന്നു.

Question 2.
What is the heart of the woman compared to?
സ്ത്രീയുടെ ഹൃദയം എന്തുമായാണ് താരതമ്യപ്പെടുത്തിരിയിക്കുന്നത്?
Answer:
The heart of the woman is compared to a bird.
സ്ത്രീയുടെ ഹൃദയത്തെ ഒരു പക്ഷിയുമായി താരതമ്യപ്പെടുത്തിരിയിക്കുന്നു.

Question 3.
Where does the heart roam? When does it fall back?
ഹൃദയം എവിടെയാണ് കറങ്ങുന്നത്? എപ്പോഴാണ് അത് പിന്നോട്ട് പോകുന്നത്?
Answer:
The heart roams through the ups and downs of life. It falls back at night.
ജീവിതത്തിന്റെ ഉയർച്ച താഴ്ചകളിലൂടെ ഹൃദയം അലയുന്നു. രാത്രിയിൽ അത് പിന്നോട്ട് പോകുന്നു.

Question 4.
Where does the heart enter its plight?
ഹൃദയം അതിന്റെ ദുരവസ്ഥയിലേക്ക് എവിടെയാണ് പ്രവേശിക്കുന്നത്?
Answer:
The heart enters its plight in an alien cage.
അന്യഗ്രഹ കൂട്ടിൽ ഹൃദയം അതിന്റെ ദുരവസ്ഥയിലേക്ക് പ്രവേശിക്കുന്നു.

Question 5.
What does the heart try to forget when it is in a cage?
ഒരു കൂട്ടിൽ ആയിരിക്കുമ്പോൾ ഹൃദയം എന്താണ് മറക്കാൻ ശ്രമിക്കുന്നത്?
Answer:
When it is in a cage, the heart tries to forget its dreams of the stars, dream of success and joy.
ഒരു കൂട്ടിൽ ആയിരിക്കുമ്പോൾ, നക്ഷത്രങ്ങളെക്കുറിച്ചുള്ള സ്വപ്നങ്ങൾ, വിജയത്തിന്റെയും സന്തോഷത്തിന്റെയും സ്വപ്നങ്ങൾ എന്നിവ മറക്കാൻ ഹൃദയം ശ്രമിക്കുന്നു.

Question 6.
In the last line, the poet uses the word ‘break’ three times. Why?
അവസാന വരിയിൽ, കവി ‘ബ്രേക്ക് ‘ എന്ന വാക്ക് മൂന്ന് തവണ ഉപയോഗിക്കുന്നു എന്തു കൊണ്ട്?
Answer:
In the last line, the poet uses the word ‘break’ three times to emphasise how broken the heart of the woman is and how sad she is.
അവസാന വരിയിൽ, സ്ത്രീയുടെ ഹൃദയം എത്രത്തോളം തകർന്നിരിക്കുന്നുവെന്നും അവൾ എത്ര ദുഃഖിതയാണെന്നും ഊന്നിപ്പറയാൻ കവി ‘ബ്രേക്ക് ‘ എന്ന വാക്ക് മൂന്ന് തവണ ഉപയോ ഗിക്കുന്നു.

Question 7.
What do the ‘sheltering bars’ in the poem mean?
കവിതയിലെ ‘ഷെൽട്ടറിംഗ് ബാറുകൾ ‘ എന്താണ് അർത്ഥമാക്കുന്നത്?
Answer:
The “sheltering bars” refer to the confinement of societal expectations and domestic life, which are ironically presented as a “shelter”. They are actually a prison for a woman’s spirit. These bars symbolize the limitations that prevent a woman from achieving the freedom as represented by the free-flying bird.
“ഷെൽട്ടറിംഗ് ബാറുകൾ” എന്നത് സാമൂഹിക പ്രതീക്ഷകളുടെയും ഗാർഹിക ജീവിതത്തിന്റെയും തടവറയെ സൂചിപ്പിക്കുന്നു. അവയെ വിരോധാഭാസമായി “ഷെൽട്ടർ” എന്ന് അവതിപ്പിക്കുന്നു. അവ യഥാർത്ഥത്തിൽ ഒരു സ്ത്രീയുടെ ആത്മാവിനുള്ള ഒരു തടവറയാണ്. സ്വതന്ത്രമായി പറ ക്കുന്ന പക്ഷി പ്രതിനിധീകരിക്കുന്ന സ്വാതന്ത്ര്യം നേടുന്നതിൽ നിന്ന് ഒരു സ്ത്രീയെ തടയുന്ന പരിമിതികളെ ഈ ബാറുകൾ പ്രതീകപ്പെടുത്തുന്നു.

The Heart of a Woman Activities

The Heart of a Woman Class 6 Question Answer – Activity 1

Look at these lines taken from the poem:
The heart of a woman goes forth with the dawn,
As a lone bird, soft winging, so restlessly on,
Afar o’er life’s turrets and vales does it roam
In the wake of those echoes the heart calls home.
The last words of the 4 lines are: dawn, on, roam, home.
Dawn rhymes with on and roam rhymes with home.

• dawn – on
• roam – home

Now, look at the second stanza and find out the rhyming pairs.
The rhyming pairs of the second stanza are:
_________
_________
Answer:
night – plight
stars – bars

Class 6 English The Heart of a Woman Activities Pdf- Activity 2

Read the following lines from the poem:
The heart of a woman goes forth with the dawn,
As a lone bird, soft winging, so restlessly on,
Here, the heart of a woman is compared to a lone bird.
Such a comparison is called simile.

a) Now, read the following lines and find the pairs of words which are compared to each other:
The moon shines bright as clear as glass
Like a silver lantern, lighting up the pass
The stars twinkle last, as diamonds in the sea
As busy as bees fluttering wild and free.
Here,
i) The moon is compared to glass and also to a silver lantern.
ii) _____________________________________
Answer:
The stars are compared to diamonds in the sea and also to the busy bees.

b) Complete the following sentences using appropriate words.
1. I am as brave as…………………………………
2. I run like ……………………………………………
3. He crawls like ……………………………………
4. She is as strong as ………………………………
Answer:
1. I am as a brave as a lion.
2. I run like a deer.
3. He crawls like a worm.
4. She is as strong as a wrestler.

The Heart of a Woman Class 6 Questions and Answers Pdf – ActMti 3

The two stanzas in the poem have two different moods. The first stanza is hopeful and dreamy, but the other stanza is dejected and sorrowful. Let us pick out the words suitable for each from the brackets and write them in the appropriate columns.
(dawn, dreamed of the stars, goes forth, soft winging, alien cage, calls home, falls back, restlessly on, plight, roam, breaks, sheltering bars)

Answer:
Hopeful and Dreamy (Stanza 1)

• dawn
• dreamed of the stars
• goes forth
• soft winging
• restlessly on
• roam

Dejected and sorrowful (Stanza 2)

• alien cage
• calls home
• falls back
• plight
• breaks
• sheltering bars

Class 6 English The Heart of a Woman Question Answer – Activity 4

Let’s revisit the poem and complete The Poetry Treasure Map.

Answer:

Expert Teachers at HSSLive.Guru has created Kerala Syllabus 6th Standard Social Science Notes Pdf Download English Medium and Malayalam Medium of SCERT Class 6 Social Science Solutions Notes Pdf, Class 6 Social Science Notes Kerala Syllabus, 6 Standard Social Science Question Answer are part of Kerala Syllabus 6th Standard Textbooks Solutions. Here we have given 6th Standard Social Science Notes Pdf in English Medium of State Syllabus Class 6 Social Science Notes Pdf Part 1 and Part 2.

SCERT Class 6 Social Science Solutions

Class 6 Social Science Notes Kerala Syllabus

6th Standard Social Science Notes Pdf in English Medium Part 1

• Chapter 1 Early Humans and Civilizations Class 6 Notes
• Chapter 2 Early States Class 6 Notes
• Chapter 3 State and Government Class 6 Notes
• Chapter 4 From the Globe to the Map Class 6 Notes
• Chapter 5 Culture and Cultural Diversities Class 6 Notes
• Chapter 6 From Agriculture to Industry Class 6 Notes
• Chapter 7 Through the Continents Class 6 Notes

State Syllabus Class 6 Social Science Notes Pdf Part 2

• Chapter 8 Towards South Indian History Class 6 Notes
• Chapter 9 An Introduction to Constitution Class 6 Notes
• Chapter 10 Through the Oceans Class 6 Notes
• Chapter 11 Let’s Save for the Future Class 6 Notes
• Chapter 12 Japan: History and the Present Class 6 Notes

SCERT Class 6 Social Science Solutions (Extra Questions)

1. Early Humans and Civilizations Class 6 Important Questions
2. Early States Class 6 Important Questions
3. State and Government Class 6 Important Questions
4. From the Globe to the Map Class 6 Important Questions
5. Culture and Cultural Diversities Class 6 Important Questions
6. From Agriculture to Industry Class 6 Important Questions
7. Through the Continents Class 6 Important Questions
8. Towards South Indian History Class 6 Important Questions
9. An Introduction to Constitution Class 6 Important Questions
10. Through the Oceans Class 6 Important Questions
11. Let’s Save for the Future Class 6 Important Questions
12. Japan: History and the Present Class 6 Important Questions

Kerala Syllabus 6th Standard Social Science Question Paper English Medium

• 6th Standard Social Science Annual Exam Question Paper 2023-24
• 6th Standard Social Science First Term Question Paper 2022-23
• 6th Standard Social Science Second Term Question Paper 2022-23
• 6th Standard Social Science Annual Exam Question Paper 2022-23
• 6th Standard Social Science Model Question Paper Kerala Syllabus

Std 6 Social Science Notes Pdf Malayalam Medium

Std 6 Social Science Notes Pdf Malayalam Medium Download Part 1

• Chapter 1 മധ്യകാല ഇന്ത്യ അധികാരകേന്ദ്രങ്ങൾ Notes
• Chapter 2 മധ്യകാല ഇന്ത്യ സമൂഹം വിഭവം വിനിമയം Notes
• Chapter 3 കേരളം മണ്ണും മഴയും മനുഷ്യനും Notes
• Chapter 4 ഉല്പാദനപ്രക്രിയയിലൂടെ Notes
• Chapter 5 ഭൂമി കഥയും കാര്യവും Notes
• Chapter 6 വൈവിധ്യങ്ങളുടെ ലോകം Notes

SCERT Class 6 Social Science Notes Pdf Malayalam Medium Part 2

• Chapter 7 മധ്യകാല ഇന്ത്യ കലയും സാഹിത്യവും Notes
• Chapter 8 മധ്യകാല ലോകം Notes
• Chapter 9 മധ്യകാല കേരളം Notes
• Chapter 10 ജനാധിപത്യവും അവകാശങ്ങളും Notes
• Chapter 11 സമൂഹജീവിതത്തിലെ വൈവിധ്യം Notes
• Chapter 12 പ്രകൃതിയുടെ വരദാനം Notes

6th Standard Social Science Question Paper Pdf Malayalam Medium

• 6th Standard Social Science First Term Question Paper 2023-24
• 6th Standard Social Science Second Term Question Paper 2023-24
• 6th Standard Social Science Annual Exam Question Paper 2023-24
• 6th Standard Social Science First Term Question Paper 2022-23
• 6th Standard Social Science Second Term Question Paper 2022-23
• 6th Standard Social Science Annual Exam Question Paper 2022-23

We hope the given Kerala SCERT Class 6 Social Science Question Answer, 6th Standard Social Science Notes State Syllabus English Medium of Class 6 Social Science Notes Pdf State Syllabus will help you. If you have any queries regarding Social Science 6th Standard Question Answer, SCERT Class 6 Social Science Notes Pdf Part 1 & 2, drop a comment below and we will get back to you at the earliest.

Expert Teachers at HSSLive.Guru has created Kerala Syllabus 6th Standard English Textbook Solutions Notes Question Answers Pdf Download English Medium of SCERT Class 6 English Solutions, 6th Standard English Activities are part of Kerala Syllabus 6th Standard Textbooks Solutions. Here we have given SCERT 6th Class English Textbook Solutions of Kerala Syllabus 6th Standard English Notes Pdf Part 1 and Part 2.

6th Standard English Textbook Question and Answers Kerala Syllabus

SCERT Class 6 English Solutions

SCERT 6th Class English Textbook Solutions Part 1

6th Standard English Unit 1 Question Answer Of Many Hues

• Chapter 1 Names and Names Questions and Answers
• Chapter 2 The Colours of Earth Questions and Answers
• Chapter 3 Crow Boy Questions and Answers

6th Standard English Unit 2 Question Answer Towards New Horizons

• Chapter 1 The Boy Who Harnessed the Wind Questions and Answers
• Chapter 2 The Aeroplane Questions and Answers
• Chapter 3 Mousetronaut Questions and Answers

6th Standard English Unit 3 Question Answer Embracing Differences

• Chapter 1 Six Dots Questions and Answers
• Chapter 2 Hello, I’m a Wheelchair Questions and Answers
• Chapter 3 A Friend Like Simon Questions and Answers

SCERT 6th Class English Textbook Solutions Part 2

6th Standard English Unit 4 Question Answer For Half the Sky

• Chapter 1 The Why – Why Girl Questions and Answers
• Chapter 2 The Heart of a Woman Questions and Answers
• Chapter 3 The Story of Dalda 13 Questions and Answers

6th Standard English Unit 5 Question Answer Hearth and Home

• Chapter 1 Unnikkuttan Goes to School Questions and Answers
• Chapter 2 The Boat Questions and Answers
• Chapter 3 Cousins From Across the Sea Questions and Answers

Kerala Syllabus 6th Standard English Summary

• Names and Names Summary
• The Colours of Earth Summary
• Crow Boy Summary
• The Boy Who Harnessed the Wind Summary
• The Aeroplane Summary
• Mousetronaut Summary
• Six Dots Summary
• Hello, I’m a Wheelchair Summary
• A Friend Like Simon Summary
• The Why – Why Girl Summary
• The Heart of a Woman Summary
• The Story of Dalda 13 Summary
• Unnikkuttan Goes to School Summary
• The Boat Summary
• Cousins From Across the Sea Summary

SCERT 6th Class English Textbook Solutions (Old Syllabus)

Unit 1 Rain of Love

• Chapter 1 Life with Grandfather Questions and Answers
• Chapter 2 The Little Boy and The Old Man Questions and Answers
• Chapter 3 Making a Mango Pickle Questions and Answers

Unit 2 Still We Rise

• Chapter 1 Cinderella Questions and Answers
• Chapter 2 Woman Work Questions and Answers
• Chapter 3 One Child, One Teacher, One Pen and One Book can Change the World Questions and Answers

Unit 3 Glimpses of Nature

• Chapter 1 The Mountain and The Squirrel Questions and Answers
• Chapter 2 The Rightful Inheritors of the Earth Questions and Answers
• Chapter 3 The Book of Nature Questions and Answers

Class 6 English Notes Kerala Syllabus Part 2

6th Standard English Unit 4 Question Answer Work is Worship

• Chapter 1 The Grain as Big as a Hen’s Egg Questions and Answers
• Chapter 2 Clever Carla Questions and Answers
• Chapter 3 The Ploughman Questions and Answers

6th Standard English Unit 5 Question Answer Helping Hands

• Chapter 1 The Champ Questions and Answers
• Chapter 2 A Glass of Milk Questions and Answers
• Chapter 3 If I Can Stop One Heart from Breaking Questions and Answers

6th Standard English Question Paper Kerala Syllabus

• Kerala Syllabus Class 6 English Annual Exam Question Paper 2023-24
• 6th Standard English First Term Question Paper 2022-23
• 6th Standard English Second Term Question Paper 2022-23
• 6th Standard English Annual Exam Question Paper 2022-23
• Std 6 English Annual Exam Question Paper 2021-22
• Class 6 English Annual Exam Question Paper 2018-19
• Kerala Syllabus 6th Standard English Annual Exam Question Paper 2017-18

Kerala Syllabus 6th Standard English Summary (Old Syllabus)

• Life with Grandfather Summary
• The Little Boy and The Old Man Summary
• Making a Mango Pickle Story Summary
• Cinderella Summary
• Woman Work Summary
• One Child One Teacher One Pen and One Book can Change the World Summary
• The Mountain and The Squirrel Summary
• The Rightful Inheritors of the Earth Summary
• The Book of Nature Summary
• The Grain as Big as a Hen’s Egg Summary
• Clever Carla Summary
• The Ploughman Poem Summary
• The Champ Summary
• A Glass of Milk Summary
• If I Can Stop One Heart from Breaking Summary

We hope the given Class 6 English SCERT Solutions, Kerala Syllabus 6th Standard English Question Answers will help you. If you have any queries regarding Class 6 English Notes Kerala Syllabus, 6th Standard English Textbook Pdf with Answers Part 1 and Part 2, drop a comment below and we will get back to you at the earliest.

Expert Teachers at HSSLive.Guru has created Kerala Syllabus Std 6 Basic Science Notes Pdf Malayalam Medium English Medium of SCERT Class 6 Basic Science Notes Textbook Solutions, Basic Science Class 6 Question Answer are part of Kerala Syllabus 6th Standard Textbooks Solutions. Here we have given Basic Science Class 6 Kerala Syllabus Notes Pdf of SCERT Class 6 Basic Science Solutions Part 1 and Part 2.

SCERT Class 6 Basic Science Notes Textbook Solutions

Basic Science Class 6 Question Answer Solutions

Basic Science Class 6 Kerala Syllabus Notes Pdf Part 1

• Class 6 Basic Science Chapter 1 Question Answer – Food for Health Class 6 Notes
• Class 6 Basic Science Chapter 2 Question Answer – Marvel of the Magnetic Realm Class 6 Notes
• Class 6 Basic Science Chapter 3 Question Answer – Let’s Stand Straight Class 6 Notes
• Class 6 Basic Science Chapter 4 Question Answer – Flowering and Fruiting Class 6 Notes
• Class 6 Basic Science Chapter 5 Question Answer – Association of Substances Class 6 Notes

Basic Science for Class 6 Questions and Answers Part 2

• Class 6 Basic Science Chapter 6 Question Answer – Tiny Chambers of Life Class 6 Notes
• Class 6 Basic Science Chapter 7 Question Answer – The World of Changes Class 6 Notes
• Class 6 Basic Science Chapter 8 Question Answer – Motion in Daily Life Class 6 Notes
• Class 6 Basic Science Chapter 9 Question Answer – Better Lifestyle for a Brighter Tomorrow Class 6 Notes

SCERT Class 6 Basic Science Solutions (Extra Questions)

1. Food for Health Class 6 Important Questions
2. Marvel of the Magnetic Realm Class 6 Important Questions
3. Let’s Stand Straight Class 6 Important Questions
4. Flowering and Fruiting Class 6 Important Questions
5. Association of Substances Class 6 Important Questions
6. Tiny Chambers of Life Class 6 Important Questions
7. The World of Changes Class 6 Important Questions
8. Motion in Daily Life Class 6 Important Questions
9. Better Lifestyle for a Brighter Tomorrow Class 6 Important Questions

Class 6 Basic Science Previous Year Question Papers English Medium

• 6th Standard Basic Science First Term Question Paper 2022-23
• 6th Standard Basic Science Second Term Question Paper 2022-23
• 6th Standard Basic Science Annual Exam Question Paper 2022-23
• 6th Standard Basic Science Annual Exam Question Paper 2021-22

Kerala Syllabus 6th Standard Basic Science Question Paper English Medium

• 6th Standard Basic Science Model Question Paper Set 1
• Class 6 Basic Science Model Question Paper Set 2

Std 6 Basic Science Notes Pdf Malayalam Medium

SCERT Class 6 Basic Science Solutions Malayalam Medium Part 1

• Class 6 Basic Science Chapter 1 Malayalam Medium – ജീവന്റെ ചെപ്പുകൾ
• Class 6 Basic Science Chapter 2 Malayalam Medium – മാറ്റത്തിന്റെ പൊരുൾ
• Class 6 Basic Science Chapter 3 Malayalam Medium – പൂവില്‍നിന്ന് പൂവിലേക്ക്
• Class 6 Basic Science Chapter 4 Malayalam Medium – ചലനത്തിനൊപ്പം
• Class 6 Basic Science Chapter 5 Malayalam Medium – ആഹാരം ആരോഗ്യത്തിന്

Std 6 Basic Science Notes Pdf Malayalam Medium Part 2

• Class 6 Basic Science Chapter 6 Malayalam Medium – ഒന്നിച്ചു നിലനിൽക്കാം
• Class 6 Basic Science Chapter 7 Malayalam Medium – ആകർഷിച്ചും വികർഷിച്ചും
• Class 6 Basic Science Chapter 8 Malayalam Medium – തിങ്കളും താരങ്ങളും
• Class 6 Basic Science Chapter 9 Malayalam Medium – ചേർക്കാം പിരിക്കാം
• Class 6 Basic Science Chapter 10 Malayalam Medium – രൂപത്തിനും ബലത്തിനും

Class 6 Basic Science Previous Year Question Papers Malayalam Medium

• Basic Science Class 6 First Term Question Paper 2023-24
• Basic Science Class 6 Second Term Question Paper 2023-24
• Basic Science Class 6 Annual Exam Question Paper 2023-24
• Basic Science Class 6 Annual Exam Question Paper 2021-22

6th Standard Basic Science Question Paper Malayalam Medium

• SCERT Class 6 Basic Science Model Question Paper Set 1
• 6th Std Basic Science Model Question Paper Set 2

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Kerala SCERT Class 6 Hindi Solutions

6th Standard Hindi Question Answer Kerala Syllabus

Kerala Syllabus 6th Standard Hindi Notes Pdf इकाई 1

• Chapter 1 नीली चिड़िया (कविता) – Neeli Chidiya Hindi Poem Question Answer
• Chapter 2 रू रू – Roo Roo Question Answer

Class 6 Hindi Notes Kerala Syllabus इकाई 2

• Chapter 1 बादल (कविता) – Baadal Hindi Poem Question Answer
• Chapter 2 सीगड़ी मछली सूखी क्यों नहीं? – Sigadi Machali Sukhi Kyon Nahin Question Answer

Std 6 Hindi Textbook Solutions इकाई 3

• Chapter 1 मीठा संतरा – Meeta Santara Question Answer
• Chapter 2 चलें – Chalen Question Answer

6th Std Hindi Notes इकाई 4

• Chapter 1 मिले सबको (कविता) – Mile Sabko Hindi Poem Question Answer
• Chapter 2 इच्छू और बिनिया – Ichuu Aur Biniya Question Answer

SCERT Class 6 Hindi Solutions इकाई 5

• Chapter 1 मुन्नू की स्वतंत्रता – Munnu Ki Swatantrata Question Answer
• Chapter 2 उल्टा-पुल्टा (कविता) – Ulta Pulta Hindi Poem Question Answer

∗∗ Kerala Syllabus 6th Standard Hindi Grammar

Kerala Syllabus 6th Standard Hindi Textbook Solutions (Old Syllabus)

इकाई 1

• Chapter 1 बादल दानी (कविता) – Badal Dani Hindi Poem Question Answer
• Chapter 2 बारिश कैसे मिली – Barish Kaise Mili Question Answer

इकाई 2

• Chapter 1 जगमग तारा (कविता) – Jagmag Thara Hindi Poem Question Answer
• ** देशभक्ति गीत – Desh Bhakti Kavita
• Chapter 2 हिंदुस्तान हमारा – Hindustan Hamara Question Answer

इकाई 3

• Chapter 1 इंसानियत की मिसाल – Insaniyat Ki Misal Question Answer
• Chapter 2 मुरझाया फूल (कविता) – Murjhaya Phool Poem Question Answer
• Chapter 3 दो भाई (कहानी) – Do Bhai Question Answer

इकाई 4

• Chapter 1 नन्हा उल्लू (कहानी) – Nanha Ullu Question Answer
• Chapter 2 बबुआ और बूढ़ा (कविता) – Babua Aur Booda Question Answer

इकाई 5

• Chapter 1 ज़मीं को जादू आता है (कविता) – Zameen Ko Jadu Aata Hai Question Answer
• Chapter 2 मार्च – March Question Answer
• Chapter 3 धूप की संदूक (कविता) – Dhoop Ki Sandhook Question Answer

Class 6 Hindi Previous Year Question Paper Kerala Syllabus

• Kerala Syllabus 6th Standard Hindi Annual Exam Question Paper 2023-24
• Kerala Syllabus 6th Standard Hindi First Term Question Paper 2022-23
• Kerala Syllabus 6th Standard Hindi Second Term Question Paper 2022-23
• Kerala Syllabus 6th Standard Hindi Annual Exam Question Paper 2022-23
• Kerala Syllabus 6th Standard Hindi Annual Exam Question Paper 2021-22

Kerala Syllabus 6th Standard Hindi Question Paper Pdf

• Hindi Question Paper Class 6 State Syllabus Set 1
• Class 6 Hindi Question Paper Pdf State Syllabus Set 2

We hope the given Kerala Syllabus 6th Standard Hindi Notes Pdf of SCERT Class 6 Hindi Solutions will help you. If you have any queries regarding 6th Standard Hindi Textbook Pdf with Answers of Class 6 Hindi Notes Kerala Syllabus Part 1 and Part 2, drop a comment below and we will get back to you at the earliest.

Expert Teachers at HSSLive.Guru has created Kerala Syllabus 6th Standard Maths Textbook Solutions Notes Pdf Download English & Malayalam Medium of SCERT Class 6 Maths Solutions are part of Kerala Syllabus 6th Standard Textbooks Solutions. Here HSSLive.Guru has given SCERT 6th Class Maths Textbook Solutions of Class 6 Maths Solutions Kerala Syllabus Part 1 and Part 2.

SCERT Class 6 Maths Solutions Pdf

Kerala Syllabus 6th Standard Maths Solutions Pdf Part 1

• Class 6 Maths Chapter 1 Kerala Syllabus – Angles Class 6 Questions and Answers
• Class 6 Maths Chapter 2 Kerala Syllabus – One Fraction Many Forms Class 6 Questions and Answers
• Class 6 Maths Chapter 3 Kerala Syllabus – Volume Class 6 Questions and Answers
• Class 6 Maths Chapter 4 Kerala Syllabus – Arithmetic of Parts Class 6 Questions and Answers
• Class 6 Maths Chapter 5 Kerala Syllabus – Decimal Forms Class 6 Questions and Answers
• Class 6 Maths Chapter 6 Kerala Syllabus – Multiples and Factors Class 6 Questions and Answers

Class 6 Maths SCERT Solutions Part 2

• Class 6 Maths Chapter 7 Kerala Syllabus – Money Math Class 6 Questions and Answers
• Class 6 Maths Chapter 8 Kerala Syllabus – Unchanging Relations Class 6 Questions and Answers
• Class 6 Maths Chapter 9 Kerala Syllabus – Lines and Angles Class 6 Questions and Answers
• Class 6 Maths Chapter 10 Kerala Syllabus – Number Relations Class 6 Questions and Answers
• Class 6 Maths Chapter 11 Kerala Syllabus – Letter Math Class 6 Questions and Answers
• Class 6 Maths Chapter 12 Kerala Syllabus – Data Pictures Class 6 Questions and Answers

6th Standard Maths Question Paper with Answers Kerala Syllabus

• 6th Standard Maths Annual Exam Question Paper 2023-24
• 6th Standard Maths First Term Question Paper 2022-23
• 6th Standard Maths Second Term Question Paper 2022-23
• 6th Standard Maths Annual Exam Question Paper 2022-23
• 6th Standard Maths Annual Exam Question Paper 2021-22
• 6th Standard Maths First Term Model Question Paper
• 6th Standard Maths Mid Term Model Question Paper
• 6th Standard Maths Annual Exam Model Question Paper

SCERT Class 6 Maths Solutions Malayalam Medium

6th Std Maths Textbook Solutions Pdf Malayalam Medium Part 1

• Class 6 Maths Chapter 1 Malayalam Medium – കോണുകൾ
• Class 6 Maths Chapter 2 Malayalam Medium – ശരാശരി
• Class 6 Maths Chapter 3 Malayalam Medium – ഭിന്നസംഖ്യകൾ
• Class 6 Maths Chapter 4 Malayalam Medium – വ്യാപ്തം
• Class 6 Maths Chapter 5 Malayalam Medium – ദശാംശരൂപങ്ങൾ

6th Class Maths Textbook Solutions Pdf Malayalam Medium Part 2

• Class 6 Maths Chapter 6 Malayalam Medium – സംഖ്യകൾ
• Class 6 Maths Chapter 7 Malayalam Medium – ദശാംശരീതി
• Class 6 Maths Chapter 8 Malayalam Medium – കോണുകൾ ചേരുമ്പോൾ
• Class 6 Maths Chapter 9 Malayalam Medium – നൂറിൽ എത്ര
• Class 6 Maths Chapter 10 Malayalam Medium – അക്ഷരഗണിതം
• Class 6 Maths Chapter 11 Malayalam Medium – സ്ഥിതിവിവരക്കണക്കുകൾ

Class 6 Maths Previous Year Question Paper Kerala Syllabus Malayalam Medium

• 6th Standard Maths First Term Question Paper 2023-24
• 6th Standard Maths Second Term Question Paper 2023-24
• 6th Standard Maths Annual Exam Question Paper 2023-24
• 6th Standard Maths First Term Question Paper 2022-23
• 6th Standard Maths Second Term Question Paper 2022-23
• 6th Standard Maths Annual Exam Question Paper 2022-23
• 6th Standard Maths Annual Exam Question Paper 2021-22
• 6th Standard Maths Second Term Question Paper 2019-20
• 6th Standard Maths First Term Model Question Paper
• 6th Standard Maths Mid Term Model Question Paper
• 6th Standard Maths Annual Exam Model Question Paper

We hope the given Class 6 Maths SCERT Solutions, Class 6 Kerala Syllabus Maths Solutions English Medium will help you. If you have any queries regarding 6th Std Maths Textbook Solutions Kerala Syllabus, 6th Standard Maths Textbook Answers Solutions Notes Pdf Part 1 and Part 2, drop a comment below and we will get back to you at the earliest.

Students often refer to Kerala State Syllabus SCERT Class 6 Maths Solutions and Class 6 Maths Chapter 5 Decimal Forms Questions and Answers Notes Pdf to clear their doubts.

SCERT Class 6 Maths Chapter 5 Solutions Decimal Forms

Class 6 Kerala Syllabus Maths Solutions Chapter 5 Decimal Forms Questions and Answers

Decimal Forms Class 6 Questions and Answers Kerala Syllabus

Decimal Places (Page No. 69)

Question 1.
Split the numbers below according to place value:
(i) 4.5
(ii) 4.57
(iii) 4.572
(iv) 45.72
(v) 457.2
Answer:

Textbook Page No. 71

Question 1.
Now try to write 4 kilograms and 55 grams as kilograms in decimal form.
Answer:
4 kilograms 55 grams
55 grams means \(\frac {55}{1000}\) kilograms.
So, 4 kilograms 55 grams = 4\(\frac {55}{1000}\) kilograms
Splitting 4\(\frac {55}{1000}\) according to place value

So we can write the decimal form of 4\(\frac {55}{1000}\) as 4.055

Question 2.
Convert the measures below into the measures specified, using fractions and decimal forms.

Answer:

Decimals and Fractions (Page No. 74)

Question 1.
The decimal form of some numbers is given below. Write each of them as a fraction with a denominator of 10, 100, or 1000.
(i) 3.7
(ii) 3.07
(iii) 30.7
(iv) 3.72
(v) 37.2
(vi) 3.072
(vii) 30.72
Answer:
(i) \(\frac {37}{10}\)
(ii) \(\frac {307}{100}\)
(iii) \(\frac {307}{10}\)
(iv) \(\frac {372}{100}\)
(v) \(\frac {372}{10}\)
(vi) \(\frac {3072}{1000}\)
(vii) \(\frac {3072}{100}\)

Question 2.
Write the decimal form of the fractions given below.
(i) \(\frac {51}{100}\)
(ii) \(\frac {513}{10}\)
(iii) \(\frac {513}{100}\)
(iv) \(\frac {513}{1000}\)
(v) \(\frac {5130}{1000}\)
Answer:
(i) 5.1
(ii) 51.3
(iii) 5.13
(iv) 0.513
(v) 5.13

Addition and Subtraction (Page No. 79)

Question 1.
Anu made an 8.5 metre long festoon and Sarah made a 7.8 metre long one to decorate their classroom for the school anniversary. What is the total length of the festoon they made?
Answer:
Length of the festoon Anu made = 8.5 metres
Length of the Festoon Sarah made = 7.8 metres
Removing the measures and converting into a fraction
8.5 = \(\frac {85}{10}\)
7.8 = \(\frac {78}{10}\)
Adding the fraction
\(\frac{85}{10}+\frac{78}{10}=\frac{163}{10}\)
Converting to decimals
\(\frac {163}{10}\) = 16.3
Total length of the festoon = 16.3 metres

Question 2.
Amal needs 2.25 metres of cloth and Sagar, 1.85 metres for a school uniform. How many metres of cloth in all?
Answer:
Length of the cloth Amal needs for the school uniform = 2.25 metres
Length of the cloth Sagar needs for the school uniform = 1.85 metres
Removing measures and converting to fractions
2.25 = \(\frac {225}{100}\)
1.85 = \(\frac {185}{100}\)
Adding these fractions
\(\frac{225}{100}+\frac{185}{100}=\frac{200+100+25+85}{100}=\frac{410}{100}\)
Converting this to decimals \(\frac {410}{100}\) = 4.1
Total length of cloth in all is 4.1 metres.

Question 3.
A tin weighs 2.85 kilograms, and it is filled with 12.5 kilograms of rice. What is the total weight?
Answer:
Weight of the tin = 2.85 kilograms
Amount of rice filled in the tin = 12.5 kilograms
Removing measures and converting to fractions
2.85 = \(\frac {285}{100}\)
12.5 = \(\frac {125}{10}\)
Adding these fractions
\(\frac{285}{100}+\frac{125}{10}\)
To add these changing \(\frac {125}{10}\) to a form with denominator
\(\frac{125 \times 10}{10 \times 10}=\frac{1250}{100}\)
Adding these fractions,
\(\frac{1250}{100}+\frac{285}{100}\)
1000 + 200 + 250 + 85 = 1200 + 335 = 1535
\(\frac{1250}{100}+\frac{285}{100}=\frac{1535}{100}\)
Converting the fractions to decimals
\(\frac {1535}{100}\) = 15.35
Total weight = 15.35 kilograms

Question 4.
Bakul walks 2.25 kilometres in the morning and 1.5 kilometres in the evening every day. What is the total distance she walks each day?
Answer:
Distance Bakul walks in the morning = 2.25 kilometres
Distance Bakul walks in the evening = 1.5 kilometres
Total distance she walks each day = 2.25 kilometres + 1.5 kilometres
Removing measures and converting to fractions
2.25 = \(\frac {225}{100}\)
1.5 = \(\frac {15}{10}\)
To add these, change \(\frac {15}{10}\) to a form with denominator 100
\(\frac{15 \times 10}{10 \times 10}=\frac{150}{100}\)
Adding the fractions
\(\frac{225}{100}+\frac{150}{100}\)
200 + 100 + 25 + 50 = 375
\(\frac{225}{100}+\frac{150}{100}=\frac{375}{100}\)
Converting the fractions to decimals
\(\frac {375}{100}\) = 3.75
Total distance she walks each day = 3.75 kilometres

Question 5.
Two small bottles contain 0.850 litres and 0.375 litres of honey. If both the bottles are emptied into a large bottle, how much honey does it contain?
Answer:
Amount of honey in the first bottle = 0.850 litres
Amount of honey in the second bottle = 0.375 litres
Amount of honey in the large bottle = 0.850 litre + 0.375 litre
Removing measures and making into fractions
0.375 = \(\frac {375}{1000}\)
0.850 = \(\frac {850}{1000}\)
Adding these \(\frac{375}{1000}+\frac{850}{1000}\)
375 + 850 = 300 + 800 + 75 + 50 = 1225
\(\frac{375}{1000}+\frac{850}{1000}=\frac{1225}{1000}\)
Converting the fractions into decimals
\(\frac {1225}{1000}\) = 1.225
Amount of honey in the large bottle = 1.225 litres.

Textbook Page No. 82

Question 1.
From a rod 14.7 metres long, a piece 7.75 metres long is cut off. What is the length of the remaining piece?
Answer:
Length of the long rod = 14.7 metres
Length of the piece cut off from the long rod = 7.75 metres
Length of the remaining piece = 14.7 metre – 7.75 metres
Changing into fractions
14.7 = \(\frac {147}{10}\)
7.75 = \(\frac {775}{100}\)
To subtract change \(\frac {147}{10}\) to a form with denominator 100
\(\frac{147 \times 10}{10 \times 10}=\frac{1470}{100}\)
Subtracting \(\frac{1470}{100}-\frac{775}{100}=\frac{695}{100}\)
Changing back to decimals
\(\frac {695}{100}\) = 6.95
Length of the remaining piece = 6.95 metres.

Question 2.
There were 38.7 kilograms of rice in a sack, and 12.350 kilograms of this were used up. How much rice remains in the sack?
Answer:
Amount of rice in the sack = 38.7 kilograms
Amount of rice used up = 12.350 kilograms
Amount of rice remaining in the sack = 38.7 kilograms – 12.350 kilograms
38.7 = \(\frac {387}{10}\)
12.350 = \(\frac {12350}{1000}\)
\(\frac{387}{10}-\frac{12350}{1000}\)
\(\frac{387 \times 100}{10 \times 100}=\frac{38700}{1000}\)
Subtracting \(\frac{38700}{1000}-\frac{12350}{1000}=\frac{26350}{1000}\)
Changing back to decimals
\(\frac {26350}{1000}\) = 26.35
Amount of rice remaining in the sack = 26.35 kilograms

Question 3.
The perimeter of a rectangle is 24 centimetres and the length of one side is 6.4 centimetres. What is the length of the other side?
Answer:
Perimeter of rectangle = 2(length + breadth) = 24 centimetres
Length of one side = 6.4 centimetres
Length of the other side = 12 – 6.4 = 5.6 centimetres

Question 4.
There were 2.50 litres of oil in a bottle, and 0.475 litres of this were used for cooking. How much oil is left in the bottle?
Answer:
Amount of oil in the bottle = 2.50 litres
Amount of oil used for cooking = 0.475 litres
Amount of oil left in the bottle = 2.50 litres – 0.475 litres
2.50 = \(\frac {250}{100}\)
0.475 = \(\frac {475}{1000}\)
\(\frac{250}{100}-\frac{475}{1000}\)
\(\frac{250 \times 10}{100 \times 10}=\frac{2500}{1000}\)
Subtracting \(\frac{2500}{1000}-\frac{475}{1000}=\frac{2025}{1000}\)
Amount of oil remaining = 2.025 litres

Question 5.
What number must we add to 14.32 to get 16.43?
Answer:
Number to be added to 14.32 to get 16.43 = 16.43 – 14.32
16.43 = \(\frac {1643}{100}\)
14.32 = \(\frac {1432}{100}\)
Subtracting \(\frac{1643}{100}-\frac{1432}{100}=\frac{211}{100}\)
Converting back to decimals
\(\frac {211}{100}\) = 2.11

Class 6 Maths Chapter 5 Kerala Syllabus Decimal Forms Questions and Answers

Class 6 Maths Decimal Forms Questions and Answers

Question 1.
Split the numbers below according to place value.
(i) 3.6
(ii) 3.64
(iii) 3.641
(iv) 36.41
(v) 364.1
Answer:

Question 2.
Convert the following measures into the specified forms, using both fractions and decimal forms.

Answer:

Question 3.
The decimal form of some numbers is given below. Write each of them as a fraction with a denominator of 10, 100, or 1000.
(i) 4.2
(ii) 4.02
(iii) 40.2
(iv) 4.25
(v) 42.5
(vi) 4.025
(vii) 40.25
Answer:
(i) \(\frac {42}{10}\)
(ii) \(\frac {402}{100}\)
(iii) \(\frac {402}{10}\)
(iv) \(\frac {425}{100}\)
(v) \(\frac {4025}{1000}\)
(vi) \(\frac {4025}{100}\)

Question 4.
Write the decimal form of the fractions given below.
(i) \(\frac {9}{10}\)
(ii) \(\frac {47}{100}\)
(iii) \(\frac {381}{1000}\)
(iv) \(\frac {15}{10}\)
(v) \(\frac {245}{100}\)
(vi) \(\frac {7}{100}\)
(vii) \(\frac {82}{1000}\)
(viii) \(\frac {3456}{1000}\)
Answer:
(i) 0.9
(ii) 0.47
(iii) 0.381
(iv) 1.5
(v) 2.45
(vi) 0.07
(vii) 0.082
(viii) 3.456

Question 5.
John ran a distance of 4.25 kilometres and then walked another 2.5 kilometres. What is the total distance he covered?
Answer:
Distance John ran = 4.25 kilometres
Distance he walked = 2.5 kilometres
Total distance he covered = 4.25 kilometres + 2.5 kilometres
Converting into fractions
4.25 = \(\frac {425}{100}\)
25 = \(\frac{25}{10}=\frac{25 \times 10}{10 \times 10}=\frac{250}{100}\)
Adding \(\frac{425}{100}+\frac{250}{100}=\frac{675}{100}\)
Converting to decimals
\(\frac {675}{100}\) = 6.75
Total distance John covered = 6.75 kilometres

Question 6.
A baker has two bags of flour, one with 1.75 kilograms of flour and the other with 2.5 kilograms. If the baker combines all the flour into a single container, what is the total weight of the flour in the container?
Answer:
Total weight of the flour in the container = Amount of flour in Bag 1 + Amount of flour in Bag 2 = 1.75 kilograms + 2.5 kilograms
1.75 = \(\frac {175}{100}\)
2.5 = \(\frac{25}{10}=\frac{25 \times 10}{10 \times 10}=\frac{250}{100}\)
Adding \(\frac{175}{100}+\frac{250}{100}=\frac{425}{100}\)
Converting into decimals
\(\frac {425}{100}\) = 4.25
Total weight of the flour in the container = 4.25 kilograms

Question 7.
A ribbon was 15.8 metres long. If a piece measuring 4.25 metres was cut from it, how much ribbon is left?
Answer:
Length of the ribbon = 15.8 metres
Length of the piece cut off from the ribbon = 4.25 metres
Length of the ribbon left = 15.8 metres – 4.25 metres
15.8 = \(\frac{158}{10}=\frac{158 \times 10}{10 \times 10}=\frac{1580}{100}\)
4.25 = \(\frac {425}{100}\)
Subtracting \(\frac{1580}{100}-\frac{425}{100}=\frac{1155}{100}\)
Converting back to decimals
\(\frac {1155}{100}\) = 11.55
Length of the ribbon left = 11.55 metres

Question 8.
A water tank holds 50.5 litres of water. If 25.5 litres are used for gardening, how much water is left in the tank?
Answer:
Amount of water left in the tank = Amount of water that the water tank can hold – Amount of water used for gardening
50.5 = \(\frac {505}{10}\)
255 = \(\frac {255}{10}\)
Subtracting \(\frac{505}{10}-\frac{255}{10}=\frac{250}{10}\)
Converting to decimals
\(\frac {250}{10}\) = 2.5

Question 9.
A carpenter uses a 2.75-metre board and a 1.5-metre board for a project. What is the total length of the wood used?
Answer:
Total length of the wood used = 2.75 metre + 1.5 metre
2.75 = \(\frac {275}{100}\)
1.5 = \(\frac{15}{10}=\frac{15 \times 10}{10 \times 10}=\frac{150}{100}\)
Adding \(\frac{275}{100}+\frac{150}{100}=\frac{425}{100}\)
Converting to decimals
\(\frac {425}{100}\) = 4.25
Total length of the wood used = 4.25 metres

Question 10.
A plant is 15.6 centimetres tall. How many more centimetres must it grow to reach a height of 20.1 centimetres?
Answer:
Height of the plant = 15.6 centimetres
Target height = 20.1 centimetres
Height the plant must grow = 20.1 centimetres – 15.6 centimetres
20.1 = \(\frac {201}{10}\)
15.6 = \(\frac {156}{10}\)
Subtracting \(\frac{201}{10}-\frac{156}{10}=\frac{45}{10}\)
Converting to decimals
\(\frac {45}{10}\) = 4.5
The plant must grow 4.5 centimetres to reach the target height.

Class 6 Maths Chapter 5 Notes Kerala Syllabus Decimal Forms

→ In the decimal form of a number, the dot (decimal point) separates the whole number part and the fractional part.

→ Digits to the left of the decimal point represent ones, tens, hundreds, and so on;

→ The digits to the right represent tenths, hundredths, thousandths, and so on.

→ Decimals allow us to represent quantities that are not whole numbers with greater precision, making them essential for measurements, money, and other real-world applications.

→ To convert a measurement from centimetres to metres in decimal form, divide the number of centimetres by 100. This is equivalent to moving the decimal point two places to the left.

→ If you have a combination of metres and centimetres, first convert the centimetres to metres as a decimal and then add them to the whole number of metres.

→ To convert a measurement from centimetres to millimetres, multiply the number by 10.

→ To convert from millimetres to centimetres, divide the number by 10.

→ To add decimal numbers representing measurements (like 4.3 cm and 2.5 cm), align the decimal points and add them directly.

→ Alternatively, you can convert the measurements to a smaller unit (like millimetres) and complete the addition, then convert the result back to the original unit.

→ To subtract a decimal from another (like subtracting 3.2 cm from 8.5 cm), you can convert both decimals to fractions with a common denominator, subtract them, and then convert the result back into a decimal.

This chapter comprehensively covers the representation and manipulation of numbers beyond whole units. Key topics include understanding decimal places to denote fractional parts, establishing the crucial relationship and conversion techniques between decimals and fractions, and mastering the fundamental operations of addition and subtraction of decimal numbers to build foundational arithmetic skills.

Decimal Places
The length of a pencil can be said in different ways:

• 5 centimetres 7 millimetres
• 5\(\frac {7}{10}\) centimetres
• 5.7 centimetres

We can write other measures also like this:
5\(\frac {7}{10}\) litres = 5.7 litres
5\(\frac {7}{10}\) kilograms = 5.7 kilograms

We can drop all references to measures and simply say that 5.7 is the decimal form of the number 5\(\frac {7}{10}\).
5\(\frac {7}{10}\) = 5.7
Similarly, 4.29 is the decimal form of 4\(\frac {29}{100}\)
4\(\frac {29}{100}\) = 4.29

We write natural numbers using ones, tens, hundreds, and so on.
For example: 247 = 2 hundreds + 4 tens + 7 ones
Splitting 247.3
Split it as the sum of a whole number and a fraction.
247.3 = 247\(\frac {3}{10}\) = 247 + \(\frac {3}{10}\)
First, we split 247.3 as the sum of a whole number and a fraction, as
247.3 = 247\(\frac {3}{10}\) = 247 + \(\frac {3}{10}\)
The \(\frac {3}{10}\) here can be written as
\(\frac{3}{10}=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}\)
That is, 3 tenths. So, we can write 247.3 in terms of hundreds, tens, ones, and tenths:
247.3 = 2 hundreds + 4 tens + 7 ones + 3 tenths

Splitting 247.39
First, we write it as
247.39 = 247\(\frac {39}{100}\)= 247 + \(\frac {39}{100}\)
Then, we can split \(\frac {39}{100}\) as
\(\frac{39}{100}=\frac{30+9}{100}=\frac{30}{100}+\frac{9}{100}=\frac{3}{10}+\frac{9}{100}\)
The \(\frac {3}{10}\) here is 3 tenths: and \(\frac {9}{100}\) is 9 hundredths.
So 247.39 = 2 hundreds + 4 tens + 7 ones + 3 tenths + 9 hundredths

In the decimal form of a number, the dot separates the whole number part and the fractional part. Digits to the left of the dot show the multiples of ones, tens, hundreds, and so on; the digits to the right show the multiples of tenths, hundredths, thousandths, and so on.
For example, the two numbers used in the above examples can be split according to place value like this:

Question 1.
What is the decimal form of 23 metres 40 centimetres?
Answer:
Method 1
23 metres 40 centimetres = 23\(\frac {40}{100}\) metres = 23.40 metres
Taking only the numbers, we have
23\(\frac {40}{100}\) = 23.40
We can write the \(\frac {40}{100}\) here as
\(\frac{40}{100}=\frac{4}{10}\)
So, we get 23\(\frac {40}{100}\) = 23\(\frac {4}{10}\) = 23.4
This means 23.40 = 23.4

Method 2
Using place value

Thus, we can write 23 metres and 40 centimetres in two different ways:
23 metres 40 centimetres = 23.40 metres
23 metres 40 centimetres = 23.4 metres

Question 2.
What is the decimal form of 23 metres 4 centimetres?
Answer:
4 centimetres = \(\frac {4}{100}\) metre.
23 metres 4 centimetres =23\(\frac {4}{100}\) metres
Split 23\(\frac {4}{100}\) according to place value:
23\(\frac {4}{100}\) = 2 tens + 3 ones + 4 hundredths

The decimal form of 23\(\frac {4}{100}\) = 23.04

Question 3.
What is the decimal form of 23 metres and 4 millimetres?
Answer:
4 millimetres means \(\frac {4}{1000}\) metres.
So 23 metres 4 millimetres = 23\(\frac {4}{1000}\) metres
Split 23\(\frac {4}{1000}\) according to place value.

So, we can write the decimal form of 23\(\frac {4}{1000}\) as
23\(\frac {4}{1000}\) = 23.004

Converting Centimetres to a Decimal Form of Metres
To convert centimetres to a decimal form of metres, first, write the number of metres as the whole number part of your decimal.
Next, express the number of centimetres as a fraction of a metre. Since there are 100 centimetres in 1 metre, the denominator of your fraction will be 100. For example, 40 centimetres would be written as \(\frac {40}{100}\) metres.
Combine the whole number and the fraction to create a mixed number, such as 23\(\frac {40}{100}\).
To get the decimal form, divide the numerator of your fraction by 100. This is the same as moving the decimal point two places to the left. So, \(\frac {40}{100}\) becomes 0.40.
Finally, add the decimal to the whole number.
For example, 23 + 0.40 = 23.40.
The result is the length in meters.

Decimals and Fractions
Conversion of decimals into fractions
Start with the decimal number you want to convert.

Example: 7.3 centimetres
Write this in millimetres
7 centimetres = 70 millimetres
To convert \(\frac {3}{10}\) centimetres into millimetres:
\(\frac {3}{10}\) is three \(\frac {1}{10}\)
\(\frac {3}{10}\) centimetres = 3 millimetres
7.3 centimetres = 70 millimetres + 3 millimetres

Converting 73 millimetres into centimetres:
Divide it by 10
73 millimetres = \(\frac {73}{10}\) centimetres
Removing measure and writing as just numbers 7.3 = \(\frac {73}{10}\)

Question 4.
How do we write 7.31 metres as a fraction?
Answer:
Write it as a whole number and a fraction
7.31 metres = 7\(\frac {31}{100}\) metres
7 metres = 700 centimetres
\(\frac {31}{100}\) metres = 31 centimetres
7.31 metres = 700 centimetres + 31 centimetres = 731 centimeters
Converting this into metres
731 centimetres = \(\frac {731}{100}\) metres
7.31 metres = \(\frac {731}{100}\) metres

Question 5.
Convert 7.319 litres as a fraction.
Answer:
7.319 litres = 7\(\frac {319}{1000}\) litres
7 litres = 7000 millilitres
\(\frac {319}{1000}\) litres = 319 millilitres
7.319 litres = 7319 millilitres
Converting back to litres
7319 millilitres = \(\frac {7319}{1000}\) litres
7.319 litres = \(\frac {7319}{1000}\) litres

Converting 12.03 to a Fraction

• Step 1: Count the digits after the decimal point in 12.03. There are two digits (0 and 3).
• Step 2: The denominator is 100 because there are two digits after the decimal.
• Step 3: Remove the decimal point from 12.03 to get the numerator, which is 1203.
• Step 4: The final fraction is \(\frac {1203}{100}\).

Question 6.
What is the decimal form of \(\frac {1203}{1000}\)?
Answer:
Looking at the denominator, we can say there will be three digits after the decimal point.
\(\frac {1203}{1000}\) = 1.203

Addition and Subtraction

Addition of Decimal Numbers
A line 4.3 centimetres long was drawn and then extended by another 2.5 centimetres:

To find the total length of the line we have to add 4.3 centimetres and 2.5 centimetres

Method 1
Convert these to centimetres and millimetres.
4.3 centimetres = 4 centimetres 3 millimetres
2.5 centimetres = 2 centimetres 5 millimetres
And add the centimetres and millimetres separately.
4 centimetres + 2 centimetres = 6 centimetres
3 millimetres + 5 millimetres = 8 millimetres
The length of the line is 6 centimetres, 8 millimetres
Convert back to centimetres.
6 centimetres 8 millimetres = \(\frac {68}{10}\) centimetres = 6.8 centimetres

Method 2
Write the lengths in millimetres.
4.3 centimetres = 43 millimetres
2.5 centimetres = 25 millimetres
Add 43 and 25
43 + 25 = 40 + 20 + 3 + 5 = 68
Thus, the length of the line is 68 millimetres
Write as centimetres in decimal form.
68 millimetres = 6 centimetres 8 millimetres = 6.8 centimetres

Method 3
Remove the measures and write the numbers as fractions.
4.3 = \(\frac {43}{10}\)
2.5 = \(\frac {25}{10}\)
And these fractions we can add like this:
\(\frac{43}{10}+\frac{25}{10}=\frac{43+25}{10}=\frac{68}{10}\)
Write the fraction as a decimal number
\(\frac {68}{10}\) = 6.8
The length of the line is 6.8 centimetres.

Question 7.
Add 4.3 centimetres and 2.8 centimetres.
Answer:
Changing the lengths into millimetres
4.3 centimetres = 43 millimetres
2.8 centimetres = 28 millimetres
Adding 43 and 28
43 + 28 = 40 + 20 + 3 + 8 = 60 + 11 = 71
Thus, the length of this line is 71 millimetres.
Write in centimetres as a decimal:
71 millimetres = 7 centimetres 1 millimetre = 7.1 centimetres
Convert the numbers to fractions
4.3 = \(\frac {43}{10}\)
2.8 = \(\frac {28}{10}\)
Add the fractions:
\(\frac{43}{10}+\frac{28}{10}=\frac{43+28}{10}=\frac{71}{10}\)
Convert the fraction back to the decimal form.
\(\frac {71}{10}\) = 7.1
The length of the line is 7.1 centimetres.

Question 8.
A jar contains 3.5 litres of oil, and 6.25 litres more is poured into it. How much oil does the jar contain now?
Answer:
Convert just the numbers to fractions:
3.5 = \(\frac {35}{10}\)
6.25 = \(\frac {625}{100}\)
We can write \(\frac {35}{10}\) also as a fraction with denominator 100:
\(\frac{35}{10}=\frac{35 \times 10}{10 \times 10}\) = \(\frac {350}{100}\)
Now we can add like this:
\(\frac{35}{10}+\frac{625}{100}=\frac{350}{100}+\frac{625}{100}=\frac{300+600+50+25}{100}\)
= \(\frac{350+625}{100}\)
= \(\frac {975}{100}\)
Amount of oil the jar contains = 9.75 litres

Question 9.
A person bought 2.5 kilograms of rice and 3.125 kilograms of vegetables. What is the total weight?
Answer:
Converting into fractions
2.5 = \(\frac {25}{10}\)
3.125 = \(\frac {3125}{1000}\)
To add these, we change \(\frac {25}{10}\) to a form with a denominator of 1000.
\(\frac{25}{10}=\frac{25 \times 100}{10 \times 100}\) = \(\frac {2500}{1000}\)
Now, we add the fractions:
\(\frac{25}{10}+\frac{3125}{1000}=\frac{2500}{1000}+\frac{3125}{1000}\) = \(\frac{2500+3125}{1000}\)
One way of adding 2500 and 3125 is this:
2500 + 3125 = 2000 + 3000 + 500 + 125 = 5000 + 625 = 5625
So, we can continue our addition of fractions:
\(\frac{25}{10}+\frac{3125}{1000}=\frac{2500+3125}{1000}\) = \(\frac {5625}{1000}\)
Converting this to decimals:
\(\frac {5625}{1000}\) = 5.625
Thus, the total weight is 5.625 kilograms.

Subtraction of Decimal Numbers
Example: From an 8.5 centimetres long eerkkil, a 3.2 centimetres long piece is broken off. What is the length of the remaining piece?
Thinking in terms of numbers alone, what we need is to subtract 3.2 from 8.5.
We change the numbers to fractions.
8.5 = \(\frac {85}{10}\)
3.2 = \(\frac {32}{10}\)
Now we can subtract:
\(\frac{85}{10}-\frac{32}{10}=\frac{85-32}{10}\)
One way to subtract 32 from 85 is this:
85 – 32 = (80 – 30) + (5 – 2) = 50 + 3 = 53
So we get \(\frac{85}{10}-\frac{32}{10}=\frac{53}{10}\)
Finally, we switch back to decimals:
\(\frac {53}{10}\) = 5.3
Thus, the length of the remaining piece of eerkkil is 5.3 centimetres.

Question 10.
From an 8.5 centimetres long eerkkil, a 3.7 centimetres long piece is broken off. What is the length of the remaining piece?
Answer:
We start as before by converting the decimals to fractions:
8.5 = \(\frac {85}{10}\)
3.7 = \(\frac {37}{10}\)
And then subtract
\(\frac{85}{10}-\frac{37}{10}=\frac{85-37}{10}\)
We have seen in earlier classes that subtraction like 85 different ways.
For example,
85 – 37 = (85 – 35) – 2 = 50 – 2 = 48
85 – 37 = (87 – 37) – 2 = 50 – 2 = 48
85 – 37 = (85 – 40) + 3 = 45 + 3 = 48
Anyway, we find
\(\frac{85}{10}-\frac{37}{10}=\frac{48}{10}\)
Changing back to decimals,
\(\frac {48}{10}\) = 4.8
The remaining piece of eerkkil is 4.8 centimetres long.

Question 11.
There are 15 kilograms of rice in a sack. 4.25 kilograms from this are put in a bag. How much rice remains in the sack?
Answer:
Thinking just in terms of numbers, what we have to do is subtract 4.25 from 15.
Write 4.25 as a fraction:
4.25 = \(\frac {425}{100}\)
Write 15 as a fraction with a denominator of 100.
15 = \(\frac{15}{1}=\frac{15 \times 100}{1 \times 100}=\frac{1500}{100}\)
Subtracting \(\frac{1500}{100}-\frac{425}{100}=\frac{1500-425}{100}\)
We can do 1500 – 425 in several ways:
1500 – 425 = 1000 + 500 – 425 = 1000 + 75 = 1075
1500 – 425 – 1425 – 425 + 75 = 1000 + 75 = 1075
1500 – 425 = 1500 – 500 + 75 = 1000 + 75 = 1075
Thus, we have:
\(\frac{1500}{100}-\frac{425}{100}=\frac{1075}{100}\)
Changing back to decimals:
\(\frac {1075}{100}\) = 10.75
So, there are 10.75 kilograms of rice still in the sack.

Students often refer to Kerala State Syllabus SCERT Class 6 Maths Solutions and Class 6 Maths Chapter 6 Multiples and Factors Questions and Answers Notes Pdf to clear their doubts.

SCERT Class 6 Maths Chapter 6 Solutions Multiples and Factors

Class 6 Kerala Syllabus Maths Solutions Chapter 6 Multiples and Factors Questions and Answers

Multiples and Factors Class 6 Questions and Answers Kerala Syllabus

Multiples of Multiples (Page No. 85)

Question 1.
For each of the multiples given below, find the other numbers they are multiples of:
(i) Multiples of 8
(ii) Multiples of 10
(iii) Multiples of 12
Answer:
(i) The factors of 8 are 2 and 4
8 is a multiple of 2 and 4
Therefore, the multiples of 8 are also the multiples of 2 and 4

(ii) The factors of 10 are 2 and 5
10 is a multiple of 2 and 5
Therefore, the multiples of 10 are also the multiples of 2 and 5

(iii) The factors of 12 are 2, 3, 4, and 6
12 is a multiple of 2, 3, 4, and 6
Therefore, the multiples of 12 are also the multiples of 2, 3, 4, and 6.

Question 2.
Check whether each of the statements below is true or false. For true statements, explain why they are so. For the false statements, give an example in which it is not true.
(i) All multiples of 20 are multiples of 10
(ii) All multiples of 10 are multiples of 2
(iii) All multiples of 15 are multiples of 5
(iv) All multiples of 15 are multiples of 3
(v) All multiples of 5 are multiples of 15
(vi) All multiples of 3 are multiples of 15
Answer:
(i) True
Since 20 = 2 × 10,
So every multiple of 20 is a multiple of 10.

(ii) True
Since 10 = 2 × 5,
So every multiple of 10 is a multiple of 2.
Or
Since 10 is an even number, and every multiple of 10 ends in 0, it is divisible by 2
That is, every multiple of 10 is also a multiple of 2.

(iii) True
Since 15 = 3 × 5,
So every multiple of 15 is a multiple of 5.

(iv) True
Since 15 = 3 × 5,
So every multiple of 15 is a multiple of 3.

(v) False
Not all multiples of 5 are divisible by 15.
E.g.: 10 is a multiple of 5 but not of 15.

(vi) False
Not all multiples of 3 are divisible by 15.
E.g.: 6 is a multiple of 3, but not a multiple of 15.

Primary Factors (Page No. 88)

Question 1.
Can you write the numbers below as a product of primes?
(i) 24
(ii) 35
(iii) 36
(iv) 60
(v) 100
Answer:
(i) 24 = 2 × 12
= 2 × 2 × 6
= 2 × 2 × 2 × 3
Therefore 24 = 2 × 2 × 2 × 3

(ii) 35 = 5 × 7

(iii) 36 = 2 × 18
= 2 × 2 × 9
= 2 × 2 × 3 × 3
Therefore 36 = 2 × 2 × 3 × 3

(iv) 60 = 2 × 30
= 2 × 2 × 15
= 2 × 2 × 3 × 5
Therefore 60 = 2 × 2 × 3 × 5

(v) 100 = 2 × 50
= 2 × 2 × 25
= 2 × 2 × 5 × 5
Therefore 100 = 2 × 2 × 5 × 5

Textbook Page No. 89

Question 1.
Write each of the numbers below as a product of primes.
(i) 72
(ii) 105
(iii) 144
(iv) 330
(v) 900
Answer:
(i) 72 = 12 × 6
12 = 2 × 2 × 3
6 = 2 × 3
Therefore, 72 = 2 × 2 × 2 × 3 × 3

(ii) 105 = 21 × 5
21 = 3 × 7
5 = 5
Therefore 105 = 3 × 5 × 7

(iii) 144 = 12 × 12
12 = 2 × 2 × 3
Therefore 144 = 2 × 2 × 3 × 2 × 2 × 3

(iv) 330 = 10 × 33
10 = 2 × 5
33 = 3 × 11
Therefore, 330 = 2 × 3 × 5 × 11

(v) 900 = 30 × 30
30 = 2 × 3 × 5
Therefore, 900 = 2 × 3 × 5 × 2 × 3 × 5

All Factors (Page No. 89)

Question 1.
Find all the factors of the number below:
(i) 35
(ii) 77
(iii) 26
(iv) 51
(v) 95
Answer:
(i) 35 = 1 × 35 = 5 × 7
Factors of 35 are: 1, 5, 7, and 35

(ii) 77 = 1 × 77 = 11 × 7
Factors of 77 are: 1, 7, 11, and 77

(iii) 26 = 1 × 26 = 2 × 13
Factors of 26 are: 1, 2, 13, and 26

(iv) 51 = 1 × 51 = 3 × 17
Factors of 51 are: 1, 3, 17, and 51

(v) 95 = 1 × 95 = 5 × 19
Factors of 95 are: 1, 5, 19, and 95

Textbook Page No. 90

Question 1.
Write each of the numbers below as a product of three primes and find all its factors:
(i) 66
(ii) 70
(iii) 105
(iv) 110
(v) 130
Answer:
(i) 66 is the product of three prime numbers.
66 = 2 × 3 × 11
Factors of 66 are:
1
2, 3, 11
2 × 3 = 6
2 × 11 = 22
3 × 11 = 33
Therefore, the factors are: 1, 2, 3, 6, 11, 22, 33, and 66

(ii) 70 as the product of three prime numbers.
70 = 2 × 5 × 7
Factors of 70 are:
1
2, 5, 7
2 × 5 = 10
2 × 7 = 14
5 × 7 = 35
Therefore, the factors are: 1, 2, 5, 7, 10, 14, 35, and 70

(iii) 105 is the product of three prime numbers.
105 = 3 × 5 × 7
Factors of 105 are:
1
3, 5, 7
3 × 5 = 15
3 × 7 = 21
5 × 7 = 35
Therefore, the factors are: 1, 3, 5, 7, 15, 21, 35, and 105

(iv) 110 as the product of three prime numbers.
110 = 2 × 5 × 11
Factors of 110 are:
1
2, 5, 11
2 × 5 = 10
2 × 11 = 22
5 × 11 = 55
Therefore, the factors are: 1, 2, 5, 10, 11, 22, 55, and 110

(v) 130 is the product of three prime numbers.
130 = 2 × 5 × 13
Factors of 130 are:
1
2, 5, 13
2 × 5 = 10
2 × 13 = 26
5 × 13 = 65
Therefore, the factors are: 1, 2, 5, 10, 13, 26, 65, and 130

Prime Numbers (Page No. 92)

Question 1.
Find all primes less than 100. Find the primes that differ by 2 among these.
Answer:
Prime numbers less than 100 are:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.
Prime numbers that differ by 2 are:
(3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), (71, 73)

Question 2.
Can the product of two natural numbers be a prime?
Answer:
The product of two natural numbers can only be a prime number if one of the numbers is 1 and the other is a prime.
If both numbers are greater than one, their product will always have more than two factors, so the result cannot be a prime.

Question 3.
Can the sum of two prime numbers be prime?
Answer:
Yes, sometimes, but not always.
If the sum of two prime numbers is a prime only when one of the numbers is 2 (the only even prime).
If 2 is added to an odd prime, the result is strange and may be prime.
But if two odd primes are added, the result is even and will never be a prime (except 2 + 2 = 4, which is not a prime number).

Class 6 Maths Chapter 6 Kerala Syllabus Multiples and Factors Questions and Answers

Class 6 Maths Multiples and Factors Questions and Answers

Question 1.
For each of the multiples given below, find the other numbers they are multiples of:
(i) Multiples of 15
(ii) Multiples of 21
(iii) Multiples of 33
Answer:
(i) The factors of 15 are 3 and 5.
15 is a multiple of 3 and 5.
Therefore, the multiples of 15 are also the multiples of 3 and 5.

(ii) The factors of 21 are 3 and 7.
21 is a multiple of 3 and 7.
Therefore, the multiples of 21 are also the multiples of 3 and 7.

(iii) The factors of are 3 and 11.
33 is a multiple of 3 and 11.
Therefore, the multiples of 33 are also the multiples of 3 and 11.

Question 2.
Write the numbers below as a product of primes?
(i) 18
(ii) 40
(iii) 150
(iv) 210
(v) 300
Answer:
(i) 18 = 2 × 9 = 2 × 3 × 3
Therefore 18 = 2 × 3 × 3

(ii) 40 = 2 × 20
= 2 × 2 × 10
= 2 × 2 × 2 × 5
Therefore 40 = 2 × 2 × 2 × 5

(iii) 150 = 2 × 75
= 2 × 3 × 25
= 2 × 3 × 5 × 5
Therefore 150 = 2 × 3 × 5 × 5

(iv) 210 = 2 × 105
= 2 × 3 × 35
= 2 × 3 × 5 × 7
Therefore 210 = 2 × 3 × 5 × 7

(v) 300 = 2 × 150
= 2 × 2 × 75
= 2 × 2 × 3 × 25
= 2 × 2 × 3 × 5 × 5
Therefore 300 = 2 × 2 × 3 × 5 × 5

Question 3.
Write the following numbers as the product of three prime numbers, and find all the factors of them.
(i) 174
(ii) 385
(iii) 182
Answer:
(i) 174 is the product of three prime numbers.
174 = 2 × 3 × 29
Factors of 174 are:
1
2, 3, 29
2 × 3 = 6
2 × 29 = 39
3 × 29 = 78
Therefore, the factors are: 1, 2, 3, 6, 29, 58, 87, 174

(ii) 385 is the product of three prime numbers.
385 = 5 × 7 × 11
Factors of 385 are:
1
5, 7, 11
5 × 7 = 35
5 × 11 = 55
7 × 11 = 77
Therefore, the factors are: 1, 5, 7, 11, 35, 55, 77, 88, and 385.

(iii) 182 as the product of three prime numbers.
182 = 2 × 7 × 13
Factors of 182 are:
1
2, 7, 13
2 × 7 = 14
2 × 13 = 26
7 × 13 = 91
Therefore, the factors are: 1, 2, 7, 13, 14, 26, 91, and 182.

Class 6 Maths Chapter 6 Notes Kerala Syllabus Multiples and Factors

→ The multiples of a natural number are the product of that number with the natural numbers 1, 2, 3,…

→ All multiples of the multiple of a number are also multiples of that number.

→ All multiples of a number are also multiples of any of its factors.

→ A natural number greater than 1, which has no factors other than 1 and itself, is called a prime number.

→ Any composite number can be written as a product of primes.

→ The only even number among the prime numbers is 2.

Multiples and factors are fundamental concepts in mathematics that help us understand the relationships between numbers. A multiple of a number is the result of multiplying that number by any natural number, while a factor is a number that divides another number exactly, without leaving a remainder.

For example, 4 is a multiple of 2, and 2 is a factor of 4. Learning about multiples and factors is essential for solving problems involving divisibility, simplifying fractions, finding the greatest common factor (GCF), the least common multiple (LCM), and much more. In this chapter, we discuss multiples of multiples, primary factors, and prime numbers.

Multiples of Multiples
The multiples of a natural number are the product of that number with the natural numbers 1, 2, 3,…
For example:
The multiples of 2 are the numbers 2, 4, 6,… obtained by multiplying the natural number by 2.
The multiples of 4 are the numbers 4, 8, 12,… obtained by multiplying the natural number by 4.
Here, all the multiples of 4 can be written as multiples of 2 also:
1 × 4 = 4
2 × 4 = 8
3 × 4 = 12
4 × 4 = 16
5 × 4 = 20
……………

2 × 2 = 4
4 × 2 = 8
6 × 2 = 12
8 × 2 = 16
10 × 2 = 20
……………….

Similarly, if 6 is a multiple of 2 and 3.
So all multiples of 6 can be written as multiples of 2 and 3.

1 × 6 = 6
2 × 6 = 12
3 × 6 = 18
4 × 6 = 24
5 × 6 = 30
………………..

3 × 2 = 6
6 × 2 = 12
9 × 2 = 18
12 × 2 = 24
15 × 2 = 30
………………….

2 × 3 = 6
4 × 3 = 12
6 × 3 = 18
8 × 3 = 24
10 × 3 = 30
………………..

In general, all multiples of the multiple of a number are also multiples of that number.

The multiples of 15 can be written as the multiples of what numbers?
Answer:
15 is a multiple of 3 and 5.
So the multiples of 10 can be written as the multiples of 2 and 5.

We have seen that multiples can also be put in terms of factors.
For example:
4 is the multiple of 2 can also be written as 2 is a factor of 4.
6 is the multiple of 2 and 3 can also be written as 2 and 3 are two factors of 6.
12 is a multiple of 3, and 4 can also be written as 3 and 4 are factors of 12.

In general, we can say that all multiples of a number are also multiples of any of its factors.

14 is a multiple of 2 and 7. Express it in the form of factors.
Answer:
14 is a multiple of 2 and 7.
Since, 2 × 7 = 14
So 2 and 7 are two factors of 14.

70 is a multiple of 2, 5, and 7. Express it in the form of factors.
Answer:
70 is a multiple of 2, 5, and 7.
Since, 2 × 5 × 7 = 70
So 2, 5, and 7 are the factors of 70.

If 2, 3, and 7 are factors of a number. Then what is that number?
Answer:
2, 3, and 7 are factors of a number.
That means 2 × 3 × 7 = 42
Therefore, the number is 42, and multiples of 42 are 2, 3, and 7.

Primary Factors
Any number can be written as the product of its factors in different ways.
For example, consider the number 70,
1 × 70 = 70
2 × 35 = 70
5 × 14 = 70
10 × 7 = 70
We can write 70 as a product of three factors, without using 1:
That is 70 = 2 × 5 × 7
The only factors of each of the numbers 2, 5, and 7 are 1 and the number itself.
For any number 1, the number itself is are factor.

The numbers below 20 with factors 1 and itself are: 1, 2, 3, 5, 7, 11, 13, 17, 19.
Such numbers, excluding 1, are said to be prime numbers.

A natural number greater than 1, which has no factors other than 1 and itself, is called a prime number.

Numbers greater than 1, which are not primes, are called composite numbers.
For example, 4 is a composite number.
Since 4 = 2 × 2

A composite number can be written as the product of a prime number.

When a number is written as the product of two factors and any one of them is not a prime, then that factor can be written as the product of two factors. This can continue till all factors are prime.

Write 48 as the product of primes.
Answer:
48 = 2 × 24
= 2 × 2 × 12
= 2 × 2 × 2 × 6
= 2 × 2 × 2 × 2 × 3
Therefore 48 = 2 × 2 × 2 × 2 × 3

Write the following as the product of primes.
(i) 30
(ii) 45
(iii) 64
Answer:
(i) 30 = 2 × 15 = 2 × 3 × 5
Therefore 30 = 2 × 3 × 5

(ii) 45 = 5 × 9 = 5 × 3 × 3
Therefore 45 = 5 × 3 × 3

(iii) 64 = 2 × 32
= 2 × 2 × 16
= 2 × 2 × 2 × 8
= 2 × 2 × 2 × 2 × 4
= 2 × 2 × 2 × 2 × 2 × 2
Therefore 64 = 2 × 2 × 2 × 2 × 2 × 2

Product of Primes:
Once we write two numbers as a product of primes, it is easy to write the product of these numbers also as a product of primes.
For example: 12 × 24 can be split like this:
12 = 2 × 2 × 3
24 = 2 × 2 × 2 × 3
Split 12 × 24 as shown below:
288 = 12 × 24
= (2 × 2 × 3) × (2 × 2 × 2 × 3)
= 2 × 2 × 3 × 2 × 2 × 2 × 3

To split a number into a product of primes, we first split it into the product of any two factors, then split each of these factors into a product of primes, and finally put these prime factors together.
For example: Split 140 into a product of primes,
140 = 14 × 10
Next, write 14 and 10 as products of primes
14 = 2 × 7
10 = 2 × 5
We can write 140 like this;
140 = 14 × 10
= (2 × 7) × (2 × 5)
= 2 × 2 × 5 × 7

Split the following numbers into a product of primes.
(i) 420
(ii) 180
(iii) 336
Answer:
(i) 420 = 15 × 28
15 = 3 × 5
28 = 2 × 2 × 7
Therefore, 420 = 2 × 2 × 3 × 5 × 7

(ii) 180 = 12 × 15
12 = 2 × 2 × 3
15 = 3 × 5
Therefore 180 = 2 × 2 × 3 × 3 × 5
(iii) 336 = 14 × 24
14 = 2 × 7
24 = 2 × 2 × 2 × 3
Therefore, 336 = 2 × 2 × 2 × 2 × 3 × 7

All Factors
If we know the prime factors of a number, we can find all its factors.
For example, the factors of 6 are: 1, 2, 3, and 6.

Write the prime factors of 15. And what are its other factors?
Answer:
Prime factors of 15 are: 3 and 5
Factors of 15 are: 1, 3, 5, and 15

Find all the factors of the numbers given below:
(i) 42
(ii) 54
(iii) 63
Answer:
(i) 42 = 1 × 42
= 2 × 21
= 3 × 14
= 6 × 7
Therefore, factors of 42 are: 1, 2, 3, 6, 7, 14, 21, and 42.

(ii) 54 = 1 × 54
= 2 × 27
= 3 × 18
= 6 × 9
Therefore, factors of 54 are: 1, 2, 3, 6, 9, 18, 27, and 54.

(iii) 63 = 1 × 63
= 3 × 21
= 7 × 9
Therefore, factors of 63 are: 1, 3, 7, 9, 21, and 63.

Product of Three Prime Numbers:
Now let’s look at the product of three different primes.

Write 42 as the product of three prime numbers and find all the factors?
Answer:
42 as the product of three prime numbers,
42 = 2 × 3 × 7
Factors of 42 are:
1
2, 3, 7
2 × 3 = 6
2 × 7 = 14
3 × 7 = 21
Therefore, the factors are: 1, 2, 3, 6, 7, 14, 21, and 42

Write the following numbers as the product of three prime numbers, and find all the factors of it?
(i) 102
(ii) 154
(iii) 195
Answer:
(i) 102 is the product of three prime numbers.
102 = 2 × 3 × 17
Factors of 102 are:
1
2, 3, 17
2 × 3 = 6
2 × 17 = 34
3 × 17 = 51
Therefore, the factors are: 1, 2, 3, 6, 17, 34, 51, and 102

(ii) 154 is the product of three prime numbers.
154 = 2 × 7 × 11
Factors of 154 are:
1
2, 7, 11
2 × 7 = 14
2 × 11 = 22
7 × 11 = 77
Therefore, the factors are: 1, 2, 7, 11, 14, 22, 77, and 154.

(iii) 195 as the product of three prime numbers.
195 = 3 × 5 × 13
Factors of 195 are:
1
3, 5, 13
1 × 5 = 15
3 × 13 = 39
5 × 13 = 65
Therefore, the factors are: 1, 3, 5, 13, 15, 39, 65, and 195

Prime Numbers
The only even number among the prime numbers, 2, 3, 5, 7, 11,… is 2.
All primes afterwards are odd numbers. But not all odd numbers are primes;
For example: 9 = 3 × 3, 15 = 3 × 5,……. They are not prime numbers.

There is no definite pattern for the odd primes.
For example, after 3, 5, 7 are consecutive primes that differ by 2, the next prime is not 9 (which is not a prime), but 11. Thus, the difference between 7 and 11 is 4. Similarly, after the prime 31, the next prime is 37, and their difference is 6; the prime after 89 is 97, with a difference of 8. But even as such consecutive primes drift further apart, there are consecutive primes like 41 and 43 or 71 and 73 in between, which are only 2 apart. There is a technique to list all primes less than a specified number. That is, first write all numbers up to 50 in rows and columns like this:

Strike off 1 from this. Then strike off all multiples of 2, except 2:

Keep 3 and strike off all multiples of 3:

Strike all multiples of 5, except 5 itself.
If we remove the multiples of 7 other than itself also, we can see that there are no multiples, except themselves, of the other numbers that remain:

Now the numbers not struck off are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47.
These are the prime numbers less than 50.